Higher Maths Vectors Strategies Click to start Vectors Higher The following questions are on Vectors Non-calculator questions will be indicated You will need a pencil, paper, ruler and rubber. Click to continue Vectors Higher The questions are in groups General vector questions (15) Points dividing lines in ratios Collinear points (8) Angles between vectors (5) Quit Quit Vectors Higher General Vector Questions Continue Quit Quit Back to menu Vectors Higher Vectors u and v are defined by u 3i 2 j and v 2i 3 j 4k Determine whether or not u and v are perpendicular to each other. Is Scalar product = 0 3 u.v 2 0 u.v 3 2 2 3 0 4 u.v 0 2 3 4 u.v 6 6 0 Hence vectors are perpendicular Hint Previous Quit Quit Next Vectors Higher For what value of t are the vectors u Put Scalar product = 0 t 2 3 t u.v 2 3 u.v 2t 2 10 3t Perpendicular u.v = 0 and v 2 10 t perpendicular ? 2 10 t u.v 5t 20 0 5t 20 t4 Hint Previous Quit Quit Next Vectors Higher VABCD is a pyramid with rectangular base ABCD. The vectors AB, AD and AV are given by AB 8i 2 j 2k AD 2i 10 j 2k AV i 7 j 7k Express CV in component form. Ttriangle rule ACV AC CV AV Triangle rule ABC AB BC AC also CV AV AB AD Previous Re-arrange CV AV AC BC AD 1 8 2 CV 7 2 10 7 2 2 9 CV 5 7 CV 9i 5 j 7k Quit Hint Quit Next Vectors Higher The diagram shows two vectors a and b, with | a | = 3 and | b | = 22. These vectors are inclined at an angle of 45° to each other. a) Evaluate i) a.a ii) b.b iii) a.b b) Another vector p is defined by p 2a 3b Evaluate p.p and hence write down | p |. i) a a a a cos 0 3 3 1 9 iii) a b a b cos 45 3 2 2 b) p p 2a 3b 2a 3b Quit 8 1 6 2 4a.a 12a.b 9b.b 36 72 72 180 Since p.p = p2 Previous bb 2 2 2 2 ii) Quit p 180 6 5 Next Hint Vectors Higher Vectors p, q and r are defined by p i j - k , a) Express p q 2r in component form b) Calculate p.r c) Find |r| q i 4k , i j - k i 4k 2 4i 3 j and r 4i 3 j 8i 5 j - 5k a) p q 2r b) p.r i j - k . 4i 3 j p.r 1 4 1 (3) (1) 0 p.r 1 c) r 42 (3)2 r 16 9 r 5 Hint Previous Quit Quit Next Vectors Higher The diagram shows a point P with co-ordinates (4, 2, 6) and two points S and T which lie on the x-axis. If P is 7 units from S and 7 units from T, find the co-ordinates of S and T. Use distance formula S ( a, 0, 0) PS 2 49 (4 a)2 22 62 a 43 T (b, 0, 0) 49 (4 a)2 40 9 (4 a)2 a 7 or a 1 hence there are 2 points on the x axis that are 7 units from P S (1, 0, 0) and i.e. S and T T (7, 0, 0) Hint Previous Quit Quit Next Vectors Higher The position vectors of the points P and Q are p = –i +3j+4k and q = 7 i – j + 5 k respectively. a) Express PQ in component form. b) Find the length of PQ. a) b) PQ q - p PQ 7 1 1 - 3 5 4 PQ 82 (4) 2 12 PQ 64 16 1 8 4 1 81 8i 4 j k 9 Hint Previous Quit Quit Next Vectors Higher P PQR is an equilateral triangle of side 2 units. PQ a, PR b, and QR c Evaluate a.(b + c) and hence identify two vectors which are perpendicular. a b Diagram Q a.(b c ) a.b a.c a.b a b cos 60 60° 60° 60° R c a.b 2 2 1 2 a.b 2 NB for a.c vectors must point OUT of the vertex ( so angle is 120° ) 1 a.c 2 2 a.c a c cos120 2 Hence a.(b c ) 0 a.c 2 so, a is perpendicular to b + c Hint Previous Table of Exact Values Quit Quit Next Vectors Higher Calculate the length of the vector 2i – 3j + 3k Length 2 (3) 2 2 3 2 493 16 4 Hint Previous Quit Quit Next Vectors Higher Find the value of k for which the vectors 1 2 1 1 0 2 1 4 3 k 1 Put Scalar product = 0 0 4 6 (k 1) and 4 3 k 1 are perpendicular 0 2 k 1 k 3 Hint Previous Quit Quit Next Vectors Higher A is the point (2, –1, 4), B is (7, 1, 3) and C is (–6, 4, 2). If ABCD is a parallelogram, find the co-ordinates of D. AD BC c b D is the displacement hence d BC AD 2 13 1 3 4 1 6 7 4 1 2 3 BC 13 3 1 from A d 11 2 3 D 11, 2, 3 Hint Previous Quit Quit Next Vectors If Higher 3 u 3 3 and v 1 5 1 write down the components of u + v and u – v Hence show that u + v and u – v are perpendicular. uv 2 8 2 u v . u v uv 2 4 8 2 2 4 4 2 4 look at scalar product u v . u v (2) (4) 8 (2) 2 4 8 16 8 0 Hence vectors are perpendicular Previous Quit Quit Hint Next Vectors Higher The vectors a, b and c are defined as follows: a = 2i – k, b = i + 2j + k, c = –j + k a) Evaluate a.b + a.c b) From your answer to part (a), make a deduction about the vector b + c a) 2 1 a.b 0 2 1 1 a.c b) 2 0 0 1 1 1 a.b 2 0 1 a.b 1 a.c 0 0 1 a.c 1 a.b a.c 0 b + c is perpendicular to a Hint Previous Quit Quit Next Vectors Higher A is the point ( –3, 2, 4 ) and B is ( –1, 3, 2 ) Find: a) the components of AB b) the length of AB a) b) AB b a AB 1 3 3 2 2 4 AB 22 12 (2)2 AB 2 1 2 AB 4 1 4 AB 3 AB 9 Hint Previous Quit Quit Next Vectors Higher In the square based pyramid, all the eight edges are of length 3 units. AV p, AD q, AB r , Evaluate p.(q + r) Triangular faces are all equilateral p.(q r ) p.q p.r p.q p q cos 60 p.r p r cos60 1 2 p.(q r ) 4 4 Previous 1 2 Table of Exact Values p.q 1 3 3 2 p.r 1 3 3 2 p.q 4 p.q 1 2 1 4 2 p.(q r ) 9 Quit Quit Hint Next Vectors Higher You have completed all 15 questions in this section Previous Quit Quit Back to start Vectors Higher Points dividing lines in ratios Collinear Points Continue Quit Quit Back to menu Vectors Higher A and B are the points (-1, -3, 2) and (2, -1, 1) respectively. B and C are the points of trisection of AD. That is, AB = BC = CD. Find the coordinates of D AB 1 AD 3 3AB AD 3b 3a d a d 2 1 3 1 2 3 1 2 Previous 3 b a d a d 3b 2a d 8 3 1 Quit D(8, 3, 1) Hint Quit Next Vectors Higher The point Q divides the line joining P(–1, –1, 0) to R(5, 2 –3) in the ratio 2:1. Find the co-ordinates of Q. R Diagram PQ 2 QR 1 3q P 1 q p 2r 2q PQ 2QR 5 1 2 2 1 3 0 2 Q 3q 2r p 1 9 q 3 3 6 Q(3, 1, 2) Hint Previous Quit Quit Next Vectors Higher a) Roadmakers look along the tops of a set of T-rods to ensure that straight sections of road are being created. Relative to suitable axes the top left corners of the T-rods are the points A(–8, –10, –2), B(–2, –1, 1) and C(6, 11, 5). Determine whether or not the section of road ABC has been built in a straight line. b) A further T-rod is placed such that D has co-ordinates (1, –4, 4). Show that DB is perpendicular to AB. a) AB b a AB b) and AB 6 2 9 3 3 3 1 AC 14 2 21 7 3 7 1 AC are scalar multiples, so are parallel. A is common. A, B, C are collinear Use scalar product Previous AB.BD 6 3 9 . 3 3 3 Quit AB.BD 18 27 9 0 Hence, DB is perpendicular to AB Quit Next Hint Vectors Higher VABCD is a pyramid with rectangular base ABCD. Relative to some appropriate axis, VA represents – 7i – 13j – 11k 6i + 6j – 6k AB represents 8i – 4j – 4k AD represents K divides BC in the ratio 1:3 Find VK in component form. VA AB VB VK VB KB VK VK KB VB 1 4 1 4 1 4 VK VA AB AD 7 6 8 1 13 6 4 11 6 4 4 Previous 1 4 KB CB DA AD VK Quit 1 8 18 Quit Hint Next Vectors Higher The line AB is divided into 3 equal parts by the points C and D, as shown. A and B have co-ordinates (3, –1, 2) and (9, 2, –4). a) Find the components of AB and AC b) Find the co-ordinates of C and D. a) b) AB b a AB 6 3 6 C is a displacement of AC from A similarly Previous d 5 2 0 1 0 2 2 1 AC AB 1 3 2 c 3 2 1 1 2 2 C (5, 0, 0) D(7, 1, 2) Hint Quit Quit Next Vectors Higher Relative to a suitable set of axes, the tops of three chimneys have co-ordinates given by A(1, 3, 2), B(2, –1, 4) and C(4, –9, 8). Show that A, B and C are collinear AB b a AB and AB 1 4 2 AC 3 1 12 3 4 6 2 AC are scalar multiples, so are parallel. A is common. A, B, C are collinear Hint Previous Quit Quit Next Vectors Higher A is the point (2, –5, 6), B is (6, –3, 4) and C is (12, 0, 1). Show that A, B and C are collinear and determine the ratio in which B divides AC AB b a AB and BC AB 2 BC 3 Previous AB 4 2 2 2 1 2 1 BC 6 2 3 3 1 3 1 are scalar multiples, so are parallel. B is common. A, B, C are collinear A 2 B 3 C B divides AB in ratio 2 : 3 Quit Quit Hint Next Vectors Higher Relative to the top of a hill, three gliders have positions given by R(–1, –8, –2), S(2, –5, 4) and T(3, –4, 6). Prove that R, S and T are collinear RS s r RS and RT RS 3 1 3 3 1 6 2 RT 4 1 4 4 1 8 2 are scalar multiples, so are parallel. R is common. R, S, T are collinear Hint Previous Quit Quit Next Vectors Higher You have completed all 8 questions in this section Previous Quit Quit Back to start Vectors Higher Angle between two vectors Continue Quit Quit Back to menu Vectors Higher The diagram shows vectors a and b. If |a| = 5, |b| = 4 and a.(a + b) = 36 Find the size of the acute angle between a and b. cos a.b a b a.a a a 25 11 cos 5 4 Previous a.(a b) 36 a.a a.b 36 25 a.b 36 11 cos 20 56.6 1 Quit a.b 11 Hint Quit Next Vectors Higher The diagram shows a square based pyramid of height 8 units. Square OABC has a side length of 6 units. The co-ordinates of A and D are (6, 0, 0) and (3, 3, 8). C lies on the y-axis. a) Write down the co-ordinates of B b) Determine the components of DA and DB c) Calculate the size of angle ADB. a) c) B(6, 6, 0) cos DA.DB DA DB cos Previous b) 3 DA 3 8 64 82 82 DA.DB DB 3 3 8 3 3 3 . 3 64 8 8 38.7 Quit Hint Quit Next Vectors Higher A box in the shape of a cuboid designed with circles of different sizes on each face. The diagram shows three of the circles, where the origin represents one of the corners of the cuboid. The centres of the circles are A(6, 0, 7), B(0, 5, 6) and C(4, 5, 0) Find the size of angle ABC Vectors to point away from vertex 6 BA 5 1 4 BC 0 6 BA 36 25 1 62 cos 18 62 52 Previous BA.BC 24 0 6 18 BC 16 36 52 71.5 Hint Quit Quit Next Vectors Higher A cuboid measuring 11cm by 5 cm by 7 cm is placed centrally on top of another cuboid measuring 17 cm by 9 cm by 8 cm. Co-ordinate axes are taken as shown. a) The point A has co-ordinates (0, 9, 8) and C has co-ordinates (17, 0, 8). Write down the co-ordinates of B b) Calculate the size of angle ABC. a) B(3, 2, 15) b) 15 BC 2 7 BA.BC 45 14 49 10 BA 9 49 49 107 Previous 3 BA 7 7 BC 225 4 49 278 10 cos 278 107 Quit Quit 93.3 Hint Next Vectors Higher A triangle ABC has vertices A(2, –1, 3), B(3, 6, 5) and C(6, 6, –2). a) Find and AB AC b) Calculate the size of angle BAC. c) Hence find the area of the triangle. a) b) 1 AB b a 7 2 AB 12 7 2 22 54 cos c) 4 AC c a 7 5 43 0.6168 54 90 Area of ABC = Previous AC 90 AB. AC 4 49 10 43 cos1 0.6168 51.9 1 ab sin C 2 Quit 1 90 54 sin 51.9 2 Quit BAC = 51.9 27.43 unit 2 Hint Next Vectors Higher You have completed all 5 questions in this section Previous Quit Quit Back to start Vectors Higher Table of exact values sin cos tan Previous 30° 45° 60° 6 1 2 4 3 1 2 1 2 3 2 3 2 1 3 1 1 2 3