1.4 : Solving Linear Systems in Three Variables

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Solving Linear Systems

(in three variables)

Section 1.4 beginning on page 30

A Linear Equation in Three Variables

What Does This Look Like?

Solving Algebraically

Solve each system:

4𝑥 + 2𝑦 + 3𝑧 = 12

Example 1: 2𝑥 − 3𝑦 + 5𝑧 = −7

6𝑥 − 𝑦 + 4𝑧 = −3

Examples

(−1,5,2) 𝑥 + 𝑦 + 𝑧 = 2

Example 2 : 5𝑥 + 5𝑦 + 5𝑧 = 3

4𝑥 + 𝑦 − 3𝑧 = −6 𝑥 − 𝑦 + 𝑧 = −3

Example 3: 𝑥 − 𝑦 − 𝑧 = −3

5𝑥 − 5𝑦 + 𝑧 = −15

𝑁𝑜 𝑆𝑜𝑙𝑢𝑡𝑖𝑜𝑛

Infinitely Many Solutions

(𝑥, 𝑥 + 3,0)

Real Life Problem

Example 4: An amphitheater charges $75 for each seat in Section A, $55 for each seat in Section B, and $30 for each lawn seat. There are three times as many seats in

Section B as in Section A. The revenue from selling all 23,000 seats is $870,000. How many seats are in each section of the amphitheater?

Declare your variables: X = Number of seats in Section A

Y = Number of seats in Section B

Z = Number of seats on the Lawn

Write three equations using the information provided:

- One equation can represent the relationship between the number of seats in section b and section a

- One equation can represent the total number of seats

- One equation can represent the revenue from selling out 𝑦 = 3𝑥 𝑥 + 𝑦 + 𝑧 = 23,000

75𝑥 + 55𝑦 + 30𝑧 = 870,000

There are 1500 seats in Section A, 4500 seats in

Section B, and 17000 lawn seats.

Monitoring Progress

Solve the system. 𝑥 − 2𝑦 + 𝑧 = −11

1) 3𝑥 + 2𝑦 − 𝑧 = 7

−𝑥 + 2𝑦 + 4𝑧 = −9

(−1,3, −4) 𝑥 + 𝑦 − 𝑧 = −1

2) 4𝑥 + 4𝑦 − 4𝑧 = −2

3𝑥 + 2𝑦 + 𝑧 = 0 𝑥 + 𝑦 + 𝑧 = 8

3) 𝑥 − 𝑦 + 𝑧 = 8

2𝑥 + 𝑦 + 2𝑧 = 16

𝑁𝑜 𝑆𝑜𝑙𝑢𝑡𝑖𝑜𝑛

(8 − 𝑧, 0, 𝑧)

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