maths hots for class xii (word file)

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CHAPTER-1
RELATION AND FUNCTION
1. Let f: R→R be defined by f(x)= x |x|
State whether the function f(x) is onto.
2. Let* be the binary operations on Z given by a* b = a+b+1๏€ข a, b ฯต Z. Find the identify
element for * on Z, if any.
1
3. State with reason whether the functions f : X→Y have inverse, where f(x) =๐‘ฅ๏€ข x ฯต X. and
X=Q - {o}, Y=Q.
4. Let Y= { n2: n ฯต N} be a subset of N and let “f ” be a function f : N→Y defined as f(x)=x2.
Show that “f” is invertible and find inverse of “f”.
5. Show that the function f : N→N given by f(x)=x- (-1)x is bijective.
6. If f be the greatest integer function and g be the absolute value function ; find the value of
(fog)(-3/2) + (gof)(4/3).
7. Consider the mapping f :[0,2]→[0,2]defined by f(x)=√4 − ๐‘ฅ 2 . Show that f is invertible and
hence find f -1.
8. Give examples of two functions f N→N and g:Z→Z such that gof is injective but g is not
injective.
9. Give examples of two functions f:N→N such that gof is onto but f is not onto.
2๐‘ฅ
10. Let f:R- ๏ป-3/5๏ฝ→ R be a function defined as f(x)=5๐‘ฅ+3, find the inverse of f.
11. Show that the relation R defined by (a,b) R (c,d)๏ƒža+d=b+ c on the set N×N is an
equivalence relation.
12. Let
Q+
be
the
° Show that the operation
set
*
of
all
positive
on Q+ defined by a*b =
rational
numbers.
1
(a+b) is a binary operation.
2
° Show that* is commutative.
° Show that * is not associative.
13. Let A= N×N. Let * be a binary operation on A defined by (a,b) * (c,d) = (ab+bc,bd)
๏€ขa,b,c,d ฯต N. Show that (i) * is commutative (ii) * is associative (iii) identity element w.r.t.*
does not exist.
14. Draw the graph of that function f(x)=x2 on R and Show that it is not invertible. Restrict its
domain suitably so that f-1may exist, find f-1 and draw its graph.
15.Show that the relation “ congruence modulo 2” on the set Z is an equivalence relation. Also
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1
find the equivalence class of 1.
CHAPTER-2
INVERSE TRIGONOMETRIC FUNCTIONS
๐œ‹
1
๐‘Ž
๐œ‹
1) Prove that tan( 4 + 2 cos −1 ๐‘)+ tan(4 −
๐‘ฅ−1
2๐‘ฅ−1
1
2
๐‘Ž
cos −1 ๐‘)=
2๐‘
๐‘Ž
.
23
2) Solve tan−1 ๐‘ฅ+1+ tan−1 2๐‘ฅ+1= tan−1 56
3) Write tan−1(๐‘ฅ + √1 + ๐‘ฅ 2 ), xฯตR,in the simplest form.
4) Solve that tan−1(๐‘ฅ + 1) + tan−1 ๐‘ฅ + tan−1 (๐‘ฅ − 1) = tan−1 3
5) Prove than
๐›ผ²
2
1
๐›ผ
๐‘๐‘œ๐‘ ๐‘’๐‘² (2 tan¯¹ ๐›ฝ) +
2๐›ผ
๐›ฝ²
2
1
๐›ฝ
sec ²(2 tan¯¹ ๐›ผ)= (๐›ผ+ ๐›ฝ)( ๐›ผ² + ๐›ฝ²)
2๐›ฝ
6) Solve for x: sin−1 1+๐›ผ2 + sin−1 ๐›ฝ2 +1 = 2 tan−1 ๐‘ฅ
7) If tan−1 ๐‘Ž + tan−1 ๐‘ + tan−1 ๐‘=๏ฐ, prove that a+b+c =abc
8) Prove that cos (tan−1
๐‘ฅ 2 +1
(sin[ cot −1 ๐‘ฅ ])) = √๐‘ฅ 2 +2
8๏ฐ
9) What is the principal value of cos−1 (cos ( 7 )) ?
๐œ‹
10) If tan-1x+tan-1y + tan-1 z = 2 , prove that ๐‘ฅ๐‘ฆ + ๐‘ฆ๐‘ง + ๐‘ง๐‘ฅ = 1
120
11) Show that 4 tan−1(15) = tan−1 (119)
12) If sin−1 ๐‘ฅ + sin−1 ๐‘ฆ + sin−1 ๐‘ง =
3๐œ‹
2
, then find the value of
1
๐‘ฅ100 + ๐‘ฆ100 + ๐‘ง100 − ๐‘ฅ 101 + ๐‘ฆ101 + ๐‘ง 101
๐‘ฅ
๐‘ฆ
13) If cos−1 ๐‘Ž + cos −1 ๐‘ = ๐›ฝ, ๐‘๐‘Ÿ๐‘œ๐‘ฃ๐‘’ ๐‘กโ„Ž๐‘Ž๐‘ก
14) If ๐‘ฅ +
1
๐‘ฅ
2
๐‘Ž2
=2, Find the value of sin-1 x
15) Find the value of sin (2 sin-10.8).
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๐‘ฅ2
−
2๐‘ฅ๐‘ฆ
๐‘Ž๐‘
๐‘ฆ2
cos ๐›ฝ + ๐‘2 = sin2 ๐›ฝ
CHAPTER-3
MATRICES
0 6 − 5๐‘ฅ
1) If [
]is symmetric, find x.
๐‘ฅ ๐‘ฅ−3
2) ๐ผ๐‘“ ๐ด = [
๐‘ฅ
๐‘ง
๐‘ฆ
]is such that A2 = I, then find the value of 2 – x2 – yz
−๐‘ฅ
−4 โ‹ฏ
3) If A =( โ‹ฎ
โ‹ฑ
3 โ‹ฏ
4) If A= [
1
โ‹ฎ ) then find f (A) when f (x) = x2 – 2x + 3.
2
๐‘– 0
] find A4n , n ฯต N
0 ๐‘–
5) Given an example of a square matrix which is both symmetric as well as skew symmetric.
6) If A and B are symmetric matrices, then show that AB + BA is also a symmetric matrix but
AB – BA is skew symmetric matrix.
7) Show that all the positive integral powers of symmetric matrix are Symmetric.
8) Find the matrix A satisfying the matrix equation
[
๐‘Ž
9) If A=[
0
1 2
4
]๐ด[
2 3
3
๐‘›
๐‘
], a ≠ 1, Prove by induction that An [๐‘Ž
1
0
10) Find x if [ ๐‘ฅ
1
][
−5 −1 0
2
0
]
1
๐‘(๐‘Ž๐‘› −1)
๐‘Ž−1
] for all positive integer n.
1
0 2 ๐‘ฅ
2 1] [4] = 0
0 3 1
11) By using elementary row transformation, find
12) If A= (
7
1
]=[
5
0
2 −3 3
A-1 where A= [2 2 3]
3 −2 2
0 1
1 0
) and I = (
) prove that (aI + bA)3 = a3I + 3a2bA.
0 0
0 1
13) If A and B are two matrices such that AB = B and BA = A find A2 + B2
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14) If A = [a] m x n is a skew-symmetric matrix, what is the value of aii for every I ?
3 −4
15) A = [
] , find the matrix B such that AB = I
−1 2
CHAPTER-4
DETERMINANTS
๐‘Ž
1. If a, b, c are non-zero real numbers, then find the inverse of matrix A=[0
0
1 0 0
2. If A=[0 2 0] then what is the |adj(adjA)|?
0 0 3
0 0
๐‘ 0]
0 ๐‘
3. If A is a square matrix of order 3 such that |Adj A| = 64, then find |A|
2๐‘๐‘œ๐‘ ๏ฑ
3
1
|
log ๐‘ ๐‘Ž
4. Find the value(s) of ๏ฑ, if the matrix [
log ๐‘
5. Evaluate the determinant| ๐‘Ž
1
1
] is singular, where 0 < ๏ฑ < ๏ฐ.
2๐‘๐‘œ๐‘ ๏ฑ
๏ฌ2 + 3๏ฌ ๏ฌ − 1 ๏ฌ + 3
6. If | ๏ฌ + 1 2 − ๏ฌ ๏ฌ − 3 |= A๏ฌ4 + B๏ฌ3 + C๏ฌ2 + D๏ฌ + E, then find the value of E
๏ฌ−3 ๏ฌ+4
3๏ฌ
7. The value of a third order determinant is 12. Find the value of the square of the determinant
formed by the cofactor.
8. Let A be a skew symmetric matrix of odd order, then what will be |A|
cos ๐‘ฅ
9. If f(x)= [ sin ๐‘ฅ
0
− sin ๐‘ฅ
cos ๐‘ฅ
0
0
0], then show that ๏ปf(x)๏ฝ-1 = f(-x)
1
10. Prove the following by using the properties of determinants
(๐‘ + ๐‘)²
| ๐‘²
๐‘²
๐‘Ž²
๐‘Ž²
(๐‘ + ๐‘Ž)²
๐‘² |=2abc(a + b + c)³
๐‘²
(๐‘Ž + ๐‘)²
๐‘Ž+๐‘ฅ
11. Using properties of determinants , solve for x. |๐‘Ž − ๐‘ฅ
๐‘Ž−๐‘ฅ
๐‘Ž−๐‘ฅ
๐‘Ž+๐‘ฅ
๐‘Ž−๐‘ฅ
๐‘Ž−๐‘ฅ
๐‘Ž − ๐‘ฅ|= 0
๐‘Ž+๐‘ฅ
2๐‘ฅ + 4 5๐‘ฅ + 7 8๐‘ฅ + ๐‘™
12. If l , m, n are in A.P. then , find value of |3๐‘ฅ + 4 6๐‘ฅ + 8 9๐‘ฅ + ๐‘š |
4๐‘ฅ + 6 7๐‘ฅ + 9 10๐‘ฅ + ๐‘›
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4
๐‘Ž
13. If | ๐‘
๐‘Ž๐›ผ + ๐‘
๐‘
๐‘
๐‘๐›ผ + ๐‘
๐‘Ž๐›ผ + ๐‘
๐‘๐›ผ + ๐‘| and ๐›ผ is not a root of the equation ax2 + bx + c = 0 , then
0
show that a, b, c are in G.P.
๐‘ฅ๐‘˜
14. Let |๐‘ฆ ๐‘˜
๐‘ง๐‘˜
๐‘ฅ ๐‘˜+2
๐‘ฆ ๐‘˜+2
๐‘ง ๐‘˜+2
๐‘ฅ ๐‘˜+3
1
๐‘ฆ ๐‘˜+3 | = (x-y)(y-z)(z-x) (๐‘ฅ +
๐‘ง ๐‘˜+3
1
๐‘ฆ
1
+ ), then find k.
๐‘ง
2
3
1
15. Let A = [−1 1
1 ], find A-1. Hence solve the following system of equations
−1 −1 −1
2๐‘ฅ − ๐‘ฆ − ๐‘ง = 7
3๐‘ฅ + ๐‘ฆ − ๐‘ง = 7
๐‘ฅ+๐‘ฆ−๐‘ง =3
−4 4
4
1
16. Given that A = [−7 1
3 ] and B = [1
5 −3 −1
2
−1 1
−2 −2] Find AB and use it to solve the
1
3
system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z =1.
(๐‘Ž + 1)(๐‘Ž + 2)
17. Prove that |(๐‘Ž + 2)(๐‘Ž + 3)
(๐‘Ž + 3)(๐‘Ž + 4)
(๐‘Ž + 2)
(๐‘Ž + 3)
(๐‘Ž + 4)
1
1|= – 2
1
18. Using
the
properties
of
mc1 mc2 mc3
๐‘š๐‘๐‘›(๐‘š−๐‘›)(๐‘›−๐‘)(๐‘−๐‘š)
| nc1 nc2 nc3 |=
.
12
pc1 pc2 pc3
1
๐‘Ž2
๐‘๐‘
19. Evaluate |๐‘
๐‘2
๐‘๐‘Ž ||
1
๐‘2
๐‘Ž๐‘
๐‘Ž
|1
๐‘
the
determinants,
prove
that
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5
20. Two schools A and B decided to award prizes to their students for three values Honesty (x),
punctuality (y) and obedience (z). School A decided to award a total Rs 15000 for the
three values to 4, 3 and 2 students respectively, while school B decided to award Rs
19000 for the three values to 5, 4 and 3 students respectively. If all the three prizes
together amount Rs 5000, then
i.
Represent the above situation by a matrix equation and form a linear equation
using matrix multiplication.
ii. Which value you prefer to be rewarded most and why?
CHAPTER-5
CONTINTUITY AND DIFFERENIABILITY
1. Show that the function f(x) =|๐‘†๐‘–๐‘› ๐‘ฅ + ๐ถ๐‘œ๐‘  ๐‘ฅ| is continuous at x = ๏ฐ.
2. Show that the logarithmic function is continuous.
1
3. Let f(x) = (x – a)Cos ๐‘ฅ−๐‘Ž for x ≠ a and let f(a) = 0. Show that f is continuous at x = a but not
derivable there at.
4. Let f(x) =x.|x| for all x ฯต R. Discuss the conti
5. Examine for continuity and differentiability of the following functions:f(x) = {
|๐‘ฅ|Sin
1
0
, ๐‘–๐‘“๐‘ฅ ≤ 0 ๐‘Ž๐‘ก ๐‘ฅ = 0
1−cos 4๐‘ฅ
๐‘ฅ2
๐‘Ž
f(x) =
๐‘ฅ>0
x
๐‘–๐‘“ ๐‘ฅ < 0
๐‘–๐‘“ ๐‘ฅ = 0
√๐‘ฅ
{√16+√๐‘ฅ−4 ๐‘–๐‘“ ๐‘ฅ > 0
6. Given that : If f(x) is continuous at x = 0, find the values of a.
3๐‘Ž๐‘ฅ + ๐‘, ๐‘–๐‘“ ๐‘ฅ > 1
๐‘–๐‘“ ๐‘ฅ = 1
7. If function f(x) = { 11
5๐‘Ž๐‘ฅ − 2๐‘ ๐‘–๐‘“ ๐‘ฅ < 1
8. Discuss for continuity of the function at x = 0
๐‘†๐‘–๐‘› 3๐‘ฅ
f(x) =
tan 2๐‘ฅ
3
2
๐‘™๐‘œ๐‘” (1+3๐‘ฅ)
๐‘–๐‘“ ๐‘ฅ < 0
๐‘–๐‘“ ๐‘ฅ = 0
๐‘–๐‘“ ๐‘ฅ > 0
{ ๐‘’ 2๐‘ฅ −1
9. Find all points of discontinuity of f where
๐‘ ๐‘–๐‘›๐‘ฅ
๐‘“(๐‘ฅ) = {
๐‘ฅ
, ๐‘–๐‘“ ๐‘ฅ < 0
๐‘ฅ + 1 , ๐‘–๐‘“ ๐‘ฅ ≥ 0
10) Show that the function
1 + ๐‘ฅ , ๐‘–๐‘“ ๐‘ฅ ≤ 2
๐‘“(๐‘ฅ) = {
is not differentiable at x = 2
5−๐‘ฅ , ๐‘ฅ >2
11) Is the function
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6
[๐‘ฅ]−1
๐‘“(๐‘ฅ) = { ๐‘ฅ−1
−1
, ๐‘ฅ≠1
, ๐‘ฅ=1
Continuous at ๐‘ฅ = 1?
12) Show that the function f is continuous at x = 0 for all values of a. Also find the value of a
for which f is derivable at x = 0 when
๐‘ฅ2 , ๐‘ฅ ≥ 0
๐‘“(๐‘ฅ) = {
๐‘Ž๐‘ฅ , ๐‘ฅ < 0
13) Examine the continuity of the function ๐‘“(๐‘ฅ) = ๐‘ก๐‘Ž๐‘›−1 (3๐‘ฅ 3 − 2๐‘ฅ + 1)
๐œ‹
๐‘ ๐‘–๐‘› 2๐‘ฅ , 0 < ๐‘ฅ < 6
14) If ๐‘“(๐‘ฅ) = {
๐œ‹
๐‘Ž๐‘ฅ + ๐‘ , 6 < ๐‘ฅ < 1
Is continuous and differentiable. Find a & b
1
๐‘’ ๐‘ฅ −1
15) Find whether the function ๐‘“(๐‘ฅ) = {๐‘’ ๐‘ฅ1 +1 , ๐‘ฅ ≠ 0
0
,๐‘ฅ = 0
16) Find whether the function ๐‘“(๐‘ฅ) = {
๐‘ฅ 4 −5๐‘ฅ 2 +4
|(๐‘ฅ−1)(๐‘ฅ−2)|
is continuous?
, ๐‘ฅ ≠ 1,2
6
, ๐‘ฅ=1
12
, ๐‘ฅ=2
17) Find the value of derivative at x = 2 of the function
๐‘“(๐‘ฅ) = |๐‘ฅ − 1| + |๐‘ฅ − 3|
18. Find the derivative of the following w.r.t.x.
1
1)
y=log (1+๐‘ฅ) .
2)
3)
4)
y=sin(xx).
y=xsiny.
xy=ex-y
5)
6)
y=๐‘’ ๐‘ฅ .
y=(sin-1x)2.
7)
y=sin-11+4๐‘ฅ .
8)
y=sin-1 (๐‘+๐‘Ž cos ๐‘ฅ)
9)
y=btan-1 [ ๐‘Ž + tan ๐‘ฆ/๐‘ฅ].
2
2๐‘ฅ+1
๐‘Ž+๐‘ cos ๐‘ฅ
๐‘ฅ
10) y =
๐‘ก๐‘Ž๐‘›−1 ๐‘ฅ
(1+√1−๐‘ฅ2 )
11) y=sin-1 [x2√1 − ๐‘ฅ 2 +x√1 − ๐‘ฅ 4
12) y = Cosx(xx)
13) y = ๐‘’ −๐‘Ž๐‘ฅ
19. ๐‘ฅ =
๐‘ ๐‘–๐‘›3 ๐‘ฅ
√๐‘๐‘œ๐‘ 2๐‘ก
2 ๐‘™๐‘œ๐‘”๐‘ ๐‘–๐‘›๐‘ฅ
,๐‘ฆ =
๐‘๐‘œ๐‘ 3 ๐‘ฅ
√๐‘๐‘œ๐‘ 2๐‘ก
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7
๐‘‘๐‘ฆ
20. If xpyq = (x + y)pq then show that ๐‘‘๐‘ฅ =
21. Differentiate (sinx)x w.r.t. xsinx
๐‘ฆ
๐‘ฅ
is continuous?
23. If x = asin2t(1 + cos2t) & y = bcos2t(1 - cos2t) Show that
24. Differentiate cos-1[
25. Differentiate sin2x
3 cos ๐‘ฅ−4 sin ๐‘ฅ
5
๐‘‘๐‘ฆ
๐‘‘๐‘ฅ
=
๐‘
๐‘Ž
] w.r.t.x.
w.r.t. ecosx.
26. Show that y = ๐‘1 ๐‘ฅ + ๐‘2 −๐‘ฅ is the general solution of
๐‘‘๐‘ฆ
๐‘‘2 ๐‘ฆ
๐‘‘๐‘ฅ 2
−๐‘ฆ =0
๐‘‘๐‘ฅ
27. prove that the solution of y = x ๐‘‘๐‘ฅ + a ๐‘‘๐‘ฆ is y = cx + a/c.
๐‘‘2 ๐‘ฆ
๐‘ฅ
1
๐‘Ž
28. if y = xlog(๐‘Ž+๐‘๐‘ฅ), Prove that ๐‘‘๐‘ฅ 2 = ๐‘ฅ (๐‘Ž+๐‘๐‘ฅ)
2
29. Differentiate y = log7(log x) w.r.t.x.
30. Differentiate y = sin (√๐‘๐‘œ๐‘ √๐‘ฅ) w.r.t. x.
31. Differentiate y = √๐‘Ž + √๐‘Ž + ๐‘ฅ w.r.t. x.
√๐‘ฅ+√๐‘Ž
),
√๐‘Ž๐‘ฅ
32. Differentiate y = tan-1 (1−
Π
w.r.t. x.
๐‘ฅ
33. Differentiate y = log๏ปtan ( 4 + 2)๏ฝ w.r.t. x.
34. Verify Rolle’s Theorem for f(x) = log (x2+2) - log3 on [-1,1]
Π
35. Verify Rolle’s Theorem for f(x) = Sin4 x + cos4x in[0, 2 ]
36. Verify Rolle’s Theorem for f(x) = e-xSinx in [0, Π]
37). Verify LMV Therorem for f(x) = Sinx - Sin2x on [0,π]
38).Find a point on the Parabola y = (x - 3)2 where the tangent is parallel to the
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8
Chord joining (3 , 0) and (4 , 1)
at t =
๐œ‹
4
CHAPTER -6
APPLICATIONS OF DERIVATIES
Page
9
1. Show that the rate of change of the perimeter of a square is 4 times the rate of change the
length of its sides.
2. Using differentials , find the approximate value of logโ‚‘ 4.01, given that logโ‚‘ 4 = 1.3863
3. The pressure p and the volume v of a gas are connected by the relation pv = 1.4 = constant.
Find the percentage error in p corresponding to a decrease of 1/2 % in v.
4. If there is an error of 2% in measuring the length of a simple pendulum, then find the
percentage error in its time period.
5. While measuring the side of an equilateral triangle, an error of 5% is made. Find the
percentage error in its area.
6. For what value of x is the rate of increase of x3 - 5x2 + 8 is twice the rate of increase of x?
7. If the rate of change of area of a circle is equal to the rate of change of its diameter, find the
radius.
8. The side of an equilateral triangle is increasing at the rate of 1/3 cm/sec. Find the rate of
increase of its perimeter.
9. Find “a” for which f(x) = a (x + sin x) +a is increasing.
10. Let g(x) = f(x) + f (2๐‘Ž − ๐‘ฅ) and f ’’(x) > 0 for all x ๐œ– [0,2a] then g(x) increasing or
decreasing on [0 , a] ?
11. Let f(x) = tan-1 g(x), where g(x) is monotonically increasing for 0 < x < π/2, then find f(x) is
increasing or decreasing on (0 , π/2).
12. Find whether the function f(x) = tan-1(sinx + Cos x) on [0 , π/4] is either strictly increasing or
strictly decreasing..
13. For what value of ‘λ’ for which the function f(x) = cos x - 2λx is monotonic decreasing.
14. Find the value of ‘a’ for which function f(x) = logax is increasing on R.
15. If the slope of tangent to curve y = x3 + ax + b at (1, -6) is -1. Find a & b.
16. If x + y = k is normal to the curve y2 = 12x, then find the value k.
17. Find the point at the curves x2=y and y2=x cut orthogonally.
๐‘ฅ
18. Find whether the function ๐‘“(๐‘ฅ) = 1+|๐‘ฅ| is increasing or decreasing
19. Is the function f(x)=2x is strictly increasing on R?
20. Find the angle of intersection of the curves xy=a2 and x2-y2=2a2.
21. Find the condition for which the curve y=aex and y=be-x cut orthogonally.
22. Find the slope of tangent of curve y=3x2+4x at the point whose abscissa is -2 ?
23. What is the slope of Normal to curve y=2x2+3 Sin x at x=0?
24. If the function f(x) = x2 – kx + 5 is increasing on [2,4] then find the value of k.
25. Find the interval for which the function f(x)=xx is decreasing.
26. A man 2 meters high walks at a uniform speed 6 meters per minute away from a lamp- post,
5 meters high. Find the rate at which the length of its shadow increases.
27. A kite is 120m high and 130m string is out. If the kite is moving away horizontally at the rate
of 52m/sec find the rate at which the string is being paid out.
28. An inverted cone has a depth of 10cm and a base of radius 5cm.Water is poured into it at the
rate of 3/2cc per minute. Find the rate at which the level of water in the cone is rising when
the depth is 4cm.
29. The time T of complete oscillation of a simple pendulum of length l is given by the eq.
๐‘™
T=2π√๐‘” , where g is constant. What is the percentage error in T when l is increased by 1%?
30. Find the approximate value of tan(46) if it is given that 1° = 0.01745
31. A man is walking at the rate of 4.5km/hr. towards the foot of the tower 120m high. At what
rate is he approaching the top of the tower when he is 50m away from the tower?
32. Find the rate of change of the curved surface of a right circular cone of radius r and height h
with respect to the change in radius.
33. Find the angle between the parabola y2=4ax and x2=4by at their point of intersection other
than origin.
34. If y=alogx+bx2+x has its extreme values at ๐‘ฅ = −1 & ๐‘ฅ = 2, then find a & b. Show that a
1
local Minimum value of ๐‘“(๐‘ฅ) = ๐‘ฅ + ๐‘ฅ , ๐‘ฅ ≠ 0 is greater than a local maximum value.
Page
10
35. Find the Absolute maxima and Absolute minimum values of the function
2
1
๐‘“(๐‘ฅ) = ( − ๐‘ฅ) + ๐‘ฅ 3 ๐‘œ๐‘› [−2, −25]
2
36. Determine the Maximum and Minimum Values of the function
๐‘ฆ = 2๐‘๐‘œ๐‘ 2๐‘ฅ − ๐‘๐‘œ๐‘ 4๐‘ฅ, 0 ≤ ๐‘ฅ ≤ ๐œ‹
37. Find the local minimum value of f(x)=3+๏ƒฏx๏ƒฏ, x ฯต R
38. A given quantity of metal is to be cast into a solid half circular cylinder (i.e. with rectangular
base and semicircular ends). Show that in order that the total surface area may be minimum,
the ratio of the length of the cylinder to the diameter of its circular ends is
39. A window has the shape of a rectangle surrounded by an equilateral triangle. If the perimeter
of the window is 12m, find the dimensions of the rectangle that will produce the largest area
of the window.
40. Show that the isosceles triangle of maximum area that can be inscribed in a given circle is an
equilateral triangle.
41. A cylinder box is to be made, which is open at the top and has a given surface area.
Souvenirs of
different life values are to be stared in the box, so we would like to have
maximum volume of the box. What should be the dimensions of cylinder box? Name some
of the values which are important to each person.
42. The total cost ๐’„(๐’™) of planting
๐’™ plants in a garden is given by
๐Ÿ‘
๐Ÿ
๐’„(๐’™) = ๐ŸŽ. ๐ŸŽ๐ŸŽ๐Ÿ“๐’™ − ๐ŸŽ. ๐ŸŽ๐Ÿ๐’™ + ๐Ÿ‘๐ŸŽ๐’™ + ๐Ÿ”๐ŸŽ๐ŸŽ๐ŸŽ. Find the marginal cost, when 200 trees are
planted. Do you think plantation helps in saving the environment?
CHAPTER-7
INTEGRALS
Indefinite Integrals
สƒ
x5√๐‘Ž3 + ๐‘ฅ 3 ๐‘‘๐‘ฅ
1. Evaluate
I=
2. Evaluate
I=
3. Evaluate
I=
๐‘Ž
สƒ √1−๐‘Ž
4. Evaluate
I=
สƒ
5. Evaluate
I=
สƒSec-1x dx
6. Evaluate
I=
สƒ sin(log x)dx
7. Evaluate
I= ∫ (๐‘ฅ 2 +1)(๐‘ฅ 2 +4) ๐‘‘๐‘ฅ
8. Evaluate
I= ∫
๐‘ก๐‘Ž๐‘›2๐‘ฅ
สƒ ๐‘†๐‘’๐‘2๐‘ฅ
๐‘‘๐‘ฅ
√๐‘’
2๐‘ ๐‘’๐‘2๐‘ฅ
๐‘ฅ
2๐‘ฅ
๐‘‘๐‘ฅ
5๐‘ฅ
๐‘ฅ
55 55 5๐‘ฅ ๐‘‘๐‘ฅ
๐‘ฅ
1
3
5
(๐‘ ๐‘–๐‘›๐‘ฅ)4 (๐‘๐‘œ๐‘ ๐‘ฅ)4
๐‘‘๐‘ฅ
9. Evaluate I = สƒ tan x tan2x tan3x dx
10. Evaluate I= สƒ
๐‘ ๐‘–๐‘›2๐‘ฅ
๐‘‘๐‘ฅ
(๐‘Ž+๐‘๐‘๐‘œ๐‘ ๐‘ฅ)2
11. Evaluate I=สƒ √๐‘ ๐‘’๐‘๐‘ฅ − 1 ๐‘‘๐‘ฅ
Page
11
12. Evaluate I= สƒ
๐‘ก๐‘Ž๐‘›๐‘ฅ+๐‘ก๐‘Ž๐‘›3 ๐‘ฅ
2+3 ๐‘ก๐‘Ž๐‘›2 ๐‘ฅ
dx
13. Evaluate
I=สƒ ๐‘ ๐‘–๐‘›๐‘ฅ+√3๐‘๐‘œ๐‘ ๐‘ฅ
14 Evaluate
I=สƒ๐‘’ ๐‘ฅ (๐‘ฅ − ๐‘ฅ 2 + ๐‘ฅ 3 )๐‘‘๐‘ฅ
15. Evaluate
I= สƒ
16. Evaluate
I= สƒ ๐‘ ๐‘–๐‘›4๐‘ฅ ๐‘‘๐‘ฅ
17. Evaluate
I= สƒ sin−1 √๐‘Ž+๐‘ฅ dx
๐‘‘๐‘ฅ
1
2
2
1
(๐‘ ๐‘–๐‘›๐‘ฅ−2๐‘๐‘œ๐‘ ๐‘ฅ)(2๐‘ ๐‘–๐‘›๐‘ฅ+๐‘๐‘œ๐‘ ๐‘ฅ)
๐‘ ๐‘–๐‘›๐‘ฅ
๐‘ฅ
๐‘‘๐‘ฅ
สƒ 1+๐‘ฅ+๐‘ฅ๐‘‘๐‘ฅ +๐‘ฅ
18. Evaluate
I=
19. Evaluate
I= สƒ x(tan-1x)2dx
20. Evaluate
I= สƒ ๐‘ ๐‘–๐‘›๐‘ฅ+๐‘ ๐‘’๐‘๐‘ฅ ๐‘‘๐‘ฅ
21. Evaluate
I= สƒ(๐‘ฅ 2 −2๐‘ฅ๐‘๐‘œ๐‘ ๐›ผ+1)3/2dx
22. Evaluate
I= สƒ
23. Evaluate
I= สƒ
24. Evaluate
I= สƒ(๐‘ฅ+1)(๐‘ฅ 2 +2๐‘ฅ+2) ๐‘‘๐‘ฅ
25. Evaluate
I=
26. Evaluate
I=
2
3
1
๐‘ฅ๐‘๐‘œ๐‘ ๐›ผ+1
√1+๐‘ฅ 2
1−๐‘ฅ 2
๐‘‘๐‘ฅ
1
๐‘ ๐‘–๐‘›4 ๐‘ฅ+๐‘๐‘œ๐‘ 4 ๐‘ฅ
๐‘‘๐‘ฅ
1
๐‘ฅ
สƒ(๐‘ฅ ๐‘ ๐‘–๐‘›๐‘ฅ+๐‘๐‘œ๐‘ ๐‘ฅ)
2
2
๐‘‘๐‘ฅ
สƒ ๐‘ฅ +๐‘ฅ๐‘ฅ +1 ๐‘‘๐‘ฅ
2
27. Evaluate I=
28. Evaluate
4
2
สƒ √๐‘ก๐‘Ž๐‘›๐‘ฅ ๐‘‘๐‘ฅ
I=สƒ3+๐‘ ๐‘–๐‘›2๐‘ฅ ๐‘‘๐‘ฅ
1
29. Evaluate I= สƒ√sin(๐‘ฅ−๐›ผ) ๐‘‘๐‘ฅ
sin(๐‘ฅ+๐›ผ)
30. Evaluate I= สƒ(๐‘’ ๐‘ฅ +1)3
๐‘‘๐‘ฅ
31. Evaluate I= สƒ
√๐‘ฅ 2 +1[log(๐‘ฅ 2 +1)−2๐‘™๐‘œ๐‘”๐‘ฅ]
๐‘ฅ4
๐‘ ๐‘’๐‘๐‘ฅ
32. Evaluate: I= สƒ 1+๐‘๐‘œ๐‘ ๐‘’๐‘๐‘ฅ ๐‘‘๐‘ฅ.
1
33. Evaluate I= สƒ๐‘ ๐‘–๐‘›๐‘ฅ+๐‘ ๐‘–๐‘›2๐‘ฅ ๐‘‘๐‘ฅ.
34. Evaluate I= สƒexsin2xdx
Page
12
35. Evaluate I= สƒx(logx)2dx
1
36. Evaluate I= สƒ๐‘ ๐‘–๐‘›๐‘ฅ+๐‘ก๐‘Ž๐‘›๐‘ฅ ๐‘‘๐‘ฅ
๐‘‘๐‘ฅ
DEFINITE ITEGRALS
๐‘ฅ2
1
37. Evaluate: ∫−1
38. Evaluate
39. Evaluate
1+ ๐‘ฅ 2
2
∫0
1
∫0
๐‘‘๐‘ฅ
๐‘ฅ √2 − ๐‘ฅ dx
1
log( ๐‘ฅ − 1)๐‘‘๐‘ฅ
๐œ‹
๐‘ฅ
40. Evaluate ∫02
๐‘ ๐‘–๐‘›๐‘ฅ+๐‘๐‘œ๐‘ ๐‘ฅ
๐œ‹
๐‘ฅ+
๐œ‹
4
๐œ‹
−
4
4
41. Evaluate ∫
๐‘‘๐‘ฅ
2−๐‘๐‘œ๐‘ 2๐‘ฅ
๐œ‹
๐‘‘๐‘ฅ
๐‘ ๐‘–๐‘›2 ๐‘ฅ
42. Evaluate ∫02
1+๐‘ ๐‘–๐‘›๐‘ฅ๐‘๐‘œ๐‘ ๐‘ฅ
๐‘’
๐‘‘๐‘ฅ
โ”‚๐‘™๐‘œ๐‘”๐‘’ ๐‘ฅโ”‚๐‘‘๐‘ฅ
43. Evaluate ∫1
๐‘’
๐œ‹
√1+๐‘๐‘œ๐‘ ๐‘ฅ
44.Evaluate ∫๐œ‹2
3
๐‘‘๐‘ฅ
(1−๐‘๐‘œ๐‘ ๐‘ฅ)2
3
1.5
[๐‘ฅ 2 ]๐‘‘๐‘ฅ
45. Evaluate ∫0
๐œ‹
2
−๐œ‹
2
โ”‚๐‘ ๐‘–๐‘›๐‘ฅโ”‚๐‘‘๐‘ฅ
46. Evaluate ∫
3
โ”‚๐‘ฅ+2โ”‚
47. Evaluate ∫−3
๐‘ฅ+2
๐‘‘๐‘ฅ
3
2
48. Evaluate ∫−1
โ”‚๐‘ฅ ๐‘ ๐‘–๐‘›๐œ‹๐‘ฅโ”‚๐‘‘๐‘ฅ
1
log(1+๐‘ฅ)
49. Evaluate ∫0
1+๐‘ฅ 2
4
๐‘‘๐‘ฅ
(|๐‘ฅ − 1| + |๐‘ฅ − 2| + |๐‘ฅ − 3|)๐‘‘๐‘ฅ
50. Evaluate ∫1
1
∫−1
Page
13
51. Evaluate as a limit of sum
๐‘Ž
52. Evaluate
∫0
53. Prove that
∫0
54. Evaluate
∫0
55. Evaluate
∫0
2๐œ‹
∞
๐œ‹
๐‘’ −5๐‘ฅ ๐‘‘๐‘ฅ
1−๐‘Ž๐‘ฅ+๐‘ฅ 2
cot −1 (
๐‘Ž
๐‘ฅ๐‘ ๐‘–๐‘›2๐‘› ๐‘ฅ
๐‘ ๐‘–๐‘›2๐‘› ๐‘ฅ+๐‘๐‘œ๐‘ 2๐‘› ๐‘ฅ
1
) ๐‘‘๐‘ฅ
๐‘‘๐‘ฅ = ๐œ‹ 2
1
๐‘™๐‘œ๐‘” (๐‘ฅ + ๐‘ฅ) 1+๐‘ฅ 2 ๐‘‘๐‘ฅ
๐‘ฅ
1−๐‘๐‘œ๐‘ ๐›ผ๐‘ ๐‘–๐‘›๐›ผ
๐‘‘๐‘ฅ
CHAPTER-8
APPLICATION OF INTEGRALS
1. Draw the graphs of the curves y = sinx and y = cosx, 0 ≤ x ≤
๐…
๐Ÿ
. Find the common area
between the above curves with the X-axis.
2. Find the area bounded by the lines ๐’™ + ๐Ÿ๐’š = ๐Ÿ;
๐’š−๐’™=๐Ÿ
and
๐Ÿ๐’™ + ๐’š = ๐Ÿ•.
3. Find the area bounded by the line y=x and the curve y=x3.
4. Find the area bounded by the lines ๐‘ฆ = 1 + โ”‚1 + ๐‘ฅโ”‚, ๐‘ฅ = −2 , ๐‘ฅ = 3 and ๐‘ฆ = 0.
5. Find the area enclosed between the curve y =√๐‘ฅ ๐‘Ž๐‘›d the line ๐‘ฆ = ๐‘ฅ.
6. Find the area bounded by the curve y=eโ”‚xโ”‚ and the line y=3 with X- axis.
7. Find the area bounded by the curve ๐‘ฆ = โ”‚๐‘ก๐‘Ž๐‘›๐‘ฅโ”‚and the line y=√3.
8. Find the area included between the curve y =๐‘ฅ − [๐‘ฅ] and the line ๐‘ฅ = 3 with X &Y axis.
9. Find the area enclosed between the curve y=โ”‚๐‘ ๐‘–๐‘› ๐‘ฅโ”‚ and the line y =
5๐œ‹ 7๐œ‹
[6 ,
6
1
2
๐‘คithin the interval
].
Page
14
10. Find the common area between the curve y = √5 − ๐‘ฅ 2 and the lines ๐‘ฆ = โ”‚๐‘ฅ − 1โ”‚.
CHAPTER -9
DIFFERENTIAL EQUATIONS
๐‘‘๐‘ฅ
1. Solve ๐‘‘๐‘ฆ+๐‘๐‘œ๐‘ ๐‘ฅ๐‘๐‘œ๐‘ ๐‘ฆ=0.
๐‘‘๐‘ฆ 2/3
2. Find the degree and order of the differential equation (1 + 3 ๐‘‘๐‘ฅ )
๐‘‘3 ๐‘ฆ
= (4 ๐‘‘๐‘ฅ 3 )
3. Find the differential equation of the family of curves given by๐‘ฅ 2 + ๐‘ฆ 2 = 2๐‘Ž๐‘ฅ
๐‘‘๐‘ฆ
4. Find the integrating factor of the differential equation ๐‘ฅ ๐‘‘๐‘ฅ − ๐‘ฆ − 2๐‘ฅ 3 = 0
5. Verify that ๐‘ฆ๐‘ฅ = ๐‘ is a solution of the differential equation
(๐‘ฆ๐‘‘๐‘ฅ−๐‘ฅ๐‘‘๐‘ฆ)
(1+๐‘’ ๐‘ฅ )
๐‘ฆ
=0
๐‘’๐‘ฅ
๐‘‘๐‘ฆ
6. Verify that y = √(1−๐‘’ ๐‘ฅ ) is solution of the differential equation ๐‘‘๐‘ฅ =
[(1−๐‘’ ๐‘ฅ )√1−๐‘’ 2๐‘ฅ ]
7. Find the equation of the family of curve whose x and y intercepts of the tangent at any point
p are respectively double the x and y co-ordinates of the same point p respectively.
8. The line normal to a given curve at each point (x, y) on the curve passes through the point
(2,0). If the curve contains the point (2, 3), find its equation. Prove that the curve with the
property that all its normal passes through a constant point is a circle.
9. A population grows at the rate of 8% per year. How long does it takes for the population to
double?
10. Solve: (1+e2x)dy + (1+y2)ex dx=0 , given that y=1 when x=0 .
11. Solve: (1+y2)dx = (tan-1y−x)dy.
12. Solve the differential equation (
13. Prove
that
the
solution
๐‘’ −2√๐‘ฅ
√๐‘ฅ
of
Page
15
๐‘ฆ 3 √1 − ๐‘ฅ 6 − ๐‘ฅ 3 √1 − ๐‘ฆ 6 = constant.
๐‘‘๐‘ฆ
2
14. Solve: ๐‘ฅ๐‘™๐‘œ๐‘”๐‘ฅ ๐‘‘๐‘ฅ + ๐‘ฆ = ๐‘ฅ ๐‘™๐‘œ๐‘”๐‘ฅ
−
๐‘ฆ
√
๐‘‘๐‘ฅ
) = 1, ๐‘ฅ ≠ 0
๐‘ฅ ๐‘‘๐‘ฆ
the
differential
equation
๐‘‘๐‘ฆ
๐‘ฅ2
1−๐‘ฆ 6
= √
๐‘‘๐‘ฅ ๐‘ฆ 2 1−๐‘ฅ 6
is
๐‘‘๐‘ฆ
15. Solve: (๐‘ฅ + ๐‘ฆ + 1) ๐‘‘๐‘ฅ =1
16.
๐‘‘๐‘ฆ
Solve: ๐‘ฅ ๐‘‘๐‘ฅ = y(logy−logx+1)
17. Solve (๐‘ฅ√๐‘ฅ 2 − ๐‘ฆ 2 − ๐‘ฆ 2 )๐‘‘๐‘ฅ + ๐‘ฅ๐‘ฆ๐‘‘๐‘ฆ = 0.
18. A bank pays interest by continuous compounding that is by treating the interest rate as the
instantaneous rate of change of the principal. Suppose that in an account the interest at 8%
per year compounded continuously. Calculate the percentage increase in such an account
over one year. (Take e0.08=1.08333 approximately.)
19. Solve the differential equation
20. Solve the differential equation
๐‘‘2 ๐‘ฅ
๐‘‘๐‘ฆ 2
๐‘‘2 ๐‘ฆ
๐‘‘๐‘ฅ 2
= 1 + ๐‘ ๐‘–๐‘›๐‘ฆ, given that ๐‘ฅ = 0 and
๐‘‘๐‘ฅ
๐‘‘๐‘ฆ
= 0 when y=0.
๐‘‘๐‘ฆ
= ๐‘ฅ๐‘’ ๐‘ฅ , given that ๐‘ฆ = 0 and ๐‘‘๐‘ฅ = 0 when x=0.
๐‘ฆ
๐‘ฆ
21. Solve (๐‘ฅ๐‘‘๐‘ฅ − ๐‘ฆ๐‘‘๐‘ฅ)sin(๐‘ฅ ) = (๐‘ฆ๐‘‘๐‘ฅ + ๐‘ฅ๐‘‘๐‘ฆ)๐‘ฅ๐‘๐‘œ๐‘  (๐‘ฅ )
22. Solve the differential equation √1 − ๐‘ฆ 2 dx=(sin-1y−x)dy.
23. Show that the differential equation
๐‘‘๐‘ฆ
(๐‘ฅ − ๐‘ฆ)๐‘‘๐‘ฅ = ๐‘ฅ + 2๐‘ฆ is homogenous and solve it.
๐‘‘๐‘ฆ
24. Find a particular solution of the differential equation ๐‘‘๐‘ฅ + ๐‘ฆ๐‘๐‘œ๐‘ก๐‘ฅ = 4๐‘ฅ๐‘๐‘œ๐‘ ๐‘’๐‘๐‘ฅ (๐‘ฅ ≠ 0) given
๐œ‹
Page
16
that y=0 when x= 2 .
CHAPTER-10
VECTORS
1. Find a unit vector parallel to XY – plane and perpendicular to the vector 4i-3j+k
โƒ— ๏ƒฏ = √26, ๏ƒฏโƒ—๐’ƒ๏ƒฏ = 7 and๏ƒฏ๐’‚
โƒ— × โƒ—๐’ƒ๏ƒฏ=35, find ๐’‚
โƒ— โˆ™ โƒ—๐’ƒ
2. If ๏ƒฏ๐’‚
3. Write number of unit vectors perpendicular to ๐‘–ฬ‚ + ๐‘—ฬ‚ ๐‘Ž๐‘›๐‘‘ ๐‘—ฬ‚ + ๐‘˜ฬ‚.
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ— = โƒ—0.
4. If G is the centroid of the triangle ๐ด๐ต๐ถ.Show that ๐‘ฎ๐‘จ
๐‘ฎ๐‘ฉ + ๐‘ฎ๐‘ช
5. If โƒ—๐’‚ is a non-zero vector of magnitude a then find the value of ๐œ† if ๐œ† โƒ—๐’‚ is a unit vector.
6. Show that the sum of three vectors determined by the medians of a triangle directed from the
vertices is zero.
7. Prove that the lines joining the mid-points of two opposite sides and the mid-points of the
diagonals of a quadrilateral form a parallelogram.
8. Show that the straight line joining the mid points of non-parallel sides of a trapezium is
parallel to the parallel sides and half of their sum.
9. Use the vector method to prove that the lines joining the vertices of a tetrahedron to the
centroids of the opposite faces are concurrent.
10. Find all the values of ๐œ† such that (๐‘ฅ, ๐‘ฆ, ๐‘ง)๏‚น(0,0,0)and (๐‘–ฬ‚ + ๐‘—ฬ‚ + 3๐‘˜ฬ‚)๐‘ฅ + (3๐‘–ฬ‚ − 3๐‘—ฬ‚ + ๐‘˜ฬ‚)๐‘ฆ +
(−4๐‘–ฬ‚ + 5๐‘—ฬ‚)๐‘ง = ๐œ†(๐‘ฅ๐‘–ฬ‚ + ๐‘ฆ๐‘—ฬ‚ + ๐‘ง๐‘˜ฬ‚)
11. Prove that the middle point of the hypotenuse of a right angled triangle is equidistant from its
vertices.
12. In a triangle ๐ด๐‘‚๐ต, angle AOB=900.If Pand Q are the points of trisection of AB, show that
OP2 + OQ2 =
5
9
AB2.
โƒ— , show that ๏ƒฏ๐‘Ž × ๐‘–ฬ‚๏ƒฏ2 + ๏ƒฏ๐‘Ž × ๐‘—ฬ‚๏ƒฏ2 + ๏ƒฏ๐‘Ž × ๐‘˜ฬ‚๏ƒฏ2 = 2๏ƒฏ๐‘Ž๏ƒฏ2.
13. For any vector ๐’‚
14. If ๐ด, ๐ต, ๐ถ, ๐ท are four points such that
โƒ— ), ๐ต๐ถ
โƒ— ).
โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘–โƒ— − 2๐‘— and โƒ—โƒ—โƒ—โƒ—โƒ—
๐ด๐ต = m (2๐‘– −6๐‘—+2๐‘˜
๐ถ๐ท= n(−6๐‘– + 15๐‘— −3๐‘˜
Find the conditions of the scalars m, n such that CD intersects AB at the same point E. Also
find the area of the triangle BCE.
Page
17
15. If ๐ด, ๐ต, ๐ถ, ๐ท be any four points in space prove that
โƒ—โƒ—โƒ—โƒ—โƒ— × โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ— × โƒ—โƒ—โƒ—โƒ—โƒ—
๏ƒฏ๐ด๐ต
๐ถ๐ท × ๐ต๐ถ
๐ด๐ท × โƒ—โƒ—โƒ—โƒ—โƒ—
๐ถ๐ด × โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐ต๐ท๏ƒฏ = 4(๐ด๐‘Ÿ๐‘’๐‘Ž ๏„ ABC).
โƒ—โƒ—โƒ—โƒ—โƒ— = 10๐‘Ž + 2๐‘โƒ— and ๐‘‚๐ถ
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘โƒ— where O is origin. Let p denote the area of the
16. Let โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ด = ๐‘Ž , ๐‘‚๐ต
quadrilateral OABC and q denote the area of the parallelogram with OA and OC as adjacent
sides. Prove that p = 6q
17. Prove that the lines joining the vertices of a tetrahedron to the centroids of opposite faces are
concurrent.
18. Points F and E are taken on the sides BC and CD of a parallelogram ABCD such that
โƒ—โƒ—โƒ—โƒ— ๏ƒฏ = ๏ญ โˆถ 1 and ๏ƒฏDE
โƒ—โƒ—โƒ—โƒ— ๏ƒฏ = ๐œ† โˆถ 1
โƒ—โƒ—โƒ—โƒ— ๏ƒฏ: ๏ƒฏFC
โƒ—โƒ—โƒ—โƒ—โƒ— ๏ƒฏ: ๏ƒฏEC
๏ƒฏBF
point O.
The straight lines FD and AR intersect at the
โƒ—โƒ—โƒ—โƒ—โƒ— |: |โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
Find the ratio of |FO
OD|.
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘โƒ—, ๐ด๐ท
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘‘ , ๐ด๐ถ
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘š๐‘โƒ— + ๐‘๐‘‘ . Show that the area
19. ABCD is a quadrilateral such that ๐ด๐ต
1
of quadrilateral ABCDE is 2๏ƒฏm + p๏ƒฏ๏ƒฏ๐‘โƒ—×๐‘‘ ๏ƒฏ.
20. The vector −๐‘–ฬ‚ + ฤต + ๐‘˜ฬ‚ bisects angle between the vectors ๐‘โƒ—โƒ— and 3๐‘–ฬ‚ + 4๐‘—ฬ‚. Determine unit vector
along ๐‘โƒ—โƒ— .
21. If ๐‘Žฬ‚ ๐‘Ž๐‘›๐‘‘ ๐‘ฬ‚ are two unit vectors and ๐œƒ is the angle between them, then show that
๐‘†๐‘–๐‘›
๐œƒ 1
= |๐‘Žฬ‚ − ๐‘ฬ‚ |
2 2
22. If ๐‘Ž
โƒ—โƒ—โƒ— , โƒ—โƒ—โƒ—
๐‘ , ๐‘โƒ—โƒ— are the position vectors of three non collinear points A, B, C respectively. Prove
that ๐‘Ž
โƒ—โƒ—โƒ—โƒ— × โƒ—โƒ—โƒ—
๐‘ + โƒ—โƒ—โƒ—โƒ—
๐‘ × ๐‘โƒ—โƒ— + ๐‘โƒ—โƒ—โƒ— × ๐‘Ž
โƒ—โƒ—โƒ—โƒ— is perpendicular to plane ABC.
23. For any three vectors ๐‘Ž
โƒ—โƒ—โƒ— , โƒ—โƒ—โƒ—
๐‘ , ๐‘โƒ—โƒ— prove that [๐‘Ž
โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—
๐‘ , โƒ—โƒ—โƒ—โƒ—
๐‘ + ๐‘โƒ—โƒ— , ๐‘โƒ—โƒ—โƒ— + ๐‘Ž
โƒ—โƒ—โƒ—โƒ— ] = 2[๐‘Ž
โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ— × ๐‘โƒ—โƒ— ) + โƒ—โƒ—โƒ—โƒ—
24. Prove that ๐‘Ž
โƒ—โƒ—โƒ—โƒ— × (๐‘
๐‘ × (๐‘โƒ—โƒ— × โƒ—โƒ—โƒ—
๐‘Ž ) + ๐‘โƒ—โƒ—โƒ— × (๐‘Ž
โƒ—โƒ—โƒ— × โƒ—โƒ—โƒ—
๐‘)=0
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18
โƒ—โƒ—โƒ—
25. Prove that [ ๐‘Ž
โƒ—โƒ—โƒ—โƒ— × ๐‘
โƒ—โƒ—โƒ—โƒ— × ๐‘โƒ—โƒ—
๐‘
๐‘โƒ—โƒ—โƒ— × ๐‘Ž
โƒ—โƒ—โƒ—โƒ— ] = [ ๐‘Ž
โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—
๐‘
2
๐‘โƒ—โƒ—โƒ— ]
โƒ—โƒ—โƒ—
๐‘
๐‘โƒ—โƒ— ]
CHAPTER-11
THREE DIMENSIONAL GEOMETRY
1. Find the direction of angles of the line joining points. (−1, −5, −10) and the point of
intersection of the line
x−2
3
=
y+1
4
=
z−2
12
and the plane ๐‘ฅ − ๐‘ฆ + ๐‘ง = 5 with ๐‘ฅ, ๐‘ฆ, ๐‘ง axes.
2. Find the perpendicular distance of a vertex of a cube from its one of the diagonal, not passes
through the vertex.
3. Find the distance of the point (−2, 3, −4) from the line
๐‘ฅ+2
3
=
2๐‘ฆ+3
4
=
3๐‘ง+4
5
measured parallel to the plane 4๐‘ฅ + 12๐‘ฆ − 3๐‘ง + 1 = 0
4. Separate the equation ๐‘ฅ๐‘ฆ + ๐‘ฆ๐‘ง = 0 into two planes and find out whether the plane are || or ๏€ ๏ž
to each other.
5. If A(1,2,3) and B (3,6,11) are images to each other w.r.t. a plane. Find the vector equation of
the plane mirror. Find the value of ๐œ† if the plane mirror is ๏ž to 2๐‘ฅ − 3๐‘ฆ + ๐œ†๐‘ง − 5 = 0.
6. Find k, if the plane 2๐‘ฅ − 4๐‘ฆ + ๐‘ง − 7 = 0 contains the line
๐‘ฅ−4=๐‘ฆ−2=
7. Find the point on the line
๐‘ฅ+2
3
=
๐‘ฆ+1
2
๐‘ง−๐‘˜
2
=
๐‘ง−3
2
at a distance 3√2 from the point (1, 2, 3).
8. Find the Direction Cosines of the line joining the images of the point (1, 2, 3) w.r.t ๐‘ฅ๐‘ฆ and ๐‘ฆ๐‘ง
planes.
9. A line makes the same angle ๐œƒ with each of the X and Z axes. If the angle ๐›ฝ, which it makes
with Y axis such that ๐‘ ๐‘–๐‘›2 ๐›ฝ = 3๐‘ ๐‘–๐‘›2 ๐œƒ, then find the value of ๐œƒ.
Page
19
10. Prove that the two planes ๐‘ฅ − 2๐‘ฆ + 2๐‘ง = 6 and 3๐‘ฅ − 6๐‘ฆ + 6๐‘ง = 2 are parallel.
Also
a) find the distance between the planes.
b) find the intercept on the line
๐‘ฅ−1
2
=
๐‘ฆ+1
3
๐‘ง
= −1 between the two planes.
11. What is the direction cosines of a line equally inclined to the axes?
12. What is the equation of Y axis in vector and Cartesian form in three dimensional space?
3
13. If the projection of the line segment on ๐‘‹, ๐‘Œ ๐‘Ž๐‘›๐‘‘ ๐‘ axes are respectively 4, 2 ๐‘Ž๐‘›๐‘‘ 1 then find
the length of the line segment.
14. Find the distance of the point
parallel to the line
๐‘ฅ+3
3
=
๐‘ฆ−2
6
(2,3,4) from the plane 3๐‘ฅ + 2๐‘ฆ + 2๐‘ง + 5 = 0 measured
๐‘ง
=2
15. Find the equation of the line passing through the point (2,3,2) and parallel to the line
โƒ— ) and also find the distance between them.
→ = −2î + 3ฤต + ๐œ†(2๐‘–ฬ‚ − 3๐‘—ฬ‚ + 6๐‘˜
๐‘Ÿ
16. Show that the equation of the plane which meets the axes in A, B and C and the centroid of
๐‘ฅ
๐‘ฆ
๐‘ง
triangle ABC is the point (๐‘ข, ๐‘ฃ, ๐‘ค) is ๐‘ข + ๐‘ฃ + ๐‘ค = 3
17. Find the vector equation of plane which is at a distance of 5 units from the origin and which
has −1, 2, 2 as the direction ratios of a normal to it.
18. A line makes angles ๐›ผ,β,๐›พ and ๐›ฟ with the four diagonals of a cube prove that
8
(i) sin2 ๐›ผ + sin2 ๐›ฝ + sin2 ๐›พ + sin2 ๐›ฟ = 3
2
(ii)๏ƒฅ ๐‘๐‘œ๐‘ 2๐›ผ = − 3
๐œ‹
19. Show that the angle between any two diagonals of a cube is 2 − cosec −1(3)
20. If a point ๐ด(1,2,3)move towards and reaches a line
the point A move towards and reaches a line
Page
20
distance between the two new locations of A.
๐‘ฅ
0
=
๐‘ฅ−6
3
๐‘ฆ−2
−3
=
=
๐‘ฆ−7
2
๐‘ง+3
3
=
๐‘ง−7
−2
in shortest distance and
in shortest distance. Find the
CHAPTER-12
LINEAR PROGRAMMING PROBLEMS
1. Find whether the maximum value of the objective function Z= - x + 2y exists or not, subject
to the following constraints.
x๏‚ณ2
x+y๏‚ณ5
x +2y ๏‚ณ 6 and y ๏‚ณ 0
2. Find whether the minimum value of the objective function Z = -50x + 20y exists or not,
subject to the following constrains
2x - y ๏‚ณ - 5
x+y๏‚ณ3
2x - 3y ๏‚ฃ 12
x ๏‚ณ 0, y ๏‚ณ 0
3. Maximize Z = 2x + 3y
Subject to the constraints
x+y๏‚ณ2
x + 2y ๏‚ณ 3
x ๏‚ณ 0, y ๏‚ณ 0
4. Kellogg is a new cereal formed of a mixture of bran and rice that contains at least 88 gms of
protein and at least 36 mg of iron. Knowing that bran contains 80 gms if protein and 40 mg
of iron per kg, and that rice contains 100 gms of protein and 30 mg of iron per kg, find the
minimum cost of producing this new cereal if bran costs Rs.5/-per Kg and rice Costs Rs.4/per Kg.
5. A brick manufacturer has two depots A and B with stock 30,000 and 20,000 bricks
respectively. He receives orders from 3 buildings P,Q and R for 15,000, 20,000 and 15,000
bricks respectively. The costs of transporting 1,000 bricks to the building from the depot (in
Rs.) are given below.
From/to
P
Q
R
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21
A
40
20
30
B
20
60
40
How should the manufacturer to fulfill the orders so as to keep the cost of transportation
minimum. Solve it graphically.
6. Find the constraints of the L.P.P if its graphical representation is given below and hence
maximize Z = 3x + 9y
7. A manufacturer produces two products A and B during a given period of time. These
products require four different operations, viz. Grinding, Turning, Assembly and Testing.
The requirement in hours per unit of manufacturing of the product is given below.
Operation
A
B
Grinding
1
2
Turning
3
1
Assembly
4
3
Testing
5
4
The available capacities of this operation in hours for the given time are:
Grinding
Assembly
30
200
Turning
Testing
60
200
Profit on each unit of A is Rs.3 , and Rs.2 for each unit of B. Formulate the problem as LPP.
Page
22
8. Constrain of a L.P.P represents the graph given below. Write the constrains and Minimize
Z=6x+7y
9. A retired person has Rs 70,000 to invest in two types of bonds. First type of bond yields an
annual income of 8% on the amount invested and the second type of bond yield 10 % per
annum. As per the norms, he has to invest minimum Rs 10,000 in first type and not more than
Rs 30,000 in second type. How should he plan his investment so as to get maximum return
after one year of investment? Do you think that a person should start saving at an early age of
his retirement? Can you name some avenues?
Page
23
10. A dietician wishes to mix two types of food. X and Y in such a way that the vitamin contents
of the mixture contain at least 8 units of vitamin A and 10 units of vitamin C, Food X contains
2 unit/Kg of vitamin A and 1 unit/Kg of vitamin C, While food Y contains 1 unit/Kg of
vitamin A and 2 unit/Kg of vitamin A and 1 unit/Kg of vitamin C. It costs at Rs 5 per Kg to
purchase the food X and Rs 7 per Kg to purchase food Y. Determine minimum cost of the
mixture. What is your opinion about healthy diet? Name few ingredients; necessary for a
healthy diet.
Chapter -13
PROBABILITY
1) Find the minimum number of tosses of a pair of dice so that the probability of getting the sum
of digits on the dice equal to 7 or at least one toss is greater than
0.95, given
3
2
๐‘™๐‘œ๐‘”10 = 0.3010 & ๐‘™๐‘œ๐‘”10 = 0.4771
2) The sum of mean and variance of a binomial distribution is 15 and their product is 54, find the
distribution.
3
1
2
3) If A and B are events such that p(A∪ ๐ต) = 4, p(๐ด ∩ ๐ต) = 4, ๐‘(ฬ…ฬ…ฬ…ฬ…
๐ด ) = 3 , find ๐‘( ๐ด ∩ ๐ต).
4) Two dice are rolled one after the other .Find the probability that the number on the first is
smaller than the number on the second.
5) A man takes a step forward with probability 0.4 and backward with probability 0.6. Find the
probability that “ at the end of eleven steps, he is one step away from the starting point”.
6) Three numbers are chosen at random without replacement 1,2, 3,……10. Find the probability
that the minimum of the chosen numbering is 3 or their maximum is 7.
7.) In a bolt factory three machines A, B, and C, where A produces one- fourth, C produces twofifth of the products. Production of defective products in % by A, B, Care respectively 5, 4
and 2. An item is drawn at random and found to be difficult. What is the probability it was
produced by either A or C.
8.) Two persons A and B throw a pair of dice alternately beginning with A. If cos ๐›ผ represents
the probability that B gets a doublet and wins before A gets a total of 9 to win. Find ๐›ผ
9.) A bag contains 6 red and 5 blue and another bag contains 5 red and 8 blue balls. A ball is
drawn at random from the first bag and without noticing its colour is put in the second bag.
A ball is then drawn from the second bag. Find the probability that the ball drawn from the
second bag is blue in colour.
10) A, B, and c throw a die alternatively till one of them gets any number “more than 4”and wins
the game. Find their respective probabilities of winning if A starts the game followed by B
and C.
Page
24
11) One letter has to come from “LONDON” or “CLIFTON”. Only ON is seen on the post mark,
find the probability of this letter from LONDON.
12 Three stamps have been selected from 21 stamps which are marked from 1 to 21. Find the
probability the numbers on selected stamps are in A.P.
13 A bag contains 3 red balls bearing one of the 1, 2, 3(one number on one ball) and two black
balls bearing the numbers 4 or 6. A ball is drawn and its number is noted and the ball is
replaced in the bag. Then another ball is drawn and its number is noted. Find the probability
of drawing:
i.
ii.
iii.
2 on the first draw and 6 on the second draw.
A number ≤2 on the first draw and 4 on the second draw.
A total of 5.
14. In an examination, an examinee either guesses or copies or knows the answer of multiple
choice questions with four choices. The probability that he makes a guess is 1/3 and the
probability that he copies the answer is 1/6. The probability that his answer is correct given
that he copied it is 1/8. Find the probability that he knew the answer to the question, given
that he correctly answered it.
15. In a class having 60% boys, 5% of the boys and 10% of the girls have an I.Q. more than 150.
A student is selected at random and found to have an I.Q. of more than 150. Find the
probability that the selected student is a boy.
16. Find the probability distribution of the numbers of kings drawn when 2 cards are drawn one
by one without replacement from a pack of 52 playing cards.
17. A bag contains 5 white, 7 red and 8 black balls. If 5 balls are thrown one by one with
replacement, find the probability distribution that exactly 5 red balls drawn.
18. A speaks truth in 60% of the cases and B in 90% of cases. In what percentage of cases are
they likely to contradict each other in stating the same fact? Which value A is lacking and
should improve upon?
19. There is a group of 100 people who are patriotic, out of which 70 believe in non-violence.
Two persons are selected at random out of them. Write the probability distribution for the
selected person who is non-violent? Also find the mean of distribution. Explain the
importance of non-violence in patriotism.
Page
25
20. India plays two matches. The probability of India getting points 0, 1 & 2 are 0.45, 0.05 &
0.50 respectively. Find the probability of India getting at least 7 points in serves.
ANSWERS/HINTS
Chapter 1
1) f is not onto
2)e = -1
3๐‘ฅ
10) ๐‘“ −1 (๐‘ฅ) = 2−5๐‘ฅ
3)No inverse
7) ๐‘“ −1 (๐‘ฅ) = √4 − ๐‘ฅ 2
6) 2
11)๐‘“ −1 (๐‘ฅ) = √๐‘ฅ
Chapter 2
4 −3
8
2) ๐‘ฅ = 3 ,
๐›ผ+๐›ฝ
4) x = -1
6) ๐‘ฅ = 1−๐›ผ๐›ฝ
2) 0
3)[
9)
6๐œ‹
7
๐œ‹
14) 2
15) 0.96
Chapter 3
1) -3
2
0 −3
1
11) ๐ด−1 = − 5 [ 1 −1 0 ]
−2 −1 2
30 −4
]
−12 6
13) A+B
4) Identity matrix of order 2.
14) Zero
6) Null matrix
1 2
15)๐ต = [ 1 3 ]
2
2
Chapter 4
1
๐‘Ž
0 0
1) ๐ด−1 = 0
1
๐‘
0
[0
0
1
๐‘]
7) 20736
19) Zero
2) 1296
3) ±8
4) ๐œƒ =
๐œ‹
6
5) Zero
6) 21
8) Zero
11) ๐‘ฅ = 0, 3๐‘Ž
12) Zero
15) ๐‘ฅ = 2, ๐‘ฆ = −1, ๐‘ง = −2
4๐‘ฅ + 3๐‘ฆ + 2๐‘ง = 15000
4 3 2 ๐‘ฅ
15000
5๐‘ฅ + 4๐‘ฆ + 3๐‘ง = 19000
20) (i) [5 4 3] [๐‘ฆ] = [19000]
๐‘ฅ + ๐‘ฆ + ๐‘ง = 5000
1 1 1 ๐‘ง
5000
(ii) Equally, to each value, as each value has its own importance in life.
Chapter – 5
4. Continuous at x = 0 Derivable only at x = 0
5) Continuous
6) a = 8
7) a =
3, b = 2
8) Continuous at x = 0
9) No point of discontinuity
11)
Discontinuous 12) Continuous for all values of a
13) yes continuous for all x ∈ R 14) a = 1, b =
3
√ , -π/6
2
15) ( 0, ∞ )
Page
26
18)
a) x + 1
b) [ cos xx { xx(1 + log x) } ]
c) y/[x(1- xcosy)]
d)
๐‘ฅ−๐‘ฆ
๐‘ฅ( 1+log ๐‘ฅ )
e) 2๐‘ฅ ๐‘’ ๐‘ฅ
2
16) Continuous at R – { 1 , 2 }
17) F-1(2) = 0
f)
2๐‘ ๐‘–๐‘›−1 x
√1−๐‘ฅ 2
g) (2x+1log2)/(1+ 4x)
h) –√(๐‘ 2 − ๐‘Ž2 )/(๐‘ + ๐‘Ž๐‘๐‘œ๐‘ ๐‘ฅ)
i)
j)
k)
l)
1
๐‘Ž−๐‘ฆ
2
๐‘ฅ +๐‘ฆ2
๐‘ฆ
๐‘ฅ
2
๐‘†๐‘’๐‘
−
๐‘ ๐‘ฅ2
+ ๐‘ฆ2
1
2√1− ๐‘ฅ 2
1
2๐‘ฅ
√1− ๐‘ฅ 2
√1− ๐‘ฅ 4
+
cosx(x)x[logcos xx - xtan xx{ xx(1 + logx) } ]
2
m) –๐‘’ −๐‘Ž๐‘ฅ ๐‘™๐‘œ๐‘”๐‘ ๐‘–๐‘›๐‘ฅ [ax2cotx + 2axlogsinx]
19). –coxt/sint [(cos2t – 3sin2t)/ 3cos2t – sin2t)]
21)
๐‘‘๐‘ฆ1
๐‘‘๐‘ฆ2
=
(๐‘ ๐‘–๐‘›๐‘ฅ)๐‘ฅ [๐‘ฅ ๐‘๐‘œ๐‘ก๐‘ฅ+log ๐‘†๐‘–๐‘›๐‘ฅ]
๐‘ฅ sin ๐‘ฅ [
๐‘†๐‘–๐‘›๐‘ฅ
+๐‘๐‘œ๐‘ ๐‘ฅ๐‘™๐‘œ๐‘”๐‘ฅ ]
๐‘ฅ
30) Cos√๐‘๐‘œ๐‘ √๐‘ฅ .
7
2
๐‘’
25) - 2cosx.e- cos x
24) 1
1
2√๐‘๐‘œ๐‘ √๐‘ฅ
.(
29) log 7 ๐‘ฅ loge x
−๐‘†๐‘–๐‘›√๐‘ฅ
)
2√๐‘ฅ
31)
−1
32) 1 / [2√๐‘ฅ(1 + ๐‘ฅ) ]
4√๐‘Ž+√๐‘Ž+๐‘ฅ.√๐‘Ž+๐‘ฅ
33) Sec x 38) x =
ฯต (3 , 4)
Chapter 6
1) 1.3838
3) 0.7
4) 1%
5) 10%
8) 1 cm/sec.
9) a> 0
10) Decreasing 11) Increasing 12) Strictly increasing
14) a>1
15) a = - 4 , b = - 3
Strictly Increasing
19) yes
24) k ∈ ( ∞ ,2 )
25) (0, 1/e)
29) ½
30)1.03490
6) x = 3, 1/3
16) K = 9
17) (0,0)
0
20) 90 or π/2 21) ab = 1
26) 4m/min
27) 20
7) 1/11
1
13) ๏ฌ ≥ 2
18)
22) -8 23) -1/3
28) [3/8 π] cm/sec
32) ds/dr ={ ะŸ(2r2+ h2)/√๐‘Ÿ 2 + โ„Ž2 }
31) –[45/26]km/hrs
1
−1
33) ๐œƒ = tan
3(๐‘Ž๐‘)3
(๐‘Ž2/3 +๐‘2/3 )
34) a = 2, b = -1/2
35)
Max value 178 at x = 10, Abs mini value 18 at x = 6
value -3 at π/2
37) minimum value 3
36) Max value 3/2 at π/6, 5 π/6 Min
38) π : (π +2)
39) [12/(6-√3)]m. & [(18 - 6√3)/ (6-√3)]m.
41) Radius of base = height of cylindrical box. Honesty, Respectful, punctual, observant
42) 622, yes.
Chapter 7
5
2
3
2
1) 15 (๐‘Ž3 + ๐‘ฅ 3 )2 – 9 ๐‘Ž3 (๐‘Ž3 + ๐‘ฅ 3 )2 + c 2) 5๐‘ฅ
1
55 +
(log 5)3
Page
27
7)
e-sec2x + c
c 5) ๐‘ฅ๐‘ ๐‘’๐‘ −1 ๐‘ฅ − ๐‘™๐‘œ๐‘”|๐‘ฅ + √๐‘ฅ 2 − 1| + ๐‘
1
๐‘ฅ 2 +1
๐‘™๐‘œ๐‘”
|
|+
6
๐‘ฅ 2 +4
−2
(log(๐‘Ž
๐‘2
1
๐‘™๐‘œ๐‘”|2 +
6
1
2
−1
๐‘
8) 4๐‘๐‘œ๐‘ก 4 ๐‘ฅ + ๐‘
๐‘Ž
3๐‘ก๐‘Ž๐‘›2 ๐‘ฅ| + ๐‘
13)
1
log ๐‘Ž
sin-1ax + c
4)
๐‘‹
6) 2 (sin(๐‘™๐‘œ๐‘”๐‘ฅ) − cos(๐‘™๐‘œ๐‘”๐‘ฅ)) + ๐‘
๐‘™๐‘œ๐‘”๐‘ ๐‘’๐‘2๐‘ฅ
− ๐‘™๐‘œ๐‘”๐‘ ๐‘’๐‘๐‘ฅ + c
2
1
11) – ๐‘™๐‘œ๐‘” |๐‘๐‘œ๐‘ ๐‘ฅ + 2 + √๐‘๐‘œ๐‘ 2๐‘ฅ + ๐‘๐‘œ๐‘ ๐‘ฅ| +
1
๐œ‹
๐œ‹
๐‘™๐‘œ๐‘” |๐‘๐‘œ๐‘ ๐‘’๐‘ (๐‘ฅ + 3 ) − ๐‘๐‘œ๐‘ก (๐‘ฅ + 3 )| + ๐‘
2
9)
+ ๐‘๐‘๐‘œ๐‘ ๐‘ฅ) + ๐‘Ž+๐‘๐‘๐‘œ๐‘ ๐‘ฅ + ๐‘)
3)
๐‘™๐‘œ๐‘”๐‘ ๐‘’๐‘3๐‘ฅ
3
−
10)
๐‘
12)
1
1
14)๐‘’ ๐‘ฅ (๐‘ฅ − ๐‘ฅ 2 ) + ๐‘
๐‘ฅ
1
๐‘ก๐‘Ž๐‘›๐‘ฅ−2
๐‘™๐‘œ๐‘” |2๐‘ก๐‘Ž๐‘›๐‘ฅ+1| +
2
15)
๐‘ฅ
๐‘ฅ
๐‘
๐‘ฅ
17) ๐‘Ž [๐‘Ž ๐‘ก๐‘Ž๐‘›−1 √๐‘Ž − √๐‘Ž + ๐‘ก๐‘Ž๐‘›−1 √๐‘Ž] + ๐ถ
16) 4
18)
1
1+√2๐‘ ๐‘–๐‘›๐‘ฅ
1
1+๐‘ ๐‘–๐‘›๐‘ฅ
๐‘™๐‘œ๐‘” |1− 2๐‘ ๐‘–๐‘›๐‘ฅ| − 8 ๐‘™๐‘œ๐‘” |1−๐‘ ๐‘–๐‘›๐‘ฅ| +
√2
√
1
[๐‘™๐‘œ๐‘”|1 +
2
๐‘
1
๐‘ฅ| − 2 ๐‘™๐‘œ๐‘”|1 + ๐‘ฅ 2 | + ๐‘ก๐‘Ž๐‘›−1 ๐‘ฅ] + ๐‘
2
−1
๐‘ฅ2
−1
2 ) + (๐‘ก๐‘Ž๐‘› ๐‘ฅ)
−
๐‘ก๐‘Ž๐‘›
๐‘ฅ.
๐‘ฅ
+
log
+
๐‘ฅ
(√1
2
2
1
sinx−cosx+√3
−1 (sinx
20) 2 3 ๐‘™๐‘œ๐‘” |cosx−sinx+ 3| + ๐‘ก๐‘Ž๐‘›
+ cosx) + c
√
√
(๐‘ก๐‘Ž๐‘›−1 ๐‘ฅ)2
+๐‘
21)
๐‘๐‘œ๐‘ ๐‘’๐‘ 2 ๐›ผ
√๐‘ฅ 2 −2๐‘ฅ๐‘๐‘œ๐‘ ๐›ผ+1
(๐‘ฅ 2 − ๐‘ฅ๐‘๐‘œ๐‘  2 ๐›ผ − 2๐‘๐‘œ๐‘ ๐›ผ)
22) ๐ผ = ๐‘ฅ + 3๐‘™๐‘œ๐‘”|๐‘ฅ − 4| − 24๐‘™๐‘œ๐‘”|๐‘ฅ − 5| + 30๐‘™๐‘œ๐‘”|๐‘ฅ − 6| + ๐‘
๐‘ก๐‘Ž๐‘›−1 ๐‘ฅ−1
)+
√2๐‘ก๐‘Ž๐‘›๐‘ฅ
23) ๐‘ก๐‘Ž๐‘›−1 (
๐‘
24)๐‘™๐‘œ๐‘” |
๐‘ฅ+1
√(๐‘ฅ 2 +2๐‘ฅ+2)
−1
25) ๐‘ฅ๐‘ ๐‘’๐‘๐‘ฅ (๐‘ฅ๐‘ ๐‘–๐‘›๐‘ฅ+๐‘๐‘œ๐‘ ๐‘ฅ) − ๐‘ก๐‘Ž๐‘›๐‘ฅ + ๐‘
|
๐‘ฅ 2 −1
1
๐‘ฅ 2 −๐‘ฅ+1
)
+
๐‘™๐‘œ๐‘”
|
|+๐‘
4
๐‘ฅ 2 +๐‘ฅ+1
√3
1
1
27) ๐‘๐‘ข๐‘ก
๐‘ก − ๐‘ก = ๐‘ข,
๐‘ก+๐‘ก =๐‘ฃ
๐‘‘๐‘ข
๐‘‘๐‘ข
= ∫ ๐‘ข2 +2 + ∫ ๐‘ข2 +2
1
๐‘ก๐‘Ž๐‘›๐‘ฅ−1
1
๐‘ก๐‘Ž๐‘›๐‘ฅ−√2๐‘ก๐‘Ž๐‘›๐‘ฅ+1
= 2 ๐‘ก๐‘Ž๐‘›−1 ( 2๐‘ก๐‘Ž๐‘›๐‘ฅ ) + 2 2 ๐‘™๐‘œ๐‘” |๐‘ก๐‘Ž๐‘›๐‘ฅ+ 2๐‘ก๐‘Ž๐‘›๐‘ฅ+1| + ๐‘
√
√
√
√
1
−1 3๐‘ก๐‘Ž๐‘›๐‘ฅ+1
−1 ๐‘๐‘œ๐‘ ๐‘ฅ
28) 2 2 ๐‘ก๐‘Ž๐‘› ( 2 2 ) + ๐‘
29) −๐‘ ๐‘–๐‘› (๐‘๐‘œ๐‘ ๐›ผ) + ๐‘™๐‘œ๐‘”|๐‘ ๐‘–๐‘›2๐‘ฅ
√
√
๐‘ฅ
1
26) 2 ๐‘ก๐‘Ž๐‘›−1 ( ๐‘ฅ
+ √๐‘ ๐‘–๐‘›2 ๐‘ฅ−๐‘ ๐‘–๐‘›2 ๐›ผ| + ๐‘
๐‘™๐‘’๐‘ก ๐‘ก = ๐‘’ + 1
30)
1
1
−๐‘™๐‘œ๐‘”๐‘ก + ๐‘ก + 2๐‘ก 2 + log(๐‘ก − 1) + ๐‘
1
1
− log(๐‘’ ๐‘ฅ + 1) + (๐‘’ ๐‘ฅ +1) + 2(๐‘’ ๐‘ฅ +1)2 + ๐‘ฅ + ๐‘
3
3
1
1
1 2
4
1 2
31) − 3 ๐‘™๐‘œ๐‘” (1 + ๐‘ฅ 2 ) (1 + ๐‘ฅ 2 ) − 9 (1 + ๐‘ฅ 2 ) + ๐‘
32) ๐ฟ๐‘œ๐‘”(1 + ๐‘ ๐‘’๐‘๐‘ฅ) + ๐‘
1
1
1
2
33) 2 log(๐‘๐‘œ๐‘ ๐‘ฅ + 1) + 6 log(๐‘๐‘œ๐‘ ๐‘ฅ − 1) − 6 log(2๐‘๐‘œ๐‘ ๐‘ฅ + 1) + ๐‘
34) 5 ๐‘’ ๐‘ฅ (๐‘ ๐‘–๐‘›2๐‘ฅ + ๐‘๐‘œ๐‘ 2๐‘ฅ) + ๐‘
๐‘ฅ2
๐‘ฅ2
๐‘ฅ2
1 1+๐‘๐‘œ๐‘ ๐‘ฅ
1
35) (๐‘™๐‘œ๐‘”๐‘ฅ)2 − ๐‘™๐‘œ๐‘”๐‘ฅ + + ๐‘
36) log(๐‘๐‘œ๐‘ ๐‘’๐‘๐‘ฅ − ๐‘๐‘œ๐‘ก๐‘ฅ) + (
)−
+๐‘
2
2
4
4 1−๐‘๐‘œ๐‘ ๐‘ฅ
2(1+๐‘๐‘œ๐‘ ๐‘ฅ)
๐œ‹
37) 2 − 2
38)
2
43) 2 − ๐‘’
39) Zero
๐œ‹
50)
40)
45) √2 ( √2 − 1)
44) 1
49) 2 ๐‘™๐‘œ๐‘”2
55)
16√2
15
19
2
1
51) 5 (๐‘’ 5 − ๐‘’ −5 )
๐œ‹
√2+1
๐‘™๐‘œ๐‘” | 2−1|
4 √2
√
46) 2
41)
√3 2
๐œ‹
18
๐œ‹
3√3
1
3
48) ๐œ‹2 + ๐œ‹
42)
47) 4
52) 2a๐‘ก๐‘Ž๐‘›−1 ๐‘Ž − log(1 + ๐‘Ž2 )
54) ๐œ‹๐‘™๐‘œ๐‘”2
4)13.5
6)
๐œ‹(๐œ‹−๐›ผ)
๐‘ ๐‘–๐‘›๐›ผ
Chapter 8
1) 2 − √2
2) 6
8) 3/2
9) 6 + (√3 − 2)
10)
2) Order = 3; Degree = 3
3) 2๐‘ฅ๐‘ฆ ๐‘‘๐‘ฆ = ๐‘ฆ 2 − ๐‘ฅ 2
3) ½
๐œ‹
2๐œ‹
√3
5) 1/6
5
1
(๐‘ ๐‘–๐‘›−1 5
2
2
− ๐‘™๐‘œ๐‘”4
1
+ ๐‘ ๐‘–๐‘›−1 5) − 2
Page
28
Chapter 9
1) Sinx + log(Siny)=c
5)
๐‘‘๐‘ฆ
๐‘‘๐‘ฅ
=−
๐‘ฆ
๐‘ฅ
6)
๐‘’๐‘ฅ
√(1−๐‘’ 2๐‘ฅ )(1−๐‘’ ๐‘ฅ )
๐‘‘๐‘ฅ
1
4) ๐‘ฅ
7) Equation of the family of curve is xy = c
19)
25
๐‘™๐‘œ๐‘”2 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ๐‘ 
2
8) (๐‘ฅ − 2)2 + ๐‘ฆ 2 = 9
9)
−1 ๐‘ฆ
(๐‘ก๐‘Ž๐‘›−1 ๐‘ฆ − 1) + ๐‘
11) ๐‘ฅ๐‘’ ๐‘ก๐‘Ž๐‘›
= ๐‘’ ๐‘ก๐‘Ž๐‘›
−1 ๐‘ฆ
12)๐‘ฆ๐‘’ 2√๐‘ฅ = ∫
14) ๐‘ฆ 3 √1 − ๐‘ฅ 6 − ๐‘ฅ 3 √1 − ๐‘ฆ 6 = ๐‘ ๐‘–๐‘›3๐‘
๐‘ฅ+๐‘ฆ
)+
๐‘Ž
17) ๐‘ฆ = ๐‘Ž๐‘ก๐‘Ž๐‘›−1 (
๐‘ฆ2
2
๐œ‹
2
๐‘’ −2√๐‘ฅ 2√๐‘ฅ
๐‘’ ๐‘‘๐‘ฅ
√๐‘ฅ
+๐‘ =
13) (๐‘ฅ − ๐‘Ž)2 + (๐‘ฆ − ๐‘)2 = 2๐‘
2√๐‘ฅ + ๐‘
20) ๐‘ฅ =
10) ๐‘ก๐‘Ž๐‘›−1 ๐‘ฆ + ๐‘ก๐‘Ž๐‘›−1 (๐‘’ ๐‘ฅ ) =
๐‘
− ๐‘ ๐‘–๐‘›๐‘ฆ + ๐‘ฆ
23) ๐‘ฅ = ๐‘ ๐‘–๐‘›−1 ๐‘ฆ − 1 + ๐‘๐‘’ ๐‘ ๐‘–๐‘›
15) 2[
−๐‘™๐‘œ๐‘”๐‘ฅ
๐‘ฅ
1
− ๐‘ฅ] + ๐‘
16) ๐‘ฅ = ๐‘ ๐‘ฆ − ๐‘ฆ − 2
๐‘ƒ1 −๐‘ƒ0
๐‘ƒ0
18)√๐‘ฅ 2 + ๐‘ฆ 2 + ๐‘ฅ๐‘™๐‘œ๐‘”๐‘๐‘ฅ = 0
19)
21) ๐‘ฆ = ๐‘ฅ๐‘’ ๐‘ฅ − 2๐‘’ ๐‘’ + ๐‘ฅ + 2
22) sec (๐‘ฅ ) = ๐‘๐‘ฅ๐‘ฆ
−1 ๐‘ฆ
25) ๐‘ฆ๐‘ ๐‘–๐‘›๐‘ฅ = 2๐‘ฅ 2 −
× 100 = 8.33%
๐‘ฆ
๐œ‹2
2
Chapter 10
1) Vector parallel to XY – plane will be of the form ๐‘Ž๐‘–โƒ— + ๐‘๐‘— . ๐ผ๐‘“ ๐‘–๐‘ก ๐‘–๐‘  ๐‘๐‘’๐‘Ÿ๐‘๐‘’๐‘›๐‘‘๐‘–๐‘๐‘ข๐‘™๐‘Ž๐‘Ÿ ๐‘ก๐‘œ 4๐‘– − 3๐‘— + ๐‘˜โƒ— ,
๐‘กโ„Ž๐‘’๐‘› (4๐‘– − 3๐‘— + ๐‘˜โƒ— ). (๐‘Ž๐‘–โƒ— + ๐‘๐‘—) = 0
=> b =
4๐‘Ž
3
∴ ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ ๐‘–๐‘  ๐‘Ž๐‘– +
4๐‘Ž
๐‘Ž
๐‘— = (3๐‘– + 4๐‘—)
3
3
∴ ๐‘‡โ„Ž๐‘’ ๐‘ข๐‘›๐‘–๐‘ก ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ =
๐‘Ž
(3๐‘–+4๐‘— )
3
๐‘Ž
(√32 +42 )
3
2) |๐‘Ž × ๐‘โƒ—| = 35 ๐‘–. ๐‘’ |๐‘Ž||๐‘|๐‘ ๐‘–๐‘›๐œƒ =
∴ ๐‘๐‘œ๐‘ ๐œƒ = √1 −
1
= ± (3๐‘– + 4๐‘—)
5
5
√26
25
1
=√
26
26
๐‘Ž. ๐‘โƒ— = ๐‘Ž๐‘๐‘๐‘œ๐‘ ๐œƒ = 7
3) 2
4) โƒ—โƒ—โƒ—โƒ—โƒ—
๐บ๐ด + โƒ—โƒ—โƒ—โƒ—โƒ—
๐บ๐ต + โƒ—โƒ—โƒ—โƒ—โƒ—
๐บ๐ถ = โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ด − โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐บ + โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ต − โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐บ + โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ถ − โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐บ
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐‘‚๐ต
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐‘‚๐ถ
โƒ—โƒ—โƒ—โƒ—โƒ— − 3๐‘‚๐บ
โƒ—โƒ—โƒ—โƒ—โƒ—
= ๐‘‚๐ด
= ๐‘Ž + ๐‘โƒ— + ๐‘ −
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29
5) |๏ฌ๐‘Ž| = 1
โŸน
โƒ— +๐‘ )
3( ๐‘Žโƒ—+๐‘
3
|๏ฌ||๐‘Ž| = 1
โƒ—
=0
โŸน
1
๏ฌ = ±๐‘Ž
6) Let ABC be the given triangle. Let AD, BE, CF be the medians. The required sum of vectors is
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—
(๐ด๐ต
๐ต๐ท) + (๐ต๐ถ
๐ถ๐ธ ) + (๐ถ๐ด
๐ด๐น )
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐ต๐ถ
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—
= (๐ด๐ต
๐ถ๐ด) + (๐ต๐ท
๐ถ๐ธ + โƒ—โƒ—โƒ—โƒ—โƒ—
๐ด๐น )
1
1
1
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐ถ๐ด
โƒ—โƒ—โƒ—โƒ—โƒ— ) + ( ๐ต๐ถ
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐ถ๐ด
โƒ—โƒ—โƒ—โƒ—โƒ— + ๐ด๐ต
โƒ—โƒ—โƒ—โƒ—โƒ— )
= (๐ด๐ถ
2
2
2
โƒ—โƒ—โƒ—โƒ—โƒ— + โƒ—โƒ—โƒ—โƒ—โƒ—
โƒ—)
= (๐ด๐ถ
๐ถ๐ด) = (0
7)Let ABCD be any quadrilateral. Let P, R be the midpoints of the sides AB, CD respectively. Let
Q,S be the mid points of the diagonals AC and BD respectively. Let ๐‘Ž, ๐‘โƒ—, ๐‘,
โƒ—โƒ— ๐‘‘ be the position
vectors of A, B, C and D respectively.
Position vectors of
๐‘ƒ=
โƒ—)
(๐‘Žโƒ— +๐‘
2
, โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐‘„ =
(๐‘Žโƒ— +๐‘ )
2
, โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐‘… =
(๐‘ +๐‘‘ )
2
, โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐‘† =
โƒ— +๐‘‘ )
(๐‘
2
, โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘ƒ๐‘„ =
โƒ—)
(๐‘ −๐‘
2
โƒ—โƒ—โƒ—โƒ—โƒ— =
, ๐‘†๐‘…
โƒ—)
(๐‘ −๐‘
2
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘Ž
โƒ—โƒ—โƒ—โƒ—โƒ— = โƒ—โƒ—โƒ—
8) ๐‘‚๐ด
โƒ—โƒ—โƒ— , โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ต = โƒ—โƒ—โƒ—
๐‘ , โƒ—โƒ—โƒ—โƒ—โƒ—
๐‘‚๐ถ = โƒ—โƒ—โƒ—
๐‘ , ๐‘‚๐ถ
๐‘‘
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘š(๐‘ − ๐‘‘), ๐‘‚๐ธ
โƒ—โƒ—โƒ—โƒ—โƒ— =
๐ด๐ต
(๐‘Žโƒ— +๐‘‘ )
2
โƒ—)
(๐‘ +๐‘
โƒ—โƒ—โƒ—โƒ—โƒ— =
, ๐‘‚๐น
2
โƒ—โƒ—โƒ—โƒ—โƒ— =
, ๐ธ๐น
(๐‘š+1)
2
โƒ—โƒ—โƒ—โƒ—โƒ—
๐ท๐ถ
9) let ABCD be the tetrahedron. . Let ๐‘Ž, ๐‘โƒ—, ๐‘,
โƒ—โƒ— ๐‘‘ be the position vectors of the vertices A, B, C and D
respectively. Let ๐บ1 , ๐บ2 , ๐บ3 , ๐บ4 be the centroid of the ABCD
( ๐‘โƒ— + ๐‘ + ๐‘‘ )
(๐‘+๐‘‘+๐‘Ž)
( ๐‘‘ + ๐‘Ž + ๐‘โƒ— )
( ๐‘Ž + ๐‘โƒ— + ๐‘ )
∴ ๐‘‚๐บ1 =
, ๐‘‚๐บ2 =
, ๐‘‚๐บ3 =
, ๐‘‚๐บ4 =
3
3
3
3
∴ ๐‘ƒ. ๐‘‰. ๐‘œ๐‘“ ๐บ =
โƒ— +๐‘
โƒ—โƒ— )
โƒ— +๐‘‘
(๐‘
)+1(โƒ—๐‘Ž)
3
3(
3+1
=
โƒ—โƒ—โƒ— +๐‘
โƒ—โƒ—โƒ— )
โƒ—โƒ— +๐‘‘
( โƒ—โƒ—โƒ—
๐‘Ž +๐‘
4
The symmetry of P.V. of G shows that G also divides the lines ๐ต๐บ2 , ๐ถ๐บ3 , ๐ท๐บ4 in the ratio 3:1
internally.
1−๏ฌ
3
−4
10)| 1
−(3 + ๏ฌ) 5 | = 0
3
1
−๏ฌ
โƒ—โƒ—โƒ—โƒ—โƒ— , ๐ถ๐ธ
โƒ—โƒ—โƒ—โƒ—โƒ— = ๐‘ž๐ถ๐ท
โƒ—โƒ—โƒ—โƒ—โƒ—
14) Let โƒ—โƒ—โƒ—โƒ—โƒ—
๐ธ๐ต = ๐‘๐ด๐ต
โˆต โƒ—โƒ—โƒ—โƒ—โƒ—
๐ธ๐ต + โƒ—โƒ—โƒ—โƒ—โƒ—โƒ—
๐ต๐ท + โƒ—โƒ—โƒ—โƒ—โƒ—
๐ถ๐ท = โƒ—โƒ—0โƒ— โŸน ๐‘ =
Then area of โˆ† ๐ต๐ถ๐ธ =
11
10
1
โƒ—โƒ—โƒ—โƒ—โƒ—
|๐ธ๐ต
2
1
,๐‘ž
2๐‘š
=
โƒ—โƒ—โƒ—โƒ—โƒ—โƒ— | =
× ๐ต๐ท
1
3๐‘›
1
√6
2
2
20) ๐‘ = − 15 ๐‘– − 15 ๐‘— − 15 ๐‘˜
Chapter 11
3
4
12
2
56 43 111
)
17
7) (17 , 17 ,
10) (i)
๐‘ฅ
0
=
๐‘ฆ
1
16
,
9
=
(ii)
๐‘ง
0
√14
9
=๏ฌ
11) (±
8) ๐ท. ๐ถ.′ ๐‘  ๐‘Ž๐‘Ÿ๐‘’
1
1
1
, ± 3 , ± 3)
√3
√
√
is Cartesian form.
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30
ฬ‚ + ๐œ‡( 2๐‘–ฬ‚ − 3๐‘—ฬ‚ + 6๐‘˜
ฬ‚) &
15) ๐‘Ÿโƒ—โƒ— = 2๐‘–ฬ‚ + 3๐‘—ฬ‚ + 2๐‘˜
1
√10
3)
5) x+2y+4z-38 = 0 & ๏ฌ = 1
4) y = 0, x + z = 0 and they are perpendicular to each other,
6) k = 7
√4580
15
2) ๐‘Ž√3 ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ′๐‘Ž′ ๐‘๐‘’ ๐‘กโ„Ž๐‘’ ๐‘ ๐‘–๐‘‘๐‘’
1) ๐‘๐‘œ๐‘  −1 (13) , ๐‘๐‘œ๐‘  −1 (13) , ๐‘๐‘œ๐‘  −1 (13)
, 0,
−3
√10
3
9) ๐‘๐‘œ๐‘  −1 (√5)
12) Equation of Y-axis ๐‘Ÿโƒ—โƒ— = ๏ฌ๐‘—ฬ‚ is vector form &
13)√19.25
√580
7
14) 7 units.
ฬ‚) = 15 20) 4√6
, 17) ๐‘Ÿโƒ—โƒ— . (−๐‘–ฬ‚ + 2๐‘—ฬ‚ + 2๐‘˜
Chapter 12
1) Maximum value does not exist
2) Minimum value does not exist
3) The objective function can be made as large as possible as we please. So the problem has
unbounded solutions.
4) Minimum cost of cereal is Rs. 4 & 60 paise.
5) Minimum transportation cost is Rs. 1,200 when0,20,000,10,000 bricks are transported from the
depot A and 15,000,0,5,000 bricks are transported from the depot B to the building P,Q and R
respectively.
6) Constraints are
๐‘ฅ + ๐‘ฆ ≥ 10
๐‘ฅ + 3๐‘ฆ ≤ 60
๐‘ฅ−๐‘ฆ ≤0
๐‘ฅ, ๐‘ฆ ≥ 0
Maximum value of Z = 180 when x = y = 15
7) Maximize Z = 3x + 2y subject to x + 2y ≤ 30;
3x + y ≤ 60; 4x + 3y ≤ 200; 5x + 4y ≤ 200
X, y ≥ 0
8) Maximum value: 14.
9) Rs 40,000 in 8% bonds and Rs 30,000 in 10% bonds for a maximum return of Rs 6200. One
should start saying at early age of his retirement. Saving bonds, NSC, Mutual funds etc.
10) ๐‘ฅ = 2, ๐‘ฆ = 4, ๐‘…๐‘ . 38, We must take balanced diet for good health. Wheat, Rice, Fruits, nuts etc.
Chapter 13
1 27
2
1) 17
2) (3 + 3)
7)41/49
8) ๐‘๐‘œ๐‘  −1 7
12) 10/133
1
13) (๐‘–) 25
4
2
(ii)
25
(๐‘–๐‘–๐‘–)
6 5
5) 462(25)
3) 5/12
4) 5/12
9) 93/154
10) 19 ,
4
25
14) 24/29
9
6
4
,
19 19
6)11/40
11) 12/17
15) 3/7
16) Probability distribution is
x
P(x)
7 5
7 5
0
1
188
221
2
32
221
1
221
7 5
17) p(x = 5 ) = 5๐‘5 (20) (20) = (20)
18) 42%, He lacks honesty and truthfulness.
19)
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31
X
P(X)
0
29/330
1
140/330
2
161/330
Mean = 1.4
Non-Violence helps in presenting yours views in a calm and better atmosphere without
distributing other activities.
20) 0.0875
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