Ch 28 Interference and Diffraction in Optics Lenses in Combination and Corrective Optics 28.2 Double Slit A laser with wavelength d/8 is shining light on a double slit with slit separation 0.500 mm. This results in an interference pattern on a screen a distance L away from the slits. We wish to shine a second laser, with a different wavelength, through the same slits. What is the wavelength λ2 of the second laser that would place its second maximum at the same location as the fourth minimum of the first laser, if d = 0.500 mm? Need help understanding? Please click here and fill in the last table d sinθ = m λ d: inverse of the grating constant in meters, in our case (non-SI units of mm) where m is the 1st order maxima, or the 2nd order maxima, etc. o if you want out of phase (maxima matching to minima), then o m - ½ corresponds to the 1st minima, when m = 2 then 2 - ½ is the 2nd minima, etc. we also know sinθ must be equal in both cases if they are the same distance. 4th Minima d sinθ = (4 - ½) λ1 2nd Maxima d sinθ = 2 λ2 28.3 Interference from Reflection off a Soap Film What is the thinnest soap (nsoap = 1.33) film that appears black when illuminated with light with a wavelength of 490 nm? 2 λ2 = (4 - ½) λ1 2 λ2 = (4 - ½) d/8 λ2 = 0.109 mm The light reflected off the top of the soap has a half-wave phase shift, while the light that reflects off the bottom has no phase shift. v=c/n v=fλ c / nair = f λair f = c / (nair λair) we also know freq can’t change c / nsoap = f λsoap c / nsoap = c / (nair λair) λsoap 1 / nsoap = 1 / (1 λair) λsoap λsoap = λair / nsoap λsoap = 490nm / 1.33 λsoap = 368 nm Since the light reflected off the top and bottom of the bubble are 180° out of phase, the thickness of the bubble must correspond to ½ λsoap ½ λsoap = 368/2 ½ λsoap = 184 nm 28.5 Rayleigh's criterion Resolving Power sinθd = 1.22 λ/D sin(1/60°) = 1.22 570x10-9 / D D = 2.39 mm If you can read the bottom row of your doctor's eye chart (λlight = 570 nm), your eye has a resolving power of one arcminute, equal to 1/60°. If this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? (The factor 1.22 comes from the fact that we are using a circular aperture for the diffraction pattern instead of an infinite slit.) Inversion glasses demo: OP-A-IG Polarized Light Reflection: OP-H-PR Diffraction Bench, Pasco: OP-C-DB Laser Tree Diffraction: OP-C-TD Speckles on the Wall Demo: OP-D-SW Color Mixing Demo: OP-F-CM