Bomb Calorimeter Questions

advertisement
1. Calculate the higher heating value using equation 2 and ΔTmeasured.
Starting with Equation 2 from Dr. Kassegne’s ME 495 Experiment 2 Bomb Calorimeter [1], we need to
isolate π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ by using the given heating value of the benzoic acid pellet, π»π‘‰π‘Žπ‘π‘–π‘‘ . We do this to use a
corrected value for the mass of the water in order to solve for the higher heating value for diesel, 𝐻𝑉𝑑𝑖𝑒𝑠𝑒𝑙 .
m C T
*
HV ο€½
V

ο€­ mwire HVwire 
m fuel
Solving for π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ ,
π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ =

corrected water
[(π»π‘‰π‘Žπ‘π‘–π‘‘ ∗ π‘šπ‘Žπ‘π‘–π‘‘ ) + (π›₯π‘šπ‘€π‘–π‘Ÿπ‘’ ∗ π»π‘‰π‘€π‘–π‘Ÿπ‘’) ]
πΆπ‘£π‘€π‘Žπ‘‘π‘’π‘Ÿ ∗ π›₯π‘‡π‘€π‘Žπ‘‘π‘’π‘Ÿ
Now that π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ has been isolated we can plug in the values of the recorded data located in Tab. 1
below.
Table 1: Recorded and calculated values for Bomb Calorimeter Experiment for the benzoic acid pellet run.
Name
Mass of Acid Pellet
π‘šπ‘Žπ‘π‘–π‘‘
Value
0.988
Units
g
π›₯π‘šπ‘€π‘–π‘Ÿπ‘’
0.0032
g
π»π‘‰π‘Žπ‘π‘–π‘‘
26430
𝐽
𝑔
Heating Value of fuse
wire
π»π‘‰π‘€π‘–π‘Ÿπ‘’
5857.60
𝐽
𝑔
Specific heating value
of water
𝐢𝑣 π‘€π‘Žπ‘‘π‘’π‘Ÿ
4.186
𝐽
𝑔 °πΆ
Temperature change
Δπ‘‡π‘€π‘Žπ‘‘π‘’π‘Ÿ
2.62
°C
Difference of mass of
wire before and after
experiment
Heating Value of
benzoic acid pellet
Variable
Plugging in the values from Tab.1, we can now calculate π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ ,
𝐽
𝐽
{(26430 [𝑔] ∗ 0.988 [𝑔]) + [(0.0032)[𝑔] ∗ 5857.60 [𝑔]]}
=
𝐽
{4.186 [𝑔 °πΆ ] ∗ (2.62)[°πΆ]}
π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ = 2382.68 𝑔
Now that we have the value for π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ we can now calculate 𝐻𝑉𝑑𝑖𝑒𝑠𝑒𝑙 by using equation 2 from the lab
manual [1].
𝐻𝑉𝑑𝑖𝑒𝑠𝑒𝑙 =
[(π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ ∗ 𝐢𝑣 ∗ π›₯π‘‡π‘€π‘Žπ‘‘π‘’π‘Ÿ ) − (π›₯π‘šπ‘€π‘–π‘Ÿπ‘’ ∗ π»π‘‰π‘€π‘–π‘Ÿπ‘’ )]
π‘šπ‘‘π‘–π‘’π‘ π‘’π‘™
Now that we have the equation for 𝐻𝑉𝑑𝑖𝑒𝑠𝑒𝑙 we can use the data recorded from the diesel run of the
experiment which is tabulated in Tab.2 below.
Table 2: Recorded and calculated values for Bomb Calorimeter Experiment for the diesel fuel run.
Name
Mass of diesel fuel
π‘šπ‘‘π‘–π‘’π‘ π‘’π‘™
Value
0.794
Units
g
π›₯π‘šπ‘€π‘–π‘Ÿπ‘’
0.0099
g
π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ
2382.68
𝑔
𝐢𝑣 π‘€π‘Žπ‘‘π‘’π‘Ÿ
4.186
𝐽
𝑔 °πΆ
Temperature change
Δπ‘‡π‘€π‘Žπ‘‘π‘’π‘Ÿ
3.60
°C
Heating value of fuse
wire
π»π‘‰π‘€π‘–π‘Ÿπ‘’
5857.60
𝐽
𝑔
Difference of mass of
wire before and after
experiment
Corrected mass of
water
Specific heating value
of water
Variable
𝐽
𝐽
( 2382.68 [𝑔] ∗ 4.186 [𝑔 °πΆ ] ∗ 3.60 [°πΆ]) − (0.0099 [𝑔] ∗ 5857.60 [𝑔 ])
=
0.794 𝑔
𝐻𝑉𝑑𝑖𝑒𝑠𝑒𝑙 = 45148.7
𝐽
π‘˜π½
= 45148.7
𝑔
π‘˜π‘”
2. Calculate a percent error verses the theoretical value of 46,446kJ/kg for diesel fuel.
Comparing the calculated value of the higher heating value of the diesel fuel with the theoretical value via
the equation for percent error yields,
%πΈπ‘Ÿπ‘Ÿπ‘œπ‘Ÿ = |
Experimental − Theoretical
| ∗ 100%
Theoretical
π‘˜π½
π‘˜π½
− 46446 [ ]
π‘˜π‘”]
π‘˜π‘”
| ∗ 100%
π‘˜π½
46446 [ ]
π‘˜π‘”
45148.7 [
=|
%πΈπ‘Ÿπ‘Ÿπ‘œπ‘Ÿ = 2.79%
Questions
1. What is m* and how is it different from mwater?
In the bomb calorimeter experiment, we use π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ to define a quantity in which all the necessary
components which have absorbed heat in the system due to combustion are taken into account. The heat
absorption in the system takes into account the heat absorbed by the cup for holding the fuel, the steel
bomb, and other parts of the system that were heated during the combustion process. This differs from
the measurable value for the mass of water, π‘šπ‘€π‘Žπ‘‘π‘’π‘Ÿ , which was measured to 2000 g because it takes into
account the various components which absorbed heat during combustion which is why the value of
π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ is larger than the measured 2000 g put into the system which assumes the other components in
the system do not absorb heat.
2. Compare the theoretical and actual heating values for diesel fuel.
From the calculated data in the Experimental Results section, we used the known heating value of the
benzoic acid pellet in order to calculate π‘š∗ π‘€π‘Žπ‘‘π‘’π‘Ÿ for the system. This let us determine how much heat
was absorbed from the components of the system and use a corrected value for the mass of water to
account for heat absorption while calculating the heating value of the diesel fuel. From this process we
calculated a heating value of 45, 148.7 π‘˜π½⁄π‘˜π‘” compared to the theoretical value of 46,466 π‘˜π½⁄π‘˜π‘” given
by Dr. Kassegne in the lab manual [1]. Using the percent error equation yielded an error of 2.79%. This
error is small and is probably due to human error, such as temperature recording or weighing the
components of the system before and after each run. There is also the possibility of data error discussed
in question 3.
3. Is there any other possible explanation for a different HHV besides experimental error?
In order for us to determine the most accurate higher heating value (HHV) we need to know what source
the theoretical heating value came from. Due to the vast resources available on the internet it is possible
for data to become corrupted or vary depending on the source used. We also do not know the type or age
of the diesel fuel contained in the container used, which may be a different quality than that of the
theoretical HHV given.
[1] Kassegne, S. “ME495 Lab – Bomb Calorimeter– Lab Number 2." Mechanical Engineering
Department.San Diego State University.Fall 2011.
Download