CH.I Chapter I OPERATORS & PRINCIPLES of WAVE MECHANICS A vector A can be represented as a linear combination of a basis vector iˆ, ˆj , kˆ , i.e., A Ax iˆ Ay ˆj Az kˆ Also it is possible to write a vector in a basis using a column matrix, that is, A x A Ay A z A basis is a set of linearly independent vectors such that every vector in a given vector space can be represented uniquely as a linear combination of these basis vectors. The dot product between two vectors in matrix form is written as A B Ax Ay Bx Az B y Ax Bx Ay B y Az Bz B z And the basis vectors are written in matrix form as 1 iˆ 0 0 0 k̂ 0 1 0 ĵ 1 0 To generalize to the N-dimensional space, a vector a can be written as 1 CH.I N a ai i i 1 Where ai are the components of the vector and i are the basis vectors such that 1 Ψ i Ψ j ij 0 i j i j In the Dirac notations the column vector is written as a a a1 a 2 aN With a is called a ket vector. The adjoint of a is called the bra vector written as a † a a1 a2 a N The dot product is written now as N a b a b aib j ij i 1 Definition: An operator A in a vector space is a rule that maps every function (or every vector a ) into a new function ' (or a new vector) , i.e., Ψ AΨ If the operator A satisfies the relation AΨ a Ψ b AΨ a AΨ b with and are arbitrary complex numbers. Then the operator A is called a linear operator. 2 CH.I b A a Now if with a ai i b bi i and i i b A ai i ai A i i i Multiply the last equation by the bra vector j j b ai j A i i But j b bi j i bi ij b j i i b j ai Aij i with Aij j A i are called the matrix element of the operator A. In matrix form the above equation can be written as b1 A11 b A N N1 A1N a1 ANN a N That is, a linear operator can be represented by a NN matrix in a N-dimensional basis. The linear operators obey the following rules (i) AB C ABC (ii) AB C AB AC (iii) AB BA (not commute) (iv) AB BA is denoted by A, B which called the commutator. If A, B 0 we say that A and B are commute. Def: The adjoint Operator If A a b and a A † † b Then the operator A is called the adjoint operator. In another word we have 3 CH.I a A† b b A a Def: The Hermitian Operator † If A A , the operator A is called Hermitian operator. That is, for Hermitian operator we have a A b b A a Def: The Unitary Operator † If A A 1 , the operator A is called Unitary operator. Now for unitary operator we have AA† A† A AA 1 A1 A 1 Let i be a set of orthonormal bases vectors, then U i i taking the adjoint j j U † multiplying the 1st equation by the 2nd one j i j U †U i † But for unitary operator we have U U 1 j i j i ij The vector i are another orthonormal basis, i.e., the Unitary operator can be regarded as defining a rotation. In another word, under a unitary operator the vector preserves its magnitude and its relative orientation (all scalars are invariant under unitary operations). 4 CH.I i A Exercise: Prove that the operator e is unitary if and only if A is Hermitian. Def: The Projection Operator With each basis vector i we introduce a projection operator Pi. The effect of Pi on an arbitrary vector a is to produce a new vector in the direction of i and its magnitude is i a , i.e., Pi a i a i i i a Pi i i (dyad product) Note that Pi j i j i ij i The basis vectors are eigenvectors of the projection operator with eigen-values of ij . Now we say that a basis is complete if any arbitrary vector can be represented completely in that basis, i.e., if i is complete N N N i 1 i 1 i 1 a i a i i i a Pi a N N i 1 i 1 Pi i i 1 (completeness relation) Theorem: The eigen-values of a Hermitian operator are all real and their eigenvectors corresponding to different eigen-values are orthogonal. Proof: Let A be a Hermitian operator and A a ai a & b A† b bi Multiplying the 1st by b and the 2nd by a b A a ai b a b A† a bi b a Now subtracting the last two equations we get 5 CH.I b A a b A† a ai bi b a † Since A is Hermitian A A ai bi b a 0 Setting a b and noting that a a 0 ai ai 0 If ai bi ai ai b a 0 The Concept of Degeneracy If two or more of the eigen-values of an operator are equal, the operator is called degenerate, otherwise it is nondegenerate. If more than one linearly independent eigen functions ( 1 2 ) corresponding to the same eigen value, we say that we have a degeneracy. Theorem: If two operators have a common set of eigen vectors, then they commute. Proof: Let A a , b ai a , b And B a , b bi a , b Operate on the 1st equation by B and on the 2nd by A and then subtract BA AB a , b ai bi bi ai a , b 0 BA AB B, A 0 Theorem: If two nondegenerate operators commute, then they have a common set of eigen vectors. Proof: Let A a a a And B b b b Operate on the 1st equation from the left by B BA a aB a but since A and B are commute AB a aB a 6 CH.I B a is an eigen vector of A with the eigen value a. But since A is nondegenerate B a must at worst be proportional to a . So we can write B a b a with b here is a proportionality constant. Again because of the nondegeneracy of B we can set a b a , b Theorems: 1- The sum of two Hermitian operators is Hermitian. 2- The identity operator, which takes every function into itself, is Hermitian. † 3- If F is non-Hermitian, F F and i F F † are Hermitian. F F F † F F F † F † F F F † F F is anti-Hermitian. iF F † iF † F iF F † iF F is Hermitian. † † † † † † 4- If F and G are two arbitrary operators, the adjoint of their product is given by FG † G†F † We know that F FG Let G F † Let F F† FG † the left hand side of the last equation becomes F † the left hand side becomes Now taking the adjoint of the first assumption assumption we get for the left hand side G† and substitute with the second G † F † . Comparing this side with the right hand side we conclude that FG † G†F † Corollary: The product of two Hermitian operators is Hermitian if and only if they commute. 7 CH.I Commutator Algebra: As defined before, the commutator is written as A, B AB BA . From this definition one can prove that 1- A, B B, A 0 2- A, A 0 3- A, B C A, B A, C 4- A B, C A, C B, C 5- A, BC BA, C A, BC 6- AB, C AB, C A, C B 7- A, B, C C , A, B B, C , A 0 B A, B A A A B e 8- e Be 9- e e 1 A, A, B 1 A, A, A, B 2! 3! A B 12 A, B Proof of (8): Let f e with A and B commute with their commutator. A Be A . Making Taylor expansion of f df 2 d 2 f f f 0 d 0 2! d2 0 But And df A e A Be A e A Be A A Af f A A, f d d2 f df A, A, A, f d2 d Knowing that f 0 B f B A, B Proof of (9): Let f e 1 A, A, B 2! A B A B e e . df Ae Ae B e A B e A BeB e A B e Ae B A B e A B d 8 (1) CH.I But from Identity (8) and since A & B commute with A, B we have e A Be A B A, B e A B B A, B e A Be A A, B e A (2) Similarly by replacing A by B one can show that e B A Ae B B, Ae B (3) Now and using Equation (2) we have e , B e B Be A A A A, B e A (4) Now using (2), Equation (1) becomes df Ae Ae B e A B BeA A, Be A e B e A B e Ae B A B e A B d Using Equation (4) df Ae Ae B e A B e A BeB e A B e Ae B A B e A B d df Ae Ae B e A B e Ae B Ae A B d (5) Using Equation (3), Equation (5) becomes df e A B, Ae B e A B A, B f d df d A, B f (6) Integrating Equation (6) from 0 to 1 we get 1 df 1 f d A, B 0 0 ln f 0 1 Noting that 2 2 1 A, B ln f 1 1 A, B f (0) 2 & f 0 1 0 f 1 e Ae B e A B e Ae B e A B e 2 1 A, B e Ae B e Postulate of Quantum Mechanics 9 A B 12 A, B CH.I Postulate I: Every physical quantity can be represented by a Hermitian operator with a complete set of eigen vectors. Such operators are called observables. x x p i Postulate II: The quantum values allowed to any observable are determined by the eigen values of the corresponding operator. Postulate III: The state of any physical system is characterized by a state vector of unit length in a complex space or by a normalized state function r, t which is continuous and differentiable. r ,t is the probability density for finding the particle at position r. Then the probability of 2 finding the particle in some finite region of space is then proportional to the integral of r,t over this region. Postulate IV: If a system is characterized by a state vector and if A i ai i , then the 2 probability of observing the system with the value ai is given by Pai i Now 2 1 Pai i i 2 i i 1 i i as expected. i The expectation value of an observable is defined as A A Postulate V: The time development of a state vector r, t is determined is determined by the equation H r , t i H r , t i r , t or t r , t t Time-dependent Schrödinger Equation Where H T V is the Hamiltonian operator representing the total energy of the system. To solve the above equation we rewrite it as d r , t H dt r , t i d r , t H t dt i t o to r , t t (with H is assumed to be t-independent) 10 CH.I i r , t exp H t t o r ,0 U t t o r ,0 With i U t t o exp H t t o is called the time evolution operator. The Schwarz Inequality: for any two functions f and g the following inequality holds f d g d f 2 2 gd 2 Or for any two vectors a and b we have a a b b a b 2 The Heisenberg Uncertainty Relation: If A, B iC with A,B and C are Hermitian then AB 12 Where A C A2 A 2 Proof: Let a A A and b B B a a A A A A A2 2 A A A 2 a a A2 A2 A 2 (1) Similarly b b B 2 (2) Substituting Equations (1) and (2) in the Schwarz Inequality we have A2 B 2 A A B B 2 (3) † It is known that If F is non-Hermitian, F F and i F F † written as a linear combination of two Hermitian operators, i.e., F F F† F F† i 2 2i 11 are Hermitian. F can be CH.I A A B B A A B B B B A A 2 i A C Denoting the 1st term by G ad noting that the 2nd term is simply i 2 A A B B B B A A 2i C A B B G i 2 (4) Substituting equation (4) into equation (3) A B G i C 2 2 2 A2 B 2 G i C 2 2 2 But since G and C are Hermitian G and C are real A2 B 2 AB 12 G 2 C 14 C 2 G i C 2 2 A2 B 2 14 G C 2 2 14 C 2 2 Note that since x, p x i and using the Heisenberg uncertainty relation we conclude that x p x 12 The Virial Theorem We have r , t d A dt t A r, t A r, t r , t A A r , t r , t r , t r , t A t t From postulate (v) we have 1 1 r , t H r , t and r , t H r , t t i t i d 1 A 1 A r , t HA r , t r , t r , t r , t AH r , t dt i t i Or d 1 A 1 A, H A A r , t H , A r , t r , t r , t dt i t i t If A commute with H and doesn’t depend on t explicitly d A 0 dt A is constant of motion or conserved. A is constant 12 CH.I Note that p commute with H if V is constant p is conserved if V is constant (F=0). Now let Ar p d 1 r p, H r p dt i But p x2 xpx , H xpx , V i p x2 x p x ,V 2 and similarly for the other two components we have. yp y , H i p 2y yp y ,V and zp z , H i p z2 z p z ,V d p2 p2 r p r ,V r V V dt d p2 r p r V V V dt For stationary state we have p2 r V d r p 0 dt 2 T r V Virial Theorem As an application for the one-dimensional harmonic oscillator we have V x 12 kx 2 2 T kx 2 2 V r V x V kx2 x T V But H T V 2V 2 T T V 12 H The Equation of Motion: From postulate (v) we have H r , t i With H T V r , t or H r , t i r , t t t 2 2 V r . 2 Letting r, t r f t 13 En 2 CH.I 2 d f t 2 r V r f t r ir f t 2 dt Dividing by r f t 2 1 i d 2 r V r f t 2 r f t dt i d f t constant E f t dt f t E i t e d E f t f t dt i e it And 2 2 r V r E r 2 Time-Independent Schrödinger Equation The Continuity Equation: From postulate (v) we have H r , t i H r , t i With H T V r , t or t r , t t 2 2 V r . 2 2 2 r , t V r r , t i r , t 2 t (1) And its complex conjugate 2 2 r , t V r r , t i r , t 2 t (2) Multiplying the 1st equation be and the 2nd one by and then subtract 2 2 2i t t 2i t 14 CH.I Denoting by the probability current density J and noting that 2i 2 J 0 t The continuity equation Now we have t d J d By Gauss's theorem we have t d Jda S Since the first integral is over all the space and noting that 0 at zero the second integral is d 0 t the probability density is continuous Expectation Values of Dynamical Variables It is known that r r d r d r d 2 d r r d dt t Using the continuity equation d r r J d rJ d r J d dt d r rJ d J d dt Using Gauss's theorem we have rJ d rJda 0 as R S d r J d d dt 2i Knowing that 15 CH.I d r d dt 2i d r d d dt i 2i The second integral will vanish if we use the fact that 0 at d 1 r d dt i d r d p dt i d d d p i d i Now dt dt t t Using Schrödinger equation and its complex conjugate we get d 2 p 2 2 d V V d dt 2 Letting v & u , the 1st integral of the last equation becomes 2 2 2 2 2 2 d v u v u d 2 2 Recalling the Green's theorem 2 2 uv vu ds u v v u d S the 1st integral becomes V 2 2 ds which vanish as R 2 S d p V V d V V V d dt d p V d V F dt Ehrenfest.s Theorem From the above we conclude that: Expectation values of dynamical quantities obey the law Classical Mechanics. 16 CH.I Stationary State Solution If at t t o 0 the system is characterized by a state function r ,0 , then its future evolution is obtained using the operation r, t U t ,0r,0 U t ,0 e with iHt Suppose that the initial state r ,0 is an eigenstate of the Hamiltonian denoted by n r , such that r ,0 n r From the above equations we can write r , t e iHt n r But since H n r n n r e r , t e int n r where n iHt n r e i nt n r n Now the expectation value of an observable A at t=0 is A t 0 r,0Ar,0dr n r A n r dr At later time t we have A t r, t Ar, t dr eint e int n r A n r dr A t 0 In a stationary state we have At A t 0 We conclude that the eigensates of the Hamiltonian are called stationary states given as r , t e int n r stationary state Note that the probability density of a stationary state is given by (r ) r, t eint e int n r n r 2 2 2 The probability density for a stationary state is constant of time. 17 CH.I Theorem: The separation constant E is real. Proof: Now from the continuity equation we have J 0 t But it is known that r , t e 2 E E i E E e i E E i J t i E E t r 2 the continuity equation gives r J 0 2 Integrating over all the space we get E E d i J d i J dS (using Gauss's theorem) S The right hand side of the last equation vanishes as R E E d 0 E E 0 or E E Theorem: The expectation values of dynamical quantities which don't depend on time explicitly are constants. Proof: The expectation value of a an operator Q corresponding to a dynamical variable is given by (because f t f t 1 ) Q r, t Q r, t d Q r d 2 d d 2 2 2 Q Q r d Q r d Q r d 0 dt dt t t Q Now But is constant. r , t H r , t H r , t d r , t i d t r , t f t i r E r , t t t H E r, t r, t d E r , t d E 2 Also we have J 0 t 18 CH.I r r , t 0 t t t 2 For stationary state we have r, t r f t For stationary state J 0 Symmetry Properties of Schrödinger Equation: 1- Space reflection (parity) Let r r r Now r, t r, t r r r r r H T V If V r V r 2 2 V r 2 2 2 H H The parity Operator: The parity operator is defined as U p f r f r Let U p g r g r g r with is eigen-value of the parity operator. Now operating again with Up we have U pU p g r U p g r U p g r 2 g r But U p g r g r 2 1 g r 2 g r 1 The eigen-value of the parity operator is 1. 2- Time Reversal The time reversal operator is defined as U t f t f t Recalling the time-dependent Schrodinger equation we have 2 2 r , t V r r , t i r , t 2 t Taking the complex conjugate of Eq.(1) and replacing t t t 19 (1) 2 CH.I 2 2 r ,t V r r ,t i r ,t 2 t This equation has the same form as Eq.(1). If r, t is a solution of Eq.(1) then r,t is also a solution. 20