2.3.3 pythag theorem and sq root work

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Your warm up is the pink
½ sheet on the back table
Operations on radicals
Addition and subtraction – numbers in the
radicals need to be the same in order to
combine. √5 + √5 = 2√5
Multiplication – multiply outsides, multiply
insides. √5 (3 + √2) = 3√5 + √10
Division – never leave a radical in the
denominator. multiply numerator and
denominator by the radical you want to
‘rationalize’. 2√5 2√5 ● √2 = 2√10 = 2√10 = √10
√2
√2
√4
2
√2
Please get a
white board
marker
eraser
Your 2 minute doodle time will start in one minute.
2.3.3 Pythagorean Theorem
a & b are the legs
c is the hypotenuse
a2 + b2 = c2
c
a
b
given:
32 + 42 = c2
a=3
9 + 16 = c2
b=4
25 = c2
find the length of c
√25 = √c2
5=c
Review from last time…. if this is not in your notes, get it there
Exact Answer
Put answer in
simplified
radical form.
Approximate Answer
Put answer in
decimal form.
Be sure to round
as instructed.
a2 + b2 = c2
c
a=8
b = 12
find the length of c
a
b
82 + 122 = c2
given:
62
a=6
36 + 100 = c2
b = 10
136 = c2
find the length of c
+
102
√136 =
=
c2
√c2
4√34 = c
64 + 144 = c2
208 = c2
√208 = √c2
4√13 = c
Find the exact area.
6
6
h
32 + h2 = 62
9 + h2 = 36
h2 = 27
√h2 = √27
6
h = 3√3
Find the exact area.
52 + h2 = 102
10
10
25 + h2 = 100
h2 = 75
√h2 = √75
10
h = 5√5
Find the exact area.
a2 + a2 = 102
10
2a2 = 100
a2 = 50
√a2 = √50
h = 5√2
Your assignment
*Sq Root Wksht
*pg 123; 118 - 122
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