Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker Which ones are you using? PLT Skills LESSON OBJECTIVES Always aim high! We are learning to: - Finding connections between different words. (Which PLT skills?) - Accurately solve equations, one linear and one nonlinear, with graphs. (Grades A/A*) Where are we in our journey? AUTHOR www.mistrymaths.co.uk Real life cross/curricular links? Creative Thinker PLT Skills Effective Participator Independent Enquirer Reflective Learner BRAIN IN GEAR Self Manager Team Worker Which ones are you using? EXAMPLE DITDIONA can be rearranged to make ADDITION TASK Work out the following Mathematical anagrams: UCIADRQAT Quadratic SADIUR Radius NINETIORDESCT Intersection EXTENSION Develop your own Mathematical anagrams as above as a creative thinker. Creative Thinker PLT Skills Effective Participator TASK 1) Find the area of: 7cm 8cm Independent Enquirer Reflective Learner STARTER standard form -4 = 2.3 x 10 86° 130° 115° Pentagon adds to = ( 540° x = 540°- 140°- 130°- 115°- 86° x = 69° 4x - 6 x + 23 2x + 4 3x + 9 + 2x + 4+ 4x - 6 + x + 23 = 360 = 360 10x + 30 10x 5) Value of: Reciprocal 3x + 9 - 30 12 x 8 Area of a triangle = 2 Area of a triangle = 48cm2 140° Which ones are you using? 2) Write 0.00023 in 3) 12cm x Team Worker Work out x: 5cm 4) Work out x: Self Manager 9 - 3 2 EXTENSION Power Root 1 9 )3 1 33 1 = 27 = 9m ÷ 10 x = 33° 6m x Work out x: x 6 x x = 330° ÷ 10 7m 2m - 30 11 2 11 x6 = 2 = = 33m Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? Quadratic Linear EXAMPLE 1 1) Find the approximate solutions to the pair of equations y = x2 + x – 2 and y = 2x + 3 by graphical means. Set up a table for the quadratic and linear equations (get the x values from the x-axis) Table for quadratic x y = x2 + x – 2 0 -2 -2 0 4 10 18 10 4 Substitute in the x values and work out y 222222 (4) (1) (4) (1) ----222-2- 2 (-4) (-4) (0) (0) (-2) (-2) (3) (3) (-3) (-3) (2) (2) (-1)++++++ (-1) 12 19 16 0 4+-+ =====16 --313 2404----2 49 1 1222 -+ Table for linear y = 2x + 3 -5 -3 -1 1 3 5 7 9 11 Substitute in the x values and work out y 2(-3) 2(2) 2(-1) 2(-4)++33 2(3) 2(4) 2(-2) 2(0) 2(1) -6 4 -2 -8++++3333 0 8 -4 2 == 6 Approximate solutions → (-1.8,-0.6) (2.8,8.6) x x x x x x x x x x x x x x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 1) Find the approximate solutions to the pair of equations y = x2 + 3x – 2 and y = x by graphical means. Table for quadratic 2 -2 -4 -4 y = x2 + 3x – 2 -2 2 8 x 16 26 x Table for linear y = x -4 -3 -2 -1 x x x x 0 1 2 3 4 Approximate solutions → (0.7,0.7)(-2.7,-2.7) x x x x x x x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 2) Find the approximate solutions to the pair of equations y = x2 - 3x – 6 and y = 2x by graphical means. y = x2 - 3x – 6 Table for quadratic x 22 4 -6 -8 -2 12 34 x x Table for linear y = 2x x x -8 -4 0 4 8 12 16 x x x Approximate solutions → (-1,-2) (6,12) x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 3) Find the approximate solutions to the pair of equations y = x2 - 3x + 1 and y = 2x - 1 by graphical means. Table for quadratic x x y = x2 - 3x + 1 x 1 -1 -1 1 5 11 19 x x x Table for linear y = 2x - 1 x -1 1 3 5 7 9 11 x x x x x Approximate solutions → (0.5,0) (4.6,8.2) x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 4) Find the approximate solutions to the pair of equations y = x2 - 3 and y = x + 3 by graphical means. Table for quadratic x y = x2 - 3 x x x 22 13 6 1 -2 -3 -2 1 6 13 22 x x Table for linear y = x + 3 x x -2 -1 0 1 2 3 4 x 5 6 7 8 x x x Approximate solutions → (-2,1)(3,6) x x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 5) Find the approximate solutions to the pair of equations y = x2 - 3x - 2 and y = 2x - 3 by graphical means. Table for quadratic y = x2 - 3x - 2 x x 38 26 16 6 2 -2 -4 -4 -2 2 8 x x Table for linear y = 2x - 3 x x x x -13 -11 -9 -7 -5 -3 -1 1 3 5 7 x x Approximate solutions → (0.2,-2.6)(4.8,6.6) x x x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner PLT Skills SOLVING BY GRAPHING EQUATION OF A CIRCLE Equation of a circle → x2 + y2 = r 2 Self Manager Team Worker Which ones are you using? with centre (0,0) Radius of a circle Draw the circles of the equations given below: 2 2 2 2 2 2 x + y = 5 (b) (a) x + y = 3 Radius of circle Radius of circle Creative Thinker Effective Participator Independent Enquirer Reflective Learner PLT Skills SOLVING BY GRAPHING EQUATION OF A CIRCLE Equation of a circle → x2 + y2 = r 2 Self Manager Team Worker Which ones are you using? with centre (0,0) Radius of a circle Draw the circles of the equations given below: 2 2 2 2 2 2 x + y = 49 (d) 7 Radius = 7 (c) x + y = 16 4 Radius = 4 Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 1) Find the approximate solutions to the pair of equations x2 + y 2 = 25 and y = 1 - x by graphical means. Table for linear y = 1 - x x 7 6 5 4 3 2 1 0 -1 -2 -3 -4 -5 Radius for circle x 2 + y 2 = 25 2 5 Radius = 5 x x x x x x x x x x x Approximate solutions → (-3,4)(4,-3) Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 2) Find the approximate solutions to the pair of equations x2 + y 2 = 4 and y = x + 1 by graphical means. Table for linear y = x + 1 x -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 Radius for circle x 2 + y 2 = 4 x 2 2 x Radius = 2 x x x x Approximate solutions → (-1.8,-0.8)(0.8,1.8) x x x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 3) Find the approximate solutions to the pair of equations x2 + y 2 = 9 and y = x - 1 by graphical means. Table for linear y = x - 1 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 Radius for circle x 2 + y 2 = 9 x 2 3 x Radius = 3 x x x x x x x Approximate solutions → (-1.6,-2.6)(2.6,1.6) x x x Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? EXTENSION (GRADE A*) 1) (a) Find the approximate solutions to the pair of equations y = x 2 + 3x - 4 and y = 5x - 5 by graphical means. (b) What is special about the intersection of the two graphs? (c) Show that 5x – 5 = x2 + 3x – 4 can be re-arranged to x2 - 2x + 1 = 0 (d) Factorise and solve x2 – 2x + 1 = 0 (e) Explain how the solution in part (d) relates to the intersection of the graphs. 2) (a) Find the approximate solutions to the pair of equations y = x 2 + 2x + 3 and y = x - 1 by graphical means. (b) What is special about the intersection of the two graphs? (c) Rearrange x – 1 = x2 + 2x + 3 into the form ax 2 + bx + c = 0 (d) Work out the discriminant b2 – 4ac for the quadratic on part (c) (e) Explain how the discriminant relates to the intersection of the graphs. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? EXTENSION ANSWERS(GRADE A*) 1) (a) Find the approximate solutions to the pair of equations y = x 2 + 3x - 4 and y = 5x - 5 by graphical means. (1,0) There is only one point of intersection. x2 + 3x – 5x - 4 + 5 = 0 x2 – 2x + 1 = 0 (x - 1 )(x - 1 ) = 0 x–1=0 +1 x +1 =1 Only one solution as the line is a tangent to the curve. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? EXTENSION ANSWERS(GRADE A*) 2) (a) Find the approximate solutions to the pair of equations y = x 2 + 2x + 3 and y = x - 1 by graphical means. There is no solution. The graphs do not intersect. x2 + 2x – x + 3 + 1 = 0 x2 + x + 4 = 0 x2 + x + 4 = 0 a=1 b=1 c=4 2 b - 4ac = 12 - 4 x 1 x 4 = -15 The discriminant is negative and you cannot find the square root of a negative number. Therefore, there are no solutions. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills TRIGONOMETRIC ANGLES Which ones are you using? MINI-PLENARY 1 – SPOT THE MISTAKE Find the approximate solutions to the pair of equations y = x2 - 2x - 1 and y = 2x - 2 by graphical means. Table for quadratic y = x2 - 2x - 1 x 34 23 14 8 2 -1 -2 0 2 7 -1 7 16 x x x 14 Table for linear y = 2x - 2 x x x x -12 -6 -8 -6 -4 0 0 2 5 6 8 -10 -2 4 x x x x x Approximate solutions → (0.3,-1.5) (3.7,5.5) x Creative Thinker PLT Skills Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker SOLVING BY GRAPHING Which ones are you using? MINI-PLENARY 2 – SPOT THE MISTAKE Find the approximate solutions to the pair of equations x2 + y 2 = 4 and y = x + 1 by graphical means. Table for linear y = x + 1 x -5 -4 -3 -2 -1 0 -1 2 3 4 5 6 7 Radius for circle x 2 + y 2 = 4 x x 2 2 x Radius = 2 x x x x x x Approximate solutions → (-3.2,-2.2)(2.2,3.2) (-1.8,-0.8)(0.8,1.8) x x x Creative Thinker PLT Skills Effective Participator Independent Enquirer Reflective Learner DISCOVERY Self Manager Team Worker Which ones are you using? LINK BACK TO OBJECTIVES - Accurately solve equations, one linear and one non-linear, with graphs. What grade are we working at? Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? PLENARY ACTIVITY– EXAM QUESTION (GRADE A*) The quadratic graph has equation y = ax 2+ bx where a and b are integers. Points P(-1,10) and Q(4,0) lie on this graph. The straight line is y = x. Find the co-ordinate of the point To find the co-ordinates of R, we marked R. You must show your working. 16a + 4b = 0 y a – b = 10 x4 need to find where the equations of the graphs intersect Solve the simultaneous 16a + 4b = 0 y = x P equations y = 2x2 - 8x y=x 4a – 4b = 40 + (-1,10) By substitution of x for y, xy R 20a = 40 x = 2x2 - 8x a =2 By substitution, 0 = 2x2 - 9x x Q a – b = 10 By factorisation, (4,0) xy 2 – b = 10 0 = x(2x – 9) x(2x – 9) = 0 Equation for (-1,10) Equation for (4,0) –b =8 x = 0 or 2x - 9 = 0 b = -8 y = ax2 + bx y = ax2 + bx 2x = 9 Sub in (-1,10) for x and y Sub in (4,0) for x and y y = ax2 + bx Sub in for a and b 10 = a(-1) 2 + b(-1) 0 = a(4)2 + b(4) x = 4.5 y = 2x2 - 8x 10 = a - b 0 = 16a + 4b y = 4.5 a - b = 10 16a + 4b = 0 . . . R(4.5,4.5) (6 marks) What have you learnt? Draw your brain In your brain, write or draw everything you can remember about graphing inequalities and shading the region defined by it. It can be a skill or a reflection, or something else that might be prominent in your brain. Where are we in our journey? What grade are we working at? Positive Thinker Creative Entrepreneur Independent Learner Reflective Learner Responsible Citizen Team Worker Enterprise Skills SELF ASSESSMENT Which ones are you using? Plenary Activity How well do you understand the task? . I don’t understand I nearly understand www.mistrymaths.co.uk I fully understand Positive Thinker Creative Entrepreneur Independent Learner Reflective Learner Responsible Citizen Team Worker Enterprise Skills SELF ASSESSMENT Which ones are you using? Plenary Activity WWW (What Went Well) EBI (Even Better If) On your post it notes… Think about how you can improve your work. www.mistrymaths.co.uk Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 1) Find the approximate solutions to the pair of equations y = x2 + 3x – 2 and y = x by graphical means. Table for quadratic Table for linear y = x y = x2 + 3x – 2 Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 2) Find the approximate solutions to the pair of equations y = x2 - 3x – 6 and y = 2x by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 3) Find the approximate solutions to the pair of equations y = x2 - 3x + 1 and y = 2x - 1 by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 4)Find the approximate solutions to the pair of equations y = x2 - 3 and y = x + 3 by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 1 (GRADE A) 5) Find the approximate solutions to the pair of equations y = x2 - 3x - 2 and y = 2x - 3 by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 1) Find the approximate solutions to the pair of equations x2 + y 2 = 25 and y = 1 - x by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 2) Find the approximate solutions to the pair of equations x2 + y 2 = 4 and y = x + 1 by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? TASK 2 (GRADE A) 3) Find the approximate solutions to the pair of equations x2 + y 2 = 9 and y = x - 1 by graphical means. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? EXTENSION (GRADE A*) 1) (a) Find the approximate solutions to the pair of equations y = x 2 + 3x - 4 and y = 5x - 5 by graphical means. (b) What is special about the intersection of the two graphs? (c) Show that 5x – 5 = x2 + 3x – 4 can be re-arranged to x2 - 2x + 1 = 0 (d) Factorise and solve x2 – 2x + 1 = 0 (e) Explain how the solution in part (d) relates to the intersection of the graphs. 2) (a) Find the approximate solutions to the pair of equations y = x 2 + 2x + 3 and y = x - 1 by graphical means. (b) What is special about the intersection of the two graphs? (c) Rearrange x – 1 = x2 + 2x + 3 into the form ax 2 + bx + c = 0 (d) Work out the discriminant b2 – 4ac for the quadratic on part (c) (e) Explain how the discriminant relates to the intersection of the graphs. Creative Thinker Effective Participator Independent Enquirer Reflective Learner Self Manager Team Worker PLT Skills SOLVING BY GRAPHING Which ones are you using? PLENARY ACTIVITY– EXAM QUESTION (GRADE A*) The quadratic graph has equation y = ax2 + bx where a and b are integers. Points P(-1,0) and Q(4,0) lie on this graph. The straight line is y = x. Find the co-ordinate of the point marked R. You must show your working. y y=x P . .R .Q x (6 marks)