7-7 Geometric Sequences as Exponential Functions
Determine whether each sequence is arithmetic, geometric, or neither. Explain.
1. 200, 40, 8, …
SOLUTION: Since the ratios are constant, the sequence is geometric. The common ratio is
.
2. 2, 4, 16, …
SOLUTION: The ratios are not constant, so the sequence is not geometric.
There is no common difference, so the sequence is not arithmetic.
Thus, the sequence is neither geometric nor arithmetic.
3. −6, −3, 0, 3, …
SOLUTION: The ratios are not constant, so the sequence is not geometric.
Since the differences are constant, the sequence is arithmetic. The common difference is 3.
4. 1, −1, 1, −1, …
SOLUTION: Since the ratios are constant, the sequence is geometric. The common ratio is –1.
Find the next three terms in each geometric sequence.
5. 10, 20, 40, 80, …
SOLUTION: eSolutions Manual - Powered by Cognero
Page 1
7-7 Geometric Sequences as Exponential Functions
Since the ratios are constant, the sequence is geometric. The common ratio is –1.
Find the next three terms in each geometric sequence.
5. 10, 20, 40, 80, …
SOLUTION: The common ratio is 2. Multiply each term by the common ratio to find the next three terms.
80 × 2 = 160
160 × 2 = 320
320 × 2 = 640
The next three terms of the sequence are 160, 320, and 640.
6. 100, 50, 25, …
SOLUTION: Calculate common ratio.
The common ratio is 0.5. Multiply each term by the common ratio to find the next three terms.
25 × 0.5 = 12.5
12.5 × 0.5 = 6.25
6.25 × 0.5 = 3.125
The next three terms of the sequence are 12.5, 6.25, and 3.125.
7. 4, −1,
,…
SOLUTION: Calculate the common ratio.
The common ratio is
× . Multiply each term by the common ratio to find the next three terms.
= × × = = The next three terms of the sequence are
8. −7, 21, −63, …
eSolutions Manual - Powered by Cognero
SOLUTION: Calculate the common ratio.
,
, and
.
Page 2
× = 7-7 Geometric
Sequences
The next three
terms of as
theExponential
sequence areFunctions
,
, and
.
8. −7, 21, −63, …
SOLUTION: Calculate the common ratio.
The common ratio is –3. Multiply each term by the common ratio to find the next three terms.
–63 × –3 = 189
189 × –3 = –567
–567 × –3 = 1701
The next three terms of the sequence are 189, −567, and 1701.
Write an equation for the nth term of the geometric sequence, and find the indicated term.
9. Find the fifth term of −6, −24, −96, …
SOLUTION: Calculate the common ratio.
Use the formula a n = a 1r
n –1
to write an equation for the nth term of the geometric series. The common ratio is 4,
so r = 4. The first term is –6, so a 1 = –6. Then, a n = −6 • (4)
n−1
.
The 5th term of the sequence is –1536.
10. Find the seventh term of −1, 5, −25, …
SOLUTION: Calculate the common ratio.
Use the formula a n = a 1r
n –1
to write an equation for the nth term of the geometric series. The common ratio is –5,
so r = –5. The first term is –1, so a 1 = –1. Then, a n = −1 • (–5)
n−1
.
The 7th term of the sequence is –15,625.
11. Find the tenth term of 72, 48, 32, …
eSolutions Manual - Powered by Cognero
SOLUTION: Calculate the common ratio.
Page 3
7-7 Geometric Sequences as Exponential Functions
The 7th term of the sequence is –15,625.
11. Find the tenth term of 72, 48, 32, …
SOLUTION: Calculate the common ratio.
Use the formula a n = a 1r
so r =
n –1
to write an equation for the nth term of the geometric series. The common ratio is
. The first term is 72, so a 1 = 72. Then, a n = 72 • The 10th term of the sequence is
,
.
.
12. Find the ninth term of 112, 84, 63, …
SOLUTION: Calculate the common ratio.
Use the formula a n = a 1r
so r =
n –1
to write an equation for the nth term of the geometric series. The common ratio is
. The first term is 112, so a 1 = 112. Then, a n = 112 • The 9th term of the sequence is
,
.
.
13. EXPERIMENT In a physics class experiment, Diana drops a ball from a height of 16 feet. Each bounce has 70%
the height of the previous bounce. Draw a graph to represent the height of the ball after each bounce.
SOLUTION: Make a table of values.
eSolutions
Manual - Powered by Cognero
Bounce
Ball Height
1
0.7(16) = 11.2
2
0.7(11.2) = 7.84
Page 4
7-7 Geometric
as Exponential
The 9th termSequences
of the sequence
is
.Functions
13. EXPERIMENT In a physics class experiment, Diana drops a ball from a height of 16 feet. Each bounce has 70%
the height of the previous bounce. Draw a graph to represent the height of the ball after each bounce.
SOLUTION: Make a table of values.
Bounce
Ball Height
1
0.7(16) = 11.2
2
0.7(11.2) = 7.84
3
0.7(7.84) = 5.488
4
0.7(5.488) = 3.8416
5
0.7(3.8416) = 2.68912
6
0.7(2.68912) = 1.882384
7
0.7(1.882384) =1.3176688
Graph the bounce on the x-axis and the ball height on the y-axis.
Determine whether each sequence is arithmetic, geometric, or neither. Explain.
14. 4, 1, 2, …
SOLUTION: Find the ratios of consecutive terms.
The ratios are not constant, so the sequence is not geometric.
Find the ratios of the differences of consecutive terms
There is no common difference, so the sequence is not arithmetic.
Thus, the sequence is neither geometric nor arithmetic.
15. 10, 20, 30, 40 …
SOLUTION: Find the ratios of consecutive terms.
eSolutions Manual - Powered by Cognero
The ratios are not constant, so the sequence is not geometric.
Page 5
There is no common difference, so the sequence is not arithmetic.
7-7 Geometric
Sequences
as Exponential
Functions
Thus, the sequence
is neither
geometric nor
arithmetic.
15. 10, 20, 30, 40 …
SOLUTION: Find the ratios of consecutive terms.
The ratios are not constant, so the sequence is not geometric.
Find the differences of consecutive terms.
Since the differences are constant, the sequence is arithmetic. The common difference is 10. 16. 4, 20, 100, …
SOLUTION: Find the ratios of consecutive terms.
Since the ratios are constant, the sequence is geometric. The common ratio is 5.
17. 212, 106, 53, …
SOLUTION: Find the ratios of consecutive terms.
Since the ratios are constant, the sequence is geometric. The common ratio is
.
18. −10, −8, −6, −4 …
SOLUTION: Find the ratios of consecutive terms.
The ratios are not constant, so the sequence is not geometric.
Find the differences of consecutive terms.
Since the differences are constant, the sequence is arithmetic. The common difference is 2.
19. 5, −10, 20, 40, …
SOLUTION: Find the ratios of consecutive terms.
eSolutions Manual - Powered by Cognero
Page 6
7-7 Geometric
Sequences as Exponential Functions
Since the differences are constant, the sequence is arithmetic. The common difference is 2.
19. 5, −10, 20, 40, …
SOLUTION: Find the ratios of consecutive terms.
The ratios are not constant, so the sequence is not geometric.
Find the differences of consecutive terms.
There is no common difference, so the sequence is not arithmetic.
Thus, the sequence is neither geometric nor arithmetic.
Find the next three terms in each geometric sequence.
20. 2, −10, 50, …
SOLUTION: Calculate the common ratio.
The common ratio is –5. Multiply each term by the common ratio to find the next three terms.
50 × –5 = –250
–250 × –5 = 1250
1250 × –5 = –6250
The next three terms of the sequence are −250, 1250, and −6250.
21. 36, 12, 4, …
SOLUTION: Calculate the common ratio.
The common ratio is . Multiply each term by the common ratio to find the next three terms.
4 × = × = × = The next three terms of the sequence are , , and
.
22. 4, 12, 36, …
SOLUTION: Calculate the common ratio.
eSolutions Manual - Powered by Cognero
The common ratio is 3. Multiply each term by the common ratio to find the next three terms.
36 × 3 = 108
Page 7
× = × = 7-7 Geometric Sequences as Exponential Functions
The next three terms of the sequence are , , and
.
22. 4, 12, 36, …
SOLUTION: Calculate the common ratio.
The common ratio is 3. Multiply each term by the common ratio to find the next three terms.
36 × 3 = 108
108 × 3 = 324
324 × 3 = 972
The next three terms of the sequence are 108, 324, and 972.
23. 400, 100, 25, …
SOLUTION: Calculate the common ratio.
The common ratio is . Multiply each term by the common ratio to find the next three terms.
25 × = × = × = The next three terms of the sequence are
,
, and
.
24. −6, −42, −294, …
SOLUTION: Calculate the common ratio.
The common ratio is 7. Multiply each term by the common ratio to find the next three terms.
–294 × 7 = –2058
–2058 × 7 = –14,406
–14,406 × 7 = –100,842
The next three terms of the sequence are −2058, −14,406, and −100,842.
25. 1024, −128, 16, …
SOLUTION: Calculate the common ratio.
The common ratio is
16 × = –2
–2 × = . Multiply each term by the common ratio to find the next three terms.
eSolutions Manual - Powered by Cognero
Page 8
The common ratio is 7. Multiply each term by the common ratio to find the next three terms.
–294 × 7 = –2058
–2058 × 7 = –14,406
–14,406 × 7 = –100,842
7-7 Geometric
Sequences as Exponential Functions
The next three terms of the sequence are −2058, −14,406, and −100,842.
25. 1024, −128, 16, …
SOLUTION: Calculate the common ratio.
The common ratio is
16 × = –2
–2 × = × = . Multiply each term by the common ratio to find the next three terms.
The next three terms of the sequence are −2,
, and
.
26. The first term of a geometric series is 1 and the common ratio is 9. What is the 8th term of the sequence?
SOLUTION: The 8th term of the sequence is 4,782,969.
27. The first term of a geometric series is 2 and the common ratio is 4. What is the 14th term of the sequence?
SOLUTION: The 14th term of the sequence is 134,217,728.
28. What is the 15th term of the geometric sequence −9, 27, −81, …?
SOLUTION: Calculate the common ratio.
The common ratio is –3.
eSolutions Manual - Powered by Cognero
The 15th term of the sequence is –43,046,721.
Page 9
7-7 Geometric Sequences as Exponential Functions
The 14th term of the sequence is 134,217,728.
28. What is the 15th term of the geometric sequence −9, 27, −81, …?
SOLUTION: Calculate the common ratio.
The common ratio is –3.
The 15th term of the sequence is –43,046,721.
29. What is the 10th term of the geometric sequence 6, −24, 96, …?
SOLUTION: Calculate the common ratio.
The common ratio is –4.
The 10th term of the sequence is –1,572,864.
30. PENDULUM A pendulum swings with an arc length of 24 feet on its first swing. On each swing after the first
swing, the arc length is 60% of the length of the previous swing. Draw a graph that represents the arc length after
each swing.
SOLUTION: Make a table of values.
Swing
Arc Length
1
24
2
0.6(24) = 14.4
3
0.6(14.4) = 8.64
4
0.6(8.64) = 5.184
5
0.6(5.184) = 3.1104
6
0.6(3.1104) = 1.86624
Graph the swing on the x-axis and the arc length on the y-axis.
eSolutions Manual - Powered by Cognero
Page 10
7-7 Geometric Sequences as Exponential Functions
The 10th term of the sequence is –1,572,864.
30. PENDULUM A pendulum swings with an arc length of 24 feet on its first swing. On each swing after the first
swing, the arc length is 60% of the length of the previous swing. Draw a graph that represents the arc length after
each swing.
SOLUTION: Make a table of values.
Swing
Arc Length
1
24
2
0.6(24) = 14.4
3
0.6(14.4) = 8.64
4
0.6(8.64) = 5.184
5
0.6(5.184) = 3.1104
6
0.6(3.1104) = 1.86624
Graph the swing on the x-axis and the arc length on the y-axis.
31. Find the eighth term of a geometric sequence for which a 3 = 81 and r = 3.
SOLUTION: Because a 3 = 81, the third term in the sequence is 81. To find the eighth term of the sequence, you need to find the
1st term of the sequence. Use the nth term of a Geometric Sequence formula.
Then a 1 is 9. Use a 1 to find the eighth term of the sequence.
eSolutions Manual - Powered by Cognero
The eighth term of the geometric sequence is 19,683.
Page 11
7-7 Geometric Sequences as Exponential Functions
31. Find the eighth term of a geometric sequence for which a 3 = 81 and r = 3.
SOLUTION: Because a 3 = 81, the third term in the sequence is 81. To find the eighth term of the sequence, you need to find the
1st term of the sequence. Use the nth term of a Geometric Sequence formula.
Then a 1 is 9. Use a 1 to find the eighth term of the sequence.
The eighth term of the geometric sequence is 19,683.
32. CCSS REASONING At an online mapping site, Mr. Mosley notices that when he clicks a spot on the map, the map
zooms in on that spot. The magnification increases by 20% each time.
a. Write a formula for the nth term of the geometric sequence that represents the magnification of each zoom level.
(Hint: The common ratio is not just 0.2.)
b. What is the fourth term of this sequence? What does it represent?
SOLUTION: a. Because the magnification increases by 20% with each click, the total magnification after each click is 120%. The
common ratio is 1.2. To find the nth term of the geometric sequence that represents the magnification of each zoom
n
level, use the formula 1.2 .
b.
The fourth term of the sequence is 2.0736. It represents the magnification after the fourth click. So, the map will be
magnified at approximately 207% of the original size after the fourth click.
33. ALLOWANCE Danielle’s parents have offered her two different options to earn her allowance for a 9-week
period over the summer. She can either get paid $30 each week or $1 the first week, $2 for the second week, $4 for
the third week, and so on.
a. Does the second option form a geometric sequence? Explain.
b. Which option should Danielle choose? Explain.
SOLUTION: a.
Calculate
common
ratio.
eSolutions
Manualthe
- Powered
by Cognero
Page 12
b.
7-7 Geometric
Sequences
as Exponential
The fourth term
of the sequence
is 2.0736.Functions
It represents the magnification after the fourth click. So, the map will be
magnified at approximately 207% of the original size after the fourth click.
33. ALLOWANCE Danielle’s parents have offered her two different options to earn her allowance for a 9-week
period over the summer. She can either get paid $30 each week or $1 the first week, $2 for the second week, $4 for
the third week, and so on.
a. Does the second option form a geometric sequence? Explain.
b. Which option should Danielle choose? Explain.
SOLUTION: a.
Calculate the common ratio.
There is a common ratio of 2. So, the second option does form a geometric sequence.
b. Calculate how much Danielle would earn with each option.
Option 1
9(30) = 270
Option 2
1 + 2 + 4 + 8+ 16 + 32 + 64 + 128 + 256 or 511
In nine weeks, Danielle would earn $270 with the first option and $511 with the second option. So, she should choose
the second option.
34. SIERPINSKI’S TRIANGLE Consider the inscribed equilateral triangles shown. The perimeter of each triangle is
one half of the perimeter of the next larger triangle. What is the perimeter of the smallest triangle?
SOLUTION: This is a geometric sequence. The first term is 3(40) or 120 and the common ratio is
. To find the perimeter of the
smallest triangle, find the 5th term of the sequence.
The perimeter of the smallest triangle is 7.5 centimeters.
35. If the second term of a geometric sequence is 3 and the third term is 1, find the first and fourth terms of the
sequence.
SOLUTION: Divide the 3rd term by the 2nd term to find the common ratio.
The common ratio is
. Substitute 2 for n and
eSolutions Manual - Powered by Cognero
for r to find the first term.
Page 13
7-7 Geometric Sequences as Exponential Functions
The perimeter of the smallest triangle is 7.5 centimeters.
35. If the second term of a geometric sequence is 3 and the third term is 1, find the first and fourth terms of the
sequence.
SOLUTION: Divide the 3rd term by the 2nd term to find the common ratio.
The common ratio is
. Substitute 2 for n and
for r to find the first term.
The first term is 9. Find the 4th term.
The fourth term is
.
36. If the third term of a geometric sequence is −12 and the fourth term is 24, find the first and fifth terms of the
sequence.
SOLUTION: Divide the 4th term by the 3rd term to find the common ratio.
The common ratio is
or –2. Substitute 3 for n and –2 for r to find the first term.
The first term is –3. Find the fifth term.
The fifth term is 48.
37. EARTHQUAKES The Richter scale is used to measure the force of an earthquake. The table shows the increase
Page 14
the Richter scale.
Richter
Increase in
Rate of
Number
Magnitude
Change
eSolutions
Manual - Powered
Cognero
in magnitude
for thebyvalues
on
7-7 Geometric Sequences as Exponential Functions
The fifth term is 48.
37. EARTHQUAKES The Richter scale is used to measure the force of an earthquake. The table shows the increase
in magnitude for the values on the Richter scale.
Richter
Increase in
Rate of
Number
Magnitude
Change
(x)
(y)
(slope)
1
1
−
2
10
9
3
100
4
1000
5
10,000
a. Copy and complete the table. Remember that the rate of change is the change in y divided by the change in x.
b. Plot the ordered pairs (Richter number, increase in magnitude).
c. Describe the graph that you made of the Richter scale data. Is the rate of change between any two points the
same?
d. Write an exponential equation that represents the Richter scale.
SOLUTION: a.
Richter
Number (x)
1
2
3
Increase in
Magnitude
(y)
1
10
100
4
1000
5
10,000
Rate of Change (slope)
−
9
b. Graph the Richter number on the x-axis and the increase in magnitude on the y-axis.
c. The graph appears to be exponential. The rate of change between any two points does not match any others.
d. Calculate the common ratio.
There
is a common
ratio
of 10,
eSolutions
Manual
- Powered by
Cognero
so this is situation can be modeled by a geometric sequence. The exponential
x−1
equation that represents the Richter scale is y = 1 • (10) .
Page 15
c. The graph appears to be exponential. The rate of change between any two points does not match any others.
d. Calculate the common ratio.
7-7 Geometric Sequences as Exponential Functions
There is a common ratio of 10, so this is situation can be modeled by a geometric sequence. The exponential
x−1
equation that represents the Richter scale is y = 1 • (10) .
38. CHALLENGE Write a sequence that is both geometric and arithmetic. Explain your answer.
SOLUTION: The sequence 1, 1, 1, 1, … is both geometric and arithmetic. The common ratio is 1 making it a geometric sequence.
The common difference is 0, making it an arithmetic sequence as well.
This can be done for any value n. n, n, n, ... is arithmetic and geometric.
39. CCSS CRITIQUE Haro and Matthew are finding the ninth term of the geometric sequence −5, 10, −20, … . Is
either of them correct? Explain your reasoning.
SOLUTION: The common ratio of the sequence is –2.
The ninth term of the sequence is –1280. Neither Haro nor Matthew is correct. Haro calculated the exponent
incorrectly. Matthew did not enclose the common ratio in parentheses which caused him to make a sign error.
40. REASONING Write a sequence of numbers that form a pattern but are neither arithmetic nor geometric. Explain
the pattern.
SOLUTION: The sequence 1, 4, 9, 16, 25, 36, … has a pattern, because each number is a perfect square. However, there is no
common ratio which means it is not a geometric sequence. There is no common difference, which means it is not an
arithmetic sequence.
41. WRITING IN MATH How are graphs of geometric sequences and exponential functions similar? different?
SOLUTION: eSolutions
Manual
- Powered
by Cognero
Sample
answer:
When
graphed,
the terms of a geometric sequence lie on a curve that can be represented by Page
an 16
exponential function. They are different in that the domain of a geometric sequence is the set of natural numbers,
while the domain of an exponential function is all real numbers. Thus,
SOLUTION: The sequence 1, 4, 9, 16, 25, 36, … has a pattern, because each number is a perfect square. However, there is no
common ratio
which means
it is not a geometric
sequence. There is no common difference, which means it is not an
7-7 Geometric
Sequences
as Exponential
Functions
arithmetic sequence.
41. WRITING IN MATH How are graphs of geometric sequences and exponential functions similar? different?
SOLUTION: Sample answer: When graphed, the terms of a geometric sequence lie on a curve that can be represented by an
exponential function. They are different in that the domain of a geometric sequence is the set of natural numbers,
while the domain of an exponential function is all real numbers. Thus,
geometric sequences are discrete, while exponential functions are continuous.
For example, the geometric sequence 1, 2, 4, 8, ... has a = 1, r = 2, and the nth term given by an = 1(2)n–1,
where n is any positive integer. The graph of the function an = 1(2)n–1 would be as follows.
The exponential function given by y = 1(2)x–1will generate similar values but the domain of x is all real numbers.
The graph of this function is below.
Even though, the two graphs contain many of the same points, the graph of the geometric sequence is discrete
while the graph of the exponential function is continuous.
42. WRITING IN MATH Summarize how to find a specific term of a geometric sequence.
SOLUTION: Sample answer: First, find the common ratio. Then, use the formula a n = a 1 • r
n−1
. Substitute the first term of the
sequence for a 1 and the common ratio for r. Let n be equal to the number of the term you are finding. Then, solve
the equation.
eSolutions
- Powered
by Cognero
the eleventh
term
of the
43. FindManual
A 1024
B 3072
sequence 3, −6, 12, −24, …
Page 17
SOLUTION: Sample answer: First, find the common ratio. Then, use the formula a n = a 1 • r
n−1
. Substitute the first term of the
sequence forSequences
a 1 and the as
common
ratio forFunctions
r. Let n be equal to the number of the term you are finding. Then, solve
7-7 Geometric
Exponential
the equation.
43. Find the eleventh term of the sequence 3, −6, 12, −24, …
A 1024
B 3072
C 33
D −6144
SOLUTION: Calculate the common ratio.
The common ratio is –2.
The eleventh term of the sequence is 3072. Choice B is the correct answer.
44. What is the total amount of the investment shown in the table below if interest is compounded monthly?
F $613.56
G $616.00
H $616.56
J $718.75
SOLUTION: Use the equation for compound interest, with P = 500, r = 0.0525, n = 12, and t = 4.
The total amount of the investment is about $616.56. Choice H is the correct answer.
45. SHORT RESPONSE Gloria has $6.50 in quarters and dimes. If she has 35 coins in total, how many of each coin
does she have?
SOLUTION: Let q = the number of quarters and let d = the number of dimes. Then, q + d = 35 and 0.25q + 0.10d = 6.50.
Solve the first equation for d.
Substitute 35 – q for d in the second equation and solve for q.
eSolutions Manual - Powered by Cognero
Page 18
7-7 Geometric Sequences as Exponential Functions
The total amount of the investment is about $616.56. Choice H is the correct answer.
45. SHORT RESPONSE Gloria has $6.50 in quarters and dimes. If she has 35 coins in total, how many of each coin
does she have?
SOLUTION: Let q = the number of quarters and let d = the number of dimes. Then, q + d = 35 and 0.25q + 0.10d = 6.50.
Solve the first equation for d.
Substitute 35 – q for d in the second equation and solve for q.
Use the value of q and either equation to find the value of d.
Gloria has 15 dimes and 20 quarters.
x
46. What are the domain and range of the function y = 4(3 ) – 2?
A D = {all real numbers}, R = {y | y > –2}
B D = {all real numbers}, R = {y | y > 0}
C D = {all integers}, R = {y | y > –2}
D D = {all integers}, R = {y | y > 0}
SOLUTION: Use a graphing calculator to graph the function Y1= 4(3x) – 2.
The graph is continuous from left to right and increases from –2 to infinity.Thus, the domain is all real numbers and
the range is all real numbers greater than –2. Therefore, the correct choice is A.
Find the next three terms in each geometric sequence.
47. 2, 6, 18, 54, …
SOLUTION: Calculate the common ratio.
eSolutions Manual - Powered by Cognero
The common ratio is 3. Multiply each term by the common ratio to find the next three terms.
54 × 3 = 162
Page 19
The graph isSequences
continuous as
from
left to right Functions
and increases from –2 to infinity.Thus, the domain is all real numbers and
7-7 Geometric
Exponential
the range is all real numbers greater than –2. Therefore, the correct choice is A.
Find the next three terms in each geometric sequence.
47. 2, 6, 18, 54, …
SOLUTION: Calculate the common ratio.
The common ratio is 3. Multiply each term by the common ratio to find the next three terms.
54 × 3 = 162
162 × 3 = 486
486 × 3 = 1458
The next three terms of the sequence are 162, 486, and 1458
48. −5, −10, −20, −40, …
SOLUTION: Calculate the common ratio.
The common ratio is 2. Multiply each term by the common ratio to find the next three terms.
–40 × 2 = –80
–80 × 2 = –160
–160 × 2 = –320
The next three terms of the sequence are −80, −160, and −320.
49. SOLUTION: Calculate the common ratio.
The common ratio is
× = × = × . Multiply each term by the common ratio to find the next three terms.
= The next three terms of the sequence are
,
, and
.
50. −3, 1.5, −0.75, 0.375, …
eSolutions
Manual - Powered by Cognero
SOLUTION: Calculate the common ratio.
Page 20
× = 7-7 Geometric
Sequences
The next three
terms of as
theExponential
sequence areFunctions
,
, and
.
50. −3, 1.5, −0.75, 0.375, …
SOLUTION: Calculate the common ratio.
The common ratio is –0.5. Multiply each term by the common ratio to find the next three terms.
0.375 × –0.5 = –0.1875
–0.1875 × –0.5 = 0.09375
0.09375 × –0.5 = –0.046875
The next three terms of the sequence are −0.1875, 0.09375, and −0.046875.
51. 1, 0.6, 0.36, 0.216, …
SOLUTION: Calculate the common ratio.
The common ratio is 0.6. Multiply each term by the common ratio to find the next three terms.
0.216 × 0.6 = 0.1296
0.1296 × 0.6 = 0.7776
0.7776 × 0.6 = 0.046656
The next three terms of the sequence are 0.1296, 0.07776, and 0.046656.
52. 4, 6, 9, 13.5, …
SOLUTION: Calculate the common ratio.
The common ratio is 1.5. Multiply each term by the common ratio to find the next three terms.
13.5 × 1.5 = 20.25
20.25 × 1.5 = 30.375
30.375 × 1.5 = 45.5625
The next three terms of the sequence are 20.25, 30.375, and 45.5625.
Graph each function. Find the y-intercept and state the domain and range.
53. SOLUTION: x
y
–2
11
–1
–1
eSolutions Manual - Powered by Cognero
0
Page 21
–4
The common ratio is 1.5. Multiply each term by the common ratio to find the next three terms.
13.5 × 1.5 = 20.25
20.25 × 1.5 = 30.375
7-7 Geometric
Sequences as Exponential Functions
30.375 × 1.5 = 45.5625
The next three terms of the sequence are 20.25, 30.375, and 45.5625.
Graph each function. Find the y-intercept and state the domain and range.
53. SOLUTION: x
y
–2
11
–1
–1
0
–4
1
2
The function crosses the y-axis at –4. The domain is all real numbers, and the range is all real numbers greater than
–5.
x
54. y = 2(4)
SOLUTION: x
x
(4)
–2
–1
–2
(4)
–1
(4)
y
=
=
0
(4) = 1
0
2
1
(4) = 4
1
8
2
(4) = 16
2
32
eSolutions Manual - Powered by Cognero
Page 22
The function crosses the y-axis at –4. The domain is all real numbers, and the range is all real numbers greater than
7-7 Geometric
Sequences as Exponential Functions
–5.
x
54. y = 2(4)
SOLUTION: x
x
(4)
–2
–1
–2
(4)
–1
(4)
y
=
=
0
(4) = 1
0
2
1
(4) = 4
1
8
2
(4) = 16
2
32
The function crosses the y-axis at 2. The domain is all real numbers, and the range is all real numbers greater than 0.
55. SOLUTION: x
x
(3)
–2
–1
–2
(3)
–1
(3)
y
=
=
0
0
(3) = 1
1
(3) = 3
2
(3) = 9
1
2
eSolutions Manual - Powered by Cognero
The function crosses the y-axis at
0.
Page 23
. The domain is all real numbers, and the range is all real numbers greater than
7-7 Geometric Sequences as Exponential Functions
The function crosses the y-axis at 2. The domain is all real numbers, and the range is all real numbers greater than 0.
55. SOLUTION: x
x
(3)
–2
–1
–2
(3)
–1
(3)
y
=
=
0
0
(3) = 1
1
(3) = 3
2
(3) = 9
1
2
The function crosses the y-axis at
. The domain is all real numbers, and the range is all real numbers greater than
0.
56. LANDSCAPING A blue spruce grows an average of 6 inches per year. A hemlock grows an average of 4 inches
per year. If a blue spruce is 4 feet tall and a hemlock is 6 feet tall, write a system of equations to represent their
growth. Find and interpret the solution in the context of the situation.
SOLUTION: Let x = the number of years the tree grows and let y = the height of the tree after x years. So, y = 48 + 6x, and y =
72 + 4x.
Substitute 48 + 6x for y in the second equation.
Use the value for x and either equation to find the value for y.
The solution is (12, 120). This means that in 12 years the trees will be the same height, 120 inches or 10 feet.
Bank
57. MONEY
eSolutions
Manual City
- Powered
byrequires
Cognero
a minimum balance of $1500 to maintain free checking services. If Mr. Hayashi isPage 24
going to write checks for the amounts listed in the table, how much money should he start with in order to have free
checking?
7-7 Geometric Sequences as Exponential Functions
The solution is (12, 120). This means that in 12 years the trees will be the same height, 120 inches or 10 feet.
57. MONEY City Bank requires a minimum balance of $1500 to maintain free checking services. If Mr. Hayashi is
going to write checks for the amounts listed in the table, how much money should he start with in order to have free
checking?
SOLUTION: Let x = the amount Mr. Hayashi should start with in order to have free checking. Then, x – (1300 + 947) ≥ 1500.
Mr. Hayashi should start with at least $3747.
Write an equation in slope-intercept form of the line with the given slope and y-intercept.
58. slope: 4, y-intercept: 2
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So, y = 4x + 2.
59. slope: −3, y-intercept:
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So,
60. slope:
.
, y-intercept: −5
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So,
61. slope:
.
, y-intercept: −9
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So,
62. slope:
.
, y-intercept:
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So,
.
63. slope: −6, y-intercept: −7
eSolutions Manual - Powered by Cognero
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So, y = −6x − 7.
Page 25
SOLUTION: 7-7 Geometric
Sequences
Functions
The slope-intercept
formasofExponential
a line is y = mx
+ b, where m = the slope and b = the y-intercept. So,
.
63. slope: −6, y-intercept: −7
SOLUTION: The slope-intercept form of a line is y = mx + b, where m = the slope and b = the y-intercept. So, y = −6x − 7.
Simplify each expression. If not possible, write simplified.
64. 3u + 10u
SOLUTION: Since 3u and 10u are like terms, this expression can be simplified.
65. 5a – 2 + 6a
SOLUTION: Since 5a and 6a are like terms, the expression can be simplified.
2
66. 6m – 8m
SOLUTION: 2
6m and 8m are not like terms. Therefore, this expression is already simplified.
2
2
67. 4w + w + 15w
SOLUTION: 2
2
Since 4w and 15w are like terms, this expression can be simplified.
68. 13(5 + 4a)
SOLUTION: Since this expression has indicated multiplication, the Distributive Property can be used to simplify the expression.
69. (4t – 6)16
SOLUTION: Since this expression contains indicated multiplication, the Distributive Property can be used to simplify the
expression.
eSolutions Manual - Powered by Cognero
Page 26
SOLUTION: Since this expression has indicated multiplication, the Distributive Property can be used to simplify the expression.
7-7 Geometric Sequences as Exponential Functions
69. (4t – 6)16
SOLUTION: Since this expression contains indicated multiplication, the Distributive Property can be used to simplify the
expression.
eSolutions Manual - Powered by Cognero
Page 27