Seasonal Indices When considering a set of data over time it is sometimes visible that there is a seasonal fluctuation in the data. An example of this would be average monthly temperatures over several years. A seasonal adjustment can be made to the data in order that a better picture of the trends can be gained so that more reliable predictions are possible. This is done using Seasonal Indices. Seasonal Indices are calculated so that their average is 1. This means the SUM OF SEASONAL INDICES = NUMBER OF SEASONS. For example, if seasons are months, the SUM SEASONAL INDICES = 12. Example1: Find the missing Seasonal Index. Quarter Q1 Q2 Q3 Seasonal Indices 1.3 1.4 0.4 Q4 A seasonal index of: 1.3 tells us data in Q1 are typically 30% above average. 1.4 tells us data in Q2 are typically 40% above average. 0.4 tells us data in Q3 are typically 60% below average. A season index is defined by the formula: Seasonal index = 𝒗𝒂𝒍𝒖𝒆 𝒇𝒐𝒓 𝒔𝒆𝒂𝒔𝒐𝒏 𝒔𝒆𝒂𝒔𝒐𝒏𝒂𝒍 𝒂𝒗𝒆𝒓𝒂𝒈𝒆 Question 1 A time series plot is to be constructed using the data contained in the table below: Month no. 1 2 3 4 5 6 7 8 9 10 11 12 Cost ($) 58 92 123 136 151 162 159 139 172 180 185 179 The data in the table is used to calculate the seasonal index for each month. The seasonal index for month 4 is closest to: A. 0.81 B. 0.85 C. 0.94 D. 1.04 E. 1.06 where the season is a month, quarter or the like. Question 2 The following (incomplete) table shows seasonal indices at Crockett’s dress shop for 2012. Summer 1.20 Autumn Winter Spring 1.05 Which one of the following statements regarding sales in 2012 is true? A. The highest sales season could not be Autumn or Winter B. Both Autumn and Winter must have sales below the season average C. Sales figures for Autumn and Winter could be identical D. Sales in Spring were generally greater than sales in Summer E. The seasonal indices for Autumn and Winter will both be greater than 1 A seasonal index is used to deseasonalise (smooth) the data, using the rule: Deseasonalised figure = 𝒂𝒄𝒕𝒖𝒂𝒍 𝒇𝒊𝒈𝒖𝒓𝒆 𝒔𝒆𝒂𝒔𝒐𝒏𝒂𝒍 𝒊𝒏𝒅𝒆𝒙 Example 2: using example 1 above, deseasonalise the following data. Quarter Actual data Deseasonalised Data 2000 Q1 Q2 Q3 Q4 1500 1650 300 1100 1500 Autumn 1.10 Winter data 0 1 Question 3 a. On Tommy’s farm, tomatoes can be grown in a hothouse all year round but production varies from one season to another. The seasonal indices for some of the seasons are given in the table below. Summer 1.25 Series2 Deseasonalised 500 What does this look like graphically? Season Seasonal Index Actual data Series1 1000 Spring 0.99 2 3 4 b. Tommy calculated the deseasonalised summer production figure to be 1500 tonnes. The actual summer production figure would have been: A. B. C. D. E. 1200 1650 1875 1364 1500 a. The seasonal index for winter is: A. B. C. D. E. 0.66 1.66 1.99 0.99 1.00 Steps to Deseasonalise Time Series Data Step 1: Yearly (cycle) Average – Find the average value for the entire seasonal cycle. Step 2: Seasonal Average: Divide each seasonal value by the yearly average. This shows how each season compares to the yearly average. Step 3: Seasonal Index: Average the seasonal values in step 2. Step 4: Deseasonalised figures (seasonally adjusted figures) – Divide each original value by each corresponding seasonal Index. Step 5: You can now plot the seasonally adjusted data to show the trend more clearly than the original data would have. Any marked change in figures will stand out more on the graph of deseasonalised data. Example 3 Step 4: Deseasonalise figures Summer Autumn Actual Sales figures 920 Winter Spring 1241 446 Desea Sales Figures = Step 5: You can now graph both seasonal data and deseasonalised data. Sketch below. 1085 Step 1: Yearly average= 920+1085+1241+446 4 Summer Autumn Step 2: Seasonal Averages. Summer Autumn Winter Spring Seasonal averages Step 3: Seasonal Indices: as this is only over 1 cycle, the seasonal averages are the seasonal Indices. Example 4: The average daily sales (in dozens) of soft drinks in a milk bar are as follows. 1985 1986 1987 1988 Summer 32 34 37 38 Autumn 17 16 19 24 Winter 12 13 17 16 Spring 22 25 26 29 Step 1: Yearly averages Step 2: Seasonal Averages: divide each season by its yearly average. Summer Autumn Winter Spring 1985 1986 1987 1988 Seasonal Indices Step 3: Seasonal Indices: Average the seasonal values. Step 4: Deseasonalise Data by dividing actual values by seasonal indices. Summer 1985 1986 1987 1988 Step 5: Sketch the seasonal and deseasonalised data. Autumn Winter Spring Winter Spring Question 4 The sales results for Rashid’s car yard over eight consecutive quarters are: 2008 2009 Q1 Q2 Q3 Q4 42 000 52 000 21 000 32 000 15 000 26 000 22 000 50 000 The seasonal index for Q2 is 0.82. Yearly average 25 000 40 000 a. The seasonal index for the first quarter is: A. B. C. D. E. b. The deseasonalised figure to the nearest 10 of Q2 in 2009 is: A. B. C. D. E. 17 220 25 610 26 240 39 020 64 630 1.3 1.49 1.68 47000 94000 7D Fitting a Trend line and Forecasting A trend line would then be fitted to this Deseasonalised data. Independent variable is time (t) and dependent variable is number of cans (y). When you predict from a trend line, the values is deseasonalised (smoothed). Hence you must re-adjust it to be seasonal if needed. Since 𝑑𝑒𝑠𝑒𝑎𝑠𝑜𝑛𝑎𝑙𝑖𝑠𝑒𝑑 𝑓𝑖𝑔𝑢𝑟𝑒 = then 𝐴𝑐𝑡𝑢𝑎𝑙 𝑓𝑖𝑔𝑢𝑟𝑒 𝑆𝑒𝑎𝑠𝑜𝑛𝑎𝑙 𝑖𝑛𝑑𝑒𝑥 Seasonalised figure = deseasonalised figure x seasonal index i.e. raw figure = smoothed prediction x seasonal index From previous example, the Least Squares regression line of deseasonalised values is: y = So a prediction for summer 1989 would be t = y= Now seasonalise it: yactual = Question 5 Hunter owns a bike shop and has noted that there is seasonal variation apparent when considering the number of bikes sold each season. Over a period of three years from 2010 to 2012 inclusive the seasonal indices for bike sales are calculated and given in the following (incomplete) table. Season Seasonal Index Summer 1.3 Autumn Winter 0.72 Using Summer 2010 as time period 1, Autumn 2010 as time period 2 etc, the following least squares regression equation was calculated: Deseasonalised sales = 540.1 + 4.25 × time period d. Calculate the residual value of deseasonalised sales for Spring 2012. Spring 1.09 a. Complete the table with the seasonal index for Autumn. b. Interpret the seasonal index for Winter in the context of the problem. e. Use the regression equation and other available information to forecast the actual number of bikes Hunter will sell during Winter 2014. Give your answer to the nearest whole number. c. During Spring 2012, Hunter sold 654 bikes. Determine the deseasonalised sales figure for this particular season. 7E