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Review for Unit 2 Test
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YOU MISSED!
10 points
Parallel, Perpendicular, or neither
2y=4x+7
-4x=-y-2
Show all work!!!
Answer:
Perpendicular
10 points
What is a line perpendicular to y=4 that goes through
point (2,-3)?
Answer: x=2
10 points
Find the error given a||b
11 12
14 13
15 16
18 17
a
<15+<14=180 consecutive interior <‘s
b
OR
<11+<14=180 Linear Pair
 17  13
 12  18
 11  14  180
 15  13
Corresponding <‘s
Alternate Exterior <‘s
Consecutive <‘s
Alternate Interior <‘s
10 points
What is the equation of the line that passes through
points (3,5), (-1,1)
y=x+2
50 points
Solve for x
Alternate Exterior
Angles ≅
given a||b
3x+15
4x-17
a
b
3𝑥 + 15 = 4𝑥 − 17
15 = 𝑥 − 17
𝑥 = 32
50 points
• Find x with Justification
3x  5  11x  7  180
11x + 7
14 x  12  180
14 x  168
3x + 5
x  12
x = 12 because consecutive interior angles are
supplementary
50 points
• Write the following as a biconditional
• If two lines that are cut by a transversal are parallel, then
alternate interior angles are congruent.
Two lines that are cut by a transversal are parallel IF AND ONLY IF
alternate interior angles are congruent.
or
Two lines that are cut by a transversal are parallel IFF alternate
interior angles are congruent.
50 points
Write a 2-column proof
Given: 𝑎||𝑏
Prove: < 1 𝑎𝑛𝑑 < 3 are supplementary
2 3
Statement
Justification
(1) 𝑎||𝑏
(1) Given
(2) 𝑚 < 2 + 𝑚 < 3 = 180
(2) Def of Linear Pair
(3) 𝑚 < 1 = 𝑚 < 2
(3) Corresponding <′ 𝑠 ≅
(4) 𝑚 < 1 + 𝑚 < 3 = 180
(4) Substitution
(5) < 1 𝑎𝑛𝑑 < 3 are
supplementary
(5) Def of supplementary
1
a
b
50 points
50 point answer
• Two non-adjacent angles formed by
intersecting lines.
50 points
50 point answer
• State the truth value of the following conditional. Give a
counter example if necessary.
• If two angles are complimentary, then they are
congruent.
FALSE, angles that measure 30° and 50° are
complimentary but NOT congruent.
100 points
100 point answer
• A pair of adjacent supplementary angles
100 points
100 ans
Match each angle pair to its example based on
the diagram
B. 1. <7 & <6
C. 2. <13 & <12
A. 3. <8 & <10
7 12
8 9
13 11
10 6
3. <8 & <10
A. Corresponding <‘s
B. Alternate Exterior <‘s 1. <7 & <6
C. Consecutive Interior <‘s
2. <13 & <12
100 points
100 point answer
• Write an equation that passes through (8, 11) and is
perpendicular to 3y+2x=15
2
old: y  3 x  5
3
New: m 
2
3
11  (8)  b
2
11  12  b
1  b
3
y  x 1
2
100 points
100 ans
• Determine the values of x and y. Find each angle measure.
𝑎||𝑏
𝟏𝟎𝟗°
4𝑥 + 5𝑦 − 13
𝟏𝟓𝒙 − 𝟏𝟎𝒚 + 𝟖
𝟐𝒙 + 𝟓𝒚 − 𝟐𝟏
𝟏𝟎𝟗°
𝟕𝟏°
a
b
4𝑥 + 5𝑦 − 13 + 𝟐𝒙 + 𝟓𝒚 − 𝟐𝟏 = 180
6𝑥 + 10𝑦 = 214
𝟏𝟓𝒙 − 𝟏𝟎𝒚 + 𝟖 = 4𝑥 + 5𝑦 − 13
11𝑥 − 15𝑦 = −21
3(6𝑥 + 10𝑦 = 214)
2(11𝑥 − 15𝑦 = −21)
18𝑥 + 30𝑦 = 642
22𝑥 − 30𝑦 = −42
40𝑥 = 600
𝑥 = 15
6 15 + 10𝑦 = 214
90 + 10𝑦 = 214
10𝑦 = 124
𝑦 = 12.4
500 points
500 ans
• Write an equation to represent this function
𝒙
𝑓(𝑥)
𝑏 = −7
(0th term)
1
-15
2
-23
3
-31
4
-39
𝑚 = −8
𝒇 𝒙 = −𝟖𝒙 − 𝟕
5
-47
500 points
500 ans
Write a 2-column Proof
Given : 𝑎||𝑏 and 𝑐||𝑑
Prove: < 1 𝑎𝑛𝑑 < 5 are supplementary
Statement
Justification
(1) 𝑎||𝑏
(1) Given
(2) 𝑚 < 4 + 𝑚 < 5 = 180
(2) Definition of Linear Pair
(3) 𝑚 < 1 = 𝑚 < 3
(3) Alternate Exterior <‘s ≅
(4) 𝑚 < 3 = 𝑚 < 4
(4) Alternate Interior <‘s ≅
(5) 𝑚 < 1 = 𝑚 < 4
(5) Transitive Property
(6) 𝑚 < 1 + 𝑚 < 5 = 180
(6) Substitution
(7) < 1 𝑎𝑛𝑑 < 5 are
supplementary
(7) Definition of supplementary
3
1 2
c
a
4 5
d
b
500 points
500 points
Solve this proportion
1000 points
1000 points