2.4 Notes

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Advanced Algebra Notes
Section 2.4: Write Equations of Lines
Given slope and y-intercept b
Use slope-intercept form
𝑦 = π‘šπ‘₯ + 𝑏
Given slope and a point (π‘₯, 𝑦)
Use point slope form
𝑦 − 𝑦1 = π‘š π‘₯ − π‘₯1
Given points (π‘₯1 , 𝑦1 ) and (π‘₯2 , 𝑦2 )
First use the slope formula to find m.
𝑅𝑖𝑠𝑒 π‘œπ‘£π‘’π‘Ÿ 𝑅𝑒𝑛 𝑔𝑒𝑑𝑠 π‘‘β„Žπ‘’ π‘—π‘œπ‘ π‘‘π‘œπ‘›π‘’! Then use point-slope form with either point
𝑅𝑖𝑠𝑒 (𝑦)
π‘ˆπ‘ π‘’ π‘ π‘™π‘œπ‘π‘’ π‘“π‘œπ‘Ÿπ‘šπ‘’π‘™π‘Ž π‘‘π‘œ 𝑓𝑖𝑛𝑑 π‘š (π‘ π‘™π‘œπ‘π‘’)
π‘š=
π‘‡β„Žπ‘’π‘› π‘’π‘–π‘‘β„Žπ‘’π‘Ÿ π‘“π‘œπ‘Ÿπ‘šπ‘’π‘™π‘Ž 𝑀𝑖𝑙𝑙 π‘€π‘œπ‘Ÿπ‘˜!
𝑅𝑒𝑛 (π‘₯)
Example 1
Write an equation of the line shown.
πΈπ‘žπ‘’π‘Žπ‘‘π‘–π‘œπ‘› π‘œπ‘“ π‘Ž 𝑙𝑖𝑛𝑒
𝑦 = π‘šπ‘₯ + 𝑏
π‘Šβ„Žπ‘Žπ‘‘ 𝑖𝑠 π‘œπ‘’π‘Ÿ π‘ π‘™π‘œπ‘π‘’? π‘Šβ„Žπ‘’π‘Ÿπ‘’
π‘‘π‘œπ‘’π‘  π‘‘β„Žπ‘’ π‘”π‘Ÿπ‘Žπ‘β„Ž π‘ π‘‘π‘Žπ‘Ÿπ‘‘ π‘œπ‘› π‘‘β„Žπ‘’
𝑦 − π‘Žπ‘₯𝑖𝑠?
3
𝑦 = π‘₯ + (−2)
4
Example 2
Write an equation of the line that passes through (5,4) and has a slope of −3.
𝑦 − 𝑦1 = π‘š(π‘₯ − π‘₯1 )
π‘ƒπ‘œπ‘–π‘›π‘‘ − π‘ π‘™π‘œπ‘π‘’ π‘“π‘œπ‘Ÿπ‘š
𝑃𝑙𝑒𝑔 𝑖𝑛 π‘‘β„Žπ‘’ 𝑔𝑖𝑣𝑒𝑛 π‘£π‘Žπ‘™π‘’π‘’π‘ !
𝑦 − 4 = −3(π‘₯ − 5)
𝑦 − 4 = −3(π‘₯ − 5)
𝑦 − 4 = −3π‘₯ + 15
𝑦 = −3π‘₯ + 19
Example 3
Write an equation of the line that passes through (−2,3) and is
Parallel to the line 𝑦 = −4π‘₯ + 1
𝐿𝑖𝑛𝑒𝑠 π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘Ÿπ‘’ π‘π‘Žπ‘Ÿπ‘Žπ‘™π‘™π‘’π‘™ β„Žπ‘Žπ‘£π‘’ π‘‘β„Žπ‘’ π‘ π‘Žπ‘šπ‘’ π‘ π‘™π‘œπ‘π‘’!
𝑦 = −4π‘₯ + 𝑏
−5 = 𝑏
𝑦 = −4π‘₯ − 5
3 = −4(−2) + 𝑏
Perpendicular to the line 𝑦 = −4π‘₯ + 1
𝐿𝑖𝑛𝑒𝑠 π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘Ÿπ‘’ π‘π‘’π‘Ÿπ‘π‘’π‘›π‘‘π‘–π‘π‘’π‘™π‘Žπ‘Ÿ β„Žπ‘Žπ‘£π‘’ π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘Ÿπ‘’π‘π‘–π‘π‘Ÿπ‘œπ‘π‘Žπ‘™ π‘ π‘™π‘œπ‘π‘’!
1
1
𝑦 − 𝑦1 = −4(π‘₯ − π‘₯1 )
1
7
𝑦 = π‘₯+ +3
𝑦= π‘₯+
1
4
2
4
2
𝑦 − 3 = (π‘₯ + 2)
4
Example 4
Write an equation of the line that passes through (5, −2) and (2,10)
πΉπ‘–π‘Ÿπ‘ π‘‘ 𝑓𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘ π‘™π‘œπ‘π‘’!
10 − (−2)
π‘š=
2−5
12
π‘š=
−3
π‘š = −4
𝑅𝑖𝑠𝑒 π‘œπ‘£π‘’π‘Ÿ 𝑅𝑒𝑛 𝑔𝑒𝑑𝑠 π‘‘β„Žπ‘’ π‘—π‘œπ‘ π‘‘π‘œπ‘›π‘’!
𝑦 − 𝑦1 = −4(π‘₯ − π‘₯1 )
πΈπ‘–π‘‘β„Žπ‘’π‘Ÿ π‘π‘œπ‘–π‘›π‘‘ 𝑀𝑖𝑙𝑙 π‘€π‘œπ‘Ÿπ‘˜!
𝑦 − (−2) = −4(π‘₯ − 5)
𝑦 + 2 = −4π‘₯ + 20
𝑦 = −4π‘₯ + 18
Example 5
In the school year ending in 1993, 2.00 million females participated in U.S.
high school sports. By 2003, the number had increased to 2.86 million. Write
a linear equation that models female sports participation.
π‘₯ = # π‘œπ‘“ π‘¦π‘’π‘Žπ‘Ÿπ‘ 
𝑦 = # π‘œπ‘“ π‘π‘Žπ‘Ÿπ‘‘π‘–π‘π‘–π‘π‘Žπ‘›π‘‘π‘ 
𝑦 = π‘šπ‘₯ + 𝑏
𝑦 = (.086)π‘₯ + 𝑏
π‘Šβ„Žπ‘Žπ‘‘ 𝑖𝑠 π‘‘β„Žπ‘’ π‘–π‘›π‘‘π‘–π‘Žπ‘™ π‘β„Žπ‘Žπ‘›π‘”π‘’ π‘“π‘Ÿπ‘œπ‘š 1993 π‘‘π‘œ 2003
… 𝑖𝑛 π‘œπ‘‘β„Žπ‘’π‘Ÿ π‘€π‘œπ‘Ÿπ‘‘π‘  … π‘‘β„Žπ‘’ π‘ π‘™π‘œπ‘π‘’!
2.86 − 2.00
π‘š=
10 − 0
π‘š = .086
2.00 𝑖𝑠 π‘‘β„Žπ‘’ π‘–π‘›π‘–π‘‘π‘–π‘Žπ‘™ π‘Žπ‘šπ‘œπ‘’π‘›π‘‘
𝑦 = (.086)π‘₯ + 2.00
Closing: How do you write an equation of a line?
π‘Œπ‘œπ‘’ 𝑒𝑠𝑒 π‘‘β„Žπ‘’ π‘ π‘™π‘œπ‘π‘’, 𝑦 − π‘–π‘›π‘‘π‘’π‘Ÿπ‘π‘’π‘π‘‘ π‘Žπ‘›π‘‘ π‘Ž 𝑔𝑖𝑣𝑒𝑛 π‘π‘œπ‘–π‘›π‘‘
π‘†π‘œπ‘™π‘£π‘’ π‘“π‘œπ‘Ÿ π‘‘β„Žπ‘’ π‘ π‘™π‘œπ‘π‘’
𝐷𝑒𝑐𝑖𝑑𝑒 π‘€β„Žπ‘–π‘β„Ž π‘“π‘œπ‘Ÿπ‘šπ‘’π‘™π‘Ž π‘€π‘œπ‘Ÿπ‘˜π‘  𝑏𝑒𝑠𝑑 …
π‘†π‘™π‘œπ‘π‘’ − π‘–π‘›π‘‘π‘’π‘Ÿπ‘π‘’π‘π‘‘
𝑦 = π‘šπ‘₯ + 𝑏
π‘ƒπ‘œπ‘–π‘›π‘‘ − π‘ π‘™π‘œπ‘π‘’ π‘“π‘œπ‘Ÿπ‘š
𝑦 − 𝑦1 = π‘š(π‘₯ − π‘₯1 )
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