Name_________________________________
Algebra Application Term 3 Review
Date_______________
Period__________
Define a variable and write an expression for the phrase.
1. the quotient of 5 times a number and 6
2.
for m = –4, n = 2, and p = 1.5
Evaluate
3. Evaluate u + xy, for u = 4, x = 10, and y = 5.
Solve the proportion.
4.
5. School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip.
How many chaperones must there be for 90 students?
6. 30% of what number is 21?
7. What percent of 50 is 38?
8.
30% of 70 is what number?
Simplify the expression.
9.
10.
(1 – c)(–1)
Solve the equation.
11. 3(y + 3) = 27
12.
2
5
x = 28
13.
Solve the equation. If there is no solution, write no solution.
14.
Solve the inequality. Then graph your solution.
15. –6q < –12
16.
17.
5x – 6 = 3x + 6
for x = –2.
18. Evaluate
Find the slope of the line that passes through the pair of points.
19. (2, 7), (9, 3)
20.
Find the slope of the line.
y
5
4
3
2
1
–5
–4
–3
–2
–1
–1
1
2
3
4
5
x
–2
–3
–4
–5
Graph the equation.
21.
y = –2
22.
y
1
y= x–4
4
y
x
x
Find the x- and y-intercept of the line and graph the equation.
23. –10x – 5y = 50
x – intercept = _____________
y-intercept = _____________
y
x
Write an equation of a line with the given slope and y-intercept.
24. m = 4, b = –6
Find the slope and y-intercept of the line.
25. 18x + 9y = 108
26.
y=
Write the equation of the line in Slope-Intercept Form.
27.
y
5
4
3
2
1
–5
–4
–3
–2
–1
–1
–2
–3
–4
–5
1
2
3
4
5
x
3
2
x+2
28. Write y =
1
8
x + 10 in standard form using integers.
29. A line passes through (1, –5) and (–3, 7).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in slope-intercept form.
Write an equation in point-slope form for the line through the given point with the given slope.
30. (4, –6); m =
Write an equation for the line that is parallel to the given line and that passes through the given point.
31. y = –5x + 3; (–6, 3)
Write the equation of a line that is perpendicular to the given line and that passes through the given
point.
32. –2x – 12y = –2; (1, 2)
Academic Algebra Midterm Review
Answer Section
SHORT ANSWER
1. ANS:
31

8
DIF: L1
REF: 4-1 Ratio and Proportion
OBJ: 4-1.2 Solving Proportions
STO: PA 2.5.A, PA 2.5.C
TOP: 4-1 Example 4
KEY: proportion
MSC: NAEP N4b, NAEP N4c, NAEP M1l, NAEP M2b, NAEP A2f, CAT5.LV19.46, CAT5.LV19.51,
IT.LV15.PS, IT.LV15.CP, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.13, TV.LV19.17,
TV.LVALG.53, TV.LVALG.54
2. ANS:
4
DIF: L1
REF: 6-1 Rate of Change and Slope
OBJ: 6-1.2 Finding Slope
STO: PA 2.8.R, PA 2.8.S
TOP: 6-1 Example 3
KEY: finding slope using a graph,slope,graphing
MSC: NAEP M1l, NAEP A2a, NAEP A2b, CAT5.LV19.46, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI,
S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.11, TV.LV19.14, TV.LV19.15, TV.LVALG.53
3. ANS:
70
DIF: L1
REF: 4-3 Proportions and Percent Equations
OBJ: 4-3.1 Applying Proportions to Percent Problems
STO: PA 2.2.B
TOP: 4-3 Example 3
KEY: proportion,percent,finding the whole
MSC: NAEP N2a, NAEP N3g, NAEP N4d, CAT5.LV19.48, CAT5.LV19.50, IT.LV15.PS, IT.LV15.DP,
IT.LV15.AM, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.11, TV.LV19.17, TV.LV19.52,
TV.LVALG.54
4. ANS:
76%
DIF: L1
REF: 4-3 Proportions and Percent Equations
OBJ: 4-3.1 Applying Proportions to Percent Problems
STO: PA 2.2.B
TOP: 4-3 Example 1
KEY: proportion,percent,finding the percent
MSC: NAEP N2a, NAEP N3g, NAEP N4d, CAT5.LV19.48, CAT5.LV19.50, IT.LV15.PS, IT.LV15.DP,
IT.LV15.AM, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.11, TV.LV19.17, TV.LV19.52,
TV.LVALG.54
5. ANS:
y = –5x – 27
DIF: L1
REF: 6-5 Parallel and Perpendicular Lines
OBJ: 6-5.1 Parallel Lines
STO: PA 2.8.E, PA 2.8.R, PA 2.8.S, PA 2.8.T
TOP: 6-5 Example 2
KEY: parallel lines,linear equation
MSC: NAEP G3g, NAEP A2e, CAT5.LV19.52, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA,
S10.TSK1.PRA, TV.LV19.14, TV.LV19.16, TV.LV19.18, TV.LVALG.54, TV.LVALG.56
6. ANS:
7
39
DIF: L1
REF: 4-6 Probability of Compound Events
OBJ: 4-6.2 Finding the Probability of Dependent Events
STO: PA 2.5.B, PA 2.5.D, PA 2.7.E
TOP: 4-6 Example 4
KEY: theoretical probability,compound events,dependent events,word problem,problem solving
MSC: NAEP D4a, NAEP D4b, NAEP D4h, CAT5.LV19.46, CAT5.LV19.53, IT.LV15.PS, IT.LV15.DP,
IT.LV15.FR, S9.TSK1.PRA, S9.TSK1.DSP, S10.TSK1.PRA, S10.TSK1.DSP, TV.LV19.11, TV.LV19.15,
TV.LVALG.53
7. ANS:
–x + 8y = 80
DIF: L1
REF: 6-3 Standard Form
OBJ: 6-3.2 Writing Equations in Standard Form
STO: PA 2.8.K, PA 2.8.L, PA 2.8.R, PA 2.8.S
TOP: 6-3 Example 4
KEY: standard form of a linear equation,transforming equations
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.15, TV.LV19.16, TV.LVALG.54, TV.LVALG.55
8. ANS:
or
–10 –8
–6
–4
–2
0
2
4
6
8
10
DIF: L2
REF: 3-6 Absolute Value Equations and Inequalities
OBJ: 3-6.2 Solving Absolute Value Inequalities
STO: PA 2.8.D
TOP: 3-6 Example 3
KEY: solving absolute value inequalities,graphing,solving a compound inequality containing OR
MSC: NAEP N1g, NAEP A4a, NAEP A4c, CAT5.LV19.50, CAT5.LV19.55, IT.LV15.CP, IT.LV15.I,
IT.LV15.AM, S9.TSK1.NS, S10.TSK1.NS, TV.LV19.10, TV.LV19.14, TV.LV19.52, TV.LVALG.54
9. ANS:
q>2
–8
–6
–4
–2
0
2
4
6
8
DIF: L1
REF: 3-3 Solving Inequalities Using Multiplication and Division
OBJ: 3-3.2 Using Division to Solve Inequalities
STO: PA 2.5.D, PA 2.8.D
TOP: 3-3 Example 3
KEY: Division Property of Inequality,graphing,solving inequalities
MSC: NAEP A4a, NAEP A4c, CAT5.LV19.50, IT.LV15.CP, IT.LV15.PS, IT.LV15.AM, S9.TSK1.PRA,
S10.TSK1.PRA, TV.LV19.10, TV.LV19.16, TV.LV19.52, TV.LVALG.54
10. ANS:
–8
–6
–4
–2
0
2
4
6
8
DIF: L1
REF: 3-5 Compound Inequalities
OBJ: 3-5.1 Solving Compound Inequalities Containing And
STO: PA 2.4.E, PA 2.5.B, PA 2.8.D
TOP: 3-5 Example 2
KEY: solving a compound inequality containing AND,compound inequality
MSC: NAEP A3a, NAEP A4c, IT.LV15.CP, IT.LV15.DI, IT.LV15.AM, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.10, TV.LV19.17, TV.LV19.52, TV.LVALG.54
11. ANS:
y + 5 = –3(x – 1); y = –3x – 2
DIF: L1
REF: 6-4 Point-Slope Form and Writing Linear Equations
OBJ: 6-4.1 Using Point-Slope Form
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.R
TOP: 6-4 Example 3
KEY: point-slope form,slope-intercept form,transforming equations,multi-part question
MSC: NAEP A1h, NAEP A1i, NAEP A2a, NAEP A2b, NAEP A3a, CAT5.LV19.53, CAT5.LV19.54,
IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.15, TV.LV19.16, TV.LV19.17,
TV.LVALG.54, TV.LVALG.55
12. ANS:
6
DIF: L1
REF: 2-3 Solving Multi-Step Equations
OBJ: 2-3.2 Using the Distributive Property to Solve Equations
STO: PA 2.5.A, PA 2.5.C, PA 2.8.D, PA 2.8.N
TOP: 2-3 Example 4
KEY: Addition and Subtraction Properties of Equality, Multiplication and Division Properties of Equality,
solving equations, multi-step equation, Distributive Property
MSC: NAEP A3b, NAEP A3c, NAEP A4a, NAEP A4c, CAT5.LV19.50, IT.LV15.CP, IT.LV15.PS,
IT.LV15.AM, S9.TSK1.PRA, S9.TSK1.GM, S10.TSK1.PRA, S10.TSK1.GM, TV.LV19.16, TV.LV19.17,
TV.LV19.47, TV.LV19.48, TV.LV19.52, TV.LVALG.54
13. ANS:
70
DIF: L1
REF: 2-1 Solving One-Step Equations
OBJ: 2-1.2 Solving Equations Using Multiplication and Division
STO: PA 2.5.D, PA 2.8.D, PA 2.8.N
TOP: 2-1 Example 5
KEY: Multiplication and Division Properties of Equality, equivalent equations, inverse operations, one-step
equation, solving equations, fractions
MSC: NAEP N5e, NAEP A4a, NAEP A4c, CAT5.LV19.50, IT.LV15.CP, IT.LV15.PS, IT.LV15.AM,
S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.16, TV.LV19.49, TV.LV19.52, TV.LVALG.54
14. ANS:
6
DIF: L1
REF: 2-4 Equations With Variables on Both Sides
OBJ: 2-4.1 Solving Equations With Variables on Both Sides
STO: PA 2.5.C, PA 2.5.D, PA 2.8.D, PA 2.8.N
TOP: 2-4 Example 1
KEY: Addition and Subtraction Properties of Equality, Multiplication and Division Properties of Equality,
solving equations, multi-step equation, equations with variables on both sides
MSC: NAEP A2e, NAEP A4a, NAEP A4c, CAT5.LV19.50, IT.LV15.CP, IT.LV15.PS, IT.LV15.AM,
S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.16, TV.LV19.17, TV.LV19.52, TV.LVALG.54
15. ANS:
2; 12
DIF: L2
REF: 6-2 Slope-Intercept Form
OBJ: 6-2.1 Writing Linear Equations
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.T
TOP: 6-2 Example 1
KEY: slope,linear equation,y-intercept
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.11, TV.LV19.16, TV.LV19.17, TV.LV19.18, TV.LVALG.54, TV.LVALG.55
16. ANS:
3
;2
2
DIF: L1
REF: 6-2 Slope-Intercept Form
OBJ: 6-2.1 Writing Linear Equations
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.T
TOP: 6-2 Example 1
KEY: linear equation,y-intercept,slope
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.11, TV.LV19.16, TV.LV19.17, TV.LV19.18, TV.LVALG.54, TV.LVALG.55
17. ANS:
–30
DIF: L1
REF: 1-6 Multiplying and Dividing Real Numbers
OBJ: 1-6.2 Dividing Real Numbers
STO: PA 2.1.A, PA 2.2.A, PA 2.5.D, PA 2.8.I
TOP: 1-6 Example 6
KEY: algebraic expression, real numbers
MSC: NAEP N3a, CAT5.LV19.47, IT.LV15.PS, IT.LV15.I, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10,
TV.LV19.49, TV.LVALG.53
18. ANS:
h = –7, h = 21
DIF: L2
REF: 3-6 Absolute Value Equations and Inequalities
OBJ: 3-6.1 Solving Absolute Value Equations
STO: PA 2.8.D
TOP: 3-6 Example 2
KEY: absolute value,Division Property of Equality
MSC: NAEP N1g, NAEP A4a, NAEP A4c, CAT5.LV19.50, CAT5.LV19.55, IT.LV15.CP, IT.LV15.I,
IT.LV15.AM, S9.TSK1.NS, S10.TSK1.NS, TV.LV19.10, TV.LV19.14, TV.LV19.52, TV.LVALG.54
19. ANS:
y
5
4
3
2
1
–5
–4
–3
–2
–1
–1
1
2
3
4
5
x
–2
–3
–4
–5
DIF: L1
REF: 6-3 Standard Form
OBJ: 6-3.1 Graphing Equations Using Intercepts
STO: PA 2.8.K, PA 2.8.L, PA 2.8.R, PA 2.8.S
TOP: 6-3 Example 3
KEY: graphing,horizontal and vertical lines
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.15, TV.LV19.16, TV.LVALG.54, TV.LVALG.55
20. ANS:
1
DIF: L1
REF: 5-2 Relations and Functions
OBJ: 5-2.2 Evaluating Functions
STO: PA 2.8.A, PA 2.8.O, PA 2.8.Q
TOP: 5-2 Example 4
KEY: function
MSC: NAEP A1g, CAT5.LV19.53, CAT5.LV19.54, IT.LV15.DI, IT.LV15.PS, S9.TSK1.PRA,
S10.TSK1.PRA, TV.LV19.14, TV.LV19.16, TV.LVALG.56
21. ANS:
DIF: L1
REF: 6-4 Point-Slope Form and Writing Linear Equations
OBJ: 6-4.1 Using Point-Slope Form
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.R
TOP: 6-4 Example 2
KEY: slope-intercept form,linear equation
MSC: NAEP A1h, NAEP A1i, NAEP A2a, NAEP A2b, NAEP A3a, CAT5.LV19.53, CAT5.LV19.54,
IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.15, TV.LV19.16, TV.LV19.17,
TV.LVALG.54, TV.LVALG.55
22. ANS:
DIF: L1
REF: 1-1 Using Variables
OBJ: 1-1.1 Modeling Relationships With Variables
STO: PA 2.5.B, PA 2.8.D
TOP: 1-1 Example 2
KEY: algebraic expression, modeling relationships
MSC: NAEP A3a, NAEP A3c, NAEP A4a, CAT5.LV19.54, IT.LV15.CP, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.18, TV.LVALG.53
23. ANS:
y = 6x – 4
DIF: L1
REF: 6-5 Parallel and Perpendicular Lines
OBJ: 6-5.2 Perpendicular Lines
STO: PA 2.8.E, PA 2.8.R, PA 2.8.S, PA 2.8.T
TOP: 6-5 Example 3
KEY: perpendicular lines,linear equation
MSC: NAEP G3g, NAEP A2e, CAT5.LV19.52, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA,
S10.TSK1.PRA, TV.LV19.14, TV.LV19.16, TV.LV19.18, TV.LVALG.54, TV.LVALG.56
24. ANS:
DIF: L1
REF: 4-6 Probability of Compound Events
OBJ: 4-6.1 Finding the Probability of Independent Events
STO: PA 2.5.B, PA 2.5.D, PA 2.7.E
TOP: 4-6 Example 1
KEY: theoretical probability,independent events,compound events
MSC: NAEP D4a, NAEP D4b, NAEP D4h, CAT5.LV19.46, CAT5.LV19.53, IT.LV15.PS, IT.LV15.DP,
IT.LV15.FR, S9.TSK1.PRA, S9.TSK1.DSP, S10.TSK1.PRA, S10.TSK1.DSP, TV.LV19.11, TV.LV19.15,
TV.LVALG.53
25. ANS:
867
DIF: L1
REF: 1-2 Exponents and Order of Operations
OBJ: 1-2.1 Simplifying and Evaluating Expressions and Formulas
STO: PA 2.1.A, PA 2.2.A, PA 2.5.C
TOP: 1-2 Example 1
KEY: order of operations, exponential expression, power
MSC: NAEP A3b, CAT5.LV19.49, CAT5.LV19.50, IT.LV15.PS, IT.LV15.I, S9.TSK1.NS, S9.TSK1.PRA,
S9.TSK1.GM, S10.TSK1.NS, S10.TSK1.PRA, S10.TSK1.GM, TV.LV19.51, TV.LV19.52, TV.LVALG.53
26. ANS:
–1 + c
DIF: L1
REF: 1-7 The Distributive Property
OBJ: 1-7.2 Simplifying Algebraic Expressions
STO: PA 2.1.A, PA 2.2.A, PA 2.5.B
TOP: 1-7 Example 4
KEY: Distributive Property, real numbers
MSC: NAEP A3b, CAT5.LV19.51, CAT5.LV19.54, IT.LV15.CP, IT.LV15.AM, S9.TSK1.NS,
S10.TSK1.NS, TV.LV19.11, TV.LV19.16, TV.LVALG.53, TV.LV19.52
27. ANS:
1
y= x1
2
DIF: L1
REF: 6-2 Slope-Intercept Form
OBJ: 6-2.1 Writing Linear Equations
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.T
TOP: 6-2 Example 3
KEY: graphing,slope,y-intercept,slope-intercept form,finding slope using a graph
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.11, TV.LV19.16, TV.LV19.17, TV.LV19.18, TV.LVALG.54, TV.LVALG.55
28. ANS:
21
DIF: L1
REF: 4-3 Proportions and Percent Equations
OBJ: 4-3.1 Applying Proportions to Percent Problems
STO: PA 2.2.B
TOP: 4-3 Example 2
KEY: proportion,percent,finding the part
MSC: NAEP N2a, NAEP N3g, NAEP N4d, CAT5.LV19.48, CAT5.LV19.50, IT.LV15.PS, IT.LV15.DP,
IT.LV15.AM, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.11, TV.LV19.17, TV.LV19.52,
TV.LVALG.54
29. ANS:
4

7
DIF: L1
REF: 6-1 Rate of Change and Slope
OBJ: 6-1.2 Finding Slope
STO: PA 2.8.R, PA 2.8.S
TOP: 6-1 Example 4
KEY: finding slope using points,slope
MSC: NAEP M1l, NAEP A2a, NAEP A2b, CAT5.LV19.46, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI,
S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.11, TV.LV19.14, TV.LV19.15, TV.LVALG.53
30. ANS:
y = 4x – 6
DIF: L1
REF: 6-2 Slope-Intercept Form
OBJ: 6-2.1 Writing Linear Equations
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.T
TOP: 6-2 Example 2
KEY: linear equation,slope,y-intercept
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.11, TV.LV19.16, TV.LV19.17, TV.LV19.18, TV.LVALG.54, TV.LVALG.55
31. ANS:
8 chaperones
DIF: L2
REF: 4-1 Ratio and Proportion
OBJ: 4-1.2 Solving Proportions
STO: PA 2.5.A, PA 2.5.C
KEY: ratio,proportion,word problem,problem solving
MSC: NAEP N4b, NAEP N4c, NAEP M1l, NAEP M2b, NAEP A2f, CAT5.LV19.46, CAT5.LV19.51,
IT.LV15.PS, IT.LV15.CP, S9.TSK1.PRA, S10.TSK1.PRA, TV.LV19.10, TV.LV19.13, TV.LV19.17,
TV.LVALG.53, TV.LVALG.54
32. ANS:
54
DIF: L1
REF: 1-2 Exponents and Order of Operations
OBJ: 1-2.1 Simplifying and Evaluating Expressions and Formulas
STO: PA 2.1.A, PA 2.2.A, PA 2.5.C
TOP: 1-2 Example 2
KEY: order of operations
MSC: NAEP A3b, CAT5.LV19.49, CAT5.LV19.50, IT.LV15.PS, IT.LV15.I, S9.TSK1.NS, S9.TSK1.PRA,
S9.TSK1.GM, S10.TSK1.NS, S10.TSK1.PRA, S10.TSK1.GM, TV.LV19.51, TV.LV19.52, TV.LVALG.53
33. ANS:
y
5
4
3
2
1
–5
–4
–3
–2
–1
–1
1
2
3
4
5
x
–2
–3
–4
–5
DIF: L1
REF: 6-2 Slope-Intercept Form
OBJ: 6-2.2 Graphing Linear Equations
STO: PA 2.8.E, PA 2.8.K, PA 2.8.L, PA 2.8.T
TOP: 6-2 Example 4
KEY: linear equation,graphing equations,slope,y-intercept
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.11, TV.LV19.16, TV.LV19.17, TV.LV19.18, TV.LVALG.54, TV.LVALG.55
34. ANS:
y
4
2
–4
–2
2
4
x
–2
–4
DIF: L2
REF: 5-3 Function Rules¸ Tables¸ and Graphs
OBJ: 5-3.1 Modeling Functions
STO: PA 2.8.A, PA 2.8.O, PA 2.8.Q
TOP: 5-3 Example 3
KEY: graphing,function,quadratic function
MSC: NAEP A1e, NAEP A2a, CAT5.LV19.53, CAT5.LV19.54, IT.LV15.DI, S9.TSK1.DSP,
S10.TSK1.DSP, TV.LV19.16, TV.LV19.18, TV.LVALG.55, TV.LVALG.56
35. ANS:
x-intercept is –5; y-intercept is –10.
DIF: L1
REF: 6-3 Standard Form
OBJ: 6-3.1 Graphing Equations Using Intercepts
STO: PA 2.8.K, PA 2.8.L, PA 2.8.R, PA 2.8.S
TOP: 6-3 Example 1
KEY: x-intercept,y-intercept,standard form of a linear equation
MSC: NAEP A1h, CAT5.LV19.54, IT.LV15.CP, IT.LV15.DI, S9.TSK1.PRA, S10.TSK1.PRA,
TV.LV19.15, TV.LV19.16, TV.LVALG.54, TV.LVALG.55