Integral Calculus super-duper notes Term Area between curves Integral Calculus super-duper notes Definition To determine the area bounded by two curves: Integral Calculus super-duper notes An example problem… Determine the area bounded by the curves y = x2 and y = x3 Intersection point Decide dx or dy Integral set-up Organize your terms Take the integral Area under a curve To determine the area under a curve, Graph it Limits Use the integral Evaluate Differential Equations To solve a differential equation Separate the dy from the dx Use an integral on both sides Check any initial condition Solve for y Determine the area bounded by y = 4x², x = 1 and x = 3 Solve the differential equation dy/ dx = 4x²y Disc method [volume] Washer Method To determine the volume of a solid using the disc method: Pi goes out front Limits Outer2 – Inner2 Work it, Baby Indefinite integrals Indefinite integrals are not evaluated using any limits Determine the volume of the solid generated by rotating the region bounded by y = x2, x = 2 and x = 8 around the x-axis Integrate the following: 3x 4 3x 2 + 2x dx – 5x dx is a prime example. Indefinite integrals and antiderivatives are somewhat synonymous – although an antiderivative is the “undoing” of a derivative which may or may not be evaluated using given limits [sin x] dx Since the derivative of any constant is zero, a “+ C” is included in the solution in order to include all possible solutions which may exist Integrating 1/x 1/ x dx = ln x + C so anytime a function is in that form, your integral will result in some type of natural log Since negative numbers can’t yield natural log values, the absolute value sign is used Determine the area bounded by y = 1/x, x = 1 and x = 10 Integrating polynomial functions When integrating polynomial functions, the power goes up by one and its coefficient becomes the reciprocal of the resulting power x Integrating trig functions 4 x 3 – 4x2 + 12x + 3 dx dx = 1/5 x5 + C When integrating trigonometric functions remember Integrate the following: [sin x] dx = -cos x + C sin 2x dx [cos x] dx = sin x + C [sec x] dx = tan x + C x sec [x2] dx 2 [sec x tan x] dx = L'Hopital's Rule Integrate the polynomial function sec x + C To determine the limit of a 0 function in the form of /0, Determine the limit of / or any other indeterminate form, simply take the derivative of the top AND of the bottom and re-evaluate the function 2 lim 0 cos [2x] – 1 sin x Shells method [volume] To determine the volume of a solid using the shell method 2 goes out front Put an x next Limits A function [or difference] goes next Calculate the volume Trigonometric substitution In order to integrate functions in the forms of a2 – x2 x2 – a2 a2 + x2 use the following steps Bust the right triangle Get x Get dx Get the triangle rebuilt Get it integrated u substitutions In order to use u substitutions: Substitute as u Hot Mama Adjust your limits Function switch Take the integral Determine the volume of the solid generated by revolving the regions bounded by y = x3, y = 1 and y = 4 around the y-axis