NE 301 - Introduction to Nuclear Science Spring 2012 Classroom Session 3: •Radioactive Decay Types •Radioactive Decay and Growth •Isotopes and Decay Diagrams •Nuclear Reactions • • • Energy of nuclear reactions Neutron Cross Sections Activation Calculations Reminder Load TurningPoint Reset slides Load List 2 Let’s do some accounting… Mass of Oxygen Atom: Mp=1.007276 amu Mn=1.008665 amu Me=5.48e-4 amu 16 8 O 1 amu = 931.49 MeV Zm p 8 1.007276 amu ( A Z )mn 8 1.008665 amu Zme 8 5.48e 4 amu 16.131912 amu M 16O 15.994915 amu 8 Mass Defect = Binding Energy (BE) 3 931.49 MeV BE 16 O = (16.131912-15.994915 amu) 127.61 MeV 1 amu Chart of the Nuclides Isobars Isotopes Z Isotones N 4 Notice radioactive decay stabilizes atoms: Question: Do fission products normally have - or + decay? 5 Reaction Energetics Reaction reactants and products A + B C + D + E If E is positive: reaction exothermic releases energy If E is negative, reaction endothermic requires energy Endoergic and exoergic is sometimes used The Energy Released (or consumed), Q A + B C + D + E Change in BE: Q BE BEC BED ( BEA BEB ) Or since BE is related to mass defect Change in M: Preferred! because we have table B.1. Q M M A M B (M C M D ) Remember: The Equation Has to Be BALANCED! Please remember… BALANCE! Before starting to work Balancing Reactions 1 16 16 1 n O N 0 8 7 1p nucleons 1 +16 = 16+1 Charges (+) 0+8= 7+1 (-) -0 -8 = -7 -0 e- missing 0 1 So in reality the reaction is: 1 0 n O N e p 1 0 n O N H 16 8 16 8 16 7 16 7 0 1 1 1 1 1 or Calculating Q… Q-value for the reaction is: 1 0 n O N H 16 8 16 7 1 1 Using atomic mass tables: M M A M B ( M C M D ) M 1.008665 15.994915 16.006101 1.007825 0.010346 amu 931.494 MeV 0.010346 amu 9.637 MeV 1 amu Endothermic reaction. Only a few fission neutrons can do it A beryllium target is irradiated in a proton accelerator to produce 10B. What is Q of the reaction? M eV 85 M 6. 5 3M eV 0% eV 0% eV 5. 7% M 4. 14% 4. 5 3. eV 2. 5.5 MeV 4.5 MeV 3 MeV 6.5 MeV 85 MeV 10 5 M 1. p Be B 9 4 5. 5 1 1 79% 11 For clicker 1 1 H 49 Be 105 B Q (1.007825 9.012182 10.012937) 931.494 6.586 MeV Excited Nuclei Many reactions involve excited nuclei Sometimes long lived states (isomers) Excitation energy has to be added to the mass of the excited nuclei when calculating Q M X M X E A Z e.g. The mass of * 22Ne* A Z 10 c 2 at 1274 MeV is: M 22 Ne* M 22 Ne * 21.991386 1274 MeV 10 * 1amu 23.3591 amu 931.494MeV 13 Decay Series The radioactive minerals contain many nuclides All of them decay by either or decay A changes by 4, Z by 2 A does not change, A by 1 Th has one long lived isotope 232Th There are 3 U has two long lived 235U, 238U natural series Series identified by relation Parent to Dauthers mass: A in multiples of 4 14 15 Notice Branching 16 17 Series are: A = 4n --- Thorium Series A = 4n+2 -- Uranium Series A = 4n+3 – Actinium Series Which one is missing? A = 4n+1 – Neptunium Series (Artificial) 18 It was there from the beginning… but notice: half life of 237Np is relatively low. 19 Main Radioactive Decay Modes Decay Type Gamma () (Table 5.1 -page 89-Shultis) Description Emission P* ZA P Gamma photon A Z Decay of excited nucleus alpha () P ZA24 D Alpha particle is emitted Alpha particle negatron (-) np++e-+ A A Z P Z 1 D Electron and antineutrino positron (β+) p+n+e++ A A P D Z Z 1 Positron and neutrino Electron Capture (EC) Orbital e- absorbed: p++e-n + Neutrino proton (p) Proton ejected Proton neutron (n) Neutron ejected Neutron Internal Conversion (IC) Electron (K-Shell) ejected* A * A Z P Z P e Electron Spontaneous Fission (sf) A Z A Z Pe A Z A Z 1 D * P D1 D2 x n Fission fragments 20 Comments: , +, - are common modes of decay Long T1/2 usually are -emitters n, p emission are rare (excess p+ atoms) is predominant for Z>83 (above Bismuth) and atoms away from the line of -stability. Some high Z atoms (Z>96) have dominant spontaneous fission mostly dominates again at Z>105 Modes of Decay , +, - are common modes of decay Long T1/2 usually are emitters n, p emission are rare (excess p+ atoms) is predominant for Z>83 (above Bismuth) and atoms away from the line of -stability. Some high Z atoms (Z>96) have dominant spontaneous fission mostly dominates again at Z>105 22 Solving momentum and KE equations Remember the conditions: 1. 2. 3. 4. Parent nucleus at rest (usually the case) Binary products only (not -decay, but OK to Emax) Calculate the correct Q (excited states are prevalent, and balance) Finally, there usually reaction paths with many outcomes, therefore multiple Q-values m2 KE1 Q m1 m2 m1 KE2 Q m1 m2 Kinetic Energy of Radioactive Decay Products Parent nucleus is at rest (Eth~ 0.025 eV~17 oC) Conservation of Linear Momentum and Kinetic Energy requires products to travel in opposite directions (2 product). v2 m2 m2 m1 Original atom that will split in 2 pieces m1 v1 m1v1=m2v2 Q=½ m1v12+ ½ m2v22 What is the energy of emitted particle? (it is what we measure) 24 Kinematics of radioactive decay… 1 1 2 Q= m1v1 m 2 v 2 2 2 2 m1v1 =m 2 v 2 v1 = m2 v2 m1 replacing... m2 v2 2 1 1 Q m1 ( ) m2 v22 2 m1 2 1 m22 v22 1 Q m2 v22 2 m1 2 Q m2 KE2 KE2 m1 m1 KE2 Q m m 1 2 1 2 and replacing m 2 v 2 by KE 2 2 solving for KE 2 similarly: Notice 2:1 m2 KE1 Q m m 1 2 25 Warm up: What % of the energy should go to the -particle? 20% 5. 20% m1 KE2 Q m m 1 2 m2 KE1 Q m m 1 2 1% 4. 10 % 3. 50 % 2. 98% 2% 50% 10% 1% 20% 4 2 2% 1. 20% Th He 234 90 98 % U 238 92 20% 26 Example of -spectroscopy? 241 Am ? 100% 1. 237Pa 2. 237U 3. 237Np 4. 237Pu 0% 23 7C m 0% 23 7A m 0% 23 7P u 0% 23 7U 23 7P a 6. 237Cm 0% 23 7N p 5. 237Am 27 Find Q for: 241 95 Am 237 93 Np He 4 2 20% 20% 20% M eV 7. 63 8 M eV 6. 63 8 M eV 5. 63 8 5. M eV 4. 4. 63 8 3. 20% MeV MeV MeV MeV MeV M eV 2. 3.638 4.638 5.638 6.638 7.638 3. 63 8 1. 20% 28 For Clicker slide: Q=(241.056823-237.048167-4.002603)*931.494=5.638MeV What is the KE of the particle in the radioactive decay of 241Am? (3 min) 25% 25% eV M 5. 64 eV M 5. 54 eV M 0. 98 4. eV 3. 25% MeV MeV MeV MeV M 2. 0.09 0.98 5.54 5.64 0. 09 1. 25% 30 For Clicker slide: KE=5.638*237/(237+4)=5.545 MeV Notice: If alpha particle ALWAYS leaves with exactly the same energy. We would expect to detect a monoenergetic beam of ’s. In reality… The real alpha spectrum of 241Am is: At least 5 different energies… Why? Excited Nuclei! The real decay path of 241Am There are actually 6 alpha peaks Last two peaks are too close to be resolved Notice frequencies (%’s) Every decay path happens all the time but not with equal probability Look in your book: Page 578. Taken from J. K. Beling, et al. Phys. Rev. 87 (1952) 670-671 241Am Diagram means: 241 95 Am 237 Np* 4 He 93 2 *170 KeV 241 95 Am 237 Np* 4 He 93 2 *114 KeV 241 95 Am 237 Np* 4 He 93 2 *71 KeV 241 95 Am 237 Np* 4 He 93 2 Energy of the -particle? Same old same old Am 237 Np* 4 He 93 2 m KE Q m m 2 *43 KeV 241 95 *11 KeV 241 95 Am 237 Np 4 He 93 2 But Q is different each time 35 3.6 36 37 4.0 By the way Notice also 38 4.0 There are a lot more hard to see peaks 39 So how is the “real” diagram? For that we need the TABLE OF ISOTOPES 40 Diagram 241Am - 1 of 2 41 Diagram 241Am - 2 of 2 42 The Table also includes a more complete list of particles emitted during decay 43 44 ’s ’s 45 Main Radioactive Decay Modes Decay Type Gamma () (Table 5.1 -page 89-Shultis) Description Emission P* ZA P Gamma photon A Z Decay of excited nucleus alpha () P ZA24 D Alpha particle is emitted Alpha particle negatron (-) np++e-+ A A Z P Z 1 D Electron and antineutrino positron (β+) p+n+e++ A A P D Z Z 1 Positron and neutrino Electron Capture (EC) Orbital e- absorbed: p++e-n + Neutrino proton (p) Proton ejected Proton neutron (n) Neutron ejected Neutron Internal Conversion (IC) Electron (K-Shell) ejected* A * A Z P Z P e Electron Spontaneous Fission (sf) A Z A Z Pe A Z A Z 1 D * P D1 D2 x n Fission fragments 46