Math 2
Lesson 3-6 The Quadratic Formula, part 1
Name ________________________
Learning Goals

I can solve quadratic equations with real numbers as coefficients by inspection (graphing), by using
the quadratic formula.
When we cannot factor to solve a quadratic equation (or the equation is difficult to factor), we can use the
quadratic formula. For any quadratic equation in the form ax 2  bx  c  0 , the quadratic formula allows
us to solve for x without factoring or complete the square. The quadratic formula is:
b  b2  4ac
If ax  bx  c  0 , then x 
.
2a
2
Use the quadratic formula to solve the equations below. Graph the equations in your calculator to
check your solutions. Write both the exact and approximate answers!
1. x2 + 6x – 9 = 0
Quick Sketch of Graph:
a = _______ b = _______ c = _______
x  _________ or x  __________
2. 2x2 – 12x + 18 = 0
a = _______ b = _______ c = _______
x  _________ or x  __________
Quick Sketch of Graph:
3. 0 = 20 – 6x + 3x2
a = _______ b = _______ c = _______
Quick Sketch of Graph:
x  _________ or x  __________
I. Where does the Quadratic Formula come from?
http://www.youtube.com/watch?v=GRluUxorUvU

What process is used to derive the formula? _________________________________

What is the first step of the proof? __________________________________

In order to add the fractions on the right side of the equations, what must be the same?
__________________________________

When square-rooting both sides of the equation, what must go in front of the square root
symbol? ___________

What does √4𝑎2 equal? ___________
II. Additional uses of the Quadratic Formula:
A. How to find the axis of symmetry and the vertex of the parabola:
The quadratic formula can be split into two separate parts:
b
b2  4ac
x

2a
2a
Consider the parabola whose equation is x 2  4 x  5  0 .
Here is its graph:

What is the equation of its axis of symmetry? _________

What are the coordinates of its vertex? _________

Now use the values from the equation to calculate 
b
.
2a
What do you notice?

What are the coordinates of the x-intercepts? ____________

Use the values from the equation to calculate
What does the result tell you about the graph?
_____________
b2  4ac .
2a
Math 2
Lesson 3-6 The Quadratic Formula, part 2




Name ________________________
I can determine the number of solutions for a quadratic equation in standard form, ax2+bx+c = 0, by
calculating the discriminant.
I can determine when a quadratic equation in standard form, ax2+bx+c=0, has complex roots by looking at a
graph of f(x) = ax2+bx+c or by calculating the discriminant.
I can identify that i is a complex number where 𝑖 2 = -1 and 𝑖 = √−1.
I can write complex number solutions for a quadratic equation in the form a+bi by using i=√−1.
B. How to predict the types of solutions to a quadratic equation:
In problems 1 through 3, we discovered that when finding the solutions of a quadratic
function there were different types of solutions.
 List the different types of possible solutions that you discovered for a quadratic function –
think back to unit 2 and the number systems!
 How many solutions are possible to a quadratic equation?
A way to find out the number of solution(s) for a quadratic function before using the quadratic
formula is to calculate the discriminant ( b 2  4ac ).
1.
a.
What was the discriminant from part 1, problem 1: _________
b.
If the discriminant is ___________________ (positive, negative, or zero), then
there is/are ____________ solution(s).
2.
a.
What was the discriminant from part 1, problem 2: __________
b.
If the discriminant is ___________________ (positive, negative, or zero), then
there is/are ____________ solution(s).
3.
a.
What was the discriminant from part 1, problem 3: __________
b.
If the discriminant is ___________________ (positive, negative, or zero), then
there is/are ____________ solution(s).
III. Imaginary Numbers
In problem #3, we found that the equation had no solutions due to the fact that we could not take the square root
of a negative number. Historically speaking, though, mathematicians were not satisfied with the idea that an
equation could not be solved. In order to solve this dilemma a new number set was invented – called the
Imaginary Numbers.
Consider the equations:
1. Graph each equation to find the x-intercepts.
x2 – 9 = 0
2. Now solve each equation for x.
3. How many solutions does each have?
NOTES:
2  8  _____ 
12  3  _____ 

 14
10  5 



25 
 1
x2 + 9 = 0
Examples: Solve the following equations.
1. x 2  225
3.
0 = 13 – 4x + x2
2. 3x 2  9  90
4.
x2  5x  7  0
NUMER SYSTEMS
HOMEWORK
Copy each problem on another sheet of paper & show all work.
Part 1
1. Solve each equation by using the Quadratic Formula. Exact answers only.
g. -16x2 + 45x + 6.5 = 0
h. -16x2 + 40.2x + 8.6 = 0
2. For each function do the following:
 Use concepts from this lesson to find the axis of symmetry.
 Use concepts from this lesson to find the vertex.
a. h(t) = -16t2 + 45t + 6.5
b. y = .05x2 – 1.2x
c. y = x2 – 10x + 14
***After you have found the vertex for the equation in c, rewrite it in vertex form using the
completing the square technique. Does the result verify your computations? If not, check your
work and make corrections.
Part 2
3. Solve the following equations.
a. x2 = -64
b.
x2 + 100 = 0
c.
-2x2 = 50
d. x2 + 40 = -63
e.
7x2 + 10 = -5
f.
-80 = 4x2
4. For each equation do the following:
 Calculate the discriminant.
 Based on the discriminant, solve the equation by either factoring or the quadratic formula.
a. x2 + 7x + 10 = 0
b.
2x2 – 7x – 10 = 0
c.
3x2 – x + 14 = 0
d. x2 – 4x = 13
e.
4x2 + 12x – 9 = -18
f.
x2 + 9x = 0