Binary Codes The usual way of expressing a decimal number in terms of a binary number is known as pure binary coding and is discussed in the Number Systems section. A number of other techniques can be used to represent a decimal number. These are summarised below. 8421 BCD Code In the 8421 Binary Coded Decimal (BCD) representation each decimal digit is converted to its 4-bit pure binary equivalent. For example: 57dec = 0101 0111bcd Addition is analogous to decimal addition with normal binary addition taking place from right to left. For example, 6 0110 BCD for 6 42 0100 0010 BCD for 42 +3 0011 BCD for 3 +27 0010 0111 BCD for 27 ____ 1001 BCD for 9 __________ 0110 1001 BCD for 69 Where the result of any addition exceeds 9(1001) then six (0110) must be added to the sum to account for the six invalid BCD codes that are available with a 4-bit number. This is illustrated in the example below 8 1001 BCD for 8 +7 0111 BCD for 7 _____ 1111 exceeds 9 (1001) so 0110 add six (0110) __________ 0001 0101 BCD for 15 Note that in the last example the 1 that carried forward from the first group of 4 bits has made a new 4-bit number and so represents the "1" in "15". In the examples above the BCD numbers are split at every 4-bit boundary to make reading them easier. This is not necessary when writing a BCD number down. This coding is an example of a binary coded (each decimal number maps to four bits) weighted (each bit represents a number, 1, 2, 4, etc.) code. 4221 BCD Code The 4221 BCD code is another binary coded decimal code where each bit is weighted by 4, 2, 2 and 1 respectively. Unlike BCD coding there are no invalid representations. The decimal numbers 0 to 9 have the following 4221 equivalents Decimal 4221 1's complement 0 0000 1111 1 0001 1110 2 0010 1101 3 0011 1100 4 1000 0111 5 0111 1000 6 1100 0011 7 1101 0010 8 1110 0001 9 1111 0000 the 1's complement of a 4221 representation is important in decimal arithmetic. In forming the code remember the following rules Below decimal 5 use the right-most bit representing 2 first Above decimal 5 use the left-most bit representing 2 first Decimal 5 = 2+2+1 and not 4+1