Cornell Notes Topic/Objective: Variation Functions Algebra 2 Pre-AP 1st, 2nd, 6th, and 7th periods October 11, 2013 Essential Question: What are variation functions? How do I use variation functions? Questions: Vocabulary Direct Variation – A linear relationship between two variables, x and y, that can be written in the form y = k x, where k is a nonzero constant. *** A direct variation equation is a linear equation in the form y = m x + b, where b = 0 and the constant of variation k is the slope. Because b = 0, the graph of a direct variation always passes through the origin. y x Constant of Variation – The constant, k, in direct and inverse variation equations. Inverse Variation – A relationship between two variables, x and y, that can be written in 𝑘 the form 𝑦 = 𝑥 , where k is a nonzero constant and x ≠ 0. Notes Taken from Algebra 2 textbook by Holt: Many real world situations, from geometry and chemistry to engineering and agriculture, can be modeled by variation functions. Direct Inverse Variation Variation k is constant 𝑦 = 𝑘𝑥 As the value of one variable increases, the value of the other increases. 𝑦 𝑘=𝑥 Constant ratio 𝑘 𝑦=𝑥 As the value of one variable increases, the value of the other decreases. 𝑘 = 𝑦𝑥 Constant product Graphs: y y x x Direct Variation Parent Function: Linear Inverse Variation Parent Function: Rational Tell whether each statement is sometimes, always, or never true. 1. Direct Variation is a linear function. Always 2. A linear function is a direct variation. Sometimes 3. An inverse variation is a linear function. Never true 4. In a direct variation, x = 0 when y = 0. Always 5. The graph of an inverse variation passes through the origin. Never true Examples Given: y varies directly as x, and y = 14 when x = 3.5. What is the constant of variation? 𝑦 = 𝑘𝑥 14 = 𝑘(3.5) 14 𝑘(3.5) = 3.5 3.5 4=𝑘 Given: y varies inversely as x, and y = 3 when x = 8. What is the constant of variation? 𝑘 𝑦= 𝑥 𝑘 3= 8 𝑘 8∗3= ∗8 8 24 = 𝑘 The wavelength λ of a wave of a certain frequency varies directly as the velocity ν of the wave. If λ = 60ft when ν = 15ft/s, then find λ when ν = 3ft/s. 𝜆 = 𝑘𝜐 SO, 𝜆 = 𝑘𝜐 60 = 𝑘(15) λ = 4*3 60 𝑘(15) = 15 λ = 12 ft. 15 4=𝑘