DVC Calculus Field Trip Carollo Engineers Dan Frost Katy Rogers lh1010recruitment-calpoly.pptx/1 November 15th, 2010 Field Trip Outline lh1010recruitment-calpoly.pptx/2 • Introduction of speakers • Introduction to Carollo • Office tour • Calculus at Carollo and lunch • Questions Dan Frost • BS/MS Env. Eng. from Cal Poly in 2008 • Carollo Engineers since 2008 • Experience Highlights: - Digester Rehab/FOG Facilities – Fresno & DSRSD - Napa Wastewater Master Plan - City of San Leandro WPCP Rehabilitation Project - City of Stockton CIP and Energy Management Plan lh1010recruitment-calpoly.pptx/3 - Algae to Biofuels Katy Rogers • BS Civil Eng. from UC Davis in 2007 • MS Env. Eng. from Stanford in 2008 • Carollo Engineers since 2008 • Experience Highlights: lh1010recruitment-calpoly.pptx/4 - City of Modesto Tertiary Wastewater Treatment Plant City of Modesto Engineer’s Report City of Turlock THM Study City of San Francisco CIP Introduction to Carollo Engineers lh1010recruitment-calpoly.pptx/5 • We are the largest firm in the United States dedicated solely to water and wastewater treatment. • Carollo Engineers provides planning, design, and construction management services for municipal clients. Carollo Statistics • • • • Founded 1933 630+ employees 300+ professional engineers Multi disciplined lh1010recruitment-calpoly.pptx/6 - Sanitary/environmental Structural Mechanical Electrical Instrumentation Civil Chemical Company Organization CEO Partners lh1010recruitment-calpoly.pptx/7 Associates Engineers Drafters Graphics Document Processing Business Development Human Resources lh1010recruitment-calpoly.pptx/8 Carollo currently maintains 32 offices in 12 states What types of projects do we work on? lh1010recruitment-calpoly.pptx/9 • Water treatment • Wastewater treatment • Infrastructure • Research and Development • Water Reuse • Construction Management • Integrated Water Resources Key drivers for water and wastewater projects include: lh1010recruitment-calpoly.pptx/10 • Growth • Regulations • Aging Infrastructure • Management/Public Policy lh1010recruitment-calpoly.pptx/11 Project Examples…. Wastewater Treatment Plant No. 1 Fountain Valley, CA lh1010recruitment-calpoly.pptx/12 Orange County Sanitation Districts Orange County, CA 360 mgd (combined) Reclamation Plant No. 2 Huntington Beach, CA lh1010recruitment-calpoly.pptx/13 City of Phoenix, AZ Southern Avenue Interceptor 160,000 LF/48-90 inch pipes City of Stockton, CA Westside Sewer Interceptor 41,000 LF/72 inch pipe GCDCorpOv903.ppt13 lh1010recruitment-calpoly.pptx/14 Clark County Water Reclamation District, NV 130-mgd of biological phosphorus removal lh1010recruitment-calpoly.pptx/15 Napa Sanitation District, CA 10-mgd DynaSand filter for reuse lh1010recruitment-calpoly.pptx/16 Stockton WWTP Facility Aerial What do we produce for our clients? lh1010recruitment-calpoly.pptx/17 • Proposals and Statements of Qualifications • Preliminary studies and reports • Master plans • Design plans and specifications Office Tour • Library and Central Files • Engineering groups - Civil/Process - Structural - Electrical and instrumentation lh1010recruitment-calpoly.pptx/18 - Mechanical • Graphics • Business development • Drafting • ISG/Tech Support lh1010recruitment-calpoly.pptx/19 Calculus at Carollo Calculus at Carollo • Do we use it? • How do we use it? - Hydraulic calculations - Volume calculations - Structural analysis lh1010recruitment-calpoly.pptx/20 • Questions? Do we use calculus at Carollo? • Short Answer: Yes • Long Answer: - We use simple calculus-derived equations lh1010recruitment-calpoly.pptx/21 - We also use software to solve several equations simultaneously Algebraic equations derived from calculus: Calculus Algebra Area under a curve b A [ f ( x ) g( x )]dx a Conservation of Mass dM u dV dV u dV u dV 0 V t V V t dt V A 1 ( Y1 Y2 ) x 2 p1A 1V1 p1A1V1 Q1 Q2 Qo Xo V( mS )X k d X Ks S Used For: Calculating rain volume, excavation volume, etc Mass and flow balances (calculating flows and masses when multiple streams are involved) (Q o Q w ) X e Q W X W Conservation of Energy 2 lh1010recruitment-calpoly.pptx/22 1 dp 2 2 VdV gdz 0 1 1 1 2 v a gha 2 1 Pb v b2 ghb 2 Pa Rate Equation CR Co dC kC dt k ln Co Co CR Hydraulic design (structures, pipes, pumps, valves, etc), Hydraulic Profiles Treatment design (reaction time) Derivation of the Bernoulli Equation lh1010recruitment-calpoly.pptx/23 • Start with Newton’s Second Law…. Bernoulli’s Equation How we use the Bernoulli Equation at Carollo: lh1010recruitment-calpoly.pptx/24 • To determine pressure, velocity, and elevation at points within a hydraulic system • To size pipes, valves, pumps, and turbines • To determine headloss through a pipe due to friction and connections • To develop hydraulic profiles lh1010recruitment-calpoly.pptx/25 Applications of the Bernoulli Equation Determining flow from a tank or reservoir lh1010recruitment-calpoly.pptx/26 Applications of the Bernoulli Equation Sizing and designing culverts lh1010recruitment-calpoly.pptx/27 Applications of the Bernoulli Equation Sizing pumps and pipelines lh1010recruitment-calpoly.pptx/28 Applications of the Bernoulli Equation Determining the flow, pressure, and headloss at points within a parallel pipe system lh1010recruitment-calpoly.pptx/29 Hydraulic Profile for the City of Modesto WWTP Calculating flow volumes from hydrographs lh1010recruitment-calpoly.pptx/30 Flow Flow • Hydrograph - flow vs. time (e.g. storm, river) • Volume of water over time = Area under curve Time Time Calculating flow volumes from hydrographs • Estimate volume of water from a rainfall event - Size culverts, pipelines - Wastewater storage • Actual data not defined by simple equations - Apply approximation methods lh1010recruitment-calpoly.pptx/31 • Trapezoidal Rule: • Average End Area Method: A = Δx(yo/2 + y1 + y2 + yn/2) A = ½ (y1+y2) * Δx Hydrograph Example • Receive raw data from client lh1010recruitment-calpoly.pptx/32 Treatment Plant Flow during Rainfall Event Time t 0 1 2 3 4 5 6 7 8 9 10 11 12 Flow Q 5 51 89 119 141 155 161 159 149 131 105 71 29 Typical Treatment Plant Flow Time Flow t Q 0 5 1 5.5 2 6 3 6.5 4 7 5 7.5 6 8 7 8.5 8 9 9 9.5 10 10 11 10.5 12 11 Hydrograph Example • Receive raw data from client lh1010recruitment-calpoly.pptx/33 Treatment Plant Flow during Rainfall Event Time t 0 1 2 3 4 5 6 7 8 9 10 11 12 Flow f(x) = f(t) = Q = -2t2+ 50t + 5 Q 5 51 89 119 141 155 161 159 149 131 105 71 29 Typical Treatment Plant Flow Time Flow g(x) = g(t) = Q = 0.5t+5 t Q 0 5 1 5.5 2 6 3 6.5 4 7 5 7.5 6 8 7 8.5 8 9 9 9.5 10 10 11 10.5 12 11 Hydrograph Example • Graph raw data 180 Flow from Rainfall = f(x) 160 Base Flow = g(x) Flow (gal/hr) 140 120 100 80 60 40 20 lh1010recruitment-calpoly.pptx/34 0 0 1 2 3 4 5 6 7 Time (Hours) 8 9 10 11 12 Hydrograph Example • Volume due to Rainfall (I&I) = Area btw Curves - Integrate equation for curves 180 Flow from Rainfall = f(x) 160 Base Flow = g(x) Flow (gal/hr) 140 120 100 80 60 lh1010recruitment-calpoly.pptx/35 40 20 0 0 1 2 3 4 5 6 7 Time (Hours) 8 9 10 11 12 Hydrograph Example • Integration of f(t): - Q = Flow During Rain Event = f(t) = -(2t)2 + 50t + 5 - f(t) = (-(2t)2 + 50t + 5)dt = -4/3t3 + 25t2 +5t + C - At t = 0, Q = 5 => C = 5 - From t = 0 to t = 12 => [-4/3(12)3 + 25(12)2 +5(12) + 5] - [-4/3(0)3 + 25(0)2 +5(0) + 5] = 1,356 gallons • Integration of g(t): - Q = Typical Flow = g(t) = 0.5t+5 lh1010recruitment-calpoly.pptx/36 - g(t) = (0.5t+5)dt = 1/4t2 + 5t + C - At t = 0, Q = 5 => C = 5 - From t = 0 to t = 12 => [1/4(12)2 + 5(12) + 5] – 5 = 96 gallons • Total Flow Due to Rainfall = 1,356 – 96 = 1,260 gallons Hydrograph Example • Volume due to Rainfall (I&I) = Area btw Curves - Approximation (Avg. End Area Method) 180 Flow from Rainfall = f(x) 160 Base Flow = g(x) 140 Flow (gal/hr) 120 100 80 60 lh1010recruitment-calpoly.pptx/37 40 20 0 0 1 2 3 4 5 6 7 Time (Hours) 8 9 10 11 12 Hydrograph Example lh1010recruitment-calpoly.pptx/38 • Approximation: 1,252 Gallons Avg Time Flow Flow Duration Volume Q t Q (gal/hr) t (Hrs) gal 0 5 1 51 28 1 28 2 89 70 1 70 3 119 104 1 104 4 141 130 1 130 5 155 148 1 148 6 161 158 1 158 7 159 160 1 160 8 149 154 1 154 9 131 140 1 140 10 105 118 1 118 11 71 88 1 88 12 29 50 1 50 Sum = 1,348 Avg Time Flow Flow Duration Volume Q t Q (gal/hr) t (Hrs) gal 0 5 1 5.5 5.25 1 5.25 2 6 5.75 1 5.75 3 6.5 6.25 1 6.25 4 7 6.75 1 6.75 5 7.5 7.25 1 7.25 6 8 7.75 1 7.75 7 8.5 8.25 1 8.25 8 9 8.75 1 8.75 9 9.5 9.25 1 9.25 10 10 9.75 1 9.75 11 10.5 10.25 1 10.25 12 11 10.75 1 10.75 Sum = 96 Structural Analysis lh1010recruitment-calpoly.pptx/39 • Structural engineers use calculus to determine the maximum stress of structural elements under different loads. Structural Analysis • Shear at a point is the sum of all vertical forces acting on an object. lh1010recruitment-calpoly.pptx/40 • Moment at a point is the total bending moment acting on an object. Structural Analysis lh1010recruitment-calpoly.pptx/41 • Step 1: Determine all forces using plane static equilibrium equations. Structural Analysis lh1010recruitment-calpoly.pptx/42 • Step 2: Calculate shear at a point by integrating the load function w(x) or the area under the load diagram up to that point. Structural Analysis lh1010recruitment-calpoly.pptx/43 • Step 3: Calculate moment at a point by integrating the shear function V(x) or the area under the shear diagram up to that point. Structural Analysis lh1010recruitment-calpoly.pptx/44 • In summary…. lh1010recruitment-calpoly.pptx/45 Another example…. lh1010recruitment-calpoly.pptx/46 More examples…. Software used to analyze complex systems lh1010recruitment-calpoly.pptx/47 • Hydraulix • BioTran/BioWin • EnerCalc • STAAD lh1010recruitment-calpoly.pptx/48 Questions? lh1010recruitment-calpoly.pptx/49 End of Presentation