Molarity and Dilutions
Concentration of Solutions
Molarity and Dilutions
E.Q.: How do we calculate the
concentration of solute in a
solution (molarity)?
Molarity
Molarity – Measurement of the concentration of a
solution (how much solute is in a volume of solution)
Molarity (M) is equal to the number of moles of solute (n)
per liter of solution
Molarity (M) = moles of solute / liters of solution
Units: M = mol / L
Molarity
Be careful not to get molarity and moles mixed up. Moles
measures the amount of material you have. Molarity
measures the concentration of the material.
Molarity
Suppose we had 1.oo mole of sucrose and proceeded to
mix it into some water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until
all the solid was gone. We then made sure that when
everything was well-mixed, there was exactly 1.00 liter of
solution.
What would be the molarity of the solution?
M = 1.00 mole / 1.00 liter = 1.00 mol/L or 1.00 M
Often, instead of writing the units as mol/L, a capital M is
used (M = mol/L)
Molarity Examples
1. Calculate the molarity of a solution prepared by mixing
1.5 g of NaCl in 500.0 mL of water
First calculate the moles of solute in the solution:
1.5 grams NaCl
1 mol NaCl
= 0.026 mol NaCl
58.443 grams NaCl
Next convert mL to L: 0.500 L
Last, plug the appropriate values into the correct variables in the equation:
M = n / V = 0.026 mol / 0.500 L = 0.052 mol/L or 0.052 M
Molarity Examples
2. Calculate the mass of NaOH needed to prepare 1.00 L of
a 1.50 M solution.
To do this, the formula for molarity needs to be rearranged in order to solve for
the number of moles:
M = moles / liters
moles = M x liters
Numbers are then plugged into rearranged formula:
moles = (1.50 mol/L) x (1.00 L) = 1.50 mol NaOH
We then find the grams in the 1.50 mol of NaOH by using dimensional analysis
1.50 mol NaOH
39.997 grams NaOH
1 mol NaOH
= 59.9955 grams NaOH = 60.0 grams NaOH
Molarity Examples
3. 965 grams of NaOH is used in preparing a 1.5M solution.
What volume of solution can be made?
First calculate the moles of solute in the solution:
965 grams NaOH
1 mol NaOH
= 24.1 mol NaOH
39.997 grams NaOH
We now rearrange the formula for molarity to solve for volume (liters):
M = moles / volume
volume = moles / M
Numbers are then plugged into rearranged formula:
volume = (24.1 mol) / (1.5 mol/L) = 16.0666 L = 16 L
Your Turn……
1. Sea water contains roughly 28.0 g of NaCl per liter. What is the
molarity of sodium chloride in sea water?
2. What is the molarity of 245.0 g of H2SO4 dissolved in 1.00 L of
solution?
3. How many moles of Na2CO3 are there in 10.0 L of 2.0 M
solution?
4. What weight (in grams) of H2SO4 would be needed to make
750.0 mL of 2.00 M solution?
5. What volume of 18.0 M H2SO4 is needed to contain 2.45 g
H2SO4?
Dilutions
Dilution: The process of decreasing the concentration of a stock
solution by adding more solvent to the solution.
-
The solvent added is usually the universal solvent, known as water.
The more solvent you add, the more diluted the solution will get.
-
A stock solution is a concentrated solution that will be diluted to a
lower concentration for actual use
Dilutions
The equation for dilution is
M1V1=M2V2
stock solution= diluted solution
• M1= molarity of the stock solution
• M2= molarity of the diluted solution
• V1= volume of stock solution
• V2= volume of diluted solution
Basically, dilution calculations involve figuring out the final concentration
or volume ( depending on what’s given and what’s known) after a volume
or concentration has been changed.
In dilution equations, you are given three things and you need to find the
fourth component.
Dilution Examples
1. If I add 25 mL of water to 125 mL of a 0.150 M NaOH solution, what will the
molarity of the diluted solution be?
2.
If I add water to 100. mL of a 0.150 M NaOH solution until the final volume is
150. mL, what will the molarity of the diluted solution be?
Dilution Examples
3. I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of
the solution is 250 mL, what will the molarity of the solution be?
4.
How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?