G.SRT.B.5 STUDENT NOTES & PRACTICE WS #1 – geometrycommoncore.com 1 Geometric mean…..? Is that the same mean referred to when we say MEAN, MEDIAN AND MODE? NO!! That mean is actually called the Arithmetic Mean. The Arithmetic mean of n numbers is the sum of values of the numbers divided by n. The Arithmetic Mean determines the ‘average’ number of the group. Geometry has its own mean and is much different than the Arithmetic Mean. The Geometric Mean of two numbers, a and b, is the unique number x such that: a x x b This is quite a special situation, where x is used as denominator in one ratio and as a numerator in the other and yet BOTH RATIOS EQUAL EACH OTHER. Let’s look at an example of this special situation. The geometric mean of 4 and 9 is 6 because 4 6 6 9 36 = 36. Let’s find the geometric mean of a few different values. What is the geometric mean of 2 and 8? 2 x x 8 x 16 2 x 4 Test out the value to see if it works 2 4 4 8 16 = 16 What is the geometric mean of 6 and 24? What is the geometric mean of 5 and 15? 6 x x 2 144 x 12 x 24 5 x x 2 75 x 75 x 15 x 5 3 Test out the value to see if it works Test out the value to see if it works 6 12 12 24 144 = 144 5 5 3 5 3 15 75 = 75 NYTS (Now You Try Some) 1. What is the geometric mean of 9 and 16? 2. What is the geometric mean of 10 and 40? 3. What is the geometric mean of 8 and 16? So the question becomes…. What does this have to do with geometry? Great question!! This unique proportion appears in a special type of triangle and it has a lot to do with similarity. G.SRT.B.5 STUDENT NOTES & PRACTICE WS #1 – geometrycommoncore.com 2 Given any right triangle, ABC. B Drop the altitude (the height) from the right angle (B) to the opposite side AC . Let the altitude be called BD . o x C A This forms three triangles. Inner Left ADB Inner Right BDC Outer Whole ABC B o x A C D B If we look carefully at ABC we see that mB = 90, mA = o and mC = x, in other words o + x + 90 = 180. x Knowing that the 3rd ’s of a must be we can determine some of the missing angle values in the diagram, mABD = x (180 - 90 - o) and that mCBD = o (180 - 90 - x). o o x A C D B Notice that all three triangles are similar to each other by AA. It is this unique relationship that will create three different geometric mean relationships. o x A GEOMETRIC MEAN #1 -- Using the fact that ADB ABC, we can set up the proportion: C D B B x left AD AB whole AB AC AB 2 AD( AC ) GEOMETRIC MEAN #2 -- Using the fact that BDC ABC, we can set up the proportion: right DC BC whole BC AC o A o D x A C B B o x o D C x A C BC 2 DC ( AC ) GEOMETRIC MEAN #3 -- Using the fact that ADB BDC, we can set up the proportion: B B o x right AD BD left BD DC BD2 AD( DC ) x o A D D C G.SRT.B.5 STUDENT NOTES & PRACTICE WS #1 – geometrycommoncore.com The three geometric means are: 3 B AB 2 AD( AC ) BC 2 DC ( AC ) BD2 AD( DC ) o AB AD( AC ) BC DC ( AC ) A BD AD( DC ) x D C Let’s apply these three geometric mean relationships to solve problems. x z y z y x 9 cm 12 cm 6 cm z y x 5 cm x y 2 (4)(9) x 2 (4)(13) 52 z 2 (9)(13) 117 z 2 36 x 2 13 2 13 z 3 13 3 13 z 6 6 x 2 (12)(12 9) z 2 (9)(9 12) y 2 (12)(9) x 2 (12)(21) 252 z 2 (9)(21) 189 z 2 108 x 6 7 6 7 z 3 21 3 21 z 6 3 6 3 From this point forward I will only list the positive value that applies to the given situation. 62 ( x)(10) 36 10 x x 3.6 z 2 (6.4)(10) y 2 (3.6)(6.4) z 2 64 z 2 23.04 z 8 8 z 4.8 4.8 52 (12)( x) 25 12 x x 2.08 y 2 (2.08)(14.08) z 2 (12)(14.08) y 2 29.29 z 2 168.96 y 5.41 5.41 z 13.00 13.00 10 cm z y z 2 (9)(4 9) Only the positive value makes sense here because we are solve for lengths. 9 cm 4 cm x 2 (4)(4 9) 12 cm Answers: 1. +12 or -12 2. +20 or -20 3. +8sqrt(2) or – 8sqrt(2) 4. x = 6sqrt(5) cm, y = 12 cm, z = 12sqrt(5) cm 5. x = 8sqrt(2) cm, y = 8 cm, z = 8sqrt(2)cm 6. x = 24 cm, z = 6sqrt(2) cm, y = 18sqrt(2) cm 6. y z 9 cm 3 cm x 5. 8 cm 8 cm x y z 4. 24 cm 6 cm y x z NYTS (Now You Try Some) Determine the values for x, y and z. G.SRT.B.5 STUDENT NOTES & PRACTICE WS #1 – geometrycommoncore.com 4