Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann’s Zeros and the Rhythm of the Primes David Borthwick Emory University November 18, 2009 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Bernhard Riemann, 1826–1866 “On the Number of Primes Less Than a Given Magnitude” 7 page paper offered to the Monatsberichte der Berliner Akademie on October 19, 1859. The exact publication date is unknown. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula The counting function We’ll use p to denote a prime number, p ∈ 2, 3, 5, 7, 11, 13, 17, 19, . . . . The prime counting function is π(x) := # primes p ≤ x . 40 π(x) 20 100 200 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Gauss’s conjecture On a larger scale, the graph looks remarkably smooth: 8000 π(x) 4000 50,000 In 1792, Gauss conjectured that π(x) ∼ 100,000 x . log x (This means that π(x)/( logx x ) → 1 as x → ∞.) Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Gauss could compute π(x) up to x = 3, 000, 000. x 10 102 103 104 105 106 107 108 109 1010 π(x) 4 25 168 1229 9592 78498 664579 5761455 50847534 455052511 Convergence is rather slow. . . x/ log x 4 22 145 1086 8686 72382 620421 5428681 48254942 434294482 ratio 0.921 1.151 1.161 1.132 1.104 1.084 1.071 1.061 1.054 1.048 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Gauss later realized that the “log integral” function, Z x dt Li(x) := (also ∼ logx x ), 2 log t would give a better approximation. x 10 102 103 104 105 106 107 108 109 1010 π(x) 4 25 168 1229 9592 78498 664579 5761455 50847534 455052511 Li(x) 6 30 178 1246 9630 78628 664918 5762209 50849235 455055615 π(x)/ Li(x) 0.64876 0.82984 0.94590 0.98625 0.99607 0.99835 0.99949 0.99987 0.99997 0.99999 The claim π(x) ∼ Li(x) became the Prime Number Conjecture. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula The zeta function Euler (1748) had studied the series ζ(s) := 1 + 1 1 1 + s + s + ..., 2s 3 4 (convergent for s > 1). Euler factored this over the primes, ζ(s) = 1 + 21s + 41s + . . . 1 + 31s + 91s + . . . 1 + 51s + . . . · · · , and used geometric series, k ∞ X 1 k=0 to conclude ps −1 1 = 1− s , p −1 Y 1 1− s ζ(s) = . p p Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Before Riemann, the zeta function was studied for real s > 1. 20 ζ(s) 10 1 2 3 From lims→1 ζ(s) = ∞, we can deduce that 1 1 1 1 1 + + + + + · · · = ∞. 2 3 5 7 11 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Analytic continuation Riemann’s innovation was to consider ζ(s) for complex values of s. -1 0 1 1 2 3 -1 Re ζ(s) 0 1 1 2 3 Im ζ(s) 4 2 2 0 0 Euler’s definition works for Re s > 1, and it appears we can bypass the obstacle at s = 1. Epilog Prime Counting Zeta Function The Hypothesis Consder a simple example: Z ∞ t−s dt = 1 Riemann’s Formula 1 . s−1 This integral converges for Re s > 1. But the expression on the right makes sense for any complex s 6= 1. We can use this formula to extend the meaning of the integral. For example, we could say Z ∞ 1 t2 dt = − . 3 1 Because the extension is an analytic function, complex analysis tells that such an extension is uniquely defined. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann’s zeta function Riemann extended ζ(s) to all s 6= 1 by deriving the formula Γ(1 − s) ζ(s) = 2πi Z +∞ +∞ (−x)s dx , ex − 1 x where the integral is taken over a contour in the complex plane: (The result equals P 1 ns for Re s > 1 and is analytic for s 6= 1.) With Riemann’s extension, we can make sense of divergent sums: 1 + 2 + 3 + 4 + · · · = ζ(−1) = − 1 . 12 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Epilog Here’s Re ζ(s) in the original domain, Re s > 1. -20 5 0 -10 -5 10 0 0 10 -10 Prime Counting Zeta Function The Hypothesis Riemann’s Formula Epilog Here’s Re ζ(s) after Riemann’s extension. -20 5 0 -10 -5 10 0 0 10 -10 Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann zeros Using the contour integral formula for ζ(s), Riemann observes ζ(s) = 0, for s = −2, −4, −6, . . . . He also shows that all other zeros lie in the strip 0 ≤ Re s ≤ 1. critical strip 20 10 trivial zeros -4 -2 0 -10 -20 critical line 1 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann’s claims about the zeros 1. The number of zeros ρ in the critical strip with 0 ≤ Im ρ ≤ T is about T T T log − . 2π 2π 2π (Proven by Mangoldt in 1905.) 2. One finds about this many roots on the critical line, . . . (Proven by Selberg in 1942: a positive fraction of the zeros lie on the critical line.) 3. . . . and it is very likely that they all do. The Riemann Hypothesis! “One would of course like to have a rigorous proof of this, but I have put aside the search for such a proof after some fleeting vain attempts. . . ” Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula The Riemann Hypothesis Any non-trivial zero ρ of ζ(s) has Re ρ = 21 . |ζ(s)|−1 We’ve verified this for the first 10,000,000,000,000 zeros! In terms of containing the zeros in a vertical strip, the best we can do is to replace 0 ≤ Re ρ ≤ 1 by 0 < Re ρ < 1. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Chebyshev’s counting function In counting primes convenient to: 1. Include prime powers pk , for k = 1, 2, 3, . . . . 2. Assign to each pk the weight log p. This defines the Chebyshev function X ψ(x) := log p. pk ≤ x 200 100 100 200 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Epilog The two counting functions are related by π(x) + 1 1 2 2 π(x ) + 1 1 3 3 π(x ) + ··· = Z 2 x dψ(t) . log t This gives two equivalent forms for the Prime Number Conjecture: π(x) ∼ Li(x) ⇐⇒ ψ(x) ∼ x. 200 40 Li(x) π(x) ψ(x) 100 20 100 200 100 200 Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann’s explicit formula Riemann gives a formula for π(x) in terms of the non-trivial zeros ρ of the zeta function. This is equivalent to ψ(x) = x − X xρ ρ ρ + X x−2n n 2n − log 2π. (Proven by Mangoldt in 1895.) Riemann’s strategy for the Prime Number Conjecture amounts to X xρ to prove that ψ(x) ∼ x. estimating ρ ρ Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Riemann’s formula reveals a deep connection between primes and zeros. To illustrate this, consider the derivative of ψ(x), ψ ′ (x) = 1 − X ρ xρ−1 − 1 . − 1) x(x2 Since ψ(x) is a step function that jumps at each prime power pk , ψ ′ (x) should be zero except for spikes at 2, 3, 4, 5, 7, 8, 9, 11, 13, 16, 17, 19, . . . . Epilog Prime Counting Zeta Function The Hypothesis In the sum ψ ′ (x) = 1 − X xρ−1 − ρ Riemann’s Formula 1 , x(x2 − 1) each conjugate pair {ρ, ρ} contributes a waveform xρ−1 + xρ−1 . 2xRe ρ−1 For each waveform, Re ρ amplitude and Im ρ frequency. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula By adding up these waveforms, we can see the distribution of prime powers emerge. Approximating ψ ′ (x) with 1 pair of zeros: 0 0 5 10 15 20 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula By adding up these waveforms, we can see the distribution of prime powers emerge. Approximating ψ ′ (x) with 10 pairs of zeros: 0 0 5 10 15 20 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula By adding up these waveforms, we can see the distribution of prime powers emerge. Approximating ψ ′ (x) with 100 pairs of zeros: 0 0 5 10 15 20 Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Rhythm of the primes The Riemann zeros define the oscillatory modes that generate the distribution of prime numbers. The Riemann Hypothesis claims a perfect balance among these modes: all modes have equal amplitudes. Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula If RH is false, then at least one “note” is louder than the others: “If anything at all in our universe is correct, it has to be the Riemann Hypothesis, if for no other reasons, so for purely esthetical reasons.” - A. Selberg Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Prime Number Theorem Riemann’s strategy does work: We can prove that Re ρ < 1 for all ρ, which implies 1 X xρ = 0. x→∞ x ρ ρ lim By the explicit formula for ψ(x), this means ψ(x) ∼ x, or π(x) ∼ Li(x). (1896: Hadamard and de la Vallée-Poussin) Epilog Prime Counting Zeta Function The Hypothesis Riemann’s Formula Cautionary tale So we’ve checked 1013 zeros. Is that strong evidence? Consider another Gauss conjecture: that π(x) ≤ Li(x) always. 40 20 100 200 We now know this to be true for all x ≤ 1014 . However, . . . Littlewood proved in 1914 that π(x) and Li(x) cross infinitely often! No value of x for which π(x) > Li(x) is currently known. Epilog