Lecture Slides on Graphing Rational Functions

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Math 139 – The Graph of a Rational Function
3 examples
General Steps to Graph a Rational Function
1) Factor the numerator and the denominator
2) State the domain and the location of any holes in the graph
3) Simplify the function by factoring if possible.
4) Find the y-intercept (x = 0) and the x-intercept(s) (y = 0)
5) Identify any existing asymptotes (vertical, horizontal, or
oblique/slant)
General Steps to Graph a Rational Function contd.
6) Identify any points intersecting a horizontal or oblique
asymptote.
7) Use test points between the zeros and vertical asymptotes
to locate the graph above or below the x-axis
8) Analyze the behavior of the graph on each side of an
asymptote
9) Sketch the graph
Example #1
๐‘ฅ 2 + ๐‘ฅ − 12
๐‘“ ๐‘ฅ =
๐‘ฅ2 − 4
1) Factor the numerator and the denominator
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
2) State the domain and the location of any holes in the graph
Domain: (−∞, −2) ∪ (−2, 2) ∪ (2, ∞)
No holes (They occur where factors cancel)
3) Simplify the function to lowest terms
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
4) Find the y-intercept (x = 0) and the x-intercept(s) (y = 0)
x-intercept(s) (y = 0)
y-intercept (x = 0)
These are the roots of
(0 + 4)(0 − 3)
the numerator.
๐‘“ 0 =
(0 + 2)(0 − 2)
๐‘ฅ+4=0
๐‘ฅ−3=0
−12
๐‘ฅ = −4
๐‘ฅ=3
๐‘“ 0 =
=3
−4
(−4, 0)
(3, 0)
(0, 3)
5) Identify any existing asymptotes (vertical, horizontal, or
oblique
๐‘ฅ 2 + ๐‘ฅ − 12
๐‘“ ๐‘ฅ =
๐‘ฅ2 − 4
Horiz. Or Oblique Asymptotes
Examine the largest exponents
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
Vertical Asymptotes
Use denominator factors
Same ∴ Horiz. - use coefficients
๐‘ฅ+2=0
๐‘ฅ−2=0
1
๐‘ฆ=
๐‘ฅ = −2
๐‘ฅ=2
1
๐‘‰๐ด: ๐‘ฅ = −2 ๐‘Ž๐‘›๐‘‘ ๐‘ฅ = 2
๐ป๐ด: ๐‘ฆ = 1
Oblique Asymptotes occur when degree is 1 greater on top.
Divide using base-x and get rid of denominator to find line.
6) Identify any points intersecting a horizontal or oblique
asymptote. (this is possible because unlike a vertical
asymptote, the function is defined at these types)
๐‘ฅ 2 + ๐‘ฅ − 12
๐‘ฆ = 1 ๐‘Ž๐‘›๐‘‘ ๐‘“ ๐‘ฅ =
๐‘ฅ2 − 4
๐‘ฅ 2 + ๐‘ฅ − 12
1=
๐‘ฅ2 − 4
๐‘ฅ 2 − 4 = ๐‘ฅ 2 + ๐‘ฅ − 12
−4 = ๐‘ฅ − 12
8=๐‘ฅ
(8,1)
7) Use test points between the zeros and vertical asymptotes
to locate the graph above or below the x-axis
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-4
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
(−5 + 4)(−5 − 3)
๐‘“ −5 =
(−5 + 2)(−5 − 2)
(−)(−)
๐‘“ −5 =
=+
(−)(−)
๐‘“ −5 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-2
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
2
3
(+)(−)
๐‘“ −3 =
=−
(−)(−)
๐‘“ −3 = ๐‘๐‘’๐‘™๐‘œ๐‘ค
(+)(−)
๐‘“ 0 =
=+
(+)(−)
๐‘“ 0 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
7) Use test points between the zeros and vertical asymptotes
to locate the graph above or below the x-axis
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-4
-2
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
๐‘๐‘’๐‘™๐‘œ๐‘ค
2
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
3
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
(+)(−)
๐‘“ 2.5 =
=−
(+)(+)
๐‘“ 2.5 = ๐‘๐‘’๐‘™๐‘œ๐‘ค
(+)(+)
๐‘“ 4 =
=+
(+)(+)
๐‘“ 4 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
8) Analyze the behavior of the graph on each side of an
asymptote
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-4
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-2
๐‘๐‘’๐‘™๐‘œ๐‘ค
2
3
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
๐‘ฅ→
−2−
(+)(−)
๐‘“(๐‘ฅ) → −
(0 )(−)
๐‘“(๐‘ฅ) → −∞
๐‘ฅ→
−2+
(+)(−)
๐‘“(๐‘ฅ) → +
(0 )(−)
๐‘“(๐‘ฅ) → ∞
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
8) Analyze the behavior of the graph on each side of an
asymptote
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-4
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-2
๐‘๐‘’๐‘™๐‘œ๐‘ค
2
3
(๐‘ฅ + 4)(๐‘ฅ − 3)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 2)(๐‘ฅ − 2)
๐‘ฅ→
2−
(+)(−)
๐‘“(๐‘ฅ) →
(+)(0− )
๐‘“(๐‘ฅ) → ∞
๐‘ฅ→
2+
(+)(−)
๐‘“(๐‘ฅ) →
(+)(0+ )
๐‘“ ๐‘ฅ → −∞
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
9) Sketch the graph
Example #2
๐‘ฅ 2 + 3๐‘ฅ − 10
๐‘“ ๐‘ฅ = 2
๐‘ฅ + 8๐‘ฅ + 15
1) Factor the numerator and the denominator
(๐‘ฅ + 5)(๐‘ฅ − 2)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 5)(๐‘ฅ + 3)
2) State the domain and the location of any holes in the graph
Domain: (−∞, −5) ∪ (−5, −3) ∪ (−3, ∞)
Hole in the graph at ๐‘ฅ = −5
3) Simplify the function to lowest terms
(๐‘ฅ − 2)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 3)
4) Find the y-intercept (x = 0) and the x-intercept(s) (y = 0)
y-intercept (x = 0)
x-intercept(s) (y = 0)
(0 − 2)
๐‘“ 0 =
(0 + 3)
2
๐‘“ 0 =−
3
2
(0, − )
3
Use numerator factors
๐‘ฅ−2=0
๐‘ฅ=2
(2, 0)
5) Identify any existing asymptotes (vertical, horizontal, or
oblique
๐‘ฅ 2 + 3๐‘ฅ − 10
๐‘“ ๐‘ฅ = 2
๐‘ฅ + 8๐‘ฅ + 15
Horiz. Or Oblique Asymptotes
Examine the largest exponents
Same ∴ Horiz. - use coefficients
1
๐‘ฆ=
1
๐ป๐ด: ๐‘ฆ = 1
(๐‘ฅ − 2)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 3)
Vertical Asymptotes
Use denominator factors
๐‘ฅ+3=0
๐‘ฅ = −3
๐‘‰๐ด: ๐‘ฅ = −3
6) Identify any points intersecting a horizontal or oblique
asymptote.
๐‘ฅ−2
๐‘ฆ = 1 ๐‘Ž๐‘›๐‘‘ ๐‘“ ๐‘ฅ =
๐‘ฅ+3
๐‘ฅ−2
1=
๐‘ฅ+3
๐‘ฅ+3=๐‘ฅ−2
3 = −2
๐‘™๐‘œ๐‘ ๐‘ก ๐‘ฃ๐‘Ž๐‘Ÿ๐‘–๐‘Ž๐‘๐‘™๐‘’
๐‘›๐‘œ ๐‘๐‘œ๐‘–๐‘›๐‘ก๐‘  ๐‘œ๐‘“ ๐‘–๐‘›๐‘ก๐‘’๐‘Ÿ๐‘ ๐‘’๐‘๐‘ก๐‘–๐‘œ๐‘› ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘Ž๐‘ ๐‘ฆ๐‘š๐‘๐‘ก๐‘œ๐‘ก๐‘’
7) Use test points between the zeros and vertical asymptotes
to locate the graph above or below the x-axis
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-3
(๐‘ฅ − 2)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 3)
(−4 − 2)
๐‘“ −4 =
(−4 + 3)
(−)
๐‘“ −4 =
=+
(−)
๐‘“ −4 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
2
(−)
๐‘“ 0 =
=−
(+)
๐‘“ 0 = ๐‘๐‘’๐‘™๐‘œ๐‘ค
(+)
๐‘“ 3 =
=+
(+)
๐‘“ 3 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
8) Analyze the behavior of the graph on each side of an
asymptote
-3
2
(๐‘ฅ − 2)
๐‘“ ๐‘ฅ =
(๐‘ฅ + 3)
๐‘ฅ→
−3−
(−)
๐‘“(๐‘ฅ) → −
(0 )
๐‘“(๐‘ฅ) → ∞
๐‘ฅ→
−3+
(−)
๐‘“(๐‘ฅ) → +
(0 )
๐‘“ ๐‘ฅ → −∞
9) Sketch the graph
Example #3
๐‘ฅ 2 + 3๐‘ฅ + 2
๐‘“ ๐‘ฅ =
๐‘ฅ−1
1) Factor the numerator and the denominator
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘“ ๐‘ฅ =
๐‘ฅ−1
2) State the domain and the location of any holes in the graph
Domain: (−∞, 1) ∪ (1, ∞)
No holes
3) Simplify the function to lowest terms
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘“ ๐‘ฅ =
(๐‘ฅ − 1)
4) Find the y-intercept (x = 0) and the x-intercept(s) (y = 0)
y-intercept (x = 0)
x-intercept(s) (y = 0)
(0 + 2)(0 + 1)
๐‘“ 0 =
(0 − 1)
2
๐‘“ 0 =
= −2
−1
(0, −2)
Use numerator factors
๐‘ฅ+2=0
๐‘ฅ = −2
๐‘ฅ+1=0
๐‘ฅ = −1
(−2, 0)
(−1, 0)
5) Identify any existing asymptotes (vertical, horizontal, or
oblique
๐‘ฅ 2 + 3๐‘ฅ + 2
๐‘“ ๐‘ฅ =
๐‘ฅ−1
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘“ ๐‘ฅ =
(๐‘ฅ − 1)
Vertical Asymptotes
Use denominator factors
Horiz. or Oblique Asymptotes
Examine the largest exponents
Oblique: Use long division
๐‘ฅ +4
2
x
๏€ซ 3x ๏€ซ 2
๐‘ฅ−1
−๐‘ฅ 2 −+๐‘ฅ
4๐‘ฅ +2
O๐ด: ๐‘ฆ = ๐‘ฅ + 4
−4๐‘ฅ −+4
0
๐‘ฅ−1=0
๐‘ฅ=1
๐‘‰๐ด: ๐‘ฅ = 1
6) Identify any points intersecting a horizontal or oblique
asymptote.
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘ฆ = ๐‘ฅ + 4 ๐‘Ž๐‘›๐‘‘ ๐‘“ ๐‘ฅ =
๐‘ฅ−1
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘ฅ+4=
๐‘ฅ−1
(๐‘ฅ + 4)(๐‘ฅ − 1) = (๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘ฅ 2 + 3๐‘ฅ − 4 = ๐‘ฅ 2 + 3๐‘ฅ + 2
๐‘™๐‘œ๐‘ ๐‘ก ๐‘ฃ๐‘Ž๐‘Ÿ๐‘–๐‘Ž๐‘๐‘™๐‘’
๐‘›๐‘œ ๐‘๐‘œ๐‘–๐‘›๐‘ก๐‘  ๐‘œ๐‘“ ๐‘–๐‘›๐‘ก๐‘’๐‘Ÿ๐‘ ๐‘’๐‘๐‘ก๐‘–๐‘œ๐‘› ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘Ž๐‘ ๐‘ฆ๐‘š๐‘๐‘ก๐‘œ๐‘ก๐‘’
7) Use test points between the zeros and vertical asymptotes
to locate the graph above or below the x-axis
๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
-2
๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
๐‘๐‘’๐‘™๐‘œ๐‘ค
-1
1
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘“ ๐‘ฅ =
(+)(−)
(๐‘ฅ − 1)
๐‘“ −1.5 =
=+
(−)
(−)(−)
(+)(+)
๐‘“ −1.5 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
๐‘“ −4 =
=−
๐‘“ 3 =
=+
(−)
(+)
(+)(+)
๐‘“ −4 = ๐‘๐‘’๐‘™๐‘œ๐‘ค
๐‘“ 3 = ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’
๐‘“ 0 =
=−
(−)
๐‘“ 0 = ๐‘๐‘’๐‘™๐‘œ๐‘ค
8) Analyze the behavior of the graph on each side of an
asymptote
1
(๐‘ฅ + 2)(๐‘ฅ + 1)
๐‘“ ๐‘ฅ =
(๐‘ฅ − 1)
๐‘ฅ→
1−
(+)(+)
๐‘“(๐‘ฅ) →
(0− )
๐‘“ ๐‘ฅ → −∞
๐‘ฅ→
1+
(+)(+)
๐‘“(๐‘ฅ) →
(0+ )
๐‘“ ๐‘ฅ →∞
9) Sketch the graph
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