6.2 Properties of Exponents Lesson 6.2, For use with pages 420-427 Simplify the expression. 1. 43 • 48 ANSWER 411 85 2. 8–4 ANSWER 89 Lesson 6.2, For use with pages 420-427 Simplify the expression. 3. √48 ANSWER 4√3 4. √30 • √15 ANSWER 15√2 Lesson 6.2, For use with pages 420-427 Simplify the expression. 5. √80 – √20 ANSWER 2√5 EXAMPLE 1 Use properties of exponents Use the properties of rational exponents to simplify the expression. a. 71/4 71/2 = 73/4 = 7(1/4 + 1/2) b. (61/2 41/3)2 = (61/2)2 (41/3)2 c. (45 35)–1/5 = [(4 3)5]–1/5 = 6(1/2 2) 4(1/3 2) = (125)–1/5 = 12[5 (–1/5)] = 61 42/3 = 12 –1 = 6 42/3 = 1 12 d. 5 = 51/3 e. 51 = 52/3 51/3 421/3 2 61/3 = 5(1 – 1/3) = 42 6 1/3 2 = (71/3)2 = 7(1/3 2) = 72/3 EXAMPLE 2 Apply properties of exponents Biology A mammal’s surface area S (in square centimeters) can be approximated by the model S = km2/3 where m is the mass (in grams) of the mammal and k is a constant. The values of k for some mammals are shown below. Approximate the surface area of a rabbit that has a mass of 3.4 kilograms (3.4 103 grams). EXAMPLE 2 Apply properties of exponents SOLUTION S = km2/3 ANSWER Write model. = 9.75(3.4 103)2/3 Substitute 9.75 for k and 3.4 103 for m. = 9.75(3.4)2/3(103)2/3 Power of a product property. 9.75(2.26)(102) Power of a product property. 2200 Simplify. The rabbit’s surface area is about 2200 square centimeters. GUIDED PRACTICE for Examples 1 and 2 Use the properties of rational exponents to simplify the expression. 1. (51/3 71/4)3 SOLUTION 5 73/4 2. 23/4 21/2 SOLUTION 25/4 SOLUTION 33/4 SOLUTION 8 3. 3 31/4 4. 201/2 51/2 3 GUIDED PRACTICE for Examples 1 and 2 Biology 5. Use the information in Example 2 to approximate the surface area of a sheep that has a mass of 95 kilograms (9.5 104 grams). SOLUTION 17,500 cm2 EXAMPLE 3 Use properties of radicals Use the properties of radicals to simplify the expression. 3 a. b. 4 4 12 80 5 3 18 = = 4 3 80 5 12 8 = 4 = 16 3 = 216 = 6 2 Product property Quotient property EXAMPLE 4 Write radicals in simplest form Write the expression in simplest form. a. 3 135 3 = 27 5 = 27 3 3 = 3 3 5 5 Factor out perfect cube. Product property Simplify. EXAMPLE 4 Write radicals in simplest form 5 b. 7 5 8 = 5 7 5 5 5 8 4 4 Make denominator a perfect fifth power. 5 28 = 5 32 Product property 5 28 = 2 Simplify. EXAMPLE 5 Add and subtract like radicals and roots Simplify the expression. 4 4 + 7 10 = (1 + 7) 4 10 b. 2 (81/5) + 10 (81/5) = (2 +10) c. 3 3 3 54 – 2 = 27 4 10 = 8 10 a. (81/5) = 12 (81/5) 3 3 3 2 – 2 = 3 2 – 2 = (3 – 1) 3 3 2 = 2 3 2 for Examples 3, 4, and 5 GUIDED PRACTICE Simplify the expression. 6. 4 27 4 3 8. 5 3 4 5 SOLUTION 3 24 SOLUTION 2 7. 3 250 9. 3 5 3 + 40 3 2 SOLUTION 5 SOLUTION 3 3 5 EXAMPLE 6 Simplify expressions involving variables Simplify the expression. Assume all variables are positive. 3 a. 3 b. (27p3q12)1/3 4 c. d. m4 n8 3 = 43(y2)3 64y6 14xy 1/3 2x 3/4 z –6 (y2)3 = 271/3(p3)1/3(q12)1/3 4 = 3 = 43 4 m4 n8 4 = m4 4 (n2)4 = 7x(1 – 3/4)y1/3z –(–6) = = 3p(3 = 4y2 1/3)q(12 1/3) m n2 = 7x1/4y1/3z6 = 3pq4 EXAMPLE 7 Write variable expressions in simplest form Write the expression in simplest form. Assume all variables are positive. a. 5 5 4a8b14c5 = 4a5a3b10b4c5 5 = a5b10c5 b. 3 x y8 3 = = 3 5 4a3b4 5 = ab2c 4a3b4 x y y8 y Product property Simplify. Make denominator a perfect cube. xy y9 Factor out perfect fifth powers. Simplify. EXAMPLE 7 Write variable expressions in simplest form 3 = xy 3 Quotient property y9 3 = xy y3 Simplify. EXAMPLE 8 Add and subtract expressions involving variables Perform the indicated operation. Assume all variables are positive. a. b. c. 1 3 w + w = 5 5 3xy1/4 – 8xy1/4 3 3 1 + 5 5 w = (3 – 8) xy1/4 3 12 2z5 – z 54z2 = 4 w 5 = –5xy1/4 3 3 = 12z 2z2 – 3z 2z2 3 = (12z – 3z) 2z2 3 = 9z 2z2 for Examples 6, 7, and 8 GUIDED PRACTICE Simplify the expression. Assume all variables are positive. 10. 3 27q9 SOLUTION 11. 5 12. 3q3 x10 3x 1/2 y 1/2 SOLUTION 13. y5 SOLUTION 6xy 3/4 x2 y 2x1/2y1/4 9w5 – w w3 SOLUTION 2w2 w