Ch 5-1 Notes - Variation Functions

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Chapter 5-1 Variation Functions
Obj: To solve problems involving direct, inverse, joint, and combined variation.
(WHY? – Variation functions can be used to determine how many people are needed to complete a task, such
as building a home, in a given time – See example 5)
Direct Variation is a relationship between two variables x & y that can be
written in the form: ๐‘ฆ = ๐‘˜๐‘ฅ, ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘˜ ≠ 0, ๐‘Ž๐‘›๐‘‘ ๐‘˜ ๐‘–๐‘  ๐‘Ž ๐‘๐‘œ๐‘›๐‘ ๐‘ก๐‘Ž๐‘›๐‘ก (also, it’s a
linear equation ๐‘ฆ = ๐‘š๐‘ฅ + ๐‘ ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘ = 0.)
Solving Direct Variation Problems
Ex 1 (p.313) Given: y varies directly as x, and y = 14 when x = 3.5. Write
the direct variation function. (hint: find k)
You try…y varies directly as x, and y = 6.5 when x = 13, write the direct
variation function.
When you want to find specific values in a direct variation problem, you
can solve for k and then use substitution or use the proportion derived
below.
๐‘ฆ1 = ๐‘˜๐‘ฅ1 →
๐‘ฆ1
๐‘ฅ1
= ๐‘˜ ๐’‚๐’๐’… ๐‘ฆ2 = ๐‘˜๐‘ฅ2 →
๐‘ฆ2
๐‘ฅ2
= ๐‘˜ ๐’”๐’
๐‘ฆ1
๐‘ฅ1
=
๐‘ฆ2
๐‘ฅ2
Ex 2 (p.314) – The circumference of a circle ๐ถ varies directly as the radius
๐‘Ÿ, and ๐ถ = 7๐œ‹ ๐‘“๐‘ก ๐‘คโ„Ž๐‘’๐‘› ๐‘Ÿ = 3.5 ๐‘“๐‘ก. ๐น๐‘–๐‘›๐‘‘ ๐‘Ÿ ๐‘คโ„Ž๐‘’๐‘› ๐ถ = 4.5๐œ‹ ๐‘“๐‘ก.
Joint Variation is a relationship among three variables that can be written
in the form:
๐‘ฆ = ๐‘˜๐‘ฅ๐‘ง, ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘˜ ๐‘–๐‘  ๐‘กโ„Ž๐‘’ ๐‘๐‘œ๐‘›๐‘ ๐‘ก๐‘Ž๐‘›๐‘ก. ๐น๐‘œ๐‘Ÿ ๐‘ฆ = ๐‘˜๐‘ฅ๐‘ง,
๐‘ฆ ๐‘ฃ๐‘Ž๐‘Ÿ๐‘–๐‘’๐‘  ๐‘—๐‘œ๐‘–๐‘›๐‘ก๐‘™๐‘ฆ ๐‘Ž๐‘  ๐‘ฅ ๐‘Ž๐‘›๐‘‘ ๐‘ง
Solving Joint Variation Problems
Ex 3 (p. 314) The area ๐ด of a triangle varies jointly as the base ๐‘, and the
height โ„Ž, ๐ด = 12 ๐‘š2 ๐‘คโ„Ž๐‘’๐‘› ๐‘ = 6 ๐‘š ๐‘Ž๐‘›๐‘‘ โ„Ž = 4๐‘š.
Find ๐‘ ๐‘คโ„Ž๐‘’๐‘› ๐ด = 36๐‘š2 ๐‘Ž๐‘›๐‘‘ โ„Ž = 8 ๐‘š
Step 1: Find k
Step 2: Use the variation function
You try…The lateral surface area ๐ฟ of a cone varies jointly as the base
radius ๐‘Ÿ and the slant height ๐‘™, and ๐ฟ = 63๐œ‹ ๐‘š2 ๐‘คโ„Ž๐‘’๐‘› ๐‘Ÿ = 3.5 ๐‘š ๐‘Ž๐‘›๐‘‘
๐‘™ = 18 ๐‘š. Find ๐‘Ÿ to the nearest tenth when ๐ฟ = 8๐œ‹ ๐‘š2 ๐‘Ž๐‘›๐‘‘ ๐‘™ = 5 ๐‘š
Inverse Variation is a relationship between two variables, x and y, that can
๐‘˜
be written in the form:
๐‘ฆ = , ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘˜ ≠
๐‘ฅ
๐‘˜
0. ๐น๐‘œ๐‘Ÿ ๐‘กโ„Ž๐‘’ ๐‘’๐‘ž๐‘ข๐‘Ž๐‘ก๐‘–๐‘œ๐‘› ๐‘ฆ = , ๐‘ฆ ๐‘ฃ๐‘Ž๐‘Ÿ๐‘–๐‘’๐‘  ๐‘–๐‘›๐‘ฃ๐‘’๐‘Ÿ๐‘ ๐‘’๐‘™๐‘ฆ ๐‘Ž๐‘  ๐‘ฅ
๐‘ฅ
Inverse Variation Problems
Ex 4 (p.315) Given: y varies inversely as x, and y = 3 when x = 8. Write
the inverse variation function. (again…find k!)
You try… Given: y varies inversely as x, and y = 4 when x = 10. Write the
inverse variation function.
When you want to find specific values in an inverse variation problem, you
can solve for k and then use substitution or use the equation derived
below.
๐‘ฆ1 =
๐‘˜
๐‘˜
→ ๐‘ฆ1 ๐‘ฅ1 = ๐‘˜ ๐’‚๐’๐’… ๐‘ฆ2 =
→ ๐‘ฆ2 ๐‘ฅ2 = ๐‘˜ ๐’”๐’ ๐‘ฆ1 ๐‘ฅ1 = ๐‘ฆ2 ๐‘ฅ2
๐‘ฅ1
๐‘ฅ2
Ex 5 (p.315) The time t that it takes for a group of volunteers to construct
a house varies inversely as the number of volunteers v. If 20 volunteers
can build a house in 62.5 working hoours, how many volunteers would be
needed to build a house in 50 working hours?
REMEMBER…….
Homework Ch 5-1/ 5.1 – Pg 317, 1 – 12 (do not graph)
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