MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . He still has 4 choices of pants π1 π1 π2 π3 π4 MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . He still has 4 choices of pants π1 And for each π1 π2 π3 π4 choice of pants, he has 6 choices of π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 jackets MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . He still has 4 choices of pants π1 So, the designer has 24 different outfits that include top, π1 . And for each π1 π2 π3 π4 choice of pants, he has 6 choices of π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 π½1 π½2 π½3 π½4 π½5 π½6 jackets MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? Tops = {π1 , π2 , π3 , π4 , π5 },Pants = {π1 , π2 , π3 , π4 }, Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 But the designer does not have to stick with Top, π1 . MATH 110 Sec 12.1 Intro π π to X1 Counting Practice Exercises 2 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 If he decided to use Top, π2 instead, there would be another 24 different outfits. MATH 110 Sec 12.1 Intro π π to X1 Counting Practice Exercises 2 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 and the designer has 24 different outfits that include top, π2 If he decided to use Top, π2 instead, there would be another 24 different outfits. MATH 110 Sec 12.1 Intro π3 π to π X1 Counting Practice Exercises 2 X A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, So, the the designer designer has has 24 24 different different outfits outfits that that include include top, top, ππ11. and the designer has 24 different outfits that include top, π2 If he decided to use Top, π3 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro π π33 π2to X1 Counting Practice Exercises X2 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 If he decided to use Top, π3 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro π X3 π toπX1 πCounting Practice Exercises 2 X 4 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, So, the the designer designer has has 24 24 different different outfits outfits that that include include top, top, ππ11. and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 If he decided to use Top, π4 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro π πX33 π2to X1 πCounting Practice Exercises X2 4 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 and the designer has 24 different outfits that include top, π4 If he decided to use Top, π4 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro Practice Exercises π π5 X3 π toπX1 πCounting 2 X4 X A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, So, the the designer designer has has 24 24 different different outfits outfits that that include include top, top, ππ11. and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 and the designer has 24 different outfits that include top, π4 Finally, if he decided to use Top, π5 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro Practice Exercises π π5 πX33 π2to X1 πCounting X2 X4 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } Suppose the designer has already decided to use the Top, π1 . So, the designer has 24 different outfits that include top, π1 and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 and the designer has 24 different outfits that include top, π4 and the designer has 24 different outfits that include top, π5 Finally, if he decided to use Top, π5 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro Practice Exercises π π5 πX33 π2to X1 πCounting X2 X4 A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 π3 model possibly π4 1 pants & 1πjacket) 2 top, 1 pair πof can the wear? Tops = {π , π , π , π , π },Pants = {π , π , π , π }, π½1 π½2 π½3 π½4 π½5 π½61 π½1 2π½2 π½33 π½4 π½45 π½65 π½1 π½2 π½3 π½4 π½5 π½6 π½11 π½2 2π½3 π½43 π½5 π½46 Jacket = {π½1 , π½2 , π½3 , π½4 , π½5 , π½6 } So, all together, there would 24 x 5 decided = 120 different outfits. Suppose the designer has be already to usepossible the Top, π1 . So, the designer has 24 different outfits that include top, π1 and the designer has 24 different outfits that include top, π2 and the designer has 24 different outfits that include top, π3 and the designer has 24 different outfits that include top, π4 and the designer has 24 different outfits that include top, π5 Finally, if he decided to use Top, π5 , there would be another 24 different outfits. MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. Note: Because we also covered the section on the Fundamental Counting Principle, we could actually use that to answer this question much more efficiently. MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. # ways to choose top x # ways to choose pants x # ways to choose jacket = possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 5 # ways to choose top x # ways to choose pants x # ways to choose jacket = possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 5 # ways to choose top x 4 x # ways to choose pants x # ways to choose jacket = possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 5 # ways to choose top x 4 x 6 x # ways to choose pants x # ways to choose jacket = possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 5 # ways to choose top x 4 x 6 = x # ways to choose pants x # ways to choose jacket = 120 possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises A designer designed 5 different tops, 4 different pants and 6 different jackets. How many different outfits (consisting of 1 top, 1 pair of pants & 1 jacket) can the model possibly wear? So the model could possibly wear 120 different outfits. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) you get the same answer as A task composed of aNotice seriesthat of sub-tasks in which the first before without havingthe to draw a tree sub-task can be performed in a ways, second in diagram. b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 5 # ways to choose top x 4 x 6 = x # ways to choose pants x # ways to choose jacket = 120 possible MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? Because a tree diagram here would be very large, we will once again take advantage of the fact that we have already covered the section on the Fundamental Counting Principle. MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. Here we will be choosing from 4 possible letters (U, V, E, A) and 3 possible numbers (8, 3, 7). MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 x 1 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 x 1 x 3 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 x 1 x 3 x 2 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 x 1 x 3 x 2 x 1 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 4 x 3 x 2 x 1 x 3 x 2 x 1 = 144 #waysto #waysto #waysto #waysto # ways # ways # ways choose x choose x choose x choose x choose x choose x choose = TOT 1st letter 2nd letter 3rd letter 4th letter 1st # 2nd # 3rd # MATH 110 Sec 12.1 Intro to Counting Practice Exercises An eyewitness to a crime said that the license plate of the getaway car began with the four letters U, V, E and A (but he couldn’t remember the order). The rest of the plate had the numbers 8, 3 and 7 but, again, he could not remember the order. How many license plates fit the eyewitness description? 144 license plates fit the eyewitness description. MATH 110 Sec 12.1 Intro to Counting Practice Exercises Two couples (Adam/Brenda and Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? MATH 110 Sec 12.1 Intro to Counting Practice Exercises Two couples (Adam/Brenda and Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? To make it easier to see how to keep the 2 males apart, let’s replace the male names with π΄π & π΄π and the female names with ππ and ππ . MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? To make it easier to see how to keep the 2 males apart, let’s replace the male names with π΄π & π΄π and the female names with ππ and ππ . MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Our task is to list every possible way that the couples could be seated without the men sitting together. MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Suppose π1 sits in the first seat. π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Suppose π1 sits in the first seat. We can’t seat π2 in seat 2 but we can seat either πΉ1 or πΉ2 there. π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Suppose π1 sits in the first seat. We can’t seat π2 in seat 2 but we can seat either πΉ1 or πΉ2 there. πΉ1 π1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π2 or πΉ2 ) can be next. πΉ1 π1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π2 or πΉ2 ) can be next. πΉ1 π1 πΉ2 π2 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π2 or πΉ2 ) can be next. πΉ1 π1 πΉ2 π2 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now let’s move to the case in which π1 sits in seat 1 and πΉ2 sits in seat 2. πΉ1 π1 πΉ2 π2 πΉ2 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π2 or πΉ1 ) can be next. πΉ1 π1 πΉ2 π2 πΉ2 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π2 or πΉ1 ) can be next. πΉ1 π1 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π1 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π2 or πΉ1 ) can be next. πΉ1 π1 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose π2 sits in the first seat. πΉ1 π1 πΉ2 π2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose π2 sits in the first seat. We can’t seat π1 in seat 2 but we can seat either πΉ1 or πΉ2 there. πΉ1 π1 πΉ2 π2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose π2 sits in the first seat. We can’t seat π1 in seat 2 but we can seat either πΉ1 or πΉ2 there. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π1 or πΉ2 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π1 or πΉ2 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ1 sits in the second seat, then either of the two remaining (π1 or πΉ2 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now let’s move to the case in which π2 sits in seat 1 and πΉ2 sits in seat 2. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π1 or πΉ1 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π1 or πΉ1 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If π2 sits in the first seat and πΉ2 sits in the second seat, then either of the two remaining (π1 or πΉ1 ) can be next. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Once 3 people are seated, the only person yet to be seated must sit in the fourth seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ1 sits in the first seat. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ1 sits in the first seat. This forces us to seat a male next. (Otherwise, the 2 males would have to sit next to each other in seats 3 & 4.) πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ1 sits in the first seat. This forces us to seat a male next. (Otherwise, the 2 males would have to sit next to each other in seats 3 & 4.) πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π1 π2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π1 sits in the second seat, then πΉ2 must sit in seat 3 and π2 in seat 4 to keep the males separated. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π1 π2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π1 sits in the second seat, then πΉ2 must sit in seat 3 and π2 in seat 4 to keep the males separated. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π1 π2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π1 sits in the second seat, then πΉ2 must sit in seat 3 and π2 in seat 4 to keep the males separated. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π1 π2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 π1 π2 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ2 sits in the first seat. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ2 sits in the first seat. This forces us to seat a male next. (Otherwise, the 2 males would have to sit next to each other in seats 3 & 4.) π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? Now suppose πΉ2 sits in the first seat. This forces us to seat a male next. (Otherwise, the 2 males would have to sit next to each other in seats 3 & 4.) π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 π1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ2 sits in the first seat and π1 sits in the second seat, then πΉ1 must sit in seat 3 and π2 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 π1 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ2 sits in the first seat and π1 sits in the second seat, then πΉ1 must sit in seat 3 and π2 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 π1 πΉ1 π2 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ2 sits in the first seat and π1 sits in the second seat, then πΉ1 must sit in seat 3 and π2 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 π1 πΉ1 π2 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 π1 πΉ1 π2 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 π2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 π1 πΉ1 π2 π2 πΉ1 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? If πΉ1 sits in the first seat and π2 sits in the second seat, then πΉ2 must sit in seat 3 and π1 in seat 4 to keep the males separated. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 π2 πΉ1 π2 πΉ2 π1 πΉ1 π1 π2 π2 πΉ2 π1 π1 πΉ1 π2 π2 πΉ1 π1 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 1 π2 2 πΉ1 3 π2 4 πΉ2 5 π1 6 πΉ1 7 π1 8 π2 9 π2 πΉ2 π1 10 π1 πΉ1 π2 11 π2 πΉ1 π1 12 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises π΄π ππ Two couples (Adam/Brenda and π΄ π ππ Carl/Darlene) bought tickets to a musical. In how many ways can the couples be seated if the men do not sit together? So, there are 12 different ways these two couples can be seated in which the men do not sit together. π1 π2 πΉ2 π2 πΉ1 π1 πΉ2 π1 πΉ1 πΉ2 πΉ2 1 π2 2 πΉ1 3 π2 4 πΉ2 5 π1 6 πΉ1 7 π1 8 π2 9 π2 πΉ2 π1 10 π1 πΉ1 π2 11 π2 πΉ1 π1 12 πΉ1 π1 πΉ2 πΉ1 π2 πΉ2 πΉ1 πΉ2 MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? Although we could draw a tree diagram here, we will once again take advantage of the fact that we have already covered the section on the Fundamental Counting Principle. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. Here we will be choosing from 2 possible answers (T or F) for each of the 4 questions. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 x 2 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 x 2 x 2 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 x 2 x 2 = 16 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 x 2 x 2 = 16 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many different ways are there to answer all 4 questions? THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 2 x 2 x 2 x 2 = 16 # ways to answer Q1 x # ways to answer Q2 x # ways to answer Q3 x # ways to answer Q4 = TOT 16 different ways to answer all four T/F questions. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get no questions wrong? MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get no questions wrong? Remember that from the previous problem, there are 16 different ways to answer all four T/F questions. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get no questions wrong? Remember that from the previous problem, there are 16 different ways to answer all four T/F questions. T F T T F F T T F T F F T F T F T F T F T F T F T F T F T F MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get no questions wrong? Remember that from the previous problem, there are 16 different ways to answer all four T/F questions. One of those 16 is the “key” to T F the quiz and unless you match the “key” exactly, you will miss T F T F at least one problem. T F T F T F T F T F T F T F T F T F T F T F T F MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get no questions wrong? Remember that from the previous problem, there are 16 different ways to answer all four T/F questions. One of those 16 is the “key” to T F the quiz and unless you match the “key” exactly, you will miss T F T F at least one problem. So, there is only 1 way to get none of the 4 questions wrong. T F T F T F T F T F T F T F T F T F T F T F T F MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: just the 1st one wrong (XRRR) or R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: just the 1st one wrong (XRRR) or R X R X just the 2nd one wrong (RXRR) or R X R X R X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: just the 1st one wrong (XRRR) or R X R X just the 2nd one wrong (RXRR) or just the 3rd one wrong (RRXR) or R X R X R X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: just the 1st one wrong (XRRR) or R X R X just the 2nd one wrong (RXRR) or just the 3rd one wrong (RRXR) or R X R X R X R X just the 4th one wrong (RRRX) R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get one question wrong? Here it might be easier to think of a quiz that has already been graded. Let ‘R’ be ‘right’ and ‘X’ be ‘wrong’. It is easy to see that the only way R X to get exactly one wrong is to get: just the 1st one wrong (XRRR) or R X R X just the 2nd one wrong (RXRR) or just the 3rd one wrong (RRXR) or R X R X R X R X just the 4th one wrong (RRRX) So, there are 4 ways to get one wrong. R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X 2. RXRX R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X 2. RXRX 3. RXXR R X R X R X R X R X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X 2. RXRX 3. RXXR R X R X 4. XRRX R X R X R X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X 2. RXRX 3. RXXR R X R X 4. XRRX R X R X R X R X 5. XRXR R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? We already have the tree diagram, so perhaps the easiest thing to do is count the number of branches with 2 X’s. 1. RRXX R X 2. RXRX 3. RXXR R X R X 4. XRRX R X R X R X R X 5. XRXR 6. XXRR R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: How many ways are there to get two questions wrong? 1. 2. 3. 4. 5. 6. RRXX RXRX RXXR XRRX XRXR XXRR R So, there are 6 ways to get two wrong. X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR 2. RRRX R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR 2. RRRX 3. RRXR R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR 2. RRRX 3. RRXR 4. RXRR R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR 2. RRRX 3. RRXR 4. RXRR 5. XRRR R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? Note that ‘3 or more correct’ means ‘3 correct’ or ‘4 correct’. Now we are counting the branches with either 3 or 4 R’s. 1. RRRR 2. RRRX So, you have 5 3. RRXR chances out of 16 4. RXRR to get three or 5. XRRR more correct. R X R R X X R R X R X X R X R X R X R X R X R X R X R X R X MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? There is actually a faster way to solve this problem if you realize that getting 3 correct is the same as getting 1 wrong and getting 4 correct is the same as getting none wrong. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? There is actually a faster way to solve this problem if you realize that getting 3 correct is the same as getting 1 wrong and getting 4 correct is the same as getting none wrong. The reason this helps is because we already found that there were 4 ways of getting one wrong and that there was just 1 way of getting no questions wrong. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you are taking a 4 question T/F quiz: If you randomly guess at each answer, what are your chances of getting 3 or more correct? There is actually a faster way to solve this problem if you realize that getting 3 correct is the same as getting 1 wrong and getting 4 correct is the same as getting none wrong. The reason this helps is because we already found that there were 4 ways of getting one wrong and that there was just 1 way of getting no questions wrong. So, there are 4 + 1 = 5 ways to get three or more correct. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. Although you could solve this with a tree diagram (where no branch can have all 3 flavors and each branch must have 2 flavors), we will instead use the Fundamental Counting Principle (FCP). MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. # ways to choose 1st flavor x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises this apoint, we need to notecone that we arevanilla, not allowed to If youAtbuy 3-scoop ice cream with chocolate and have 3 of same flavor nor how can we havedifferent one of each flavor. strawberry asthe possible flavors, many cones are possible if matter your cone 2 of can the only flavors? (Flavors can be So, no what,has theonly 3rd flavor be chosen from repeated and two cones are considered different if the amongor2 not of the 3 available flavors. This is because if the first 2 flavors are match, the same but occur a different order. flavors we can’t chooseinthat flavor again and if the 2 flavors not match, we can’t choose thePRINCIPLE 3rd flavor. (FCP) THEdo FUNDAMENTAL COUNTING A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises this apoint, we need to notecone that we arevanilla, not allowed to If youAtbuy 3-scoop ice cream with chocolate and have 3 of same flavor nor how can we havedifferent one of each flavor. strawberry asthe possible flavors, many cones are possible if matter your cone 2 of can the only flavors? (Flavors can be So, no what,has theonly 3rd flavor be chosen from repeated and two cones are considered different if the amongor2 not of the 3 available flavors. This is because if the first 2 flavors are match, the same but occur a different order. flavors we can’t chooseinthat flavor again and if the 2 flavors not match, we can’t choose thePRINCIPLE 3rd flavor. (FCP) THEdo FUNDAMENTAL COUNTING A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises this apoint, we need to notecone that we arevanilla, not allowed to If youAtbuy 3-scoop ice cream with chocolate and have 3 of same flavor nor how can we havedifferent one of each flavor. strawberry asthe possible flavors, many cones are possible if matter your cone 2 of can the only flavors? (Flavors can be So, no what,has theonly 3rd flavor be chosen from repeated and two cones are considered different if the amongor2 not of the 3 available flavors. This is because if the first 2 flavors are match, the same but occur a different order. flavors we can’t chooseinthat flavor again and if the 2 flavors not match, we can’t choose thePRINCIPLE 3rd flavor. (FCP) THEdo FUNDAMENTAL COUNTING A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x 2 x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x 2 = 18 x # ways to choose 3rd flavor = TOTAL MATH 110 Sec 12.1 Intro to Counting Practice Exercises If you buy a 3-scoop ice cream cone with vanilla, chocolate and strawberry as possible flavors, how many different cones are possible if your cone has only 2 of the flavors? (Flavors can be repeated or not and two cones are considered different if the flavors are the same but occur in a different order. THE FUNDAMENTAL COUNTING PRINCIPLE (FCP) A task composed of a series of sub-tasks in which the first sub-task can be performed in a ways, the second in b ways, the third in c ways, and so on, can be done in a x b x c x ... ways. 3 # ways to choose 1st flavor x 3 x # ways to choose 2nd flavor x 2 = 18 x # ways to choose 3rd flavor = TOTAL So, there are 18 different cones satisfying the given conditions.