Biology 30

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Biology 30
Module 4
Assignment 16
Copyright: Ministry of Education, Saskatchewan
May be reproduced for educational purposes
Biology 30
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Assignment 16
Biology 30
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Assignment 16
Biology 30
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Assignment 16
Assignment 16
Assignment 16 consists of a prototype examination for Biology 30. This examination
is a similar format as the Departmental Examination you will be writing to complete
your course.
Biology 30
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Assignment 16
Biology 30
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Assignment 16
Grade 12 Prototype Examination
Biology
Course Code 8211
Barcode Number
Month
Date of Birth
Day
Assigned I.D. Number
Biology 30
116
Assignment 16
Biology 30
117
Assignment 16
Biology 30
Time: Two and One-Half Hours
Do not spend too much time on any question. Read the questions carefully.
All items are multiple-choice questions which will be machine scored. Record
your answers on the Student Examination Form which is provided. Each question
has four suggested answers, one of which is better than the others. Select the best
answer and record it on the Student Examination Form as shown in the example
below:
Example:
1.
Organic molecules always contain
Answers:
A. carbon.
B. oxygen.
C. carbon and nitrogen.
D. hydrogen and nitrogen.
Student Examination Form:
1.
A
B
C
D
E
Use an ordinary HB pencil to mark your answers on the Student Examination Form.
If you change your mind about an answer, be sure to erase the first mark
completely. There should be only one answer marked for each question. Be sure
there are no stray pencil marks on your answer sheet. If you need space for rough
work, use the space in the examination booklet beside each question.
Do not fold either the Student Examination Form or the examination booklet.
Be sure to complete the blue identification section of the Student Examination
Form.
Upon completion of the examination, place your Student Examination Form behind
the examination booklet and insert both in the same envelope. Be sure to seal
the envelope and complete the information requested on the face of the
envelope.
Biology 30
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Assignment 16
The Codon Wheel – mRNA codons
amino acid
mRNA codons
amino acid
mRNA codons
alanine-Ala
GCU GCC GCA
GCG
histidine-His
CAU CAC
isoleucine-Ile
AUC AUU AUA
arginine-Arg
CGA CGU CGC
CGG AGA AGG
leucine-Leu
UUA UUG CUU
CUC CUA CUG
asparagine-Asn
AAU AAC
lysine-Lys
AAA AAG
aspartate-Asp
GAU GAC
methionine-Met
AUG
cysteine-Cys
UGU UGC
phenylalanine-Phe
UUU UUC
glutamate-Glu
GAA GAG
glutamine-Gln
CAG CAA
glycine-Gly
GGA GGC GGU
GGG
Biology 30
amino acid
mRNA codons
threonine-Thr
ACU ACC ACG
ACA
tryptophan-Trp
UGG
tyrosine-Tyr
UAU UAC
valine-Val
GUU GUC GUA
GUG
CCG
Terminator-(Stop)
UAA UAG UGA
UCG UCU UCA
UCC AGU AGC
Initiator-(Start)
AUG
CCA CCC CCU
proline-Pro
serine-Ser
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Assignment 16
GRADE 12 DEPARTMENTAL EXAMINATION
BIOLOGY 30 PROTOTYPE EXAM
VALUE
100
(50  2)
ANSWER THE FOLLOWING 50 QUESTIONS ON THE COMPUTER
SHEET ENTITLED “STUDENT EXAMINATION FORM.”
1.
Hydrogen bonds are of special interest to biologists since these
bonds:
A.
B.
C.
D.
2.
Which of the following equations represents a reaction that could
provide immediate energy to a living organism?
A.
B.
C.
D.
3.
A + B  AB
AB  A + B
A + B + 30 kJ  AB
AB  A + B + 30 kJ
The chemical elements found in all amino acids are:
A.
B.
C.
D.
Biology 30
contain a large amount of energy.
help to maintain pH balance.
connect nitrogen base pairs in DNA.
are difficult to break.
carbon,
carbon,
carbon,
carbon,
hydrogen, oxygen, and nitrogen.
oxygen, sulfur, and nitrogen.
hydrogen, oxygen, and phosphorous.
hydrogen, nitrogen, and phosphorous.
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Assignment 16
4.
A student tested a potato chip for sugar and starch. He also tested
his saliva for the presence of sugar and starch. He then chewed
the potato chip for two minutes and retested. The results of his
experiment are recorded in the table below.
Potato Chip
Before Chewing
After chewing
Saliva
Before Chewing
Starch
present
present
Sugar
not present
present
Starch
not present
Sugar
not present
Which of the following statements best explains the fact that sugar
was not present in the potato chip before chewing but was present
after chewing?
A.
B.
C.
D.
There must have been an error made in the tests before
chewing the potato chip.
Sugar diffused out of the student’s cheek cells while he was
chewing the potato chip.
Enzymes in the student’s saliva aided in the synthesis of
sugar molecules from starch molecules.
Enzymes in the student’s saliva helped break down the
starch molecules in the potato chip into sugar molecules.
Use the following graph showing the progress of an enzyme-catalyzed
reaction at two different temperatures to answer question 5.
A (45 °C)
Amount of
Product
B (25 °C)
Time (minutes)
5.
From the graph, it is correct to infer that:
A.
B.
C.
D.
Biology 30
reaction A is slower than reaction B.
the optimum temperature for reaction B is 45° C.
the reaction is slower at lower temperatures.
the enzymes in reaction A become activated at lower
temperatures than the enzymes in reaction B.
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Assignment 16
6.
Proteins are synthesized from amino acids in long chains called:
A.
B.
C.
D.
7.
The amount of adenine in a DNA molecule is:
A.
B.
C.
D.
8.
equal to the amount of thymine.
double the amount of cytosine.
half the amount of thymine.
almost equal to the amount of guanine and uracil.
The cell organelles that contain digestive enzymes responsible for
the breakdown of worn out cell parts are called:
A.
B.
C.
D
9.
carbon chains.
polypeptides.
polysaccharides.
sulphur chains.
ribosomes.
mitochondrion.
lysosomes.
chloroplasts.
The following diagram represents the three stages of cellular
respiration.
For stage 3, the number of molecules (n) of ATP derived from a
single glucose molecule would be
A.
B.
C.
D.
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2
4
34
42
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Assignment 16
10.
The fluid mosaic model is the currently accepted model for the
structure of membranes. According to this model, the cell
membrane is composed of:
A.
B.
C.
D.
11.
In a unicellular organism such as an Amoeba (Ameba), pinocytosis
would be the method used for:
A.
B.
C.
D.
12.
D.
oxidizing glucose in a series of chemical reactions.
synthesizing ATP from ADP.
trapping and accumulating energy in the form of ATP
molecules.
splitting water and giving off oxygen as a by-product.
The stages of aerobic cellular respiration are:
A.
B.
C.
D.
Biology 30
ingestion.
secretion.
osmoregulation.
excretion.
The basic process used by living cells to release energy from
glucose includes all of the following except:
A.
B.
C.
13.
a double layer of lipids containing various “floating” proteins.
a double layer of carbohydrates containing various “floating”
proteins.
a single layer of lipids containing various “floating” proteins.
a single layer of carbohydrates containing various “floating”
proteins.
light-dependent and light-independent reactions.
glycolysis, Kreb’s cycle, and electron transport system.
glycolysis and alcohol fermentation.
light-dependent reaction, electron transport system, and
Kreb’s cycle.
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Assignment 16
14.
A freshwater plant is put into a hypertonic (highly concentrated)
salt solution. The cells of the plant will probably:
A.
B.
C.
D.
15.
take in more fluid.
lose fluid.
show no effect.
take in starch.
When studying heredity, probability is the term used to identify:
A.
B.
C.
D.
sources of unexpected outcomes.
actual events.
predicted outcomes of events.
causes of different events.
Use the diagram below to answer questions 16 and 17.
Flower Colour
White
P1
WW
Pink
RR
Red
F1
WR
WR
?
16.
?
?
What is the expected ratio of flower colour when the F1 generation
is crossed with each other?
A.
B.
C.
D.
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?
3
3
1
1
pink : 1 white
red : 1 white
red : 2 pink : 1 white
pink : 3 white
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Assignment 16
17.
The pedigree shown is an example of:
A.
B.
C.
D.
dominant-recessive inheritance.
incomplete dominance inheritance.
sex-linked inheritance.
multiple-allele inheritance.
________________________________________
18.
In the fruit fly, grey body (B) is dominant over black body (b). Two
grey flies were mated, and they produced 158 grey and 49 black
offspring. The probable genotypes of these parents were:
A.
B.
C.
D.
19.
BB × Bb
Bb × bb
BB × BB
Bb × Bb
When crossing true-breeding white wool sheep and true-breeding
black wool sheep, all the offspring ( F1 generation) have white wool.
In the F1 generation, the allele for white wool would be found in:
A.
B.
C.
D.
20.
Hemophilia is an example of a condition resulting from sex-linkage.
Two parents (neither of whom have hemophilia) have a hemophiliac
son. The woman is pregnant again. What is the probability that the
second child will suffer from hemophilia?
A.
B.
C.
D.
Biology 30
about 50% of the female gametes and 50% of the male
gametes produced by F1 sheep.
all of the female gametes and none of the male gametes
produced by F1 sheep.
all of the male gametes and none of the female gametes
produced by F1 sheep.
none of the male gametes or female gametes produced by F1
sheep.
100% if it is a boy
50% if it is a boy
100% if it is a girl
50% if it is a girl
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Assignment 16
21.
The sequence given below is a short segment of a coding strand of a
DNA molecule.
ATG TCC CTG
The complementary mRNA strand that this DNA sequence could
produce would be:
A.
B.
C.
D.
UAC AGG GAC
TAC TGG GTC
UAG ACC GAC
AUG UCC CUG
Use the codon wheel to answer question 22.
22.
What is the correct sequence of mRNA codons that would produce
valine-valine-alanine-tyrosine?
A.
B.
C.
D.
23.
The skin cells of an organism contain 28 chromosomes. How
many chromosomes would be found in a sperm cell produced by
this organism?
A.
B.
C.
D.
24.
none
14
28
56
Which of the following events occurs in meiosis but not in mitosis?
A.
B.
C.
D.
Biology 30
CAA CAA CGA AUA
CGA CAA UCU AUA
AUA CGA CAA UCU
GUU GUU GCU UAU
Separation of chromatids.
Duplication of chromosomes before division.
Pairing up of homologous chromosomes.
Separation of chromosomes into two cells.
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Assignment 16
Use the following information on Roundup Ready soybeans to
answer questions 25, 26, and 27.
Monsanto Canada created Roundup Ready Canola and Roundup Ready
Soybean by inserting a gene that creates CP4 EPSPS protein. This
protein makes the plants resistant to Roundup. Farmers can then spray
Roundup on their crops and kill all the weeds.
Roundup Ready Soybean was approved by Health Canada in 1996 for
sale as food in the Canadian marketplace. As a result of their routine
quality control program, Monsanto Canada detected additional DNA in
their Roundup Ready Soybean.
Health Canada regulators conducted a thorough and vigorous review and
found no health or safety concerns. The newly detected DNA does not
express mRNA or proteins and only the expected full length mRNA and
CP4 EPSPS protein is found in Roundup Ready Soybean. This soybean
has undergone a thorough process of testing, analysis, and assessment
to ensure that it is wholesome, nutritious, and safe to eat.
25.
Monsanto inserted the CP4 EPSPS protein into soybeans in order to:
A.
B.
C.
D.
26.
The additional DNA mentioned was a concern for Health Canada
because the additional DNA:
A.
B.
C.
D.
27.
alter the flavour of the soybeans.
remove toxic substances from the soybean plant.
make their soybeans resistant to Roundup.
increase the number of soybeans per plant.
may
may
may
may
make soybeans sterile.
not be resistant to Roundup.
produce larger soybeans.
code for harmful proteins.
Technologies applied by Monsanto to prepare Roundup Ready
soybean would include:
A.
B.
C.
D.
recombinant DNA and cloning.
DNA fingerprinting and traditional plant breeding.
hybridization with canola and plasmids.
irradiation and gene screening.
________________________________________
Biology 30
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Assignment 16
28.
The nervous and endocrine systems in mammals are linked by the:
A.
B.
C.
D.
29.
The direction of fluid flow in a closed circulatory system is
determined by the:
A.
B.
C.
D.
30.
31.
number of heart chambers.
presence of capillaries.
size of the arteries and veins.
valves in the vessels.
Which arrangement correctly identifies the type of blood that the
four chambers of the heart collect and pump?
right atrium
right ventricle left atrium
left ventricle
A.
oxygenated
deoxygenated
oxygenated
deoxygenated
B.
deoxygenated
oxygenated
deoxygenated oxygenated
C.
deoxygenated
deoxygenated
oxygenated
D.
oxygenated
oxygenated
deoxygenated deoxygenated
oxygenated
The pathway through which air enters the alveoli of the lungs is:
A.
B.
C.
D.
Biology 30
autonomic nervous system.
hypothalamus.
prostaglandins.
pituitary gland.
trachea, bronchi, bronchioles,
bronchi, bronchioles, trachea,
bronchioles, bronchi, trachea,
trachea, bronchioles, bronchi,
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alveoli.
alveoli.
alveoli.
alveoli.
Assignment 16
Refer to the information below to answer question 32.
Identification bracelets were accidentally removed from three newborn
babies. The blood types for the babies and their parents were
Baby I
Baby II
Baby III
32.
B.
C.
D.
Baby I
Baby II
Baby III
any of the three
The hypothalamus produces controlling factors that act
upon the anterior pituitary to produce ACTH which acts
upon the adrenal glands to produce corticosteroids.
The hypothalamus produces controlling factors that act
upon the anterior pituitary to produce follicle stimulating
hormone (FSH) which acts upon the ovaries to produce
estrogen.
The hypothalamus produces controlling factors that act
upon the anterior pituitary to produce thyroid stimulating
hormone (TSH) which acts upon the thymus to produce
testosterone.
The hypothalamus produces a nerve impulse that acts upon
the posterior pituitary to release antidiuretic hormone (ADH)
which acts upon the kidneys to stimulate the reabsorption of
water.
Grasshoppers have a circulatory system that is:
A.
B.
C.
D.
Biology 30
Mrs. Black--Type B
Mrs. Brown--Type O
Mrs. White--Type O
Which of the following is an incorrect sequence of events?
A.
34.
Mr. Black--Type A
Mr. Brown--Type AB
Mr. White--Type O
Which baby could belong to Mr. and Mrs. Black?
A.
B.
C.
D.
33.
Type A
Type O
Type AB
always closed.
always open.
open or closed dependent on the species.
open in the nymph and closed in the adult.
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Assignment 16
35.
An investigation was carried out to determine the rates of flow and
the composition of fluids in human kidneys. These were measured
at positions I, II, III, and IV as shown in the diagram below, which
represents a nephron and some associated blood vessels. Blood
vessels associated with the tubule are not shown.
The results are given in the table below.
I. from
II. Bowman's
renal
artery
capsule
IV. collecting
tubule
III. proximal
convoluted
tubule
Position
I
II
III
IV
Total Flow Rate
( cm 3 /min )
1000
100
20
1
Solute Concentration
g/100cm 3
Protein
Glucose
Urea
7.5
0.1
0.03
0.0
0.1
0.10
0.0
0.0
0.15
0.0
0.0
1.80
The results indicate that:
A.
B.
C.
D.
36.
Carbon dioxide functions like a hormone when:
A.
B.
C.
D.
Biology 30
proteins enter Bowman’s capsule and are reabsorbed.
glucose does not pass from the glomerulus into Bowman’s
capsule.
proteins are secreted from the blood into the proximal
convoluted tubule.
urea enters Bowman’s capsule, and is concentrated in the
tubule as water is reabsorbed.
it is released from individual cells.
it travels through the body via blood vessels.
an increased concentration stimulates the nerves to quicken
breathing.
it is released from the blood to the lungs.
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Assignment 16
37.
Cells in the Islets of Langerhans secrete glucagon and insulin,
which function to keep blood glucose levels relatively constant.
Which of the following statements correctly describes the function
of these two hormones?
A.
B.
C.
D.
38.
Glucagon increases blood glucose levels, and insulin speeds
the absorption of glucose by cells.
Glucagon decreases blood glucose levels, and insulin
increases blood glucose levels.
Glucagon and insulin both increase blood glucose levels.
Glucagon stimulates glycogen synthesis, and insulin
prevents absorption of glucose by cells.
Use the following information to answer question 38.
Impulse Transmission Across a Synapse
1.
2.
3.
4.
5.
Neurotransmitters attach to receptor molecules on the
postsynaptic neuron.
Neurotransmitters are destroyed by an enzyme.
Neurotransmitters diffuse across the synapse.
An impulse travels along the axon of the presynaptic
neuron.
Neurotransmitters are released from the presynaptic
neuron.
The correct sequence of events that would occur when a nerve
impulse crosses a synapse is:
A.
B.
C.
D.
39.
1,
5,
1,
1,
4,
3,
5,
4,
3,
1,
4,
2,
2
2
2
5
During the normal sequence of events in the menstrual cycle, there
is an increase in progesterone, FSH, and estrogen. Beginning with
menstruation, which of the following shows the correct sequence of
increases in each hormone?
A.
B.
C.
D.
Biology 30
5,
4,
3,
3,
Estrogen, FSH, progesterone
FSH, estrogen, progesterone
Estrogen, progesterone, FSH
Progesterone, estrogen, FSH
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Assignment 16
40.
A vasectomy is a common operation used to sterilize human males.
The procedure involves cutting and tying off the vas deferens
(sperm ducts). From your understanding of the male reproductive
system, this procedure will:
A.
B.
C.
D.
41.
Which one of the following statements concerning evolution is
TRUE?
A.
B.
C.
D.
42.
behavioural isolation.
geographical isolation.
reproductive isolation.
the passage of time.
For thirty generations, the tails of newborn mice were removed at
birth and the mice were allowed to mature and reproduce. The most
probable result, after five more generations, would be that:
A.
B.
C.
D.
Biology 30
Darwin identified the genetic causes of evolution.
Variations occur due to gene mutations only.
Genes responsible for successful adaptations usually
increase in frequency.
Gene frequencies vary independently from other evolutionary
factors.
Darwin believed that several species of finches on different islands
all developed from a common ancestor. This speciation probably
resulted from:
A.
B.
C.
D.
43.
cause immediate destruction of sperm cells.
prevent testosterone synthesis.
prevent the release of semen.
prevent sperm cells from reaching the urethra.
all the mice will be born without a tail.
all the mice will be born with a tail.
some mice will be born without a tail.
a new species will develop.
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Assignment 16
44.
Which of the following statements would be an illustration of
Darwin’s theory of evolution?
A.
B.
C.
D.
Birds that eat seeds will grow stronger beaks.
People who frequently suntan will have children with slightly
darker skin.
If a mother plays the violin during pregnancy, she will have a
musically-gifted child.
Desirable traits in domestic stock can be developed through
artificial breeding.
Use the following information to answer questions 45 and 46.
In rabbits, the spotted-coat gene is dominant to the solid-coat gene. In a
large population, the frequency of the spotted-coat allele is 0.6, and the
frequency of the solid-coat allele is 0.4.
45.
If the assumptions of the Hardy-Weinberg principle are valid, then
the expected gene frequency of the spotted-coat allele in 10 years
would be:
A.
B.
C.
D.
46.
Feral (untamed) cats were introduced to the area inhabited by the
rabbit population. Ten years later, the frequency of the
spotted-coat allele increased to 0.8. Which of the following
assumptions of Hardy-Weinberg was not met?
A.
B.
C.
D.
Biology 30
0
0.36
0.6
1.0
No net mutations occur in the population.
Individuals mate randomly.
Individuals neither enter nor leave the population.
Selection does not occur.
________________________________________
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Assignment 16
47.
If drastic genetic change were to affect an individual within a
population, one would expect to see:
A.
B.
C.
D.
48.
Two populations of the same animal species may exhibit
differences in their gene pools when:
A.
B.
C.
D.
49.
C.
D.
each pine species lives in a different habitat.
the two species evolved from a common ancestral
population.
they belong to the same species.
they did not change enough while separated to evolve
different reproductive mechanisms.
Primate evolution has been characterized by the development of all
of the following except:
A.
B.
C.
D.
Biology 30
the two populations freely interbreed.
both populations exceed the carrying capacity.
one of the populations is small and isolated by a barrier.
competition between the two populations is great.
Jack pine and lodgepole pine are physically very similar, but
cannot interbreed. The best explanation for this is that:
A.
B.
50.
an increase in the frequency of the variation produced.
that individual becoming dominant and destroying others
within the population.
loss of the resulting variation because the organism would
probably die or fail to breed.
significant interbreeding with other members of the
population.
prehensile tails.
opposable digits.
stereoscopic vision.
complex brains.
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Assignment 16
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