Example 1

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Consider Dakota example discussed in modeling. Use the Lindo output in the figure
given to answer the following questions. Let x1, x2, x3 be the number of desks, tables
and chairs produced.
a. If the price of a table is $ 40, what would be the new optimal solution to the
problem?
Current basis is no longer optimal
b. If the price of a table is $ 25, what would be the new optimal solution to the
problem?
Still $ 280
c. If the price of a desk is $70, what would be the new optimal solution to the
problem?
$ 300
d. If maximum available finishing hours were 25 hrs., what would be the profit?
Current basis is no longer optimal
e. If maximum available finishing hours were 18 hrs., what would be the new profit?
$ 260
f. If maximum available lumber were 38 board ft., what would be the new, profit?
Still $ 280
LP OPTIMUM FOUND AT STEP 2
OBJECTIVE FUNCTION VALUE
1)
280.0000
VARIABLE
VALUE
REDUCED COST
X1
2.000000
0.000000
X2
0.000000
5.000000
X3
8.000000
0.000000
ROW
lumber)
finishinq)
carpentry)
demand)
SLACK OR SURPLUS
24.000000
0.000000
0.000000
5.000000
DUAL PRICES
0.000000
10.000000
10.000000
0.000000
RANGES IN WHICH THE BASIS IS UNCHANGED:
X1
X2
X3
CURRENT
CQEF
60.000000
30.000000
20.000000
OBJ COEFFICIENT RANGES
ALLOWABLE
ALLLOWABLE
INCREASE
DECREASE
20.000000
4.000000
5.000000
INFINITY
2.500000
5.000000
lumber
finishinq
carpentry
demand'
CURRENT
RHS
48.000000
20.000000
8.000000
5.000000
RIGHTHAND SIDE RANGES
ALLOWABLE
ALLLOWABLE
INCREASE
DECREASE
INFINITY
24.000000
4.000000
4.000000
2.000000
1.333333
INFINITY
5.000000
VARIABLE
ROW
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