Curriculum 2.0 Geometry: Unit 1 – Topic 4, SLT 41 Name: Proving Parallelogram Properties Sample Answers Date: Period: Proof 1 If a quadrilateral is a parallelogram, then its opposite sides are congruent. Complete the diagram and develop an appropriate “Given” and “Prove” for this case. Given: ππ’πππππππ‘ππππ π΄π΅πΆπ· ππ π πππππππππππππ Μ Μ Μ Μ ≅ πΆπ· Μ Μ Μ Μ ; π΄π· Μ Μ Μ Μ ≅ πΆπ΅ Μ Μ Μ Μ Prove: π΄π΅ B A D C Use triangle congruence criteria to demonstrate why opposite sides of a parallelogram are congruent. Proof Statement Reason 1. ππ’πππππππ‘ππππ π΄π΅πΆπ· ππ π πππππππππππππ 1. Given Μ Μ Μ Μ 2. Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ πΆπ·; Μ Μ Μ Μ π΄π· β₯ πΆπ΅ 2. Definition of a Parallelogram 3. ∠π΄π΅π· ≅ ∠πΆπ·π΅ 3. Alternate Interior Angles 4. Μ Μ Μ Μ π΅π· ≅ Μ Μ Μ Μ π΅π· 4. Reflexive Property 5. ∠πΆπ΅π· ≅ ∠π΄π·π΅ 5. Alternate Interior Angles 6. βπ΄π΅π· ≅ βπΆπ·π΅ 6. ASA Μ Μ Μ Μ 7. Μ Μ Μ Μ π΄π΅ ≅ Μ Μ Μ Μ πΆπ·; Μ Μ Μ Μ π΄π· ≅ πΆπ΅ 7. CPCTC Page 1 of 4 Curriculum 2.0 Geometry: Unit 1 – Topic 4, SLT 41 Name: Proving Parallelogram Properties Sample Answers Date: Period: Proof 2 If a quadrilateral is a parallelogram, then its opposite angles are congruent. Complete the diagram and develop an appropriate “Given” and “Prove” for this case. Given: ππ’πππππππ‘ππππ π΄π΅πΆπ· ππ π πππππππππππππ Prove: ∠π΅π΄π· ≅ ∠π·πΆπ΅; π∠π΄π·πΆ = π∠π΄π΅πΆ B A D C Use triangle congruence criteria to demonstrate why opposite angles of a parallelogram are congruent. Proof Statement Reason 1. ππ’πππππππ‘ππππ π΄π΅πΆπ· ππ π πππππππππππππ 1. Given Μ Μ Μ Μ 2. Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ πΆπ·; Μ Μ Μ Μ π΄π· β₯ πΆπ΅ 2. Definition of a Parallelogram 3. ∠π΄π΅π· ≅ ∠πΆπ·π΅; ∠πΆπ΅π· ≅ ∠π΄π·π΅ 3. Alternate Interior Angles Μ Μ Μ Μ ≅ π΅π· Μ Μ Μ Μ 4. π΅π· 4. Reflexive Property of Equality 5. βπ΄π΅π· ≅ βπΆπ·π΅ 5. ASA 6. ∠π΅π΄π· ≅ ∠π·πΆπ΅ 6. CPCTC 7. π∠π΄π·π΅ + π∠πΆπ·π΅ = π∠π΄π·πΆ; 7. Angle Addition Postulate π∠π΄π΅π· + π∠πΆπ΅π· = π∠π΄π΅πΆ 8. π∠πΆπ΅π· + π∠π΄π΅π· = π∠π΄π·πΆ 8. Substitution from #3 into #7 9. π∠π΄π·πΆ = π∠π΄π΅πΆ 9. Substitution or Transitive Property Page 2 of 4 Curriculum 2.0 Geometry: Unit 1 – Topic 4, SLT 41 Name: Proving Parallelogram Properties Sample Answers Date: Period: The converse of Proof 1 If the opposite sides of a quadrilateral are congruent, then the quadrilateral is a parallelogram. Complete the diagram and develop an appropriate “Given” and “Prove” for this case. Μ Μ Μ Μ Given: Quadrilateral ABCD with Μ Μ Μ Μ π΄π΅ ≅ Μ Μ Μ Μ πΆπ·; Μ Μ Μ Μ π΄π· ≅ πΆπ΅ Prove: Quadrilateral ABCD is a parallelogram B A D C Use triangle congruence criteria to determine that quadrilateral ABCD is a parallelogram. Proof Statement Reason Μ Μ Μ Μ ≅ πΆπ· Μ Μ Μ Μ ; π΄π· Μ Μ Μ Μ ≅ πΆπ΅ Μ Μ Μ Μ 1. Quadrilateral ABCD with π΄π΅ 1. Given Μ Μ Μ Μ ≅ π΅π· Μ Μ Μ Μ 2. π΅π· 2. Reflexive Property 3. βπ΄π΅π· ≅ βπΆπ·π΅ 3. SSS 4. ∠π΄π΅π· ≅ ∠πΆπ·π΅, ∠π΄π·π΅ ≅ ∠πΆπ΅π· 4. CPCTC Μ Μ Μ Μ β₯ πΆπ· Μ Μ Μ Μ , π΄π· Μ Μ Μ Μ β₯ πΆπ΅ Μ Μ Μ Μ 5. π΄π΅ 5. Converse of Alternate Interior Angles 6. Quadrilateral ABCD is a parallelogram 6. Definition of a Parallelogram Page 3 of 4 Curriculum 2.0 Geometry: Unit 1 – Topic 4, SLT 41 Name: Proving Parallelogram Properties Sample Answers Date: Period: Converse of Proof 2 If the opposite angles of a quadrilateral are equal, then the quadrilateral is a parallelogram. A Complete the diagram and develop an appropriate “Given” and “Prove” for this case. 1 Given: π∠πΆπ·π΄ = π∠π΄π΅πΆ; π∠1 = π∠4 B 2 3 6 D Prove: Quadrilateral ABCD is a parallelogram 5 4 C Use triangle congruence criteria to demonstrate that quadrilateral ABCD is a parallelogram. Proof Statements Reasons 1. mοCDA ο½ mοABC 1. Given mοCDA ο½ mο5 ο« mο6 mοABC ο½ mο2 ο« mο3 3. mο5 ο« mο6 ο½ mο2 ο« mο3 2. Angle Addition 2. 4. mο1 ο« mο2 ο« mο6 ο½ 180o mο3 ο« mο4 ο« mο5 ο½ 180 o 5. mο1 ο« mο2 ο« mο6 ο½ mο3 ο« mο4 ο« mο5 6. mο1 ο½ mο4 7. mο4 ο« mο2 ο« mο6 ο½ mο3 ο« mο4 ο« mο5 8. mο2 ο« mο6 ο½ mο3 ο« mο5 9. mο5 ο mο2 ο½ mο2 ο mο5 10. 2mο5 ο½ 2mο2 3. Substitution or Transitive (statements from #2 and#1) 4. Sum of the measures of the angles of a triangle is 180o 5. Substitution or Transitive (both expressions in statement #4 equal 180o) 6. Given 7. Substitution (replacing mο1 from statement #5 with mο4 in statement #6) 8. Subtraction Property of Equality (subtract mο4 from both sides) 9. Subtraction Property of Equality (statement #3 minus statement #8) 10. Addition Property of Equality (add mο2 and mο5 to both sides) 11. mο5 ο½ mο2 11. Division Property of Equality (divide both sides by 2) 12. AB / /CD 12. Converse of Alternate Interior Angles 13. mο5 ο« mο6 ο½ mο3 ο« mο5 13. Substitution (replacing mο2 in statement #8 with mο5 from statement #11) 14. Subtraction Property of Equality (subtract mο5 from both sides) 14. mο6 ο½ mο3 15. AD / / BC 16. Quadrilateral ABCD is a parallelogram 15. Converse of Alternate Interior Angles 16. Definition of a parallelogram Page 4 of 4