Algebra 2 Chapter 6 Ms. Fisher th Thursday March 19 Agenda Introduction: My name is Ms. Fisher and I will be your Math teacher for the remainder of the school year. **Please frequently visit my website, everything & anything you will need is posted on there! -My powerpoints, notes, answer keys, tutorials, textbook, etc… Ms. Fisher’s Website Agenda for today: Begin Ch 6 Teach lesson 6.1 ο Independent Work Time Objective: To review and practice using the properties of exponents in preparation to simplify expressions containing exponents. Section 6.1- Simplifying Radical Expressions If n is odd, If n is even π π The nth root rule ππ = a ππ = a Example: 64 = +/- 8 (when n is even) b/c -8*-8 = 64 and 8 * 8=64 Principal root: |8| = 8 3 8 =2 can not be -2 bc -2*-2*-2= -8 Principal root: Is the Positive root, You will be looking for the Principal root when n is even! Section 6.1- Simplifying Radical Expressions Simplify 4 16π4 = 4 π4 24 = |2a| = 2|a| 2*2*2*2=16 (you have to put absolute value signs around the variable a because you do not know if a is positive) 3 27π3 π 6 = 3 33 π3 (π2 )3 = 3aπ 2 Section 6.1- Simplifying Radical Expressions with cube roots Steps Used to Simplify: 1. Factor expression under radicand into perfect squares, cubes, or whatever is appropriate… 2. Use Multiplication Property to break into parts π π π π π = ππ 3. Simplify assume all variables are positive so no absolute values needed EX: 75π2 π 3 = 52 3π2 π 2 π = 52 π 2 π 2 3π = 5ab 3π All perfect squares go here All non-perfect squares go here 6.1 Simplifying Expressions 3 Example: = 24π₯ 4 π¦ 6 3 23 All Perfect cubes go here ∗ = 3 π₯ 3 (π¦ 2 )³ 23 ∗ 3 ∗ π₯ 3 ∗ π₯ ∗ (π¦ 2 )³ 3 3x All Non- Perfect cubes go here Independent Work Time…. Begin your homework. Whatever you do not complete in class you must finish at home. Remember, you can access the textbook online from home! Student Link to Textbook online Username: Council Rock South1 Password: CouncilRockSouth1 Homework: Practice Form G #’s 13-32 Agenda: 6.2 ο§Go over home – volunteers to board – Explain “Parking Lot” ο§Warm-up: Who can tell me the Multiplication Property? π π π π π = ππ Key componentο Need to have the same n ο§Teach Lesson 6.2 ο§Independent Work Time ο§Objective: To use sums of perfect squares to solve a problem 6.2 Multiplying and Dividing Radical Expressions Same index ο§To multiply radical expressions make sure they have the same n. Then use the multiplication property to multiply factors into perfect squares, cubes whatever the index is… Then simplify Example: 12π2 π 3 * 3ππ 2 c = (12π2 π 3 )(3ππ 2 c) = 36π3 π 5 c *Remember when multiplying, add the exponents! = 62 π2 π(π²)2 π ∗ π = 6²π2 (π²)2 * πππ Perfect squares simplest form Non-Perfect squares = 6ab² πππ 6.2 Multiplying Radical Expressions Same index ο§To multiply radical expressions make sure they have the same n. Then use the multiplication property to multiply factors into perfect squares, cubes whatever the index is… Then simplify Example: 3 9π₯ 5 π¦ 2 54 6π₯π¦ 2 = = 9 3 3 * 3 6 2 27 *2 = 3 = 3 3 (9π₯ 5 π¦ 2 )(6π₯π¦ 2 ) 54π₯ 6 π¦ 4 *Remember π₯ 5 * x = π₯ 5+1 π₯6 3 33 2(π₯²)3 π¦ 3 π¦ 3 3³(π₯²)3 𦳠* ³ 2π¦ Perfect cube simplest form *Remember (π₯²)3 you multiply 2*3=6 Non-Perfect cube = 3x²y * ³ 2π¦ 6.2 Dividing Radical Expressions Property Dividing Radical Expression If π a Example: π b are real numbers and b≠ 0, then 24a2 π³ = π a = π b π a π 24a2 π³ 6ππ 6ππ Step 1: Put under one square root sign 4ππ² 2²π² π = 2b π Step 2: Reduce a2−1=1 b3−1=2 Step3: Simplify; take all of our perfect squares & factor them out Step 4: Simplify 6.2 Dividing Radical Expressions 4y −32π₯ Example: ³ −32π₯ 4 y = ³ 2 ³ 2 Step 1: Put under one cube root sign ³ −16π₯ 4 y ³ −23 ∗ 2 ∗ π₯ 3 ∗ x ∗y ³ −23 ∗ π₯ 3 ³ 2π₯π¦ = -2x ³ 2xy Step 2: Reduce -16 Step3: Simplify; take all of our perfect cubes & factor them out (cube bc index is 3) Step 4: Simplify 6.2 Dividing Radical Expressions by rationalizing the denominator A fraction should NOT have a radical in the denominator, if it does, you need to rationalize the denominator. ππ 3π₯ π¦ What do you do? Look at the index. Square root. Rewrite as a square root of a fraction, then get a denominator that is a perfect square. 3π₯π¦ 3π₯ ∗ π¦ 3π₯ = = = π¦ ∗ π¦ 𦲠π¦ 3π₯π¦ y 6.2 Dividing Radical Expressions by rationalizing the denominator πΌπ the radical in the denominator is not a square root, the idea is the same. You need to get a perfect square, cube, fourth, etc… in the denominator to get rid of the radical in the denominator. 50π₯ 2π₯ ∗ 5² ³ 2π₯ = ³ =³ = ³ 50π₯ = ³ 50π₯ 5³ 5 ∗ 5² ³ 5³ 5 ³ 5 6.3 Adding & Subtracting Radical Expressions