POSITIVE DEGREE AND ARITHMETIC BIGNESS Huayi Chen Abstract. — We establish, for a generically big Hermitian line bundle, the convergence of truncated Harder-Narasimhan polygons and the uniform continuity of the limit. As applications, we prove a conjecture of Moriwaki asserting that the arithmetic volume function is actually a limit instead of a sup-limit, and we show how to compute the asymptotic polygon of a Hermitian line bundle, by using the arithmetic volume function. Contents 1. Introduction. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2. Notation and reminders. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3. Positive degree and number of effective elements. . . . . . . . . . . . . . . . 4. Asymptotic polygon of a big line bundle. . . . . . . . . . . . . . . . . . . . . . . . . 5. Volume function as a limit and arithmetic bigness. . . . . . . . . . . . . . . 6. Continuity of truncated asymptotic polygon. . . . . . . . . . . . . . . . . . . . . 7. Computation of asymptotic polygon by volume function. . . . . . . . . References. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 3 6 8 13 16 18 20 1. Introduction Let πΎ be a number field and πͺπΎ be its integer ring. Let π³ be a projective arithmetic variety of total dimension π over Spec πͺπΎ . For any Hermitian line bundle β on π³ , the arithmetic volume of β introduced by Moriwaki (see [20]) is ⊗π (1) βΜ0 (π³ , β ) ˆ vol(β) = lim sup , ππ /π! π→∞ huayi.chen@polytechnique.org. 2 HUAYI CHEN ⊗π where βΜ0 (π³ , β ) := log #{π ∈ π» 0 (π³ , β⊗π ) β£ ∀π : πΎ → β, β₯π β₯π,sup ≤ 1}. The ˆ Hermitian line bundle β is said to be arithmetically big if vol(β) > 0. The notion of arithmetic bigness had been firstly introduced by Moriwaki [19] §2 in a different form. Recently he himself ([20] Theorem 4.5) and Yuan ([25] Corollary 2.4) have proved that the arithmetic bigness in [19] is actually equivalent to the strict positivity of the arithmetic volume function (1). In [20], Moriwaki has proved the continuity of (1) with respect to β and then deduced some comparisons to arithmetic intersection numbers (loc. cit. Theorem 6.2). Note that the volume function (1) is an arithmetic analogue of the classical volume function for line bundles on a projective variety: if πΏ is a line bundle on a projective variety π of dimension π defined over a field π, the volume of πΏ is (2) vol(πΏ) := lim sup π→∞ rkπ π» 0 (π, πΏ⊗π ) . ππ /π! Similarly, πΏ is said to be big if vol(πΏ) > 0. After Fujita’s approximation theorem (see [13], and [23] for positive characteristic case), the sup-limit in (2) is in fact a limit (see [18] 11.4.7). During a presentation at Institut de Mathématiques de Jussieu, Moriwaki has ) ( conjectured that, in arithmetic case, the sequence βΜ0 (π³ , β)/ππ π≥1 also converges. In other words, one has actually ⊗π βΜ0 (π³ , β ) ˆ . = lim vol(β) π→∞ ππ /π! The strategy proposed by him is to develop an analogue of Fujita’s approximation theorem in arithmetic setting (see [20] Remark 5.7). In this article, we prove Moriwaki’s conjecture by establishing a convergence result of Harder-Narasimhan polygons (Theorem 4.2), which is a generalization of the author’s previous work [11] where the main tool was the Harder-Narasimhan filtration (indexed by β) of a Hermitian vector bundle on Spec πͺπΎ and its associated Borel measure. To apply the convergence of polygons, we shall compare βΜ0 (πΈ), defined as ˆ (πΈ), the logarithm of the number of effective points in πΈ, to the positive degree deg + which is the maximal value of the Harder-Narasimhan polygon of πΈ. Here πΈ denotes a Hermitian vector bundle on Spec πͺπΎ . We show that the arithmetic volume function coincides with the limit of normalized positive degrees and therefore prove the conjecture. In [20] and [25], the important (analytical) technic used by both authors is the estimation of the distortion function, which has already appeared in [1]. The approach in the present work, which is similar to that in [21], relies on purely algebraic arguments. We also establish an explicit link between the volume function and some geometric invariants of β such as asymptotic slopes, which permits us to prove that ⊗π β is big if and only if the norm of the smallest non-zero section of β decreases exponentially when π tends to infinity. This result is analogous to Theorem 4.5 of [20] or Corollary 2.4 (1)⇔(4) of [25] except that we avoid using analytical methods. POSITIVE DEGREE AND ARITHMETIC BIGNESS 3 In our approach, the arithmetic volume function can be interpreted as the limit of maximal values of Harder-Narasimhan polygons. Inspired by Moriwaki’s work [20], we shall establish the uniform continuity for limit of truncated Harder-Narasimhan polygons (Theorem 6.4). This result refines loc. cit. Theorem 5.4. Furthermore, we show that the asymptotic polygon can be calculated from the volume function of the Hermitian line bundle twisted by pull-backs of Hermitian line bundles on Spec πͺπΎ . Our method works also in function field case. It establishes an explicit link between the geometric volume function and some classical geometry such as semistability and Harder-Narasimhan filtration. This generalizes for example a work of Wolfe [24] (see also [12] Example 2.12) concerning volume function on ruled varieties over curves. Moreover, recent results in [7, 8, 2] show that at least in function field case, the asymptotic polygon is “differentiable” with respect to the line bundle, and there may be a “measure-valued intersection product” from which we recover arithmetic invariants by integration. The rest of this article is organized as follows. We fist recall some notation in Arakelov geometry in the second section. In the third section, we introduce the notion of positive degree for a Hermitian vector bundle on Spec πͺπΎ and we compare it to the logarithm of the number of effective elements. The main tool is the Riemann-Roch inequality on Spec πͺπΎ due to Gillet and Soulé [15]. In the fourth section, we establish the convergence of the measures associated to suitably filtered section algebra of a big line bundle (Theorem 4.2). We show in the fifth section that the arithmetic bigness of β implies the classical one of βπΎ . This gives an alternative proof for a result of Yuan [25]. By the convergence result in the fourth section, we are able to prove that the volume of β coincides with the limit of normalized positive degrees, and therefore the sup-limit in (1) is in fact a limit (Theorem 5.2). Here we also need the comparison result in the third section. Finally, we prove that the arithmetic bigness is equivalent to the positivity of asymptotic maximal slope (Theorem 5.4). In the sixth section, we establish the continuity of the limit of truncated polygons. Then we show in the seventh section how to compute the asymptotic polygon. Acknowledgement This work is inspired by a talk of Moriwaki at Institut de Mathématiques de Jussieu. I am grateful to him for pointing out to me that his results in [20] hold in continuous metric case as an easy consequence of Weierstrass-Stone theorem. I would like to thank J.-B. Bost for a stimulating suggestion and helpful comments, also for having found several errors in a previous version of this article. I am also grateful to R. Berman, S. Boucksom, A. Chambert-Loir, C. Mourougane and C. Soulé for discussions. Most of results in the present article are obtained and written during my visit at Institut des Hautes Études Scientifiques. I would like to thank the institute for hospitalities. 2. Notation and reminders Throughout this article, we fix a number field πΎ and denote by πͺπΎ its algebraic integer ring, and by ΔπΎ its discriminant. By (projective) arithmetic variety we mean an integral projective flat πͺπΎ -scheme. 4 HUAYI CHEN 2.1. Hermitian vector bundles. — If π³ is an arithmetic variety, one calls Hermitian vector bundle on π³ any pair β° = (β°, (β₯ ⋅ β₯π )π:πΎ→β ) where β° is a locally free πͺπ -module, and for any embedding π : πΎ → β, β₯ ⋅ β₯π is a continuous Hermitian norm on β°π,β . One requires in addition that the metrics (β₯ ⋅ β₯π )π:πΎ→β are invariant by the action of complex conjugation. The rank of β° is just that of β°. If rk β° = 1, one says that β° is a Hermitian line bundle. Note that Spec πͺπΎ is itself an arithmetic variety. A Hermitian vector bundle on Spec πͺπΎ is just a projective πͺπΎ -module equipped with Hermitian norms which are invariant under complex conjugation. For any real number π, denote by L π the Hermitian line bundle (3) L π := (πͺπΎ , (β₯ ⋅ β₯π,π )π:πΎ→β ), where β₯1β₯π,π = π−π , 1 being the unit of πͺπΎ . 2.2. Arakelov degree, slope and Harder-Narasimhan polygon. — Several invariants are naturally defined for Hermitian vector bundles on Spec πͺπΎ , notably the Arakelov degree, which leads to other arithmetic invariants (cf. [4]). If πΈ is a Hermitian vector bundle of rank π on Spec πͺπΎ , the Arakelov degree of πΈ is defined as the real number ( ) ( ) 1 ∑ ˆ deg(πΈ) log det β¨π π , π π β©π 1≤π,π≤π , := log # πΈ/(πͺπΎ π 1 + ⋅ ⋅ ⋅ + πͺπΎ π π ) − 2 π:πΎ→β π where (π π )1≤π≤π is an element in πΈ which forms a basis of πΈπΎ . This definition does not depend on the choice of (π π )1≤π≤π . If πΈ is non-zero, the slope of πΈ is defined to ˆ be the quotient π ˆ(πΈ) := deg(πΈ)/ rk πΈ. The maximal slope of πΈ is the maximal value of slopes of all non-zero Hermitian subbundles of πΈ. The minimal slope of πΈ is the minimal value of slopes of all non-zero Hermitian quotients of πΈ. We say that πΈ is semistable if π ˆ(πΈ) = π ˆmax (πΈ). Recall that the Harder-Narasimhan polygon ππΈ is by definition the concave function ˆ )), defined on [0, rk πΈ] whose graph is the convex hull of points of the form (rk πΉ, deg(πΉ where πΉ runs over all Hermitian subbundles of πΈ. By works of Stuhler [22] and Grayson [16], this polygon can be determined from the Harder-Narasimhan flag of πΈ, which is the only flag (4) πΈ = πΈ0 ⊃ πΈ1 ⊃ ⋅ ⋅ ⋅ ⊃ πΈπ = 0 such that the subquotients πΈ π /πΈ π+1 are all semistable, and verifies (5) π ˆ(πΈ 0 /πΈ 1 ) < π ˆ(πΈ 1 /πΈ 2 ) < ⋅ ⋅ ⋅ < π ˆ(πΈ π−1 /πΈ π ). ˆ π )). In fact, the vertices of ππΈ are just (rk πΈπ , deg(πΈ For details about Hermitian vector bundles on Spec πͺπΎ , see [4, 5, 10]. 2.3. Reminder on Borel measures. — Denote by πΆπ (β) the space of all continuous functions of compact support on β. Recall that a Borel measure on β is just a positive linear functional on πΆπ (β), where the word “positive” means that the linear functional sends a positive function to a positive number. One says that a sequence (ππ )π≥1 of Borel measures on β converges vaguely to the Borel measure π if, for any POSITIVE DEGREE AND ARITHMETIC BIGNESS 5 (∫ ) ∫ β ∈ πΆπ (β), the sequence of integrals β dππ π≥1 converges to β dπ. This is also equivalent to the convergence of integrals for any β in πΆ0∞ (β), the space of all smooth functions of compact support on β. Let π be a Borel∫ probability∫ measure on β. If π ∈ β, we denote by ππ π the Borel measure such ∫ that β∫dππ π = β(π₯ + π)π(dπ₯). If π > 0, let ππ π be the Borel measure such that β dππ π = β(ππ₯)π(dπ₯). If π is a Borel probability measure on β whose support is bounded from above, we denote by π (π) the Legendre transformation (see [17] II §2.2) of the function ∫ +∞ π₯ 7→ − π₯ π(]π¦, +∞[) dπ¦. It is a concave function on [0, 1[ which takes value 0 at the origin. If π is a linear combination of Dirac measures, then π (π) is a polygon (that is to say, concave and piecewise linear). An alternative definition of π (π) is, if ∫π‘ we denote by πΉπ∗ (π‘) = sup{π₯ β£ π(]π₯, +∞[) > π‘}, then π (π)(π‘) = 0 πΉπ∗ (π ) dπ . One has π (ππ π)(π‘) = π (π)(π‘) + ππ‘ and π (ππ π) = ππ (π). For details, see [11] §1.2.5. If π1 and π2 are two Borel probability measures on β, we use the symbol π1 β» π2 or π2 βΊ π1 to denote the following condition: ∫ ∫ for any increasing and bounded function β, β dπ1 ≥ β dπ2 . It defines an order on the set of all Borel probability measures on β. If in addition π1 and π2 are of support bounded from above, then π (π1 ) ≥ π (π2 ). 2.4. Filtered spaces. — Let π be a field and π be a vector space of finite rank over π. We call filtration of π any family β± = (β±π π )π∈β of subspaces of π subject to the following conditions 1) for all π, π ∈ β such that π ≤ π, one has β±π π ⊃ β±π π , 2) β±π π = 0 for π sufficiently positive, 3) β±π π = π for π sufficiently negative, 4) the function π 7→ rkπ (β±π π ) is left continuous. Such filtration corresponds to a flag π = π0 β π1 β π2 β ⋅ ⋅ ⋅ β ππ = 0 together with a strictly increasing real sequence (ππ )0≤π≤π−1 describing the points where the function π 7→ rkπ (β±π π ) is discontinuous. We define a function π : π → β ∪ {+∞} as follows: π(π₯) = sup{π ∈ β β£ π₯ ∈ β±π π }. This function actually takes values in {π0 , ⋅ ⋅ ⋅ , ππ−1 , +∞}, and is finite on π β {0}. If π is non-zero, the filtered space (π, β±) defines a Borel probability measure ππ which is a linear combination of Dirac measures: π−1 ∑ rk ππ − rk ππ+1 πΏππ . ππ = rk π π=0 Note that the support of ππ is just {π0 , ⋅ ⋅ ⋅ , ππ−1 }. We define πmin (π ) = π0 and πmax (π ) = ππ−1 . Denote by ππ the polygon π (ππ ). If π = 0, by convention we define ππ as the zero measure. 6 HUAYI CHEN /π / 0 is an exact sequence of filtered vector / π′ / π ′′ If 0 spaces, where π β= 0, then the following equality holds (cf. [11] Proposition 1.2.5): (6) ππ = rk π ′ rk π ′′ ππ ′ + ππ ′′ . rk π rk π If πΈ is a non-zero Hermitian vector bundle on Spec πͺπΎ , then the HarderNarasimhan flag (4) and the successive slope (5) defines a filtration of π = πΈπΎ , called the Harder-Narasimhan filtration. We denote by ππΈ the Borel measure associated to this filtration, called the measure associated to the Hermitian vector bundle πΈ. One has the following relations: (7) πmax (π ) = π ˆmax (πΈ), πmin (π ) = π ˆmin (πΈ), ππ = ππΈ = π (ππΈ ). For details about filtered spaces and their measures and polygons, see [11] §1.2. 2.5. Slope inequality and its measure form. — For any maximal ideal π of πͺπΎ , denote by πΎπ the completion of πΎ with respect to the π-adic valuation π£π on πΎ, and by β£ ⋅ β£π be the π-adic absolute value such that β£πβ£π = #(πͺπΎ /π)−π£π (π) . Let πΈ and πΉ be two Hermitian vector bundles on Spec πͺπΎ . Let π : πΈπΎ → πΉπΎ be a non-zero πΎ-linear homomorphism. For any maximal ideal π of πͺπΎ , let β₯πβ₯π be the norm of the linear mapping ππΎπ : πΈπΎπ → πΉπΎπ . Similarly, for any embedding π : πΎ → β, let β₯πβ₯π be the norm of ππ,β : πΈπ,β → πΉπ,β . The height of π is then defined as ∑ ∑ (8) β(π) := log β₯πβ₯π + log β₯πβ₯π . π π:πΎ→β Recall the slope inequality as follows (cf. [4] Proposition 4.3): ˆmax (πΉ ) + β(π). Proposition 2.1. — If π is injective, then π ˆmax (πΈ) ≤ π The following estimation generalizing [11] Corollary 2.2.6 is an application of the slope inequality. Proposition 2.2. — Assume π is injective. Let π = rk πΈ/ rk πΉ . Then one has ππΉ β» ππβ(π) ππΈ + (1 − π)πΏπˆmin (πΉ ) . Proof. — We equip πΈπΎ and πΉπΎ with Harder-Narasimhan filtrations. The slope inequality implies that π(π(π₯)) ≥ π(π₯) − β(π) for any π₯ ∈ πΈπΎ (see [11] Proposition 2.2.4). Let π be the image of π, equipped with induced filtration. By [11] Corollary 2.2.6, ππ β» πβ(π) ππΈ . By (6), ππΉ β» πππ + (1 − π)πΏπˆmin (πΉ ) , so the proposition is proved. 3. Positive degree and number of effective elements Let πΈ be a Hermitian vector bundle on Spec πͺπΎ . Define βΜ0 (πΈ) := log #{π ∈ πΈ β£ ∀π : πΎ → β, β₯π β₯π ≤ 1}, POSITIVE DEGREE AND ARITHMETIC BIGNESS 7 which is the logarithm of the number of effective elements in πΈ. Note that if / ′ /πΈ / ′′ / 0 is a short exact sequence of Hermitian vector 0 πΈ πΈ ′ ′′ ′ bundles, then βΜ0 (πΈ ) ≤ βΜ0 (πΈ). If in addition βΜ0 (πΈ ) = 0, then βΜ0 (πΈ ) = βΜ0 (πΈ). In this section, we define an invariant of πΈ, suggested by J.-B. Bost, which is called the positive degree: ˆ (πΈ) := max π (π‘). deg + πΈ π‘∈[0,1] ˆ (πΈ)/ rk πΈ. Using If πΈ is non-zero, define the positive slope of πΈ as π ˆ+ (πΈ) = deg + the Riemann-Roch inequality established by Gillet and Soulé [15], we shall compare ˆ (πΈ). βΜ0 (πΈ) to deg + 3.1. Reminder on dualizing bundle and Riemann-Roch inequality. — Denote by π πͺπΎ the arithmetic dualizing bundle on Spec πͺπΎ : it is a Hermitian line bundle on Spec πͺπΎ whose underlying πͺπΎ -module is ππͺπΎ := Homβ€ (πͺπΎ , β€). This πͺπΎ -module is generated by the trace map trπΎ/β : πΎ → β up to torsion. We choose Hermitian metrics on ππͺπΎ such that β₯trπΎ/β β₯π = 1 for any embedding π : πΎ → β. The arithmetic degree of π πͺπΎ is log β£ΔπΎ β£, where ΔπΎ is the discriminant of πΎ over β. We recall below a result in [15], which should be considered as an arithmetic analogue of classical Riemann-Roch formula for vector bundles on a smooth projective curve. Proposition 3.1 (Gillet and Soulé). — There exists an increasing function πΆ0 : β∗ → β+ satisfying πΆ0 (π) βͺπΎ π log π such that, for any Hermitian vector bundle πΈ on Spec πͺπΎ , one has 0 ˆ βΜ (πΈ) − βΜ0 (π πͺ ⊗ πΈ ∨ ) − deg(πΈ) ≤ πΆ0 (rk πΈ). (9) πΎ ˆ . — Proposition 3.3 below is a comparison 3.2. Comparison of βΜ0 and deg + 0 ˆ . The following lemma, which is consequences of the Riemannbetween βΜ and deg + Roch inequality (9), is needed for the proof. Lemma 3.2. — Let πΈ be a non-zero Hermitian vector bundle on Spec πͺπΎ . 1) If π ˆmax (πΈ) < 0, then βΜ0 (πΈ) = 0. ˆ ≤ πΆ0 (rk πΈ). 2) If π ˆmin (πΈ) > log β£ΔπΎ β£, then βΜ0 (πΈ) − deg(πΈ) 0 ˆ ≤ log β£ΔπΎ β£ rk πΈ + πΆ0 (rk πΈ). 3) If π ˆmin (πΈ) ≥ 0, then βΜ (πΈ) − deg(πΈ) Proof. — 1) Assume that πΈ has an effective section. There then exists a homomorphism π : L 0 → πΈ whose height is negative or zero. By slope inequality, we obtain π ˆmax (πΈ) ≥ 0. ∨ ∨ 2) Since π ˆmin (πΈ) > log β£ΔπΎ β£, we have π ˆmax (π πͺπΎ ⊗πΈ ) < 0. By 1), βΜ0 (π πͺπΎ ⊗πΈ ) = 0. Thus the desired inequality results from (9). 3) Let π = log β£ΔπΎ β£ + π with π > 0. Then π ˆmin (πΈ ⊗ L π ) > log β£ΔπΎ β£. By 2), ˆ ⊗ L π ) + πΆ0 (rk πΈ) = deg(πΈ) ˆ βΜ0 (πΈ ⊗ L π ) ≤ deg(πΈ + π rk πΈ + πΆ0 (rk πΈ). Since π > 0, ˆ βΜ0 (πΈ) ≤ βΜ0 (πΈ ⊗ L π ). So we obtain βΜ0 (πΈ) − deg(πΈ) ≤ π rk πΈ + πΆ0 (rk πΈ). Moreover, 8 HUAYI CHEN ∨ ˆ (9) implies βΜ0 (πΈ) − deg(πΈ) ≥ βΜ0 (π πͺπΎ ⊗ πΈ ) − πΆ0 (rk πΈ) ≥ −πΆ0 (rk πΈ). Therefore, we 0 ˆ ≤ π rk πΈ + πΆ0 (rk πΈ). Since π is arbitrary, we obtain the always have βΜ (πΈ) − deg(πΈ) desired inequality. Proposition 3.3. — The following inequality holds: 0 ˆ (πΈ) ≤ rk πΈ log β£ΔπΎ β£ + πΆ0 (rk πΈ). βΜ (πΈ) − deg (10) + Proof. — Let the Harder-Narasimhan flag of πΈ be as in (4). For any integer π such that 0 ≤ π ≤ π−1, let πΌπ = π ˆ(πΈ π /πΈ π+1 ). Let π be the first index in {0, ⋅ ⋅ ⋅ , π−1} such ˆ (πΈ) = deg(πΈ ˆ π ). that πΌπ ≥ 0; if such index does not exist, let π = π. By definition, deg + Note that, if π > 0, then π ˆmax (πΈ/πΈ π ) = πΌπ−1 < 0. Therefore we always have 0 0 β (πΈ/πΈ π ) = 0 and hence βΜ (πΈ) = βΜ0 (πΈ π ). ˆ (πΈ). Otherwise π If π = π, then βΜ0 (πΈ π ) = 0 = deg ˆmin (πΈ π ) = πΌπ ≥ 0 and by + Lemma 3.2 3), we obtain 0 ˆ (πΈ) = βΜ0 (πΈ π ) − deg(πΈ ˆ π ) βΜ (πΈ) − deg + ≤ rk πΈπ log β£ΔπΎ β£ + πΆ0 (rk πΈπ ) ≤ rk πΈ log β£ΔπΎ β£ + πΆ0 (rk πΈ). 4. Asymptotic polygon of a big line bundle ⊕ Let π be a field and π΅ = π≥0 π΅π be an integral graded π-algebra such that, for π sufficiently positive, π΅π is non-zero and has finite rank. Let π : β∗ → β+ be a mapping such that lim π (π)/π = 0. Assume that each vector space π΅π is equipped π→∞ with an β-filtration β± (π) such that π΅ is π -quasi-filtered (cf. [11] §3.2.1). In other words, we assume that there exists π0 ∈ β∗ such that, for any integer π ≥ 2 and all homogeneous elements π₯1 , ⋅ ⋅ ⋅ , π₯π in π΅ respectively of degree π1 , ⋅ ⋅ ⋅ , ππ in β≥π0 , one has π ( ) ∑ π(π₯1 ⋅ ⋅ ⋅ π₯π ) ≥ π(π₯π ) − π (ππ ) . π=1 We suppose in addition that supπ≥1 πmax (π΅π )/π < +∞. Recall below some results in [11] (Proposition 3.2.4 and Theorem 3.4.3). Proposition 4.1. — 1) The sequence (πmax (π΅π )/π)π≥1 converges in β. 2) If π΅ is finitely generated, then the sequence of measures (π π1 ππ΅π )π≥1 converges vaguely to a Borel probability measure on β. In this section, we shall generalize the second assertion of Proposition 4.1 to the case where the algebra π΅ is given by global sections of tensor power of a big line bundle on a projective variety. POSITIVE DEGREE AND ARITHMETIC BIGNESS 9 4.1. Convergence of measures. — Let π be an integral projective scheme of dimension π defined over π and πΏ be a big invertible πͺπ -module: recall that an invertible πͺπ -module πΏ is said to be big if its volume, defined as vol(πΏ) := lim sup π→∞ rkπ π» 0 (π, πΏ⊗π ) , ππ /π! is strictly positive. ⊕ 0 ⊗π Theorem 4.2. — With the above notation, if π΅ = ), then the π≥0 π» (π, πΏ sequence of measures (π π1 ππ΅π )π≥1 converges vaguely to a probability measure on β. Proof. — For any integer π ≥ 1, denote by ππ the measure π π1 ππ΅π . Since πΏ is big, for sufficiently positive π, π» 0 (π, πΏ⊗π ) β= 0, and hence ππ is a probability measure. In addition, Proposition 4.1 1) implies that the supports of the measures ππ are uniformly bounded from above. After Fujita’s approximation theorem (cf. [13, 23], see also [18] Ch. 11), the volume function vol(πΏ) is in fact a limit: rkπ π» 0 (π, πΏ⊗π ) . π→∞ ππ /π! Furthermore, for any real number π, 0 < π < 1, there exists ⊕ an integer π ≥ 1 together with a finitely generated sub-π-algebra π΄π of π΅ (π) = π≥0 π΅ππ which is generated by elements in π΅π and such that vol(πΏ) = lim rk(π΅ππ ) − rk(π΄ππ ) ≤ π. π→∞ rk(π΅ππ ) lim The graded π-algebra π΄π , equipped with induced filtrations, is π -quasi-filtered. Therefore Proposition 4.1 2) is valid for π΄π . In other words, If we denote by πππ the Borel π 1 ππ΄π = π 1 (π 1 ππ΄π ), then the sequence of measures (π )π≥1 converges measure π ππ π π π π π π vaguely to a Borel probability measure ) β. In particular, for any function ( ∫ π on β dπππ π≥1 is a Cauchy sequence. This asβ ∈ πΆπ (β), the sequence of integrals sertion is also true when β is a continuous function on β whose support is bounded from below: the supports of the measures πππ are uniformly bounded from above. The / π΄ππ / π΅ππ / π΅ππ /π΄ππ / 0 implies that exact sequence 0 ππ΅ππ = rk π΄ππ rk π΅ππ − rk π΄ππ ππ΄ππ + ππ΅ππ /π΄ππ . rk π΅ππ rk π΅ππ Therefore, for any bounded Borel function β, one has ∫ ∫ rk π΄ππ rk π΅ππ − rk π΄ππ β dπππ ≤ β₯ββ₯sup . (11) β dπππ − rk π΅ππ rk π΅ππ Hence, for any bounded continuous function β satisfying inf(supp(β)) > −∞, there exists πβ,π ∈ β such that, for any π, π ≥ πβ,π , ∫ ∫ (12) β dπππ − β dπππ ≤ 2πβ₯ββ₯sup + π. Let β be a smooth function on β whose support is compact. We choose two increasing continuous functions β1 and β2 such that β = β1 −β2 and that the supports 10 HUAYI CHEN of them are bounded from below. Let π0 ∈ β∗ be sufficiently large such that, for any π ∈ {π0 π + 1, ⋅ ⋅ ⋅ , π0 π + π − 1}, one has π» 0 (π, πΏ⊗π ) β= 0. We choose, for such π, a nonzero element ππ ∈ π» 0 (π, πΏ⊗π ). For any π ∈ β and any π ∈ {π0 π + 1, ⋅ ⋅ ⋅ , π0 π + π − 1}, ′ let ππ,π = ππ π΅ππ ⊂ π΅ππ+π , ππ,π = π2π0 π+π−π ππ,π ⊂ π΅(π+2π0 +1)π and denote by ′ ′ 1 ππ 1 ππ ′ ππ,π = π ππ , π = π , where ππ,π and ππ,π are equipped with the π,π π,π π,π ππ induced filtrations. As the algebra π΅ is π -quasi-filtered, we obtain, by [11] Lemma ′ 1.2.6, ππ,π β» πππ,π ππ,π β» πππ,π πππ , where π(ππ ) − π (ππ) − π (π) π(π2π0 π+π−π ) − π (ππ + π) − π (2π0 π + π − π) , ππ,π = ππ,π + . ππ ππ This implies ∫ ∫ ∫ ′ (13) βπ dππ,π ≥ βπ dπππ,π ππ,π ≥ βπ dπππ,π πππ , π = 1, 2. ππ,π = In particular, ∫ ∫ ∫ ∫ ′ (14) βπ dπππ,π ππ,π − βπ dπππ,π πππ ≤ βπ dππ,π − βπ dπππ,π πππ As lim π→∞ (15) rk π΅(π+2π0 +1)π − rk π΅ππ = 0, rk π΅(π+2π0 +1)π ∫ ∫ ′ lim βπ dππ,π − βπ dπ(π+2π0 +1)π = 0. π→∞ Moreover, lim ππ,π = 0. By [11] Lemma 1.2.10, we obtain π→∞ ∫ ∫ (16) lim βπ dπππ,π πππ − βπ dπππ = 0. π→∞ We deduce, from (12), (15) and (16), ∫ ∫ ′ lim sup βπ dππ,π − βπ dπππ,π πππ π→∞ ∫ (17) ∫ = lim sup βπ dπ(π+2π0 +1)π − βπ dπππ ≤ 2πβ₯βπ β₯sup + π. π→∞ By (14), ∫ ∫ lim sup βπ dπππ,π ππ,π − βπ dπππ,π πππ ≤ 2πβ₯βπ β₯sup + π. (18) π→∞ Note that lim π→∞ rk π΅ππ+π − rk π΅ππ = lim ππ,π = 0. π→∞ rk π΅ππ+π So ∫ ∫ ∫ ∫ lim βπ dππ,π − βπ dπππ+π = lim βπ dππ,π − βπ dπππ,π ππ,π = 0. π→∞ π→∞ Hence, by (16) and (18), we have ∫ ∫ lim sup β dπππ+π − β dπππ ≤ 2π(β₯β1 β₯sup + β₯β2 β₯sup ) + 2π. π→∞ 11 POSITIVE DEGREE AND ARITHMETIC BIGNESS ′ According to (12), we obtain that there exists πβ,π ∈ β∗ such that, for all integers π ′ ′ ′ ′ and π such that π ≥ πβ,π , π ≥ πβ,π , one has ∫ ∫ β dπ − β dππ′ ≤ 4π(β₯β1 β₯sup + β₯β2 β₯sup ) + 2πβ₯ββ₯sup + 6π, π ∫ which implies that the sequence ( β dππ )π≥1 converges in β. Let πΌ : πΆ0∞ (β) ∫ → β be the linear functional defined by πΌ(β) = lim π→∞ β dππ . It extends in a unique way to a continuous linear functional on πΆπ (β). Furthermore, it is positive, and so defines a Borel measure π on β. Finally, by (11), β£π(β) − (1 − π)π π (β)β£ ≤ π. Since π is arbitrary, π is a probability measure. 4.2. Convergence of maximal values of polygons. — If π is a Borel probability measure on β and πΌ ∈ β, denote by π (πΌ) the Borel probability measure on β such that, for any β ∈ πΆπ (β), ∫ ∫ β dπ (πΌ) = β(π₯)11[πΌ,+∞[ (π₯)π(ππ₯) + β(πΌ)π(] − ∞, πΌ[). The measure π (πΌ) is called the truncation of π at πΌ. The truncation operator preserves the order “β»”. Assume that the support of π is bounded from above. The truncation of π at πΌ modifies the “polygon” π (π) only on the part with derivative < πΌ. More precisely, one has π (π) = π (π (πΌ) ) on {π‘ ∈ [0, 1[ πΉπ∗ (π‘) ≥ πΌ}. In particular, if πΌ ≤ 0, then (19) max π (π)(π‘) = max π (π (πΌ) )(π‘). π‘∈[0,1[ π‘∈[0,1[ The following proposition shows that given a vague convergence sequence of Borel probability measures, almost all truncations preserve vague limit. Proposition 4.3. — Let (ππ )π≥1 be a sequence of Borel probability measures which converges vaguely to a Borel probability measure π. Then, for any πΌ ∈ β, the sequence (πΌ) (ππ )π≥1 converges vaguely to π (πΌ) . Proof. — For any π₯ ∈ β and πΌ ∈ β, write π₯∨πΌ := max{π₯, πΌ}. Assume that β ∈ πΆπ (β) and π is a Borel probability measure. Then ∫ ∫ β(π₯)π (πΌ) (dπ₯) = β(π₯ ∨ πΌ)π(dπ₯). By [9] IV §5 nβ 12 Proposition 22, for any πΌ ∈ β, ∫ ∫ ∫ ∫ lim β(π₯)ππ(πΌ) (dπ₯) = lim β(π₯ ∨ πΌ)ππ (dπ₯) = β(π₯ ∨ πΌ)π(dπ₯) = β(π₯)π (πΌ) (dπ₯). π→∞ π→∞ Therefore, the proposition is proved. 12 HUAYI CHEN Corollary 4.4. — Under the assumption of Theorem 4.2, the sequence ( ) max ππ΅π (π‘)/π π≥1 π‘∈[0,1] converges in β. Proof. — For π ∈ β∗ , denote by ππ = π π1 ππ΅π . By Theorem 4.2, the sequence (ππ )π≥1 converges vaguely to a Borel probability measure π. Let πΌ < 0 be a number such that (πΌ) (ππ )π≥1 converges vaguely to π (πΌ) . Note that the supports of πππΌ are uniformly (πΌ) bounded. So π (ππ ) converges uniformly to π (π (πΌ) ) (see [11] Proposition 1.2.9). By ( ) (19), max ππ΅π (π‘)/π π≥1 converges to max π (π)(π‘). π‘∈[0,1] π‘∈[0,1] If π is a finite dimensional filtered vector space over π, we shall use the expression π+ (π ) to denote max ππ (π‘). With this notation, the assertion of Corollary 4.4 π‘∈[0,1] becomes: lim π+ (π΅π )/π exists in β. π→∞ Lemma 4.5. — Assume that π1 and π2 are two Borel probability measures whose supports are bounded from above. Let π ∈]0, 1[ and π = ππ1 + (1 − π)π2 . Then max π (π)(π‘) ≥ π max π (π1 )(π‘). (20) π‘∈[0,1] π‘∈[0,1] Proof. — After truncation at 0 we may assume that the supports of π1 and π2 are contained in [0, +∞[. In this case π β» ππ1 + (1 − π)πΏ0 and hence π (π) ≥ π (ππ1 + (1 − π)πΏ0 ). Since { ππ (π1 )(π‘/π), π‘ ∈ [0, π], π (ππ1 + (1 − π)πΏ0 )(π‘) = ππ (π1 )(1), π‘ ∈ [π, 1[, we obtain (20). Theorem 4.6. — Under the assumption of Theorem 4.2, one has lim π+ (π΅π )/π > 0 π→∞ if and only if lim πmax (π΅π )/π > 0. π→∞ Furthermore, in this case, the inequality lim π+ (π΅π )/π ≤ lim πmax (π΅π )/π holds. π→∞ π→∞ Proof. — For any filtered vector space π , πmax (π ) > 0 if and only if π+ (π ) > 0, and in this case one always has πmax (π ) ≥ π+ (π ). Therefore the second assertion is true. Furthermore, this also implies 1 1 lim π+ (π΅π ) > 0 =⇒ lim πmax (π΅π ) > 0. π→∞ π π→∞ π It suffices then to prove the converse implication. Assume that πΌ > 0 is a real number such that lim πmax (π΅π )/π > 4πΌ. Choose sufficiently large π0 ∈ β such that π→∞ π (π) < πΌπ for any π ≥ π0 and such that there exists a non-zero π₯0 ∈ π΅π0 satisfying π(π₯0 ) ≥ 4πΌπ0 . Since the algebra π΅ is π -quasi-filtered, π(π₯π 0 ) ≥ 4πΌπ0 π − ππ (π) ≥ 3πΌππ0 . By Fujita’s approximation theorem, there exists an integer π divisible by π0 ⊕ and a subalgebra π΄ of π΅ (π) = π≥0 π΅ππ generated by a finite number of elements in π΅π and such that lim inf rk π΄π / rk π΅ππ > 0. By possible enlargement of π΄ we π→∞ POSITIVE DEGREE AND ARITHMETIC BIGNESS π/π0 may assume that π΄ contains π₯0 13 . By Lemma 4.5, lim π+ (π΄π )/π > 0 implies π→∞ lim π+ (π΅ππ )/ππ = lim π+ (π΅π )/π > 0. Therefore, we reduce our problem to the π→∞ case where π→∞ 1) π΅ is an algebra of finite type generated by π΅1 , 2) there exists π₯1 ∈ π΅1 , π₯1 β= 0 such that π(π₯1 ) ≥ 3πΌ with πΌ > 0, 3) π (π) < πΌπ. Furthermore, by Noether’s normalization theorem, we may assume that π΅ = π[π₯1 , ⋅ ⋅ ⋅ , π₯π ] is an algebra of polynomials, where π₯1 coincides with the element in condition 2). Note that π(π₯π1 1 ⋅ ⋅ ⋅ π₯ππ π ) ≥ (21) π ∑ π=1 π ∑ ( ) ( ) ππ π(π₯π ) − πΌ ≥ 2πΌπ1 + ππ π(π₯π ) − πΌ . π=2 Let π½ > 0 such that −π½ ≤ π(π₯π ) − πΌ for any π ∈ {2, ⋅ ⋅ ⋅ , π}. We obtain from (21) that π π½ ∑π ∗ π(π₯π1 1 ⋅ ⋅ ⋅ π₯π π ) ≥ πΌπ1 as soon as π1 ≥ πΌ π=2 ππ . For π ∈ β , let } { π½ π’π = # (π1 , ⋅ ⋅ ⋅ , ππ ) ∈ βπ π1 + ⋅ ⋅ ⋅ + ππ = π, π1 ≥ (π2 + ⋅ ⋅ ⋅ + ππ ) πΌ { } π½ = # (π1 , ⋅ ⋅ ⋅ , ππ ) ∈ βπ π1 + ⋅ ⋅ ⋅ + ππ = π, π1 ≥ π πΌ+π½ ( ) π½ π − ⌊ πΌ+π½ π⌋ + π − 1 = , π−1 and } { π£π = # (π1 , ⋅ ⋅ ⋅ , ππ ) ∈ βπ π1 + ⋅ ⋅ ⋅ + ππ = π = Thus lim π’π /π£π = π→∞ ( ( ) π+π−1 . π−1 πΌ )π−1 1 > 0, which implies lim π+ (π΅π ) > 0 by Lemma π→∞ π πΌ+π½ 4.5. 5. Volume function as a limit and arithmetic bigness Let π³ be an arithmetic variety of dimension π and β be a Hermitian line bundle on π³ . Denote by π = π³πΎ and πΏ = βπΎ . Using the convergence result established in the previous section, we shall prove that the volume function is in fact a limit of normalized positive degrees. We also give a criterion of arithmetic bigness by the positivity of asymptotic maximal slope. 5.1. Volume function and asymptotic positive degree. — For any π ∈ β, ⊗π we choose a Hermitian vector bundle π∗ (β ) = (π∗ (β⊗π ), (β₯ ⋅ β₯π )π:πΎ→β ) whose underlying πͺπΎ -module is π∗ (β⊗π ) and such that (22) max log β₯π β₯sup − log β₯π β₯π βͺ log π, π > 1. ⊗π 0β=π ∈π∗ (β ) 14 HUAYI CHEN Denote by ππ the rank of π∗ (β⊗π ). One has ππ βͺ ππ−1 . For any π ∈ β, define ⊗π βΜ0 (π³ , β ) := log #{π ∈ π» 0 (π³ , β⊗π ) β£ ∀π : πΎ → β, β₯π β₯π,sup ≤ 1}. Recall that the arithmetic volume function of β defined by Moriwaki (cf. [20]) is ⊗π βΜ0 (π³ , β ) ˆ vol(β) := lim sup , ππ /π! π→∞ ˆ > 0 (cf. [20] Theorem 4.5 and [25] and β is said to be big if and only if vol(β) Corollary 2.4). We emphasize that this definition does not depend on the Hermitian metrics on π∗ (β⊗π ) satisfying the condition (22). In the following, we give an alternative proof of a result of Morkwaki and Yuan. Proposition 5.1. — If β is big, then πΏ is big on π in usual sense. (1) Proof. — For any integer π ≥ 1, we choose two Hermitian vector bundles πΈ π ⊗π (π∗ (β ), (β₯ ⋅ (1) β₯π )π:πΎ→β ) and (2) πΈπ = (π∗ (β ⊗π ), (β₯ ⋅ (2) β₯π )π:πΎ→β ) = such that (2) (1) β₯π β₯(1) π ≤ β₯π β₯π,sup ≤ β₯π β₯π ≤ ππ β₯π β₯π , where ππ is the rank of π∗ (β⊗π ). This is always possible due to an argument of John and Löwner ellipsoid, see [14] definition-theorem 2.4. Thus (2) ⊗π (1) βΜ0 (πΈ π ) ≤ βΜ0 (π³ , β ) ≤ βΜ0 (πΈ π ). (1) ˆ (πΈ (2) ) ≤ ππ log ππ . By (10), Furthermore, by [11] Corollary 2.2.9, ˆ deg+ (πΈ π ) − deg + π we obtain 0 βΜ (π³ , β⊗π ) − βΜ0 (πΈ (1) π ) ≤ 2ππ log β£ΔπΎ β£ + 2πΆ0 (ππ ) + ππ log ππ . (1) ˆ (π∗ (β⊗π )) = π(ππ log ππ ). Hence Furthermore, ˆ deg+ (πΈ π ) − deg + 0 βΜ (π³ , β⊗π ) − βΜ0 (π∗ (β⊗π )) = π(ππ log ππ ). Since ππ βͺ ππ−1 , we obtain 0 ˆ (π∗ (β⊗π )) βΜ (π³ , β⊗π ) deg + = 0, (23) lim − π→∞ ππ /π! ππ /π! ˆ (π∗ (β⊗π )) deg + ˆ ˆ = lim sup . If β is big, then vol(β) > 0, and and therefore vol(β) ππ /π! π→∞ hence π∗ (β⊗π ) β= 0 for π sufficiently positive. Combining with the fact that lim sup π→+∞ we obtain lim sup π→+∞ ⊗π ˆ (π∗ (β⊗π )) deg π ˆmax (π∗ (β )) + ≤ lim < +∞, π→+∞ πππ π ππ > 0. ππ−1 POSITIVE DEGREE AND ARITHMETIC BIGNESS 15 Theorem 5.2. — The following equalities hold: (24) ⊗π ⊗π ˆ (π∗ (β⊗π )) deg βΜ0 (π³ , β ) π ˆ+ (π∗ (β )) + ˆ = lim = lim = vol(πΏ) lim , vol(β) π→∞ π→∞ π→∞ ππ /π! ππ /π! π/π where the positive slope π ˆ+ was defined in §3. Proof. — We first consider the case where πΏ is big. The graded algebra π΅ = ⊕ 0 ⊗π ) equipped with Harder-Narasimhan filtrations is quasi-filtered for π≥0 π» (π, πΏ a function of logarithmic increasing speed at infinity (see [11] §4.1.3). Therefore Corollary 4.4 shows that the sequence (π+ (π΅π )/π)π≥1 converges in β. Note that ⊗π π+ (π΅π ) = π ˆ+ (π∗ (β )). So the last limit in (24) exists. Furthermore, πΏ is big on π, so ⊗π rk(π∗ (β )) , π→∞ ππ−1 /(π − 1)! vol(πΏ) = lim which implies the existence of the third limit in (24) and the last equality. Thus the existence of the first limit and the second equality follow from (23). When πΏ is not big, since π ˆ+ (π∗ (β π→∞ π/π lim ⊗π )) ⊗π π ˆmax (π∗ (β π→∞ π/π ≤ lim )) < +∞ the last term in (24) vanishes. This implies the vanishing of the second limit in (24). Also by (23), we obtain the vanishing of the first limit. Corollary 5.3. — The following relations hold: (25) ⊗π ˆ ∗ (β⊗π )) π(π∗ (β )) deg(π ˆ vol(β) ≥ lim sup = lim sup . ππ /π! ππ /π! π→∞ π→∞ Proof. — The inequality is a consequence of Theorem 5.2 and the comparison ˆ ˆ (πΈ) ≥ deg(πΈ). deg Here πΈ is an arbitrary Hermitian vector bundle on Spec πͺπΎ . + The equality follows from a classical result which compares Arakelov degree and Euler-Poincaré characteristic. 5.2. A criterion of arithmetic bigness. — We shall prove that the bigness of β is equivalent to the positivity of the asymptotic maximal slope of β. This result is strongly analogous to Theorem 4.5 of [20]. In fact, by a result of Borek [3] (see also [6] Proposition 3.3.1), which reformulate Minkowski’s First Theorem, the maximal slope of a Hermitian vector bundle on Spec πͺπΎ is “close” to the opposite of the logarithm of its first minimum. So the positivity of the asymptotic maximal slope is equivalent to the existence of (exponentially) small section when π goes to infinity. 16 HUAYI CHEN Theorem 5.4. — β is big if and only if lim π ˆmax (π∗ (β π→∞ the following inequality holds: ⊗π ))/π > 0. Furthermore, ⊗π ˆ vol(β) π ˆmax (π∗ (β )) ≤ lim . πvol(πΏ) π→∞ π Proof. —⊕ Since both conditions imply the bigness of πΏ, we may assume that πΏ is big. Let π΅ = π≥0 π» 0 (π, πΏ⊗π ) equipped with Harder-Narasimhan filtrations. One has ⊗π π ˆ+ (π∗ (β )) = π+ (π΅π ), π ˆmax (π∗ (β ⊗π ) = πmax (π΅π ). Therefore, the assertion follows from Theorems 4.6 and 5.2. Remark 5.5. — After [6] Proposition 3.3.1, for any non-zero Hermitian vector bundle πΈ on Spec πͺπΎ , one has 1 ∑ 1 1 log β£ΔπΎ β£ (26) ˆ πmax (πΈ) + log inf β₯π β₯2π ≤ log[πΎ : β] + log rk πΈ + . 0β=π ∈πΈ 2 2 2 2[πΎ : β] π:πΎ→β Therefore, by (26), the bigness of β is equivalent to each of the following conditions: 1) πΏ is big, and there exists π > 0 such that, when π is sufficiently large, β global section π π satisfying β₯π π β₯π,sup ≤ π−ππ for any π : πΎ → β. 2) πΏ is big, and there exists an integer π ≥ 1 such that β satisfying β₯π π β₯π,sup < 1 for any π : πΎ → β. ⊗π ⊗π has a has a global section π π Thus we recover a result of Moriwaki ([20] Theorem 4.5 (1)⇐⇒(2)). Corollary 5.6. — Assume πΏ is big. Then there exists a Hermitian line bundle π on Spec πͺπΎ such that β ⊗ π ∗ π is arithmetically big. 6. Continuity of truncated asymptotic polygon Let us keep the notation of §5 and assume that πΏ is big on π. For any integer π ≥ 1, denote by ππ the dilated measure π π1 ππ∗ (β⊗π ) . Recall that in §4 we have actually established the following result: Proposition 6.1. — 1) the sequence of Borel measures (ππ )π≥1 converges vaguely to a Borel probability measure π; 2) there exists a countable subset π of β such that, for any πΌ ∈ β β π, the sequence of (πΌ) polygons (π (ππ ))π≥1 converges uniformly to π (π (πΌ) ), which implies in particular (πΌ) that π (π ) is Lipschitz. (πΌ) Let π be as in the proposition above. For any πΌ ∈ β β π, denote by πβ concave function π (π definition: (πΌ) ) on [0, 1]. The following property of Proposition 6.2. — For any integer π ≥ 1, on has π (ππΌ) ⊗π β (πΌ) πβ (πΌ) = ππβ . the results from the 17 POSITIVE DEGREE AND ARITHMETIC BIGNESS (πΌ) Proof. — By definition π π1 ππ∗ (β⊗ππ ) = ππ ππ . Using (ππ ππ )(ππΌ) = ππ ππ , we obtain the desired equality. ˆ ⊗π ) = Remark 6.3. — We deduce from the previous proposition the equality vol(β ˆ ππ vol(β), which has been proved by Moriwaki ([20] Proposition 4.7). The main purpose of this section is to establish the following continuity result, which is a generalization of the continuity of the arithmetic volume function proved by Moriwaki (cf. [20] Theorem 5.4). line bundle on π³ . Then, for any πΌ ∈ β, Theorem 6.4. — Assume ( L is a Hermitian ) (ππΌ) (πΌ) the sequence of functions π1 π ⊗π converges uniformly to πβ . β ⊗L π≥1 Corollary 6.5 ([20] Theorem 5.4). — With the assumption of Theorem 6.4, one has 1 ˆ ⊗π ˆ lim vol(β ⊗ L ) = vol(β). π→∞ ππ In order to prove Theorem 6.4, we need the following lemma. Lemma 6.6. — Let L be an arbitrary Hermitian line bundle on Spec πͺπΎ . If β is ⊗π arithmetically big, then there exists an integer π ≥ 1 such that β ⊗ L is arithmetically big and has at least one non-zero effective global section, that is, a non-zero section π ∈ π» 0 (π³ , β⊗π ⊗ L ) such that β₯π β₯π,sup ≤ 1 for any embedding π : πΎ → β. Proof. — As β is arithmetically big, we obtain that πΏ is big on π. Therefore, there exists an integer π0 ≥ 1 such that πΏ⊗π0 ⊗ LπΎ is big on π and π∗ (β⊗π0 ⊗ L ) β= 0. Pick an arbitrary non-zero section π ∈ π» 0 (π³ , β⊗π0 ⊗L ) and let π = sup β₯π β₯π,sup . π:πΎ→β After Theorem 5.4 (see also Remark 5.5), there exists π1 ∈ β such that β⊗π1 has a section π ′ such that β₯π ′ β₯π,sup ≤ (2π )−1 for any π : πΎ → β. Let π = π0 + π1 . Then ⊗π ⊗π π ⊗ π ′ is a non-zero strictly effective section of β ⊗ L . Furthermore, β ⊗ L is arithmetically big since it is generically big and has a strictly effective section. Proof of Theorem 6.4. — After Corollary 5.6, we may assume that β is arithmetically ⊗π big. Let π ≥ 1 be an integer such that β ⊗ L is arithmetically big and has a nonzero effective section π 1 (cf. Lemma 6.6). For any integers π and π such that π > π, π ≥ 1, let ππ,π : π∗ (β⊗(π−π)π ) → π∗ (β⊗ππ ⊗ L ⊗π ) be the homomorphism defined by the multiplication by π ⊗π 1 . Since π 1 is effective, β(ππ,π ) ≤ 0. Let ππ,π = rk(π∗ (β⊗(π−π)π ))/ rk(π∗ (β⊗ππ ⊗ L ⊗π )). Note that lim ππ,π = vol(πΏ⊗(π−π) )/vol(πΏ⊗π ⊗ LπΎ ). π→∞ ⊗ππ ⊗π Denote by ππ this limit. Let ππ,π be the measure associated to π∗ (β ⊗ L ). ⊗π ⊗ππ Let ππ,π = π ˆmin (π∗ (β ⊗ L )). After Proposition 2.2, one has ππ,π β» 18 HUAYI CHEN ππ,π π(π−π)π π(π−π)π + (1 − ππ,π )πΏππ,π , or equivalently (27) 1 ππ,π β» ππ,π π(π−π)/π π(π−π)π + (1 − ππ,π )πΏπ π ππ . π,π /ππ As πΏ⊗π ⊗ LπΎ is big, the sequence of measures (π π1 ππ,π )π≥1 converges vaguely to a Borel probability measure ππ . By truncation and then by passing π → ∞, we obtain from (27) that, for any πΌ ∈ β, (π π1 ππ )(πΌ) β» ππ (π(π−π)/π π)(πΌ) + (1 − ππ )πΏπΌ , (28) (πΌ) where we have used the trivial estimation πΏπ β» πΏπΌ . ∨ Now we apply Lemma 6.6 on the dual Hermitian line bundle L and obtain that ∨ ⊗π there exists an integer π ≥ 1 and an effective section π 2 of β ⊗ L . Consider the homomorphism ππ,π : π∗ (β⊗ππ ⊗ L ⊗π ) → π∗ (β⊗(π+π)π ) induced by multiplication by π ⊗π 2 . Its height is negative. Let ππ,π = rk(π∗ (β⊗ππ ⊗ L ⊗π ))/ rk(π∗ (β⊗(π+π)π )). When π tends to infinity, ππ,π converges to ππ := vol(πΏ⊗π ⊗ LπΎ )/vol(πΏ⊗(π+π) ). By a similar argument as above, we obtain that, for any πΌ ∈ β, (π(π+π)/π π)(πΌ) β» ππ (π π1 ππ )(πΌ) + (1 − ππ )πΏπΌ . (29) We obtain from (28) and (29) the following estimations of polygons (30) (31) (πΌ) π−1 )(ππ π‘) ≥ π ((π π1 ππ )(πΌ) )(π‘) π π ((π(π+π)/π π) { ππ π ((π(π−π)/π π)(πΌ) )(π‘/ππ ), 0 ≤ π‘ ≤ ππ , π ((π π1 ππ )(πΌ) )(π‘) ≥ . ππ π ((π(π−π)/π π)(πΌ) )(1) + πΌ(π‘ − ππ ), ππ ≤ π‘ ≤ 1. Finally, since lim ππ = lim ππ = 1 (which is a consequence of the continuity of π→∞ π→∞ the geometric volume function), combined with the fact that both π(π−π)/π π and π(π+π)/π π converge vaguely to π when π → ∞, we obtain, for any πΌ ∈ β, the uniform convergence of π ((π π1 ππ )(πΌ) ) to π (π (πΌ) ). 7. Computation of asymptotic polygon by volume function In this section we shall show how to compute the asymptotic polygon of a Hermitian line bundle by using arithmetic volume function. Our main method is the Legendre transformation of concave functions. Let us begin with a lemma concerning Borel measures. Lemma 7.1. — Let π be a Borel measure on β whose support is bounded from below. Then ∫ (32) max π (π)(π‘) = π₯+ π(dπ₯), π‘∈[0,1[ where π₯+ stands for max{π₯, 0}. β 19 POSITIVE DEGREE AND ARITHMETIC BIGNESS Proof. — The function πΉπ∗ defined in §2.3 is essentially the inverse of the distribution function of π. In fact, one has πΉπ∗ (πΉπ (π₯)) = π₯ π-a.e.. Therefore, if π is a Borel measure of compact support, then ∫ ∫ 1 πΉπ (π‘) dπ‘ = π₯π(dπ₯). π (π)(1) := 0 Applying this equality on π = π β (0) , we obtain ∫ ∫ ∫ (0) (0) (0) max π (π)(π‘) = π (π )(1) = π₯π (dπ₯) = π₯+ π (dπ₯) = π₯+ π(dπ₯). π‘∈[0,1[ β β β Now let π³ be an arithmetic variety of total dimension π. For any Hermitian line bundle β on π³ whose generic fibre is big, we denote by πβ the vague limite of the sequence of measures (π π1 ππ∗ (β⊗π ) )π≥1 . The existence of πβ has been established in Theorem 4.2. Proposition 7.2. — Let πΏ = βπΎ . For any real number π, one has ∫ ˆ ⊗ π ∗ L −π ) vol(β , (π₯ − π)+ πβ (dπ₯) = πvol(πΏ) β where L −π is the Hermitian line bundle on Spec πͺπΎ defined in (3). Proof. — If π is a Hermitian line bundle on Spec πͺπΎ , one has the equality πβ⊗π∗ π = πdeg(π π . ˆ ) β Applying this equality on π = L −π , one obtains ∫ ˆ ⊗ π ∗ L −π ) ∫ vol(β = π₯+ π−π πβ (dπ₯) = (π₯ − π)+ πβ (dπ₯). πvol(πΏ) β β Remark 7.3. — Proposition 7.2 calculates actually the polygon π (πβ ). In fact, one has ∫ ∫ +∞ − πβ (]π¦, +∞[)dπ¦ = − (π − π)+ πβ (dπ ). π β Applying the Legendre transformation, we obtain the polygon π (πβ ). As an application, we prove that the asymptotic maximal slope of β is in fact the derivative at the origin of the concave curve π (πβ ), which is however not a formal consequence of the vague convergence of measures π π1 ππ∗ (β⊗π ) . Proposition 7.4. — Denote by π ˆπmax (β) the limite of (ˆ πmax (β has ˆπmax (β). π (πβ )′ (0) = π ⊗π )/π)π≥1 . Then one 20 HUAYI CHEN Proof. — For any integer π ≥ 1, let ππ = π π1 ππ∗ (β⊗π ) . Since π (ππ ) is a concave curve on [0, 1], for any π‘ ∈]0, 1], one has ⊗π π ˆmax (π∗ (β )) π (ππ )(π‘) = π (ππ )′ (0) ≥ . π π‘ As the sequence of polygons π (ππ ) converges uniformly to π (π), we obtain π ˆπmax (β) ≥ π (π)(π‘)/π‘, ∀π‘ ∈]0, 1]. ′ π ˆπmax (β) Therefore ≥ π (π) (0). Let π > 0 be an arbitrary positive real number. Let π = π ˆπmax (πΏ) − π. Then π ∗ π ˆmax (β ⊗ π L −π ) = π > 0. Therefore, Lemma 7.1, Proposition 7.2 and the first part of Theorem 5.4 implies that ( ) ∫ max π (π)(π‘) − ππ‘ = (π₯ − π)+ πβ (dπ₯) > 0. π‘∈[0,1] β Hence ( ) π (π)(π‘) ≥ max π (π)(π‘) − ππ‘ + π > π. π‘ π‘∈]0,1] π‘∈[0,1] π (π)′ (0) = max Since π is arbitrary, we obtain π (π)′ (0) ≥ π ˆπmax (β). References [1] A. Abbes & T. Bouche – “Théorème de Hilbert-Samuel “arithmétique” ”, Université de Grenoble. Annales de l’Institut Fourier 45 (1995), no. 2, p. 375–401. [2] R. Berman & S. Boucksom – “Capacities and weighted volumes of line bundles”, 2008. [3] T. 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Paris 8 β E-mail : huayi.chen@polytechnique.org Url : http://www.math.polytechnique.fr/~chen Université