Chapter 5-1 Variation Functions Obj: To solve problems involving direct, inverse, joint, and combined variation. (WHY? – Variation functions can be used to determine how many people are needed to complete a task, such as building a home, in a given time – See example 5) Direct Variation is a relationship between two variables x & y that can be written in the form: ๐ฆ = ๐๐ฅ, ๐คโ๐๐๐ ๐ ≠ 0, ๐๐๐ ๐ ๐๐ ๐ ๐๐๐๐ ๐ก๐๐๐ก (also, it’s a linear equation ๐ฆ = ๐๐ฅ + ๐ ๐คโ๐๐๐ ๐ = 0.) Solving Direct Variation Problems Ex 1 (p.313) Given: y varies directly as x, and y = 14 when x = 3.5. Write the direct variation function. (hint: find k) You try…y varies directly as x, and y = 6.5 when x = 13, write the direct variation function. When you want to find specific values in a direct variation problem, you can solve for k and then use substitution or use the proportion derived below. ๐ฆ1 = ๐๐ฅ1 → ๐ฆ1 ๐ฅ1 = ๐ ๐๐๐ ๐ฆ2 = ๐๐ฅ2 → ๐ฆ2 ๐ฅ2 = ๐ ๐๐ ๐ฆ1 ๐ฅ1 = ๐ฆ2 ๐ฅ2 Ex 2 (p.314) – The circumference of a circle ๐ถ varies directly as the radius ๐, and ๐ถ = 7๐ ๐๐ก ๐คโ๐๐ ๐ = 3.5 ๐๐ก. ๐น๐๐๐ ๐ ๐คโ๐๐ ๐ถ = 4.5๐ ๐๐ก. Joint Variation is a relationship among three variables that can be written in the form: ๐ฆ = ๐๐ฅ๐ง, ๐คโ๐๐๐ ๐ ๐๐ ๐กโ๐ ๐๐๐๐ ๐ก๐๐๐ก. ๐น๐๐ ๐ฆ = ๐๐ฅ๐ง, ๐ฆ ๐ฃ๐๐๐๐๐ ๐๐๐๐๐ก๐๐ฆ ๐๐ ๐ฅ ๐๐๐ ๐ง Solving Joint Variation Problems Ex 3 (p. 314) The area ๐ด of a triangle varies jointly as the base ๐, and the height โ, ๐ด = 12 ๐2 ๐คโ๐๐ ๐ = 6 ๐ ๐๐๐ โ = 4๐. Find ๐ ๐คโ๐๐ ๐ด = 36๐2 ๐๐๐ โ = 8 ๐ Step 1: Find k Step 2: Use the variation function You try…The lateral surface area ๐ฟ of a cone varies jointly as the base radius ๐ and the slant height ๐, and ๐ฟ = 63๐ ๐2 ๐คโ๐๐ ๐ = 3.5 ๐ ๐๐๐ ๐ = 18 ๐. Find ๐ to the nearest tenth when ๐ฟ = 8๐ ๐2 ๐๐๐ ๐ = 5 ๐ Inverse Variation is a relationship between two variables, x and y, that can ๐ be written in the form: ๐ฆ = , ๐คโ๐๐๐ ๐ ≠ ๐ฅ ๐ 0. ๐น๐๐ ๐กโ๐ ๐๐๐ข๐๐ก๐๐๐ ๐ฆ = , ๐ฆ ๐ฃ๐๐๐๐๐ ๐๐๐ฃ๐๐๐ ๐๐๐ฆ ๐๐ ๐ฅ ๐ฅ Inverse Variation Problems Ex 4 (p.315) Given: y varies inversely as x, and y = 3 when x = 8. Write the inverse variation function. (again…find k!) You try… Given: y varies inversely as x, and y = 4 when x = 10. Write the inverse variation function. When you want to find specific values in an inverse variation problem, you can solve for k and then use substitution or use the equation derived below. ๐ฆ1 = ๐ ๐ → ๐ฆ1 ๐ฅ1 = ๐ ๐๐๐ ๐ฆ2 = → ๐ฆ2 ๐ฅ2 = ๐ ๐๐ ๐ฆ1 ๐ฅ1 = ๐ฆ2 ๐ฅ2 ๐ฅ1 ๐ฅ2 Ex 5 (p.315) The time t that it takes for a group of volunteers to construct a house varies inversely as the number of volunteers v. If 20 volunteers can build a house in 62.5 working hoours, how many volunteers would be needed to build a house in 50 working hours? REMEMBER……. Homework Ch 5-1/ 5.1 – Pg 317, 1 – 12 (do not graph)