Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Lesson 8: How Do Dilations Map Lines, Rays, and Circles? Student Outcomes ο§ Students prove that a dilation maps a ray to a ray, a line to a line, and a circle to a circle. Lesson Notes The objective in Lesson 7 was to prove that a dilation maps a segment to a segment; in Lesson 8, students prove that a dilation maps a ray to a ray, a line to a line, and a circle to a circle. An argument similar to that in Lesson 7 can be made to prove that a ray maps to a ray; allow students the opportunity to establish this argument as independently as possible. Classwork Opening (2 minutes) As in Lesson 7, remind students of their work in Grade 8, when they studied the multiplicative effect that dilation has on points in the coordinate plane when the center is at the origin. Direct students to consider what happens to the dilation of a ray that is not on the coordinate plane. ο§ Today we are going to show how to prove that dilations map rays to rays, lines to lines, and circles to circles. ο§ Just as we revisited what dilating a segment on the coordinate plane is like, so we could repeat the exercise here. How would you describe the effect of a dilation on a point (π₯, π¦) on a ray about the origin by scale factor π in the coordinate plane? οΊ ο§ A point (π₯, π¦) on the coordinate plane dilated about the origin by scale factor π would then be located at (ππ₯, ππ¦). Of course, we must now consider what happens in the plane versus the coordinate plane. Opening Exercise (3 minutes) Opening Exercise MP.3 a. Is a dilated ray still a ray? If the ray is transformed under a dilation, explain how. Accept any reasonable answer. The goal of this line of questioning is for students to recognize that a segment dilates to a segment that is π times the length of the original. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 120 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY b. Dilate the ray ββββββ π·πΈ by a scale factor of π from center π. MP.3 i. Is the figure βββββββββ π·′πΈ′ a ray? Yes. The dilation of ray π·πΈ produces a ray π·′πΈ′. ii. How, if at all, has the segment π·πΈ been transformed? The segment π·′πΈ′ in ray π·′πΈ′ is twice the length of the segment π·πΈ in ray π·πΈ. The segment has increased in length according to the scale factor of dilation. iii. Will a ray always be mapped to a ray? Explain how you know. Students will most likely say that a ray always maps to a ray; they may defend their answers by citing the definition of a dilation and its effect on the center and a given point. ο§ We are going to use our work in Lesson 7 to help guide our reasoning today. ο§ In proving why dilations map segments to segments, we considered three variations of the position of the center relative to the segment and value of the scale factor of dilation: (1) A center π and scale factor π = 1 and segment ππ, (2) A line ππ that does not contain the center π and scale factor π ≠ 1, and (3) A line ππ that does contain the center π and scale factor π ≠ 1. Point out that the condition in case (1) does not specify the location of center π relative to the line that contains segment ππ; they can tell by this description that the condition does not impact the outcome and, therefore, is not more particularly specified. ο§ We use the setup of these cases to build an argument that shows dilations map rays to rays. Examples 1–3 focus on establishing the dilation theorem of rays: A dilation maps a ray to a ray sending the endpoint to the endpoint. The arguments for Examples 1 and 2 are very similar to those of Lesson 7, Examples 1 and 3, respectively. Use discretion and student success with the Lesson 7 examples to consider allowing small-group work on the following Examples 1–2, possibly providing a handout of the solution once groups arrive at solutions of their own. Again, since the arguments are quite similar to those of Lesson 7, Examples 1 and 3, it is important to stay within the time allotments of each example. Otherwise, Examples 1–2 should be teacher led. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 121 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Example 1 (2 minutes) Encourage students to draw upon the argument from Lesson 1, Example 1. This is intended to be a quick exercise; consider giving 30-second time warnings or using a visible timer. Example 1 Does a dilation about center πΆ and scale factor π = π map ββββββ π·πΈ to βββββββββ π·′πΈ′? Explain. A scale factor of π = π means that the ray and its image are equal. That is, the dilation does not enlarge or shrink the image of the figure but remains unchanged. Therefore, when the scale factor of a dilation is π = π, then the dilation maps the ray to itself. Example 2 (6 minutes) Encourage students to draw upon the argument for Lesson 1, Example 3. Scaffolding: Example 2 The line that contains ββββββ π·πΈ does not contain point πΆ. Does a dilation π« about center πΆ and scale βββββββ onto a point ofββββββββββ factor π ≠ π map every point of π·πΈ π·′πΈ′? MP.1 ο§ A restatement of this problem is as follows: If π is a point on βββββ ππ , then is π·(π ) a ′ ′ ′ ′ ββββββββ ββββββββ point on π π ? Also, if a point π′ lies on the ray π π , then is there a point π on the ray βββββ ππ such that π·(π) = π ′? ο§ Consider the case where the center π is not in the line that contains βββββ ππ , and the scale factor is π ≠ 1. Then, points π, π, and π form β³ πππ. Draw the following figure on the board. ο§ If students have difficulty following the logical progression of the proof, ask them instead to draw rays and dilate them by a series of different scale factors and then make generalizations about the results. ο§ For students who are above grade level, ask them to attempt to prove the theorem independently. ο§ We examine the case with a scale factor π > 1; the proof for 0 < π < 1 is similar. ο§ Under a dilation about center π and π > 1, π goes to π′ , and π goes to π’; ππ′ = π ⋅ ππ and ππ′ = π ⋅ ππ. What conclusion can we draw from these lengths? ο§ Summarize the proof and result to a partner. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 122 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Draw the following figure on the board. οΊ ο§ ο§ We can rewrite each length relationship as ππ′ ππ = ππ′ ππ = π. By the triangle side splitter theorem, what else can we now conclude? οΊ The segment ππ splits β³ ππ′π′ proportionally. οΊ ββββββββ are parallel; β‘ββββ β‘ββββββ ; therefore, βββββ The lines that contain βββββ ππ and π′π′ ππ β₯ π′π′ ππ β₯ ββββββββββ π′π′ . By the dilation theorem for segments (Lesson 7), the dilation from π of the segment ππ is the segment π′π′, that is, π·(ππ) = π′ π′ as sets of points. Therefore, we need only consider an arbitrary point π on βββββ ππ that lies outside of ππ. For any such point π , what point is contained in the segment ππ ? οΊ ο§ The point π ′ Let π = π·(π ). P' Q' R' MP.7 P Q R O ο§ By the dilation theorem for segments, the dilation from π of the segment ππ is the segment π′π ′. Also by the dilation theorem for segments, the point π·(π) = π′ is a point on segment π′π ′. Therefore, ββββββββ π′ π′ and ββββββββ π′ π ′ must be the same ray. In particular, π ′ is a point on ββββββββ π′ π′ , which was what we needed to show. To show that for every point π′ on ββββββββ π′ π′ there is a point π on βββββ ππ such that π·(π) = π ′, consider the dilation from center 1 π with scale factor (the inverse of the dilation π·). This dilation maps π′ to a point π on βββββ ππ by the same reasoning as π above. Then, π·(π) = π ′ . ο§ We conclude that the points of βββββ ππ are mapped onto the points of ββββββββ π′π′ and, more generally, that dilations map rays to rays. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 123 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Example 3 (12 minutes) Encourage students to draw upon the argument for Lesson 1, Example 3. Example 3 βββββββββ ? βββββββ contains point πΆ. Does a dilation about center πΆ and scale factor π map π·πΈ βββββββ to π·′πΈ′ The line that contains π·πΈ ο§ Consider the case where the center π belongs to the line that contains βββββ ππ . a. ο§ ββββββ coincides with the center πΆ of the dilation. Examine the case where the endpoint π· of π·πΈ ββββββ ? If the endpoint π of βββββ ππ coincides with the center π, what can we say about βββββ ππ and ππ Ask students to draw what this looks like, and draw the following on the board after giving them a head start. ββββββ ; βββββ ββββββ . All the points on βββββ ππ also belong to ππ ππ = ππ οΊ ο§ By definition, a dilation always sends its center to itself. What are the implications for the dilation of π and π? Since a dilation always sends its center to itself, then π = π = π′ = π′. οΊ MP.1 ο§ ββββββ so that π ≠ π. What happens to π under a dilation about π with scale factor π? Let π be a point on ππ The dilation sends π to π′ on βββββ ππ, and ππ ′ = π ⋅ ππ. οΊ Ask students to draw what the position of π and π′ might look like if π > 1 or π < 1. Points may move farther away (π > 1) or move closer to the center (π < 1). They do not draw this for every case; rather, it is a reminder up front. π>1 π<1 ο§ Since π, π, and π are collinear, then π, π′, and π are also collinear; π′ is on the ray ππ, which coincides with ββββββ by definition of dilation. ππ ο§ Therefore, a dilation of ββββββ ππ is βββββ ππ (or when the endpoint of π of βββββ ππ coincides with the center π) about center ββββββββ ββββββββ π and scale factor π maps π′π′ to π′π′. We have answered the bigger question that a dilation maps a ray to a ray. b. ββββ is between πΆ and πΈ on the line containing πΆ, π·, and πΈ. Examine the case where the endpoint π· of π·πΈ Ask students to draw what this looks like, and draw the following on the board after giving them a head start. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 124 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY ο§ ββββββ maps onto itself. All we need to show We already know from the previous case that the dilation of the ray ππ is that any point on the ray that is farther away from the center than π maps to a point that is farther away from the center than π′. ο§ Μ Μ Μ Μ ? Let π be a point on βββββ ππ so that π ≠ π. What can be concluded about the relative lengths of Μ Μ Μ Μ ππ and ππ Ask students to draw what this looks like, and draw the following on the board after giving them a head start. The following is one possibility. οΊ ο§ MP.1 ππ < ππ Describe how the lengths ππ′ and ππ′ compare once a dilation about center π and scale factor π sends π to π′ and π to π′. οΊ ππ′ = π ⋅ ππ and ππ ′ = π ⋅ ππ οΊ Multiplying both sides of ππ < ππ by π > 0 gives π ⋅ ππ < π ⋅ ππ, so ππ′ < ππ′. Ask students to draw what this might look like if π > 1, and draw the following on the board after giving them a head start. ο§ Therefore, we have shown that any point on the ray βββββ ππ that is farther away from the center than π maps to a point that is farther away from the center than π′. In this case, we still see that a dilation maps a ray to a ray. c. ο§ Examine the remaining case where the center πΆ of the dilation and point πΈ are on the same side of π· on the line containing πΆ, π·, and πΈ. Now consider the relative position of π and π on βββββ ππ . We use an additional point π as a reference point so the π is between π and π . Draw the following on the board; these are all the ways that π and π are on the same side of π. Q R P O P O=Q R O R P Lesson 8: Q How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 125 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY MP.1 ο§ By case (a), we know that a dilation with center π maps βββββ ππ to itself. ο§ Also, by our work in Lesson 7 on how dilations map segments to segments, we know that Μ Μ Μ Μ ππ is taken to Μ Μ Μ Μ Μ π′π , where π′ lies on βββββ ππ . ο§ The union of the π′π and βββββ ππ is ββββββ π′π . So, the dilation maps βββββ ππ to ββββββ π′π . ο§ Since π′ is a point on ββββββ π′π and π′ ≠ π′, we see ββββββββ π′ π = ββββββββ π′π′. Therefore, in this case, we still see that βββββ ππ maps to ββββββββ under a dilation. π′π′ Example 4 (6 minutes) In Example 4, students prove the dilation theorem for lines: A dilation maps a line to a line. If the center π of the dilation lies on the line or if the scale factor π of the dilation is equal to 1, then the dilation maps the line to the same line. Otherwise, the dilation maps the line to a parallel line. The dilation theorem for lines can be proved using arguments similar to those used in Examples 1–3 for rays and to Examples 1–3 in Lesson 7 for segments. Consider asking students to prove the theorem on their own as an exercise, especially if time is an issue, and then provide the following proof: ο§ We have just seen that dilations map rays to rays. How could we use this to reason that dilations map lines to lines? ββββββββ and β‘ββββ ππ is the union of the two rays βββββ ππ and βββββ ππ . Dilate rays βββββ ππ and βββββ ππ ; the dilation yields rays π′π′ βββββββ β‘ββββββ is the union of the two rays π′π′ ββββββββ and βββββββ π′π ′. π′π′ π′π ′. Since the dilation maps the rays βββββ ππ and βββββ ππ to οΊ MP.3 the rays ββββββββ π′π′ and βββββββ π′ π′ , respectively, then the dilation maps β‘ββββ ππ to the β‘ββββββ π′π′. Example 5 (8 minutes) In Example 5, students prove the dilation theorem for circles: A dilation maps a circle to a circle and maps the center to the center. Students need the dilation theorem for circles for proving that all circles are similar in Module 5 (G-C.A.1). Example 5 Does a dilation about a center πΆ and scale factor π map a circle of radius πΉ onto another circle? a. ο§ Examine the case where the center of the dilation coincides with the center of the circle. We first do the case where the center of the dilation is also the center of the circle. Let πΆ be a circle with center π and radius π . Draw the following figure on the board. ο§ If the center of the dilation is also π, then every point π on the circle is sent to a point π′ on βββββ ππ so that ππ′ = π ⋅ ππ = ππ ; that is, the point goes to the point π′ on the circle πΆ′ with center π and radius ππ . Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 126 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY ο§ We also need to show that every point on πΆ′ is the image of a point from πΆ: For every point π′ on circle πΆ′, put a coordinate system on β‘βββββ ππ′ such that βββββββ ππ′ corresponds to the nonnegative real numbers with zero corresponding to point π (by the ruler axiom). Then, there exists a point π on βββββββ ππ′ such that ππ = π ; that is, π is a point on the circle πΆ that is mapped to π′ by the dilation. Draw the following figure on the board. ο§ Effectively, a dilation moves every point on a circle toward or away from the center the same amount, so the dilated image is still a circle. Thus, the dilation maps the circle πΆ to the circle πΆ′. ο§ Circles that share the same center are called concentric circles. b. Examine the case where the center of the dilation is not the center of the circle; we call this the general case. ο§ The proof of the general case works no matter where the center of the dilation is. We can actually use this proof for case (a), when the center of the circle coincides with the center of dilation. ο§ Let πΆ be a circle with center π and radius π . Consider a dilation with center π· and scale factor π that maps π to π′. We will show that the dilation maps the circle πΆ to the circle πΆ′ with center π′ and radius ππ . Draw the following figure on the board. C P π D O ο§ If π is a point on circle πΆ and the dilation maps π to π′ , the dilation theorem implies that π′ π′ = πππ = ππ . So, π′ is on circle πΆ′. ο§ We also need to show that every point of πΆ′ is the image of a point from πΆ. There are a number of ways to prove this, but we will follow the same idea that we used in part (a). For a point π′ on circle πΆ′ that is not on β‘ββββββ π·π′ , consider ββββββββ π′ π′ (the case when π′ is on line π·π′ is straightforward). Construct line β through π such that β β ββββββββ π′ π′ , and let π΄ be a point on β that is in the same half-plane of β‘ββββββ π·π′ as π′ . Put a coordinate system on β βββββ corresponds to the nonnegative numbers with zero corresponding to point π (by the such that the ray ππ΄ ruler axiom). Then, there exists a point π on βββββ ππ΄ such that ππ = π , which implies that π is on the circle πΆ. By the dilation theorem, π is mapped to the point π′ on the circle πΆ′. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 127 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY ο§ The diagram below shows how the dilation maps points π, π, π , π, and π of circle πΆ. Ask students to find point π on circle πΆ that is mapped to point π′ on circle πΆ′. C' Q' P' C Q P R' R D O O' S T S' W' T' Closing (1 minute) Ask students to respond to the following question and summarize the key points of the lesson. ο§ How are the proofs for the dilation theorems on segments, rays, and lines similar to each other? Theorems addressed in this lesson: ο· DILATION THEOREM FOR RAYS: A dilation maps a ray to a ray sending the endpoint to the endpoint. ο· DILATION THEOREM FOR LINES: A dilation maps a line to a line. If the center π of the dilation lies on the line or if the scale factor π of the dilation is equal to 1, then the dilation maps the line to the same line. Otherwise, the dilation maps the line to a parallel line. ο· DILATION THEOREM FOR CIRCLES: A dilation maps a circle to a circle and maps the center to the center. Lesson Summary ο§ DILATION THEOREM FOR RAYS: A dilation maps a ray to a ray sending the endpoint to the endpoint. ο§ DILATION THEOREM FOR LINES: A dilation maps a line to a line. If the center πΆ of the dilation lies on the line or if the scale factor π of the dilation is equal to π, then the dilation maps the line to the same line. Otherwise, the dilation maps the line to a parallel line. ο§ DILATION THEOREM FOR CIRCLES: A dilation maps a circle to a circle and maps the center to the center. Exit Ticket (5 minutes) Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 128 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Name Date Lesson 8: How Do Dilations Map Lines, Rays, and Circles? Exit Ticket Given points π, π, and π below, complete parts (a)–(e): a. Draw rays ββββ ππ andβββββ ππ. What is the union of these rays? b. Dilate ββββ ππ from π using scale factor π = 2. Describe the image of ββββββ ππ. c. ββββ from π using scale factor π = 2. Describe the image of ββββ Dilate ππ ππ. d. What does the dilation of the rays in parts (b) and (c) yield? e. Dilate circle πΆ with radius ππ from π using scale factor π = 2. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 129 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 8 M2 GEOMETRY Exit Ticket Sample Solutions Given points πΆ, πΊ, and π» below, complete parts (a)–(e): a. βββ . What is the union of these rays? Draw rays βββββ πΊπ» and π»πΊ βββββ and π»πΊ βββββ is line πΊπ». The union of πΊπ» b. βββββ from πΆ using scale factor π = π. Describe the image of πΊπ» βββββ . Dilate πΊπ» The image of βββββ πΊπ» is βββββββ πΊ′π»′. c. Dilate βββ π»πΊ from πΆ using scale factor π = π. Describe the image of βββ π»πΊ. βββββββ . βββββ is π»′πΊ′ The image of π»πΊ d. What does the dilation of the rays in parts (b) and (c) yield? β‘ββββββ . βββββ and π»πΊ βββββ yields πΊ′π»′ The dilation of rays πΊπ» e. Dilate circle π» with radius π»πΊ from πΆ using scale factor π = π. See diagram above. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 130 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Problem Set Sample Solutions 1. In Lesson 8, Example 2, you proved that a dilation with a scale factor π > π maps a ray π·πΈ to a ray π·′πΈ′. Prove the remaining case that a dilation with scale factor π < π < π maps a ray π·πΈ to a ray π·′πΈ′. Given the dilation π«πΆ,π , with π < π < π maps π· to π·′ and πΈ to πΈ′, prove that π«πΆ,π maps ββββββ π·πΈ to βββββββββ π·′πΈ′. By the definition of dilation, πΆπ·′ = π(πΆπ·), and likewise, πΆπ·′ πΆπ· = π. By the dilation theorem, Μ Μ Μ Μ Μ Μ π·′πΈ′ β₯ Μ Μ Μ Μ π·πΈ. β‘βββββββ . β‘ββββ β₯ π·′πΈ′ Through two different points lies only one line, so π·πΈ ββββββ , and then draw πΆπΉ ββββββ . Mark point πΉ′ at the intersection of πΆπΉ ββββββ and βββββββββ Draw point πΉ on π·πΈ π·′πΈ′. By the triangle side splitter theorem, Μ Μ Μ Μ Μ Μ π·′πΉ′ splits Μ Μ Μ Μ πΆπ· and Μ Μ Μ Μ πΆπΉ proportionally, so πΆπΉ′ πΆπΉ = πΆπ·′ πΆπ· = π. ββββββ . Therefore, because πΉ was chosen as an arbitrary point, πΆπΉ′ = π(πΆπΉ) for any point πΉ on π·πΈ Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 131 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY 2. ββββββ under a dilation from point πΆ with an unknown scale factor; π¨ maps In the diagram below, ββββββββ π¨′π©′ is the image of π¨π© to π¨′ , and π© maps to π©′. Use direct measurement to determine the scale factor π, and then find the center of dilation πΆ. By the definition of dilation, π¨′ π©′ = π (π¨π©), πΆπ¨′ = π(πΆπ¨), and πΆπ©′ = π(πΆπ©). By direct measurement, π¨′ π© ′ π¨π© = π π = π. The images of π¨ and π© are pushed to the right on β‘ββββ π¨π© under the dilation, and π¨′ π©′ > π¨π©, so the center of dilation β‘ββββ must lie on π¨π© to the left of points π¨ and π©. By the definition of dilation: π (πΆπ¨) π π (πΆπ¨ + π¨π¨′ ) = (πΆπ¨) π πΆπ¨ + π¨π¨′ π = πΆπ¨ π ′ πΆπ¨ π¨π¨ π + = πΆπ¨ πΆπ¨ π π¨π¨′ π π+ = πΆπ¨ π π¨π¨′ π = πΆπ¨ π π π¨π¨′ = (πΆπ¨) π π ′ (π¨π¨ ) = πΆπ¨ π πΆπ¨′ = 3. β‘ββββ , and dilate points π¨ and π© from center πΆ where πΆ is not on π¨π© β‘ββββ . Use your diagram to explain why a Draw a line π¨π© line maps to a line under a dilation with scale factor π. ββββββ and π©π¨ ββββββ on the points π¨ and π© point in opposite directions as shown in the diagram below. The union Two rays π¨π© ββββββββ ; likewise, π©π¨ β‘ββββ . We showed that a ray maps to a ray under a dilation, so π¨π© ββββββ maps to π¨′π©′ ββββββ maps of the two rays is π¨π© ββββββββ . The dilation yields two rays π¨′π©′ ββββββββ and π©′π¨′ ββββββββ on the points π¨′ and π©′ pointing in opposite directions. The to π©′π¨′ β‘βββββββ ; therefore, it is true that a dilation maps a line to a line. union of the two rays is π¨′π©′ Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 132 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY 4. Μ Μ Μ Μ be a line segment, and let π be a line that is the perpendicular bisector of π¨π© Μ Μ Μ Μ . If a dilation with scale factor Let π¨π© Μ Μ Μ Μ Μ Μ (sending π¨ to π¨′ and π© to π©′) and also maps line π to line π′, show that line π′ is the Μ Μ Μ Μ to π¨′π©′ π maps π¨π© perpendicular bisector of Μ Μ Μ Μ Μ Μ π¨′π©′. Let π· be a point on line π, and let the dilation send π· to the point π·′ on line π′. Since π· is on the perpendicular bisector of Μ Μ Μ Μ π¨π©, π·π¨ = π·π©. By the dilation theorem, π·′ π¨′ = ππ·π¨ and π·′ π©′ = ππ·π©. So, π·′ π¨′ = π·′ π©′ , and π·′ is on the perpendicular bisector of Μ Μ Μ Μ Μ Μ π¨′π©′. 5. π π Dilate circle πͺ with radius πͺπ¨ from center πΆ with a scale factor π = . Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 133 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 8 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY 6. In the picture below, the larger circle is a dilation of the smaller circle. Find the center of dilation πΆ. ββββββ . Center πΆ lies on πͺ′πͺ ββββββ . Since π¨′ is not on a line with both πͺ and πͺ′, I can use the parallel method to find Draw πͺ′πͺ β‘ββββββ . β‘ββββ β₯ πͺ′π¨′ point π¨ on circle πͺ such that πͺπ¨ Under a dilation, a point and its image(s) lie on a ray with endpoint πΆ, the center of dilation. Draw βββββββ π¨′π¨, and label the center of dilation πΆ = ββββββ πͺ′πͺ ∩ βββββββ π¨′π¨. Lesson 8: How Do Dilations Map Lines, Rays, and Circles? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 134 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.