§7.1 Properties of the Normal Distribution Example 1: Imagine that a friend of yours is always late. In fact, your friend is always a minimum of 35 to 55 minutes late. Let the random variable X represent the number of minutes that your friend will be late where x is 1-minute intervals, all of which are equally likely and x is between x = 35 and x = 55. That is to say your friend is just as likely to be 41 to 42 minutes late or 52 to 53 minutes late. Because any two intervals of equal length between 35 and 55, inclusive, are equally likely, the random variable X is said to follow a uniform probability distribution. For discrete random variables, we usually substitute the value of the random variable into a formula to compute probabilities. Things are not as easy for continuous variables however. Since there are an infinite number of possible outcomes, the probability of observing a particular value of a continuous random variable is 0. For instance, the probability that your friend is exactly 38.99735797456 minutes late is 0. Calculating this probability, there is 1 way for your friend to be exactly this late, out of an infinite number of possible values between 35 and 55. To deal with this problem, we will compute probabilities of continuous random variables over intervals. Definition: A probability density function (pdf) is an equation used to compute probabilities of continuous random variables. It must satisfy the following two properties: Two Properties of a Probability Density Function (pdf) 1. The total area under the graph of the equation over all possible values of the random variable must equal 1. 2. The height of the graph of the equation must be greater than or equal to 0 for all values of the random variable. That is, the graph of the equation must lie on or above the horizontal axis for all values of the random variable. SECTION 7.1 1 Density Example 1 (continued): Below is the graph of the probability density function for the random variable X where X = how late your friend is. 0 35 55 X Time (mins) OBJECTIVE 1: Utilize the Uniform Probability Distribution To find the probability of a certain interval, you must find the area of the graph that is above the interval. Example 1 (continued): What is the probability that your friend will be between 40 and 45 minutes late? SECTION 7.1 2 Practice: The reaction time x (in minutes) of a certain chemical process follows a uniform probability distribution with (a) Draw the graph of the density curve. (b) What is the probability that the reaction time is between 6 and 8 minutes? (c) What is the probability that the reaction time is less than 8 minutes? SECTION 7.1 3 OBJECTIVE 2: Graph of a Normal Curve Definition: A continuous random variable is normally distributed, or has a normal probability distribution, if the relative frequency histogram of the random variable has the shape of a normal curve. Each curve is determined by two parameters – its mean, and its standard deviation, The figures below are different normal curves and show how changing the mean and standard deviation affect the curve. In figure (a), there are two normal density curves. The density curve to the left has and the density curve to the right has . We can see that increasing the mean from 0 to 3 caused the graph to shift three units to the right, but the graphs maintained their shape since the standard deviations are the same. SECTION 7.1 In figure (b), two normal density curves are drawn. The taller density curve has and the other has . We can see that increasing the standard deviation from 1 to 2 causes the graph to become flatter and more spread out, but maintained its location of center since their means are the same. 4 Characteristics of the Normal Density Curve 1. The mean = mode = median and are located at the center of the distribution, which is the highest point on the curve. 2. The points at and are the inflection points on the normal curve. These are the points where the curvature changes. 3. The standard deviation of the variable determines the spread of the curve about the mean. 4. The area under the curve is 1. 5. The curve is symmetric about the mean. The area to the left of the mean is 0.5 and the area to the right of the mean is 0.5. 6. As x increases, without bound (gets larger and larger), the graph approaches, but never reaches the horizontal axis. As x decreases without bound (gets smaller and smaller), the graph approaches, but never reaches the horizontal axis. 7. The Empirical Rule: Approximately 68% of the area under the normal curve is between and . Approximately 95% of the area under the normal curve is between and . Approximately 99.7% of the area under the normal curve is between and . SECTION 7.1 5 Example 2: Suppose and . Graph the normal curve. OBJECTIVE 3: Standardizing the Normal Curve We saw that when we change the mean and/or the standard deviation, it changes the graph of the normal curve. Since the mean and the standard deviation can be any value, this means that there are an infinite number of different normal curves that we could potentially have to work with. Instead of this, we will “standardize” each normal curve to the standard normal curve. In doing this, we will only have to work with one normal curve, the standard normal curve. The way that we will be standardizing the normal curves will be through using z-scores. Standardizing a Normal Random Variable Suppose the random variable X is normally distributed with mean Then, the random variable is normally distributed with mean the standard normal distribution. SECTION 7.1 and and standard deviation The random variable Z is said to have 6 Example 3: A random variable X is normally distributed with (a) Compute for (b) Compute (c) The area under the first normal curve between is the area between and SECTION 7.1 and and for is 0.2880. What 7 Example 4: The lives of refrigerators are normally distributed with mean and standard deviation years. years (a) Draw a normal curve with the parameters labeled. Then, shade the region that represents the proportion of refrigerators that last for more than 17 years. (b) Suppose that the area under the normal curve to the right of x = 17 is 0.1151. Provide two interpretations of this result. SECTION 7.1 8