CAPM Betas and OLS

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CAPM Betas
The Capital Asset Pricing Model (“CAPM”)
[ R s- R f ] = b 0 + b 1 [ R M - R f ] + e
• People commonly refer to the b0 in this model as the stock’s “alpha” and the b1 is simply
called “beta.”
• “R” stands for return. The subscript “s” indicates that the model is for stock “s” (e.g.,
Coca Cola or Microsoft). The subscript “f” stands for the risk-free security (e.g., a 30-day
Treasury bill). The subscript “M” stands for the stock market.
• [ Rs- Rf ] is the risk premium of a stock; [ RM - Rf ] is the risk premium of the market.
• The “e” designates the error term.
• If you work with daily data, all your returns should be daily returns and you are
calculating a daily beta of the stock. If you work with monthly data, all your returns
should be monthly returns and you are calculating the stock’s monthly beta. Etc.
• If you want to calculate the CAPM beta for a mutual fund or an investment portfolio, just
use the returns from the mutual fund or portfolio instead of the returns of an individual
stock.
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CAPM Betas (continued)
From earlier slide, the Capital Asset Pricing Model (“CAPM”) is:
[ Rs- Rf ] = b0 + b1 [ RM - Rf ] + e
To estimate b0 ( “alpha”) and the b1 (CAPM “beta”), you estimate the model (i.e.,
perform the OLS regression):
y = b0 + b 1 x + e
Note that [ Rs- Rf ] is “y” and [ RM - Rf ] is “x”. Don’t reverse them! 
You’ll need to perform all the steps.
• Step 1: Collect the Raw Data.
• Step 2: Calculate descriptive statistics.
• Step 3: Plot the data.
• Step 4: Specify the model.
• Step 5: Estimate the model (i.e., perform the regression).
• Step 6: Determine whether the model is good in a statistical sense.
2
Can outdoor temperature be estimated using cricket chirps?
Step 1 – Collect the Raw Data:
Go outside some evening with a thermometer. Count the number of cricket chirps you
hear for 15 seconds. Repeat on various evenings when the temperature is different.
Temperature
57
60
64
65
68
71
74
77
Chirps
18
20
21
23
27
30
34
39
3
Can outdoor temperature be estimated using cricket chirps?
Step 2 – Calculate descriptive statistics:
Can use Excel’s formulas for mean and sample standard deviation.
Temperature
57
60
64
65
68
71
74
77
Chirps
18
20
21
23
27
30
34
39
Mean (Excel f x = AVERAGE)
67.0
26.5
Std. Dev. (Excel f x = STDEV)
6.845
7.387
4
Can outdoor temperature be estimated using cricket chirps?
Step 3 – Plot the data:
Can use Excel’s XY (Scatter) chart type. Temperature is “y”. Chirps is “x”.
90
80
70
Temperature
60
50
40
30
20
10
0
0
5
10
15
20
25
Chirps
30
35
40
45
5
Can outdoor temperature be estimated using cricket chirps?
Step 4 – Specify the model:
y =
b0 + b 1 x + e
• Temperature is “y”.
• Chirps is “x”.
• “e” is “error”, which is the difference between our model’s prediction of temperature
and the temperature we actually observed.
• We’ll estimate b0 and b1 using ordinary least squares (“OLS”) regression.
• If our model’s any good, once we’ve estimated b0 and b1 , we can use the following
formula to estimate temperature just by counting cricket chirps:
Temperature = b0 + (b1 )( # of chirps) + 0
• Note: our model assumes that “y” and “x” have a linear relationship --i.e., our model is the equation of a line with intercept b0 and slope b1 .
6
How will we determine the best line?
We’ll use Excel to perform an ordinary least squares (OLS) regression.
?
90
80
?
?
70
Temperature
60
50
40
30
20
10
0
0
5
10
15
20
25
Chirps
30
35
40
45
7
Can outdoor temperature be estimated using cricket chirps?
Step 5 – Estimate the model (i.e., perform the regression):
y =
b0 + b1 x + e
• We’ll need Excel’s “Analysis ToolPak” Add-In. You may already have added it. If not,
here’s how you do it:
– For Excel 1997-2003: On the tool bar, click “Tools”, “Add-Ins”, “Analysis ToolPak”.
– For Excel 2007: On the upper left-hand corner “MS” logo, click “Excel Options”,
“Add-Ins”, “Analysis ToolPak”.
• If you’ve added the “Analysis ToolPak” Add-In., you’ll be able to:
– For Excel 1997-2003: On the tool bar, click “Tools”, “Data analysis”, “Regression”.
– For Excel 2007: On the tool bar, click “Data”, “Data analysis”, “Regression”.
>>>>
8
Can outdoor temperature be estimated using cricket chirps?
9
Can outdoor temperature be estimated using cricket chirps?
10
Can outdoor temperature be estimated using cricket chirps?
y
=
=
b0
+
b1 x + e
42.997 + 0.906 x + e
11
Best estimate: Temperature = 42.997 + (0.906)(Chirps) + e.
In other words, the best line intercepts the y-axis at about 43, and it
has a slope of about 0.9.
90
80
70
Temperature
60
50
40
30
20
10
0
0
5
10
15
20
25
Chirps
30
35
40
45
12
For each of our temperature observations, we can determine how
much our model’s prediction for temperature is in error.
“Predicted y”
=
=
b0
+
b1 x + e
42.997 + 0.906 x + 0
Error (“e”) = “Predicted y” – “Actual y”.
For 1st observation, “Predicted y” = 42.997 + (0.906)(18) = 59.30.
Error = 59.30 – 57 = 2.30.
Temp.
57
60
64
65
68
71
74
77
Chirps
18
20
21
23
27
30
34
39
Predicted
y
Error (e)
59.30
2.30
61.11
1.11
62.02
-1.98
63.83
-1.17
67.45
-0.55
70.17
-0.83
73.79
-0.21
78.32
1.32
13
For each of our temperature observations, we can determine how
much our model’s prediction for temperature is in error.
“Predicted y”
=
=
b0
+
b1 x + e
42.997 + 0.906 x + 0
Error (“e”) = “Predicted y” – “Actual y”.
For 1st observation, “Predicted y” = 42.997 + (0.906)(18) = 59.30.
Error = 59.30 – 57 = 2.30.
Temp.
57
60
64
65
68
71
74
77
Chirps
18
20
21
23
27
30
34
39
Predicted
y
Error (e)
59.30
2.30
61.11
1.11
62.02
-1.98
63.83
-1.17
67.45
-0.55
70.17
-0.83
73.79
-0.21
78.32
1.32
e2
5.29
1.24
3.93
1.37
0.30
0.69
0.04
1.75
14.61
= sum of the e2
Ordinary least squares (OLS) finds the line that minimizes the sum of the squared errors (e2).
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It looks like our model is pretty good. We can tell how good it is in a
statistical sense by examining the Adjusted R Square (R2) of the
regression and the t-statistics and p-values of the coefficients.
Adjusted R2 = 94.8%.
This means our model has
explained 94.8% of the
variance of Temperature.
You could look up these T-stats in a
statistical table to determine
whether they were significantly
different from 0.
It’s easier just to use the P-values.
The P-values are the probability of
obtaining our coefficients (b0 , b1) if
they were truly equal to 0.
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Step 6 – Determine whether the model is good in a statistical sense.
The p-value of each of the coefficients is less than 5%. Therefore, we say each coefficient is significantly
different from zero at the 5% level.
The p-value of the F-stat tells us how good the model is overall. It also has a p-value less than 5%.
Therefore, we say the regression is significant at the 5% level.
Parameter b 0 : "Intercept"
1) Coefficient estimate
2) t-stat
3) p-value
4) Is this coefficient significantly different
from zero at the 5% significance level?
Parameter b 1 : "# of Chirps"
1) Coefficient estimate
2) t-stat
3) p-value
4) Is this coefficient significantly different
from zero at the 5% significance level?
MEMO:
1) Adjusted R-squared
2) F-stat
3) p-value of the F-stat
4) Is the regression significant
at the 5% level?
42.997
19.67
1.12E-06
yes -- 0.000001 < .05
0.9058
11.35
2.81E-05
yes -- 0.000028 < .05
0.948
128.73
2.81E-05
yes -- 0.000028 < .05
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Suppose the p-value of the coefficient for CHIRPS had been > 5%.
We would have concluded that it was NOT significantly different from zero at the 5% level.
In that case, we would have to conclude that our best model for estimating temperature would be:
Temperature = b0 . And b0 would just equal the average of our Temperatures (67 degrees). We would
have to conclude that CHIRPS are of no help for determining outdoor temperature.
Parameter b 0 : "Intercept"
1) Coefficient estimate
2) t-stat
3) p-value
4) Is this coefficient significantly different
from zero at the 5% significance level?
Parameter b 1 : "# of Chirps"
1) Coefficient estimate
2) t-stat
3) p-value
4) Is this coefficient significantly different
from zero at the 5% significance level?
MEMO:
1) Adjusted R-squared
2) F-stat
3) p-value of the F-stat
4) Is the regression significant
at the 5% level?
42.997
19.67
1.12E-06
yes -- 0.000001 < .05
0.9058
11.35
2.81E-05
yes -- 0.000028 < .05
0.948
128.73
2.81E-05
yes -- 0.000028 < .05
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