KEY
Kinematics Worksheet (Part 2)
Name:___________________________
___________
Date:______________
Mod:______________
Directions: Answer the following motion problems using the kinematic equations. Show your
work and circle your final answer.
1. A speedboat increases in speed uniformly from 20m/s to 30m/s in a distance of 200m.
What is the acceleration of the speedboat?
𝑣𝑓 2 = 𝑣𝑖 2 + 2𝑎𝑑
𝑚
𝑣𝑓 = 30 𝑠
𝑣𝑓 2 − 𝑣𝑖 2
𝑚
𝑎
=
𝑣𝑖 = 20 𝑠
2𝑑
2
2
𝑚
𝑎 =?
(30 𝑠 ) − (20𝑚
𝑠)
𝑎=
𝑡 = 𝑥𝑥𝑥
2(200𝑚)
𝑑 = 200𝑚
𝑚
𝑎 = 1.25 𝑠2
2. A driver in a car traveling at a speed of 60 mi/hr sees a deer in the middle of the road
100m away. What is the minimum constant acceleration that is necessary for the car to
stop?
60𝑚𝑖 5280𝑓𝑡 12𝑖𝑛 2.54𝑐𝑚
1𝑚
1ℎ𝑟
𝑥
𝑥
𝑥
𝑥
𝑥
= 26.82𝑚𝑠
𝑚
1ℎ𝑟
1𝑚𝑖
1𝑓𝑡
1𝑖𝑛
100𝑐𝑚
3600𝑠
𝑣𝑓 = 0 𝑠
𝑚
𝑣𝑖 = 26.82 𝑠
𝑎 =?
𝑡 = 𝑥𝑥𝑥
𝑑 = 100𝑚
𝑣𝑓 2 = 𝑣𝑖 2 + 2𝑎𝑑
𝑣𝑓 2 − 𝑣𝑖 2
𝑎=
2𝑑
2
2
−
(0𝑚
)
(26.82𝑚
𝑠
𝑠)
𝑎=
2(100𝑚)
𝑚
𝑎 = −3.60 𝑠2
3. Julie is walking around a track at a 2m/s for some exercise. She then decides to start
jogging so she accelerates at a rate of 0.5m/s² for 3 seconds. How far did Julie travel
from the time she started to accelerate to the end of the 3 seconds?
𝑣𝑓 = 𝑥𝑥𝑥
1
𝑚
𝑑 = 𝑣𝑖 𝑡 + 2𝑎𝑡 2
𝑣𝑖 = 2 𝑠
𝑚
𝑎 = 0.5𝑠2
𝑡 = 3𝑠
𝑑 =?
𝑚
1
𝑚
𝑑 = (2 𝑠 ) (3 𝑠) + 2 (0.5𝑠2 ) (3 𝑠)2
𝑑 = 8.25𝑚
4. A rocket accelerates at a rate of 16.4m/s² for a distance of 50m. What is the velocity at
the end of the 50m?
𝑣𝑓 2 = 𝑣𝑖 2 + 2𝑎𝑑
𝑣𝑓 = ?
𝑚
𝑣𝑓 = √𝑣𝑖 2 + 2𝑎𝑑
𝑣𝑖 = 0 𝑠
𝑚
𝑚
𝑣𝑓 = √2 (16.4 2 ) (50𝑚)
𝑎 = 16.4 2
𝑠
𝑡 = 𝑥𝑥𝑥
𝑑 = 50𝑚
Kinematics Worksheet (Part 2)
Methacton High School Physics Department
𝑠
𝑚
𝑣𝑓 = 40.50 𝑠
1
5. A car can finish a 4.0x102 m race in 6.0 seconds. What is the minimum constant
acceleration necessary?
𝑑 = 𝑣𝑖 𝑡 + 12𝑎𝑡 2
2(𝑑 − 𝑣𝑖 𝑡)
𝑣𝑓 = 𝑥𝑥𝑥
𝑎=
𝑚
𝑡2
𝑣𝑖 = 0 𝑠
2(400𝑚 − (0𝑚
𝑠 )(6.0𝑠))
𝑎 =?
𝑎=
2
6.0𝑠
𝑡 = 6.0𝑠
𝑑 = 400𝑚
𝑚
𝑎 = 22.22 𝑠2
6. A car on a wet road can achieve an acceleration of only -1.00 m/s2 without sliding. Find
the required stopping distance for a speed of 48km/hr.
48𝑘𝑚 1000𝑚
1ℎ𝑟
𝑚
𝑥 1𝑘𝑚 𝑥 3600𝑠 = 13.33𝑚𝑠
𝑣 = 0
1ℎ𝑟
𝑓
𝑠
𝑘𝑚
𝑣𝑖 = 48 ℎ𝑟
𝑣𝑓 2 = 𝑣𝑖 2 + 2𝑎𝑑
𝑣𝑓 2 − 𝑣𝑖 2
𝑑=
2𝑎
2
𝑚 2
(0 𝑠 ) − (13.33𝑚
𝑠)
𝑑=
2(−1.00𝑠𝑚2 )
𝑚
𝑎 = −1.00𝑠2
𝑡 = 𝑥𝑥𝑥
𝑑 =?
𝑑 = 88.84𝑚
7. The normal reaction time for a human to respond to stimuli is around 0.60 seconds. A
person driving a car is going 25.5 m/s at a constant speed when all of a sudden a deer
jumps out onto the road. The person slams on his brakes and it takes 4.70 seconds to
come to a complete stop. How far did the car travel once the driver saw the deer?
𝑑1 = 𝑣1 𝑡1
𝑚
𝑑1 = (25.5 𝑠 ) (0.60𝑠)
𝑑1 = 15.3𝑚
𝑚
𝑣𝑓2 = 0 𝑠
𝑚
𝑣𝑖2 = 25.5 𝑠
𝑎2 = 𝑥𝑥𝑥
𝑡2 = 4.70𝑠
𝑑2 = ?
Reaction Time
=
Constant
Velocity
𝑑1
Kinematics Worksheet (Part 2)
Methacton High School Physics Department
𝑣𝑖2 + 𝑣𝑓2
𝑑2 = (
) 𝑡2
2
𝑚
25.5 𝑠 + 0𝑚
𝑠
𝑑2 = (
) 4.70 𝑠
2
𝑑𝑡𝑜𝑡𝑎𝑙= 𝑑1 + 𝑑2 = 15.30𝑚 + 59.93
𝑑𝑡𝑜𝑡𝑎𝑙 = 75.23𝑚
𝑑2 = 59.93 𝑚
𝑑2
Brake Applied
=
Deceleration
2