NPTEL – ADVANCED FOUNDATION ENGINEERING-I Module 4 Lecture 14 SHALLOW FOUNDATIONS: ALLOWABLE BEARING CAPACITY AND SETTLEMENT Topics 1.1 SETTLEMENT CALCULATION 1.2 ELASTIC SETTLEMENT BASED ON THE THEORY OF ELASTICITY 1.3 ELASTIC SETTLEMENT OF FOUNDATION ON SATURATED CLAY 1.4 SETTLEMENT OF SANDY SOIL: USE OF STRAIN INFLUENCE FACTOR 1.5 RANGE OF MATERIAL PARAMETERS FOR COMPUTING ELASTIC SETTLEMENT 1.6 CONSOLIDATION SETTLEMENT 1.7 SKEMPTON-BJERRUM MODIFICATION FOR CONSOLIDATION SETTLEMENT 1.8 CONSOLIDATION SETTLEMENT-GENERAL COMMENTS AND A CASE HISTORY NPTEL – ADVANCED FOUNDATION ENGINEERING-I SETTLEMENT CALCULATION ELASTIC SETTLEMENT BASED ON THE THEORY OF ELASTICITY The elastic settlement of a shallow foundation can be estimated by using the theory of elasticity. Referring to figure 4.16 and using Hooke’s law, Figure 4.16 Elastic settlement of shallow foundation H 1 H Se = ∫0 εz dz = E ∫0 �∆pz − μs Δpx − μs Δpy �dz Where s [4.27] Se = elastic settlement Es = modulus of elasticity of soil H = thickness of the soil layer μs = Poisson′ s ratio of the soil Δpx , Δpy , Δpz = stress increase due to the net applied foundation load in the x, y, and z, directions, respectively NPTEL – ADVANCED FOUNDATION ENGINEERING-I Theoretically, if the depth of foundation Df = 0, H = ∞, and the foundation is perfectly flexible, according to Harr (1966) the settlement may be expressed as (figure 4.17) Figure 4.17 Elastic settlement of flexible and rigid foundations Se = Se = Bq o Es Bq o Es Where (1 − μ2s ) α 2 (1 − μ2s )α 1 �1+m 21 +m 1 α = π �In � m1 = L/B �1+m 21 −m 1 (corner of the flexible foundation) (center of the flexible foundation) �1+m 21 +1 � + m In � �1+m 21 −1 �� [4.28] [4.29] [4.30] [4.31] B = width of foundation L = length of foundation The values of α for various length-to-width (L/B) ratios are shown in figure 4.18. The average immediate settlement for a flexible foundation also may be expressed as NPTEL – ADVANCED FOUNDATION ENGINEERING-I Se = Bq o Es Figure 4.18 Values of α, αav , and αr −equations (28, 29, 32 and 32a) (1 − μ2s )αav = average for flexible foundation) [4.32] Figure 18 also shows the values of αav for various L/B ratios of foundation. However, if the foundation shown in figure 17 is rigid, the immediate settlement will be different and may be expressed as Se = Bq o Es (1 − μ2s )αr = (rigid foundation) [4.32a] The value of αr for various L/B ratios of foundation are shown in figure 4.18. If Df = 0 and H < ∞ due to the presence of a rigid (incompressible) layer as shown in figure 17, Se = Bq o Se = Bq o Es And Es (1 − μ2s ) [�1−μ 2s �F 1 +�1−μ s −2μ 2s �F 2 ] 2 (corner of flexible foundation) (1 − μ2s )[(1 − μ2s )F1 + (1 − μs − 2μ2s )F2 ](corner of flexible foundation) [4.33a] [4.33b] The variation of F1 and F2 with H/B are given in figures 4.19 and 4.20, respectively (Steinbrenner, 1934). NPTEL – ADVANCED FOUNDATION ENGINEERING-I Figure 4.19 Variation of F1 with H/B (based on Steinbrener, 1934 Figure 4.20 Variation of F2 with H/B (based on Steinbrenner, 1934) NPTEL – ADVANCED FOUNDATION ENGINEERING-I It is also important to realize that the preceding relationships for Se assume that the depth of the foundation is equal to zero. ForDf > 0, the magnitude of Se will decrease. Example 5 A foundation is 1m × 2m in plan and carries a net load per unit area, q o = 150 kN/m2 . Given, for the soil, Es = 10,000 kN/m2 ; μs = 0.3. Assuming the foundation to be flexible, estimate the elastic settlement at the center of the foundation for the following conditions: a. Df = 0; H = ∞ b. Df = 0; H = 5 m Solution Part a From equation (29) Se = Bq o Se = (1)(150) Es (1 − μ2s )α For L/B = 2/1 = 2, from figure 18, α ≈ 1.53, so 10,000 Part b (1 − 0. 32 )(1.53) = 0.0209 m = 20.9 mm From equation (33b) Se = Bq o Se = (1)(150) Es (1 − μ2s )[(1 − μ2s )F1 + (1 − μs − 2μ2s )F2 ] For L/B = 2 and H/B = 5, from figures 19 and 20, F1 ≈ 0.525 and F2 ≈ 0.06 10,000 (1 − 0. 32 )[(1 − 0. 32 )(0.525) + (1 − 0.3 − 2 × 0. 32 )(0.06)] = 0.007 m = 7.0 mm ELASTIC SETTLEMENT OF FOUNDATION ON SATURATED CLAY Janbu et al. (1956) proposed an equation for evaluating the average settlement of flexible foundations on saturated clay soils (Poisson’s ratio, μs = 0.5). For the notation used in figure 4.21, this equation is NPTEL – ADVANCED FOUNDATION ENGINEERING-I Figure 4.21 Values of A1 and A2 for elastic settlement calculation-equation (34) (after Christian and Carrier, 1978) Se = A1 A2 qo B Es [4.34] Where A1 is a function of H/B and L/B and A2 is a function of Df /B Christian and Carrier (1978) modified the values of A1 and A2 to some extent, as presented in figure 21. SETTLEMENT OF SANDY SOIL: USE OF STRAIN INFLUENCE FACTOR Settlement of granular soils can be evaluated by use of a semi-empirical strain influence factor (figure 4.22) proposed by Schmertmann and Hartman (1978). According to this method, the settlement is NPTEL – ADVANCED FOUNDATION ENGINEERING-I z I Se = C1 C2 (q� − q) ∑02 Ez ∆z s [4.35] Figure 4.22 Elastic settlement calculation by using strain influence factor Where Iz = strain influence factor C1 = a 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑓𝑓𝑓𝑓𝑓𝑓 𝑡𝑡ℎ𝑒𝑒 𝑑𝑑𝑑𝑑𝑑𝑑𝑑𝑑ℎ 𝑜𝑜𝑜𝑜 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 = 1 − 0.5[𝑞𝑞/(𝑞𝑞� − 𝑞𝑞)] 𝐶𝐶2 = 𝑎𝑎 𝑐𝑐𝑐𝑐𝑐𝑐r𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑡𝑡𝑡𝑡 𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 𝑓𝑓𝑓𝑓𝑓𝑓 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑖𝑖𝑖𝑖 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 = 1 + 0.2 𝑙𝑙𝑙𝑙𝑙𝑙(𝑡𝑡𝑡𝑡𝑡𝑡𝑡𝑡 𝑖𝑖𝑖𝑖 𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦𝑦/0.1) 𝑞𝑞� = 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑎𝑎𝑎𝑎 𝑡𝑡ℎ𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑞𝑞 = 𝛾𝛾𝐷𝐷𝑓𝑓 The variation of the strain influence factor with depth below the foundation is shown in figure 22a. Note that, for square or circular foundations, 𝐼𝐼𝑧𝑧 = 0.1 𝑎𝑎𝑎𝑎 𝑧𝑧 = 0 𝐼𝐼𝑧𝑧 = 0.5 𝑎𝑎𝑎𝑎 𝑧𝑧 = 𝑧𝑧1 = 0.5 𝐵𝐵 𝐼𝐼𝑧𝑧 = 0 𝑎𝑎𝑎𝑎 𝑧𝑧 = 𝑧𝑧2 = 2𝐵𝐵 Similarly, for foundation with 𝐿𝐿/𝐵𝐵 ≥ 10, 𝐼𝐼𝑧𝑧 = 0.2 𝑎𝑎𝑎𝑎 𝑧𝑧 = 0 NPTEL – ADVANCED FOUNDATION ENGINEERING-I 𝐼𝐼𝑧𝑧 = 0.5 𝑎𝑎𝑎𝑎 𝑧𝑧 = 𝑧𝑧1 = 𝐵𝐵 𝐼𝐼𝑧𝑧 = 0 𝑎𝑎𝑎𝑎 𝑧𝑧 = 𝑧𝑧2 = 4𝐵𝐵 Where 𝐵𝐵 = 𝑤𝑤𝑤𝑤𝑤𝑤𝑤𝑤ℎ 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑎𝑎𝑎𝑎𝑎𝑎 𝐿𝐿 = 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙ℎ 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 For values of 𝐿𝐿/𝐵𝐵 between 1 and 10, necessary interpolations can be made. To use equation (35) first requires evaluation of the approximate variation of he modulus of elasticity with depth (figure 4.22). This evaluation can be made by using the standard penetration numbers or cone penetration resistances. The soil layer can be divided into several layers to a depth of 𝑧𝑧 = 𝑧𝑧2 , and the elastic settlement of each layer can be estimated. The sum of the settlement of all layers equals 𝑆𝑆𝑒𝑒 , Schmertmann (1970) provided a case history of a rectangular foundation (Belgian bridge pier) having L = 23 m and B = 2.6 m and being supported by a granular soil deposit. For this foundation we may assume that 𝐿𝐿/𝐵𝐵 ≈ 10 for plotting the strain influence factor diagram. Figure 4.23 shows the details of the foundation along with the approximate variation of the cone penetration resistance, 𝑞𝑞𝑜𝑜 , with depth. For this foundation [equation (35)], note that Figure 4.23 Variation of 𝐼𝐼𝑧𝑧 𝑎𝑎𝑎𝑎𝑎𝑎 𝑞𝑞𝑟𝑟 below the foundation NPTEL – ADVANCED FOUNDATION ENGINEERING-I � = 178.54 𝑘𝑘𝑘𝑘/𝑚𝑚2 𝑞𝑞 𝑞𝑞 = 31.39 𝑘𝑘𝑘𝑘/𝑚𝑚2 𝑞𝑞 31.39 𝐶𝐶1 = 1 − 0.5 𝑞𝑞�−𝑞𝑞 = 1 − (0.5) �178.54−31.39� = 0.893 𝑡𝑡 𝑦𝑦𝑦𝑦 𝐶𝐶2 = 1 + 0.2 𝑙𝑙𝑙𝑙𝑙𝑙 � 0.1 � For 𝑡𝑡 = 5 𝑦𝑦𝑦𝑦 5 𝐶𝐶2 = 1 + 0.2 𝑙𝑙𝑙𝑙𝑙𝑙 �0.1� = 1.34 𝑧𝑧 The following table shows the calculation of ∑02 (𝐼𝐼𝑧𝑧 /𝐸𝐸𝑠𝑠 ) ∆𝑧𝑧 in conjunction with figure 4.23. ∆𝑧𝑧(𝑚𝑚) Layer 𝑞𝑞𝑐𝑐 (𝑘𝑘𝑘𝑘/ 𝑚𝑚2 ) 𝐸𝐸𝑠𝑠𝑎𝑎 (𝑘𝑘𝑘𝑘/ 𝑚𝑚2 ) 𝑧𝑧 to the 𝐼𝐼𝑧𝑧 at the (𝐼𝐼𝑧𝑧 / center of center of 𝐸𝐸𝑠𝑠 ) ∆𝑧𝑧(𝑚𝑚2 / the layer the layer 𝑘𝑘𝑘𝑘) (m) 1 1 2,450 8,575 0.5 0.258 2 1.6 3,430 12,005 1.8 0.408 3 0.4 3,430 12,005 2.8 0.487 4 0.5 6,870 24,045 3.25 0.458 5 1.0 2,950 10,325 4.0 0.410 6 0.5 8,340 29,190 4.75 0.362 3.00 × 10−5 5.43 × 10−5 1.62 × 10−5 0.95 × 10−5 3.97 × 10−5 0.62 × 10−5 NPTEL – ADVANCED FOUNDATION ENGINEERING-I 7 1.5 14,000 49,000 5.75 0.298 8 1 6,000 21,000 7.0 0.247 9 1 10,000 35,000 8.0 0.154 10 1.9 4,000 14,000 9.45 0.062 a 𝛴𝛴 10.4 𝑚𝑚 = 4 𝐵𝐵 𝐸𝐸𝑠𝑠 ≈ 3.5𝑞𝑞𝑜𝑜 [𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 (40)] 0.91 × 10−5 1.17 × 10−5 0.44 × 10−5 0.84 × 10−5 𝛴𝛴 18.95 × 10−5 Hence the immediate settlement is calculated as 𝐼𝐼 𝑆𝑆𝑒𝑒 = 𝐶𝐶1 𝐶𝐶2 (𝑞𝑞� − 𝑞𝑞)𝛴𝛴 𝐸𝐸𝑧𝑧 𝛥𝛥𝑧𝑧 𝑠𝑠 = (0.893)(1.34)(178.54 − 31.39)(18.95 × 10−5 ) = 0.03336 ≈ 33 𝑚𝑚𝑚𝑚 After five years, the actual maximum settlement observed for the foundation was about 39 mm. RANGE OF MATERIAL PARAMETERS FOR COMPUTING ELASTIC SETTLEMENT Section 8-10 presented the equations for calculating immediate settlement of foundations. These equations contain the elastic parameters, such as 𝐸𝐸𝑠𝑠 𝑎𝑎𝑎𝑎𝑎𝑎 𝜇𝜇𝑠𝑠 . If the laboratory test results for these parameters are not available, certain realistic assumptions have to be made. Table 5 shows the approximate range of the elastic parameters for various soils. Several investigators have correlated the values of the modulus of elasticity, 𝐸𝐸𝑠𝑠 , with the field standard penetration number, 𝑁𝑁𝐹𝐹 and the cone penetration resistance, 𝑞𝑞𝑐𝑐 , Mitchell and Gardner (1975) compiled a list of these correlations, Schmertmann (1970) indicated that the modulus of elasticity of sand may be given by 𝐸𝐸𝑠𝑠 (𝑘𝑘𝑘𝑘/𝑚𝑚2 ) = 766𝑁𝑁𝐹𝐹 [4.36] NPTEL – ADVANCED FOUNDATION ENGINEERING-I Where 𝑁𝑁𝐹𝐹 = 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠a𝑟𝑟𝑟𝑟 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛 In English units 𝐸𝐸 (𝑈𝑈. 𝑆𝑆. 𝑡𝑡𝑡𝑡𝑡𝑡/𝑓𝑓𝑓𝑓 2 ) = 8𝑁𝑁𝐹𝐹 [4.37] Table 5 Elastic Parameters of Various Soils Modulus of elasticity, 𝐸𝐸𝑠𝑠 Loose sand 𝑙𝑙𝑙𝑙/𝑖𝑖𝑖𝑖2 1,500-3,500 𝑀𝑀𝑀𝑀/𝑚𝑚2 10.35-24.15 Poisson’s ratio, 𝜇𝜇𝑠𝑠 Medium dense sand 2,500-4,000 17.25-27.60 0.25-0.40 Dense sand 5,000-8000 34.50-55.20 0.30-0.45 Silty sand 1,500-2,500 10.35-17.25 0.20-0.40 Sand and gravel 10,000-25,000 69.00-172.50 0.15-0.35 Soft clay 600-3,000 4.1-20.7 Medium clay 3,000-6,000 20.7-41.4 Stiff clay 6,000-14,000 41.4-96.6 Type of soil 0.20-0.40 0.20-0.50 Similarly, 𝐸𝐸𝑠𝑠 = 2𝑞𝑞𝑐𝑐 [4.38] Where 𝑄𝑄𝑐𝑐 = 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟 Schmertmann and Hartman (1978) further suggested that the following correlations may be used with the strain influence factors described in section 10: 𝐸𝐸𝑠𝑠 = 2.5𝑞𝑞𝑐𝑐 [4.39] And (𝑓𝑓𝑓𝑓𝑓𝑓 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑎𝑎𝑎𝑎𝑎𝑎 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓) 𝐸𝐸𝑠𝑠 = 3.5𝑞𝑞𝑐𝑐 (𝑓𝑓𝑓𝑓𝑓𝑓 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓) [4.40] Note: Any consistent set of units may be used in equation (38)-(40). NPTEL – ADVANCED FOUNDATION ENGINEERING-I The modulus of elasticity of normally consolidated clays may be estimated as 𝐸𝐸𝑠𝑠 = 250𝑐𝑐 𝑡𝑡𝑡𝑡 500 𝑐𝑐 [4.41] 𝐸𝐸𝑠𝑠 = 750𝑐𝑐 𝑡𝑡𝑡𝑡 1000 𝑐𝑐 [4.42] And for overconsolidated clays as Where 𝑐𝑐 = 𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢 𝑐𝑐𝑐𝑐ℎ𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 𝑜𝑜𝑜𝑜 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 CONSOLIDATION SETTLEMENT As mentioned before, consolidation settlement occurs over time, and it occurs in saturated clayey soils when they are subjected to increased load caused by foundation construction (figure 4.24). Based on the one-dimensional consolidation settlement equations given in chapter 1, we write Figure 4.24 Consolidation settlement calculation 𝑆𝑆𝑐𝑐 = ∫ 𝜀𝜀𝑧𝑧 𝑑𝑑𝑑𝑑 Where 𝜀𝜀𝑧𝑧 = 𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝛥𝛥𝑒𝑒 = 1+𝑒𝑒 𝑜𝑜 NPTEL – ADVANCED FOUNDATION ENGINEERING-I 𝛥𝛥𝑒𝑒 = 𝑐𝑐ℎ𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 𝑜𝑜𝑜𝑜 𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣 𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟 = 𝑓𝑓(𝑝𝑝𝑜𝑜 , 𝑝𝑝𝑐𝑐 , 𝑎𝑎𝑎𝑎𝑎𝑎 𝛥𝛥𝑝𝑝) So 𝑐𝑐 𝑐𝑐 𝑆𝑆𝑐𝑐 = 1+𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙 𝐶𝐶 𝐻𝐻 𝑝𝑝 𝑜𝑜 +𝛥𝛥𝑝𝑝 𝑎𝑎𝑎𝑎 𝐶𝐶 𝐻𝐻 𝑝𝑝 𝑜𝑜 +𝛥𝛥𝑝𝑝 𝑎𝑎𝑎𝑎 𝑜𝑜 (𝑓𝑓𝑓𝑓𝑓𝑓 𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐) 𝑝𝑝 𝑜𝑜 (From chapter 1) 𝑠𝑠 𝑐𝑐 𝑆𝑆𝑐𝑐 = 1+𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙 𝑜𝑜 [64] (𝑓𝑓𝑓𝑓𝑓𝑓 𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐) 𝑝𝑝 𝑜𝑜 (From chapter 1) 𝐶𝐶 𝐻𝐻 𝑝𝑝 [66] 𝐶𝐶 𝐻𝐻 𝑠𝑠 𝑐𝑐 𝑐𝑐 𝑐𝑐 𝑆𝑆𝑐𝑐 = 1+𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙 𝑝𝑝 𝑐𝑐 + 1+𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙 𝑜𝑜 𝑜𝑜 𝑝𝑝𝑐𝑐 < 𝑝𝑝𝑜𝑜 + 𝛥𝛥𝑝𝑝𝑎𝑎𝑎𝑎 ) 𝑜𝑜 𝑝𝑝 𝑜𝑜 +𝛥𝛥𝑝𝑝 𝑎𝑎𝑎𝑎 𝑝𝑝 𝑜𝑜 (From chapter 1) (𝑓𝑓𝑓𝑓𝑓𝑓 𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜𝑜 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑤𝑤𝑖𝑖𝑖𝑖ℎ 𝑝𝑝𝑜𝑜 < [66] Where 𝑝𝑝a = 𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙 𝑏𝑏𝑏𝑏𝑏𝑏𝑏𝑏𝑏𝑏𝑏𝑏 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝛥𝛥𝑝𝑝𝑎𝑎𝑎𝑎 = 𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖 𝑜𝑜𝑜𝑜 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑏𝑏𝑏𝑏 𝑡𝑡ℎ𝑒𝑒 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑝𝑝𝑐𝑐 = 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑒𝑒𝑜𝑜 = 𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖 𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣 𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟𝑟 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙 𝐶𝐶𝑐𝑐 = 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖 𝐶𝐶𝑠𝑠 = 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑖𝑖𝑖𝑖d𝑒𝑒𝑒𝑒 𝐻𝐻𝑐𝑐 = 𝑡𝑡ℎ𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖 𝑜𝑜𝑜𝑜 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙𝑙 The procedures for determining the compression and swelling indexes were discussed in chapter 1. Note that the increase of pressure, 𝛥𝛥𝑝𝑝, on the clay layer is not constant with depth. The magnitude of 𝛥𝛥𝑝𝑝 will decrease with the increase of depth measured from the bottom of the foundation. However, the average increase of pressure may be approximated by 𝛥𝛥𝑝𝑝𝑎𝑎𝑣𝑣 = 16(𝛥𝛥𝑝𝑝𝑡𝑡 + 4𝛥𝛥𝑝𝑝𝑚𝑚 + 𝛥𝛥𝑝𝑝𝑏𝑏 ) [4.43] NPTEL – ADVANCED FOUNDATION ENGINEERING-I where 𝛥𝛥𝑝𝑝𝑡𝑡 , 𝛥𝛥𝑝𝑝𝑚𝑚 , 𝑎𝑎𝑎𝑎𝑎𝑎 𝛥𝛥𝑝𝑝𝑏𝑏 are the pressure increases at the top, middle, and bottom of the clay layer that are caused by the foundation construction. The method of determining the pressure increase caused by various types of foundation load is discussed in sections 2-7, 𝛥𝛥𝑝𝑝𝑎𝑎𝑎𝑎 can also be directly obtained from the method presented in section 5. Example 6 A foundation 1 𝑚𝑚 × 2𝑚𝑚 in plan is shown in figure 4.25. Estimate the consolidation settlement of the foundation. Figure 4.25 Solution The clay is normally consolidated. Thus 𝐶𝐶 𝐻𝐻 𝑐𝑐 𝑆𝑆𝑐𝑐 = 1+𝑒𝑒 𝑙𝑙𝑙𝑙𝑙𝑙 𝑜𝑜 𝑝𝑝 𝑜𝑜 +𝛥𝛥𝑝𝑝 𝑎𝑎𝑎𝑎 𝑝𝑝 𝑜𝑜 𝑝𝑝𝑜𝑜 = (2.5)(16.5) + (0.5)(17.5 − 9.81) + (1.25)(16 − 9.81) = 41.25 + 3.85 + 7.74 = 52.84𝑘𝑘𝑘𝑘/𝑚𝑚2 From equation (43), 𝛥𝛥𝑝𝑝𝑎𝑎𝑎𝑎 = 16(𝛥𝛥𝑝𝑝𝑡𝑡 + 4𝛥𝛥𝑝𝑝𝑚𝑚 + 𝛥𝛥𝑝𝑝𝑏𝑏 ) Now the following table can be prepared (note: 𝐿𝐿 = 2 𝑚𝑚; 𝐵𝐵 = 1 𝑚𝑚): 2 2 𝑚𝑚̇1 = 𝐿𝐿/𝐵𝐵 2 𝑧𝑧(𝑚𝑚) 2+2.5/2 = 3.25 𝑧𝑧/(𝐵𝐵/2) = 𝑛𝑛1 4 6.5 0.190 𝐼𝐼𝑐𝑐 ≈ 0.085 ∆𝑝𝑝 = 𝑞𝑞𝑜𝑜 𝐼𝐼𝑐𝑐 28.5 = ∆𝑝𝑝𝑡𝑡 12.75 = ∆𝑝𝑝𝑚𝑚 NPTEL – ADVANCED FOUNDATION ENGINEERING-I 2 2+2.5 = 4.5 9 0.045 Table 3 6.75 = ∆𝑝𝑝𝑏𝑏 Equation (10) 𝛥𝛥𝑝𝑝𝑎𝑎𝑎𝑎 = 16(28.5 + 4 × 12.75 + 6.75) = 14.38 𝑘𝑘𝑘𝑘/𝑚𝑚2 So 𝑆𝑆𝑐𝑐 = (0.32)(2.5) 1+0.8 52.84+14.38 𝑙𝑙𝑙𝑙𝑙𝑙 � 52.84 SKEMPTON-BJERRUM SETTLEMENT � = 0.0465 = 46.5 𝑚𝑚𝑚𝑚 MODIFICATION FOR CONSOLIDATION The consolidation settlement calculation presented in the preceding section is based on equations (64, 66, and 68). These equations, as shown in chapter 1, are based on onedimensional laboratory consolidation tests. The underlying assumption for these equations is that the increase of pore water pressure, ∆𝑢𝑢, immediately after the load application equals the increase of stress, ∆𝑝𝑝, at any depth. For this case ∆𝑒𝑒 𝑆𝑆𝑐𝑐(𝑜𝑜e𝑑𝑑) = ∫ 1+𝑒𝑒 𝑑𝑑𝑑𝑑 = ∫ 𝑚𝑚𝑣𝑣 ∆𝑝𝑝(1) 𝑑𝑑𝑑𝑑 Where 𝑜𝑜 𝑆𝑆𝑐𝑐(𝑜𝑜𝑜𝑜𝑜𝑜 ) = 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑏𝑏𝑏𝑏 𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢𝑢 𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒𝑒 (64, 66, 𝑎𝑎𝑎𝑎𝑎𝑎 68 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 𝑐𝑐ℎ𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 1) ∆𝑝𝑝(1) = 𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣 𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠𝑠 𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖𝑖 (𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛 𝑡𝑡ℎ𝑒𝑒 𝑐𝑐ℎ𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 𝑜𝑜𝑜𝑜 𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛𝑛 𝑓𝑓𝑓𝑓𝑓𝑓𝑓𝑓 ∆𝑝𝑝) 𝑚𝑚𝑣𝑣 = 𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣𝑣 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 𝑜𝑜𝑜𝑜 𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐 (𝑠𝑠𝑠𝑠𝑠𝑠 𝑐𝑐ℎ𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎𝑎 1) In the field, however, when load is applied over a limited area on the ground surface, this assumption will not be correct. Consider the case of a circular foundation on a clay layer as shown in figure 4.26. The vertical and the horizontal stress increases at a point in the clay layer immediately below the center of the foundation are ∆𝑝𝑝(1) 𝑎𝑎𝑎𝑎𝑎𝑎 ∆𝑝𝑝(3) , respectively. For saturated clay, the pore water pressure increase at that depth (chapter 1) is ∆𝑢𝑢 = ∆𝑝𝑝(3) + 𝐴𝐴[∆𝑝𝑝(1) − ∆𝑝𝑝(3) ] [4.44] NPTEL – ADVANCED FOUNDATION ENGINEERING-I Figure 4.26 Circular foundation on a clay layer Where 𝐴𝐴 = 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑤𝑤𝑤𝑤𝑤𝑤𝑤𝑤𝑤𝑤 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝𝑝 For this case S𝑐𝑐 = ∫ 𝑚𝑚𝑣𝑣 ∆𝑢𝑢 𝑑𝑑𝑑𝑑 = ∫(𝑚𝑚𝑣𝑣 )�∆𝑝𝑝(3) + 𝐴𝐴�∆𝑝𝑝(1) − ∆𝑝𝑝(3) ��𝑑𝑑𝑑𝑑 [4.45] Thus we can write 𝐾𝐾𝑐𝑐𝑐𝑐𝑐𝑐 = 𝑆𝑆 Where 𝑆𝑆𝑐𝑐 𝑐𝑐(𝑜𝑜𝑜𝑜𝑜𝑜 ) = 𝐻𝐻 ∫0 𝑐𝑐 𝑚𝑚 𝑣𝑣 ∆𝑢𝑢 𝑑𝑑z H ∫0 c m v ∆p (1) dz = A + (1 − A) � H ∫0 c ∆p (3) dz � H ∫0 c ∆p (1) dz K cir = settlement ratios for circular foundations [4.46] The settlement ratio for a continuous foundation (K str ) can be determined in a manner similar to that or a circular foundation. The variation of K cir and K str with A and Hc /B is given in figure 4.27. (Note: B = diameter of a circular foundation, and B = width of a continuous foundation). NPTEL – ADVANCED FOUNDATION ENGINEERING-I Figure 4.27 Settlement ratios for circular (K cir ) and continuous (K str ) foundation Following is the procedure for determining consolidation settlement according to Skempton and Bjerrum (1957). 1. Determine the consolidation settlement, Sc(oed ) , using the procedure outlined in section 12. (Note the change of notation from Sc . 2. Determine the pore water pressure parameter, A. 3. Determine Hc /B. 4. Obtain the settlement ratio-in this case, from figure 27. 5. Calculate the actual consolidation settlement: Sc = Sc(oed ) × settlement ratio [4.47] This technique is generally referred to as the Skempton-Bjerrum modification for consolidation settlement calculation. CONSOLIDATION SETTLEMENT-GENERAL COMMENTS AND A CASE HISTORY In predicting the consolidation settlement and the time rate of settlement for actual field conditions, an engineer has to make several simplifying assumptions. They include the NPTEL – ADVANCED FOUNDATION ENGINEERING-I compression index, coefficient of consolidation, preconsolidation pressure, drainage conditions, and thickness of the clay layer. Soil layering is not always uniform with ideal properties; hence field performance may deviate from the prediction, requiring adjustments during construction. The following case history on consolidation, as reported by Schnabel (1972), illustrates this reality. Figure 4.28 shows the subsoil conditions for the construction of a school building in Waldorf, Maryland. Upper Pleistocene sand and gravel soils are underlain by deposits of very loose fine silty sand, soft silty clay, and clayey silt. The softer surface layers are underlain by various layers of stiff to firm silty clay, clayey silt, and sandy silt to a depth of 50 ft. before construction of the building began; a compacted fill having a thickness of 8-10 ft was placed on the ground surface. This fill initiated the consolidation settlement in the soft silty clay and clayey silt. Figure 4.28 Subsoil conditions for the construction of school building (note: SPT N value are uncorrected, i.e., after Schnabel, 1972) To predict the time rate of settlement, based on the laboratory test results, the engineers made the following approximations: NPTEL – ADVANCED FOUNDATION ENGINEERING-I a. The preconsolidation pressure, pc was 1600 to 2800 lb/ft 2 in excess of the existing overburden pressure. b. The swell index, Cs , was 0.01 to 0.03. c. For the more compressive layers Cv ≈ 0.36 ft 2 /day, and for the stiffer soil layers Cv ≈ 3.1 ft 2 /day. The total consolidation settlement was estimated to be about 3 in. under double drainage conditions, 90% settlement was expected to occur in 114 days. Figure 4.29 shows a comparison of measured and predicted settlement with time, with indicates that a. S c (observed ) S c (estimated ) ≈ 0.47 b. 90% of the settlement occurred in about 70 days; hence t 90(observed ) / t 90(estimated ) ≈ 0.58. The reality rapid settlement in the field is believed to be due to the presence of a fine sand layer within the Miocene deposits. Figure 4.29 Comparison of measured and predicted consolidation settlement with time (after Schnabel, 1972) NPTEL – ADVANCED FOUNDATION ENGINEERING-I