Introduction to Nanomechanics (Spring 2012) Martino Poggio Preliminary Logistics and Introduction Course outline and expectations; What is nanomechanics? Why study nanomechanics? People • Course Leader/Lectures: – Martino Poggio • Teaching Assistants/Exercise Sessions: – Michele Montinaro – Fei Xue – Gunter Wüst – Jonathan Prechtel 21.02.2012 Introduction to Nanomechanics 3 Format and requirements • Language: English • Prerequisites: Physics III; course-work in solidstate physics and statistical mechanics • Lectures: 10-12 on Tues. (21.02-29.05.2012) • Exercise Sessions: 13-14 on Wed. • Assignments: exercises and reading of current papers • Final paper: 4-5 page report on significant experimental paper due on 29.06.2012 • Grading: Pass/fail 21.02.2012 Introduction to Nanomechanics 4 Literature • Foundations of Nanomechanics, A. N. Cleland (Springer, 2003) • Fundamentals of Statistical and Thermal Physics, F. Reif (McGraw-Hill, 1965) • Original papers from Nature, Science, Physical Review Letters, Applied Physics Letters, Review of Scientific Instruments, Physics Today, etc. 21.02.2012 Introduction to Nanomechanics 5 Website http://poggiolab.unibas.ch/NanoMechSpring2012.htm • Overview • Format and Requirements • Schedule – Lecture content – Exercise session • Documents (PDF) – Optional reading • Documents (PDF) 21.02.2012 Introduction to Nanomechanics 6 http://poggiolab.unibas.ch/NanoMechSpring2012.htm 21.02.2012 Introduction to Nanomechanics 7 http://poggiolab.unibas.ch/NanoMechSpring2012.htm 21.02.2012 Introduction to Nanomechanics 8 What is nanomechanics? • Well… it’s the study of the mechanical properties of very very small things • A nanometer is 10-9 meters 1 nm = 0.000000001 m 100,000 nm ≈ diameter of a human hair 1 nm ≈ diameter of 10 atoms 21.02.2012 Introduction to Nanomechanics 9 Size scales Visible light 0.4 DNA - 0.8 mm Matterhorn Basel 2.5 nm 1.0 km RedThe Hblood atom suncell Proton 50 mm pm 1.2 10 Average Mm man 1.75 fm 1.4 Gm 1.75 m Lecce Dog flea 2 mm BIG small 109 m 106 m 103 m 100 m 10-3 m 10-6 m 10-9 m 10-12 m 10-15 m Gm Mm km m mm mm nm pm fm 21.02.2012 Introduction to Nanomechanics 10 (Macro)mechanics Nanomechanics 109 m 106 m 103 m 100 m 10-3 m 10-6 m 10-9 m 10-12 m 10-15 m Gm Mm km m mm mm nm pm fm 21.02.2012 Introduction to Nanomechanics 11 How is nanomechanics different than (macro)mechanics? • Thermal fluctuations significantly affect the motion of small bodies • Quantum mechanical fluctuations affect the motion of even bodies smaller 21.02.2012 Introduction to Nanomechanics 12 Brownian motion Fat droplets suspended in milk through a 40x objective. The droplets are 0.5 - 3.0 mm in size. 21.02.2012 Introduction to Nanomechanics 13 Thermal energy Particle mass Boltzmann constant 1 3 2 m v k BT 2 2 Mean square velocity Temperature 21.02.2012 Introduction to Nanomechanics 14 Brownian motion Mean square displacement (a measure of the size of the fluctuations) r 2 k BT t a Viscosity of medium 21.02.2012 Introduction to Nanomechanics Elapsed time Particle radius 15 Cantilever F x F kx Spring constant 21.02.2012 k Introduction to Nanomechanics wt l 3 3 16 Cantilever F k BT x F kxk x 2 3 1 2 2 1 l xk x kBT k B3T 2 2 wt Mean square displacement 21.02.2012 Introduction to Nanomechanics 17 1st mode 21.02.2012 Introduction to Nanomechanics 18 (Macro)mechanics L=2m w = 100 mm t = 50 mm ESS = 200 GPa k xth = 0.2 pm Ewt 3 for T = 300 K 4L3 k = 78 kN/m xth 21.02.2012 x 2 kB T k Introduction to Nanomechanics 19 Nanomechanics L = 120 mm w = 3 mm t = 100 nm ESi = 169 GPa k xth = 8 nm Ewt 3 for T = 300 K 4L3 k = 73 mN/m xth 21.02.2012 x 2 kB T k Introduction to Nanomechanics 20 Quantum fluctuations Zero point fluctuations 21.02.2012 xZPF 2mmk x ZPF l Mass wt Introduction to Nanomechanics Planck constant Resonant frequency 2 21 (Macro)mechanics l=2m w = 100 mm t = 50 mm ESS = 200 Gpa r = 7.85 g/cm3 k xZPF = 0.2 am xZPF = 0.2 x 10-18 m Ewt 3 4l 3 k = 78 kN/m m rlwt 4 xZPF 2 mk m = 20 kg 21.02.2012 Introduction to Nanomechanics 22 Nanomechanics L = 120 mm w = 3 mm t = 100 nm ESi = 169 Gpa r = 2.3 g/cm3 k xZPF = 0.2 pm xZPF = 0.2 x 10-12 m Ewt 3 4l 3 k = 73 mN/m m rlwt 4 xZPF 2 mk m = 20 pg 21.02.2012 Introduction to Nanomechanics 23 Carbon nanotube m = 10-21 kg = 2 x 500 MHz xZPF = 4 pm xZPF = 4 x 10-12 m xZPF 21.02.2012 2 mk Introduction to Nanomechanics 24 Quantum fluctuations of a drum Lehnert, 2011 21.02.2012 Introduction to Nanomechanics 25 Why study nanomechanics? • Link between classical mechanics and statistical mechanics • Link between classical mechanics and quantum mechanics • Smaller sensors are more sensitive 21.02.2012 Introduction to Nanomechanics 26 What is nanomechanics good for? • Smaller sensors are more sensitive! – Measurement of displacement – Measurement of mass – Measurement of force – Measurement of charge – Measurement of magnetic moment 21.02.2012 Introduction to Nanomechanics 27 Atomic force microscopy (AFM) Si (111) (AFM) Giessibl, 2000 DNA (AFM) 10 nm Magnetic Bits (MFM) Hamon, 2007 500 nm Folks, 2000 10 mm 21.02.2012 Introduction to Nanomechanics 28 Scanning tunneling microscopy (STM) Eigler, 1993 21.02.2012 Introduction to Nanomechanics 29 Quantum effects Quantum of Thermal Conductance Schwab et al., 2000 21.02.2012 Casimir Force Measurement Decca, 2003 Introduction to Nanomechanics 30 Weighing a single atom Zettl, 2008 31 Measuring a single electron spin Rugar, 2004 21.02.2012 Introduction to Nanomechanics 32 Nano-magnetic resonance imaging (nanoMRI) Degen, 2009 50 nm 21.02.2012 Introduction to Nanomechanics 33 Cantilever Basics (statics) 21.02.2012 Introduction to Nanomechanics 34