MasteringPhysics: Print View with Answers

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MasteringPhysics: Print View with Answers
10/19/15, 6:18 AM
Signed in as Andrew Bagley , Instructor
APPY2 (4th Period)
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College Physics: A Strategic Approach , 3e
Knight/Jones/Field
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Equations of State
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Equations of State
Due: 10:00am on Monday, October 19, 2015
You will receive no credit for items you complete after the assignment is due. Grading Policy
Problem 12.6
Description: An ideal gas is at T. (a) If we times the average kinetic energy of the gas atoms, what is the new
temperature in degree(s) C?
An ideal gas is at 50 ∘ C.
Part A
If we double the average kinetic energy of the gas atoms, what is the new temperature in ∘ C?
ANSWER:
T=
= 373
∘
C
Problem 12.7
Description: An ideal gas is at T. The gas is cooled, reducing the thermal energy by p%. (a) What is the new
temperature in degree(s) C?
An ideal gas is at 40 ∘ C. The gas is cooled, reducing the thermal energy by 30%.
Part A
What is the new temperature in ∘ C?
Express your answer using two significant figures.
ANSWER:
https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=4015016
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MasteringPhysics: Print View with Answers
10/19/15, 6:18 AM
= -54
T=
Also accepted:
∘
C
= -53.9,
= -54
Problem 12.8
Description: An ideal gas at 0 degree(s) C consists of 1.0 * 10^23 atoms. E of thermal energy are added to the gas.
(a) What is the new temperature in degree(s) C?
An ideal gas at 0∘ C consists of 1.0 × 1023 atoms. 12
J of thermal energy are added to the gas.
Part A
What is the new temperature in ∘ C?
Express your answer using two significant figures.
ANSWER:
T=
= 5.8
Also accepted:
∘
C
= 5.80,
= 5.8
Problem 12.9
Description: An ideal gas at 20 degree(s) C consists of 2.2 * 10^22 atoms. E of thermal energy are removed from
the gas. (a) What is the new temperature in degree(s) C?
An ideal gas at 20∘ C consists of 2.2 × 1022 atoms. 6.9
J of thermal energy are removed from the gas.
Part A
What is the new temperature in ∘ C?
Express your answer using two significant figures.
ANSWER:
https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=4015016
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MasteringPhysics: Print View with Answers
T=
10/19/15, 6:18 AM
= 4.8
∘
C
Also accepted:
= 4.85,
= 4.8
Problem 12.17
Description: nu of gas at a temperature of T degree(s) C fills a V container. (a) What is the gas pressure?
1.0
mol of gas at a temperature of -120 ∘ C fills a 2.7 L container.
Part A
What is the gas pressure?
Express your answer using two significant figures.
ANSWER:
P=
Also accepted:
= 4.6
atm
= 4.65,
= 4.6
Problem 12.18
Description: The lowest pressure ever obtained in a laboratory setting is 4.0 * 10^( - 11) Pa. (a) At this pressure,
how many molecules of air would there be in a T experimental chamber with a volume of V?
The lowest pressure ever obtained in a laboratory setting is 4.0 × 10−11
Pa.
Part A
At this pressure, how many molecules of air would there be in a 20 ∘ C experimental chamber with a volume of
0.020 m 3 ?
Express your answer using two significant figures.
ANSWER:
https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=4015016
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MasteringPhysics: Print View with Answers
N=
Also accepted:
10/19/15, 6:18 AM
= 2.0×108
= 1.98×108,
= 2.0×108
A message from your instructor...
This one is tougher. Try it for practice or an extra challenge! Your won't lose points for skipping or getting it wrong.
Problem 12.15
Description: nu of helium are in a V cylinder. The pressure gauge on the cylinder reads P. (a) What is the
temperature of the gas in degree(s)(C)? (b) What is the average kinetic energy of a helium atom?
7.9
mol of helium are in a 18 L cylinder. The pressure gauge on the cylinder reads 67 psi .
Part A
What is the temperature of the gas in ∘ C?
Express your answer using two significant figures.
ANSWER:
T=
= -120
Also accepted:
∘
C
= -119,
= -120
Part B
What is the average kinetic energy of a helium atom?
Express your answer to two significant figures and include the appropriate units.
ANSWER:
https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=4015016
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MasteringPhysics: Print View with Answers
10/19/15, 6:18 AM
= 3.2×10−21
E=
= 3.20×10−21
Also accepted:
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