Tuesday, Feb 25
Chapter 10
Review
Chapter 10 Review
Find the area of the Base. Round to the
nearest tenth, if necessary.
Chapter 10 Review
What is the area of the Base? Round to the
nearest tenth, if necessary.
B = 9.1 x 8 = 72.8in²
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
V = lwh
V = 9.1x 8 x 8 = 582.4in³ or
V = Bh = 72.8 · 8 = 582.4in³
Chapter 10 Review
Find the area of the Base. Round to the
nearest tenth, if necessary.
Chapter 10 Review
Find the area of the Base. Round to the
nearest tenth, if necessary.
B = 18 x 9 = 162mm²
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
V = lwh
V = 18 x 9 x 36 = 5832mm³ or
V = Bh = 162 · 36 = 5832mm³
Chapter 10 Review
Find the area of the Base. Round to the
nearest tenth, if necessary.
Chapter 10 Review
Find the area of the Base. Round to the
nearest tenth, if necessary.
B = 10 x 6 ÷ 2 = 30cm²
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
V = lwh ÷ 2
V = 10 x 6 x 4 ÷ 2 = 120cm³ or
V = Bh = 30 · 4 = 120cm³
Chapter 10 Review
Find the Area of the Base. Round to the
nearest tenth, if necessary.
Chapter 10 Review
Find the Area of the Base. Round to the
nearest tenth, if necessary.
B = 3 x 4 ÷ 2 = 6cm²
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
Chapter 10 Review
Find the volume. Round to the nearest tenth, if
necessary.
V = lwh ÷ 2
V = 4 x 3 x 8 ÷ 2 = 48cm³ or
V = Bh = 6 · 8 = 48cm³
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
A = 7 x 4 = 28
A = 4 x 10 = 40
A = 10 x 7 = 70
28 + 28 + 40 + 40 + 70 + 70 = 276in²
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
SA = 2B + hp
B = 72.8
h=8
p = 34.2
SA = 2 x 72.8 + 8 x 34.2 =
= 145.6 + 273.6 = 419.2in²
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
SA = 2B + hp
B = 162
h= 36
p = 54
SA = 2 x 162 + 36 x 54 =
= 324 + 1944 = 2268mm²
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
SA = 2B + hp
B=3x4÷2=6
h= 8
p = 12
SA = 2 x 6 + 8 x 12 =
= 12 + 96 = 108cm²
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
Chapter 10 Review
Find the surface area. Round to the nearest
tenth, if necessary.
SA = 2B + hp
B = 10 x 6 ÷ 2 = 30
h= 4
p = 25.6
SA = 2 x 30 + 4 x 25.6 =
= 60 + 102.4 = 162.4cm²
Chapter 10 Review
A special box designed to hold an antique
artifact is shaped like a triangular prism. The
height of the box is 6.9 inches, the length is 8
inches and the width is 7.1 inches. What is the
volume of box?
Chapter 10 Review
A special box designed to hold an antique
artifact is shaped like a triangular prism. The
height of the box is 6.9 inches, the length is 8
inches and the width is 7.1 inches. What is the
volume of box?
V = lwh ÷ 2
V = 8 x 7.1 x 6.9 ÷ 2 = 195.96in³
Chapter 10 Review
There is a sale at the candy store. They have
two containers that can be filled with candy
and they are the same price. One container is
5in by 6in by 9in. The other container is 4in
by 8in by 8in. Which container would hold
more candy?
Chapter 10 Review
There is a sale at the candy store. They have
two containers that can be filled with candy
and they are the same price. One container is
5in by 6in by 9in. The other container is 4in
by 8in by 8in. Which container would hold
more candy?
V = lwh
V₁ = 5 x 6 x 9 = 270in³
V₂ = 4 x 8 x 8 = 256in³
Chapter 10 Review
You are painting a room that is a rectangular
prism and is 20ft by 35ft and 10ft high. You
are painting the walls, floor and ceiling. A
gallon of paint will cover 1250ft². How many
gallons will you need?
Chapter 10 Review
You are painting a room that is a rectangular
prism and is 20ft by 35ft and 10ft high. You
are painting the walls, floor and ceiling. A
gallon of paint will cover 1250ft². How many
gallons will you need?
SA = 2B + hp
B = 20 · 35 = 700
h = 10
p = 20+35+20+35=110
SA = 2 x 700 + 110 x 10 = 2500ft²
2500 ÷ 1250 = 2 gallons
Chapter 10 Review
Formulas you will need to have memorized for
tomorrow:
Volume of a rectangular prism
V = lwh and V = Bh
Volume of a triangular prism
V = lwh ÷ 2 and V = Bh
Surface Area of a prism
SA = 2B + hp
Chapter 10 Review
Agenda Notes
Homework –
Chapter 10 Review Homework(extra credit for 4th period)
Due Wednesday, Feb 26
Chapter 10 Test - Wednesday, Feb 26