UNIVERSITY OF TORONTO FACULTY OF APPLIED SCIENCES AND ENGINEERING Mid-term examination BME 205S: Engineering Biology Examiner: M.V.Sefton February 21, 2005 Answer all questions All questions are of equal value Answer each question in a different book and label with your name and the question 1. (a) The cytoskeleton is made up of elaborate arrays of protein fibers, which form networks throughout the cytosol. i. What general function does the cytoskeleton perform? ii. What are the three major types of protein filaments that make up the cytoskeleton and what are their primary functions? (b) The F-class proton pump is one of a family of ATP powered pumps involved in the transport of ions and various small molecules against their concentration gradients. i. How is the typical operation of the F-class proton pump different from the other “ATP powered” pumps? ii. In a mammalian cell, which membrane are you most likely to find this pump on? iii. This pump, as indicated by its name, is involved in proton transport. Name two strategies the cell can use to operate this pump without generating an electrical potential across the relevant membrane. 2. A novel glucose sensor is being created with an optical readout based on a change in colour of a strip of immobilized enzyme that also contains a reagent that changes colour when the pH changes (Figure 1). The concept is to produce a linear gradient of immobilized enzyme (along the x direction); i.e., more enzyme at one end than at the other. Adding the substrate (a solution containing glucose) uniformly over the strip for a known time results in no colour where the strip has too low a glucose concentration to effect 1 of 4 significant colour change and a strong colour if the glucose concentration is high enough. This results in a discontinuity in colour at a particular value of x. A calibration curve linking the position of the colour discontinuity to glucose concentration results in a user determining the glucose concentration in a test sample, through visual determination of the position of the discontinuity for that sample. In order to detect colour using the intended reagents requires at least 15 µmol/cm2 of glucose to react; assume the discontinuity is very sharp. The minimum glucose concentration to be detected is 1 mM and the maximum is 25 mM. At one end, there is 0.5 mg/cm2 of enzyme immobilized (enough to detect the low concentration limit). The enzyme specific activity (kr) is 172 µmol/minmg of enzyme and the Michaelis-Menten constant, Km is 1.5 mM. (a) What is the required minimum exposure time to see the needed colour change. (b) What is the required gradient in enzyme concentration if the strip is to be 3 cm long. (c) Sketch the scale that could be marked on the strip to enable a direct readout of glucose concentration from the colour discontinuity. Comment on the problem implicit in this scale. Immobilized enzyme – uniform in y direction; linear gradient in x direction (i.e., there is more enzyme at one end than at another) Figure 1 Coloured zone y x Position of coloured front denotes concentration of glucose in test sample (the discontinuity) 3. In the European Union there is strong pressure to eliminate the use of animals in research, and thus there is a major focus on developing tissues that can serve as materials in toxicology tests. Wagner et al.1 are developing 1 Wager, H., et al., Interrelation of permeation and penetration parameters obtained from in vitro experiments with human skin and skin equivalents. J. Control. Release, 75:283-295(2001). 2 of 4 a new tissue-engineered skin called Epiderm for use in testing dermal penetration and toxicity. This skin is made from living human donor cells, grown into a dermal equivalent (the soft, underlying layer of skin) and an epidermal equivalent (the surface layer) in culture. One important assessment is how it compares to normal skin (Figure 2) in terms of permeability. outside epidermis Stratum corneum dermis Figure 2: normal skin An experiment is conducted in which the test “skins” are placed in a two chamber diffusion apparatus (Figure 3). The surface area of the skin between the two chambers is 2 cm2. The amount of a model compound (a “penetrant”, flufenamic acid, a lipophilic molecule) that diffuses across the skin is determined in the sink (downstream or receiving) chamber as a function of time and used to calculate the amount permeating as a function of time. In these experiments, the concentration of the molecule in the source chamber is much greater than that in the sink chamber, so the concentration profile in the skin can be assumed to be steady state after a very short initial transient. The data, collected in Table 1, were all taken in the steady state regime. Initially the sink is filled with fluid that contains no penetrant and the small increases in concentration, although negligible compared to the source concentration, are used to calculate the cumulative amount of penetrant that has permeated through the “skin”. It is determined in a separate experiment that the partition coefficient (“solubility”) for the penetrant in epidermis is 1.5, in stratum corneum (a thin layer between the epidermis and dermis) is 5.6, in the full skin is 0.8 and in Epiderm is 1.3. The partition coefficient, H, is defined here as H = C skin layer / Csource. The concentration in the source chamber is kept constant at 4.5 mg/cm3 (Csource). On the basis of the data in table 1: a) Calculate the steady-state flux in each case; b) Calculate the diffusion coefficient in each case; c) Explain how close is Epiderm to Full skin and why might it be different? Include discussion of thicknesses, diffusivities and fluxes. 3 of 4 Test Skins Epidermis, Skin Normal Stratum Corneum, Normal Skin Full skin, Normal Skin Epiderm Thickness = 2910 m Thickness = 67.3 m Time (hr) Amount sink (g) Time (hr) Amount sink (g) Thickness = 75.2 m Thickness = 12.2 m Time (hr) Amount sink (g) Time (hr) Amount sink (g) 5 9.5 5 10 5 3.5 5 115 10 19 10 20 10 7 10 230 20 38 20 40 20 14 20 460 in Source in in in Sink Csource X=0 Csink X=l Test skins Figure 3 4 of 4