Physics 05: Electric Currents

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Physics 05: Electric Currents
BY HEI MAN KWOK 12N03S
5.1 ELECTRIC POTENTIAL DIFFERENCE,
CURRENT AND RESISTANCE
Model of electric conduction in a
metal – energy transfer
1.
2.
3.
4.
5.
Charge carriers have kinetic energy
These collide with lattice ions
Increasing amplitude of vibrations
This is seen in an increase in temperature
Electrons loses it energy and transfers it to
thermal energy
Speed of electron through a conductor = drift
speed
Charge (Q)
• Measured in Coulombs (C)
• Charge of 1 electron = 1.6 π‘₯ 10−19 𝐢
• 1 Coulomb =
1
1.6π‘₯ 10−19
= 6.2 x 1018 electrons
Electric Potential Difference
• Energy taken per unit charge
𝐸 (π‘’π‘›π‘’π‘Ÿπ‘”π‘¦)
𝑉(π‘£π‘œπ‘™π‘‘π‘Žπ‘”π‘’) =
𝑄 (πΆβ„Žπ‘Žπ‘Ÿπ‘”π‘’)
1 volt = wd per unit charge, 1 joule per coulomb
Change in potential energy when a
charge moves between two points at
different potentials
• Potential energy (J) = Voltage (V) x Charge
(C)
𝐸𝑝 = π‘‰π‘ž
Insert diagram 
Electronvolt (eV)
• Amount of energy (work done) one electron
would gain by moving through a potential
difference of 1 volt
• eV = 1.6 π‘₯ 10−19 𝐽
• Charge of a electron = −1.6 π‘₯ 10−19 𝐢
Electric Current (in a conductor)
The rate flow of electric charge (from positive to
negative potential)
𝑄 (πΆβ„Žπ‘Žπ‘Ÿπ‘”π‘’)
𝐼 π‘π‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘ =
𝑑 (π‘‘π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› 𝑖𝑛 π‘ π‘’π‘π‘œπ‘›π‘‘π‘ )
Ampere = force per unit length between parallel
current-carrying conductors why? 2x 10^7 N
Resistance
• Ratio of Voltage to Current
• How easily does current flow through
𝑉 (π‘π‘œπ‘‘π‘’π‘›π‘‘π‘–π‘Žπ‘™ π‘‘π‘–π‘“π‘“π‘’π‘Ÿπ‘’π‘›π‘π‘’)
𝑅 π‘…π‘’π‘ π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ =
𝐼 (π‘π‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘)
Resistor = a component with a known resistance
Resistivity
𝐿 (π‘™π‘’π‘›π‘”π‘‘β„Ž)
𝑅(π‘Ÿπ‘’π‘ π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’) = 𝜌
𝐴 (π‘π‘Ÿπ‘œπ‘ π‘  − π‘ π‘’π‘π‘‘π‘–π‘œπ‘›π‘Žπ‘™ π‘Žπ‘Ÿπ‘’π‘Ž)
𝜌 = π‘Ÿπ‘’π‘ π‘–π‘ π‘‘π‘–π‘£π‘–π‘‘π‘¦ π‘œπ‘“ π‘‘β„Žπ‘’ π‘šπ‘Žπ‘‘π‘’π‘Ÿπ‘–π‘Žπ‘™
More current flows through a short fat conductor
than a long thin one
Ohm’s Law
• The ratio of potential difference to current are
proportional at constant temperature
• V = IR
• Eg. Wires and fixed resistors
Non-Ohmic – Filament lamp
• As current increases, temperature increases,
atoms vibrate more, collisions between
electrons and metal atoms are more frequent
so resistance increases, and graph flattens
• The current is not directly proportional to the
voltage – disobeys ohm’s law
• Graph = symmetrical
Diode
• One way value for electrons
• No current when negative V
• Positive = current flows easily as diode has low
resistance above about 0.7V
• LEDs also one way :D
Component’s Potential Difference
Cannot be equal to the p.d. of the battery:
• Some voltage will be lost to internal resistance
and/ or the resistance in wires
Cannot equal to zero
• Low voltage requires very high resistance,
max. resistance of the variable resistor cannot
be infinite, there will always be some
resistance from the component
5.2 ELECTRIC CIRCUITS
Electromotive Force (emf)
• Work done per unit charge made available by
the energy source (cell or battery)
• Power supplied by the cell per unit current
from the cell
Law of Conservation of Energy
• Energy cannot be created or destroyed – the
energy converted from chemical to electrical
in the cell must be equal to the amount
converted from electrical to heat in the
resistor
πΉπ‘Ÿπ‘œπ‘š π‘‚β„Žπ‘š′ 𝑠 πΏπ‘Žπ‘€: 𝑉 = 𝐼𝑅
Internal Resistance
• The resistance of the cell is ^
πœ€ = 𝐼𝑅 + πΌπ‘Ÿ
• As current flows through the internal resistance –
some energy is converted from electrical to heat
inside the cell (so the cell gets hot)
• This means that there is less energy to be
converted to heat in the resistor – p.d. across the
resistor is therefore less than the emf of the cell
Finding Internal Resistance
Experimentally
• V = E – Ir
• By recording values of current and terminal pd as the
external resistance changes you can plot the graph and find
the internal resistance and the emf of the cell.
• If there is more than one cell in series the internal
resistances of the cells must be added.
Power Dissipated
𝑃 = 𝐼𝑉
𝑃 = 𝐼2 𝑅
𝑉2
𝑃=
𝑅
P = Power; I = Current; V = Voltage; R =
Resistance
Power Delivered
𝑃 = πœ€πΌ
In a real battery – actual power delivered will be
a bit less, since there will be some power
dissipated in the internal resistance
V, I, R in Series
π‘‰π‘œπ‘™π‘‘π‘Žπ‘”π‘’ = 𝑉1 + 𝑉2 + 𝑉3
πΆπ‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘ 𝑖𝑠 π‘ π‘Žπ‘šπ‘’
π‘…π‘’π‘ π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ = 𝑅1 + 𝑅2 + 𝑅3
V, I, R in Parallel
πΆπ‘’π‘Ÿπ‘Ÿπ‘’π‘›π‘‘ = 𝐼1 + 𝐼2 + 𝐼3
π‘‰π‘œπ‘™π‘‘π‘Žπ‘”π‘’ 𝑖𝑠 π‘ π‘Žπ‘šπ‘’
1
1
1
1
=
+
+
π‘…π‘’π‘ π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’
𝑅1 𝑅2 𝑅3
Ideal Ammeter
• Zero resistance so it does not change the
current in the circuit
• Connected in series so the current will flow
through the ammeter as it flows through a
component
Ideal Voltmeter
• Infinite resistance so it does not take any
current from the circuit
• Connected in parallel to see the difference in
potential energy between two points
Thermistor and LDR
• Made of semi-conducting material
• Heat and light frees more charge carriers: as the
temperature/ light intensity increases, the
resistance decreases
• The current is not directly proportional to the
voltage
LDR
Thermistor
Strain Gauge
• Think metal wire
• If stretch – length increases and crosssectional area decreases = increase in
resistance
Potential Divider
π‘‰π‘œπ‘’π‘‘
𝑅2
= 𝑉𝑖𝑛
𝑅1 + 𝑅2
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