2. STATICS OF PARTICLES 2.1 Concurrent Forces. In this chapter we shall study the effect of forces on particles. The use of the word particle does not imply that we shall restrict our study to that of small corpuscles. It means that the size and shape of the bodies under considerations will not affect the solution of problems treated in this chapter and that all the forces acting on given body will be assumed to have the same point of application. Forces whose lines of action intersect at one point are said to be concurrent. A system of concurrent forces acting on a particle A can be replaced by an equivalent force, i.e. by the resultant R (Fig.2.1) The problem of determining the resultant of concurrent forces F1, F2 , …, Fn is reduced, according to the 3rd principle of statics, to the composition of the given forces, i.e. R = F1 + F2 + … + Fn (2.1) 2.2 Resolution of Forces. As we know from the chapter Elements of Vector Algebra, the problem of resolution of a force, F, into components is indeterminate and can be solved uniquely only if additional conditions are stated. Two cases are of particular interest: 1. One of the two components, P, is known. The second component, Q, is obtained by applying the triangle rule and joining the tip of P to the tip of F (Fig.2.2a). Ones Q has been determined graphically or by trigonometry, both components P and Q should be applied at A ; 2. The line of action of each component is known. Both components are obtained by means of parallelogram law (Fig.2.2b). This process leads to well-defined components, P and Q, which may be determined graphically or by applying of the law of sines. 2.3 Analytical method of addition of concurrent forces. We shall determine the resultant R of two or more forces in space by summing their orthogonal components. Graphical or trigonometrical methods are generally not practical in StP-1 the case of forces in space. Thus, consider n forces F1, F2 , …, Fn and suppose that their orthogonal components are known. The resultant R is given by eq. (2.1). Resolving each force in (2.1) into its orthogonal components, we write ( ) r r r r r r r r r R x i + R y j + R z k = ∑ Fix i + Fiy j + Fiz k = (∑ Fix )i + (∑ Fiy ) j + (∑ Fiz )k (2.2) from which it follows that R x = ∑ Fix ; R y = ∑ Fiy ; R z = ∑ Fiz (2.3) The magnitude of the resultant and the angles θx, θy, θz it forms with the axes of coordinates are as follows: R = R 2x + R 2y + R 2z cos θ x = Rx ; R cos θ y = Ry R ; (2.4) cos θ z = Rz R (2.5) 2.4 Equilibrium of a particle. It follows from the laws of mechanics that a particle subjected to the action of an external set of mutually balanced forces can either be at rest or in inertial motion, i.e. a motion without acceleration. In such cases the particle is said to be in equilibrium. For a system of concurrent forces acting on a body to be in equilibrium it is necessary and sufficient for the resultant of the forces to be zero. The conditions which the forces themselves must satisfy can be expressed in either graphical or analytical form. Analytical form of conditions of equilibrium . To express algebraically the conditions for the equilibrium of a particle, we write R = ∑F = 0 (2.6) Resolving each force F into rectangular (=orthogonal) components, we conclude that the necessary and sufficient conditions for the equilibrium of a particle are ∑ Fx = 0, ∑ Fy = 0, StP-2 ∑ Fz =0 (2.7) Graphical form of conditions of equilibrium . Since the resultant R of a system of concurrent forces is defined as the closing side of a force polygon constructed with the given forces, it follows that R can be zero only if the polygon is closed. Thus, for a system of concurrent forces to be in equilibrium it is necessary and sufficient for the force polygon drawn with these forces to be closed. If all concurrent forces acting on a body lie in one plane, they form a coplanar system of concurrent forces. Obviously, for such a force system only two equations are required to express the conditions of equilibrium. 2.5 Solution of problems of static’s. Free-body diagram. In practice, a problem in engineering mechanics is derived from an actual physical situation. A sketch showing the physical conditions of the problem is known as a space diagram. The methods of analysis discussed in this chapter apply to a system of forces acting on a particle. A large number of problems involving actual structures, however, may be reduced to problems concerning the equilibrium of a particle. This is done by choosing a significant particle and drawing a separate diagram showing this particle and all forces acting on it. Such diagram is called a freebody diagram. A next stage of problem solution requires application of the equilibrium conditions in either graphical or analytical form. The final stage of problem solution relies upon the determination of unknown quantities and analysis of results. In practical problems where the equilibrium of either particles or rigid bodies is considered, the reactions of the constraints are unknown quantities. Their number depends on the number and type of the constraints. A problem can be, however, solved only if the number of unknown reactions is not greater than the number of equilibrium equations in which they are present. Such system as well as the corresponding reactions are said to be statically determinate. StP-3 Systems in which the number of unknown reactions of the constraints is greater than the number of equilibrium equations in which they are present are called statically indeterminate similarly as the corresponding reactions. An example of statically indeterminate system is a weight hanging from three strings lying in one plane (Fig.2.3). There are three unknown quantities (the tensions T1, T2, T3 of the strings), but only two equations can be formed. Bibliography Beer F.P, Johnston E.R., Jr., Vector Mechanics for Engineers, McGraw-Hill Shames I.H., Engineering Mechanics – Statics, Prentice-Hall, 1959 StP-4