Name (print): UIN: 1. /10 = /10 Problem 1 (10 points) Find Ix, Vx and

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ECE 225 Circuit Analysis
Quiz #2
University of Illinois at Chicago
Summer 2011
Name (print):
UIN:
1.
/10
=
/10
Problem 1 (10 points)
Find Ix , Vx and the power absorbed by the controlled voltage source.
Ix
2Ω
3Ω
+ Vx −
42V +
−
Ix =
Dr. Vahe Caliskan
+ 3Vx
−
Vx =
Pabs =
1 of 1
Handed out: June 27, 2011
ECE 225 Circuit Analysis
Quiz #3
University of Illinois at Chicago
Summer 2011
Name (print):
UIN:
1.
/5
2.
/5
=
/10
Problem 1 (5 points)
Find node voltages V1 , V2 and current Ix , using nodal analysis.
10V
V1
+−
V2
Ix
5A
V1 =
Dr. Vahe Caliskan
3Ω
6Ω
V2 =
2Ix
Ix =
1 of 2
Handed out: June 29, 2011
University of Illinois at Chicago
Summer 2011
ECE 225 Circuit Analysis
Quiz #3
Problem 2 (5 points)
Find loop (mesh) currents I1 , I2 and voltage Vx , using loop (mesh) analysis.
5Ω
20Ω
+ Vx −
+
30V −
I1 =
Dr. Vahe Caliskan
I1
3Vx
I2 =
I2
+
−
5V
Vx =
2 of 2
Handed out: June 29, 2011
ECE 225 Circuit Analysis
Quiz #4
University of Illinois at Chicago
Summer 2011
Name (print):
UIN:
1.
/6
2.
/4
=
/10
Problem 1 (6 points)
50Ω
40Ω
Ix
14A
10Ω
+
Vx
−
60Ω
+ 100V
−
(a) Find the voltage Vx due to the 100V voltage source acting alone.
(b) Find the current Ix due to the 14A current source acting alone.
Ix |14A =
Vx |100V =
Dr. Vahe Caliskan
1 of 2
Handed out: July 6, 2011
University of Illinois at Chicago
Summer 2011
ECE 225 Circuit Analysis
Quiz #4
Problem 2 (4 points)
Find the power dissipated in the 50Ω resistor using a method of your choice.
30Ω
+
60V −
60Ω
1A
2A
10Ω
50Ω
Pdiss =
Dr. Vahe Caliskan
2 of 2
Handed out: July 6, 2011
ECE 225 Circuit Analysis
Quiz #5
University of Illinois at Chicago
Summer 2011
Name (print):
UIN:
1.
/4
2.
/6
=
/10
Problem 1 (4 points)
Find the Thevenin resistance (RT H ) looking into terminals a-b in the circuit shown below.
50Ω
50Ω
40Ω
a
14A
10Ω
60Ω
+ 100V
−
b
RT H =
Dr. Vahe Caliskan
1 of 2
Handed out: July 11, 2011
University of Illinois at Chicago
Summer 2011
ECE 225 Circuit Analysis
Quiz #5
Problem 2 (6 points)
Find the Thevenin equivalent circuit (VT H and RT H ) and the Norton equivalent circuit (IN and RN ) looking
into terminals a-b in the circuit shown below.
30Ω
60Ω
10Ω
a
+
60V −
1A
2A
b
VT H =
Dr. Vahe Caliskan
RT H =
IN =
2 of 2
RN =
Handed out: July 11, 2011
ECE 225 Circuit Analysis
Quiz #8
University of Illinois at Chicago
Summer 2011
Name (print):
UIN:
1.
/10
=
/10
Problem 1 (10 points)
Given inductor current iL (t), find and sketch the source voltage vs (t).
iL (t) (A)
6
vs (t)
+
−
iL (t)
5Ω
3
t (s)
3H
−3
2
4
7
9
12
−6
Dr. Vahe Caliskan
1 of 2
Handed out: July 20, 2011
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