KEY FORMULAS Chapter 2 ο· ο· Mean for ungrouped data: µ=∑x/N and π₯Μ =∑x/n Mean for grouped data: µ=∑mf/N and π₯Μ =∑mf/n where m is the midpoint and f is the frequency of a class ο· Median for ungrouped data = Value of the ( ο· ο· term in a ranked data set Range = Largest Value-Smallest Value Standard deviation for ungrouped data: π=√ 2 ∑π π=1(π₯π −µ) ο· 2 ∑π π=1(π₯π −π₯Μ ) 2 ∑πΎ π=1 ππ (ππ −µ) Standard deviation of discrete random variable x: π = √∑ π₯ 2 π(π₯) − π2 ο· ο· ο· ο· ο· Hypergeometric probability Formula: P(x)= (π₯π )(π−π π−π₯ ) (π π) π −π ππ₯ ο· Poisson probability Formula: P(x)= ο· Mean and variance of the Poisson probability distribution: E(x)= π = π, Var(x)= π = π. π₯! Chapter 5 ο· 2 ∑πΎ π=1 ππ (ππ −π₯Μ ) π−1 π π π π₯Μ Chebyshev’s Theorem: For any population with mean µ, Standard deviation π , and k>1, the percent of observations that lie within the interval [µ±k π] is at least [1-(1/π 2 )]% where k is the number of Standard deviations. Emprical Rule: For many large populations the empirical rule provides an estimate of the approximate percentage of observations that are contained within one, two, or three Standard deviations of the mean: o Approximately 68% of the observations are in the interval (π ± π) , o Approximately 95% are in the interval (π ± 2π), o Almost all of the observations are in the interval (π ± 3π). Interquartile Range: IQR = π3 − π1 where π3 is the third quartile and π1 is the first quartile. ∑(π₯π −π₯Μ )(π¦π −π¦Μ ) ο· πΆππ£(π₯, π¦) = ο· Correlation coefficient; π−1 ππ₯π¦ = Mean and Standard deviation of the uniform probability distribution: π= Coefficient of Variation: πΆππ£(π₯, π¦) π π₯ π π¦ Chapter 3 ο· (N )= n ο· ο· ο· P(A ∪ B) = P(A) + P(B) − P(A ∩ B) ο· N! n!(N−n)! Bayes′ Theorem: P( Ai β£ B ) = P(Ai )P(Bβ£Ai ) P(A1 )P( Bβ£β£A1 )+β―+P(An )P( Bβ£β£An ) π+π 2 and π = √ (π−π)2 12 π§ value for an x value: π₯−π π Normal Distribution Approximation for Binomial Distribution: π§= ο· Z= π−ππ √ππ(1−π) ο· Exponential Distribution The probability that the time btw arrivals is π‘π or less is as follows: π(π ≤ π‘π ) = (1 − π −ππ‘π ) Chapter 6 ο· ο· Standard deviation (Standard error) of πΜ π ππΜ = √π If n/N>0.05 Standard deviation (Standard error) of πΜ ππΜ = ο· π √π π−π .√ π−1 Standard deviation of πΜ π(1 − π) ππΜ = √ π Chapter 7 Confidence Interval for; ο· population mean with known variance π π₯Μ ±π§πΌ/2 √π ο· population mean with unknown variance π π₯Μ ± π‘π−1,πΌ/2 √π ο· population proportion πΜ ± π§πΌ/2 √ P(A ∩ B) = P(B)P(A β£ B) Chapter 4 Mean and Standard deviation of the binomial distribution: π = ππ πππ π = √πππ CV = π₯ 100% or π₯ 100% ο· Binomial probability Formula: P(x)=(ππ₯)π π₯ ππ−π₯ , where p+q=1. and π π = √ ο· where π and π are population π−1 and sample Standard deviations, respectively. Standard deviation for grouped data: π=√ ο· 2 Mean of a discrete random variable x: π = ∑ π₯π(π₯) )th and π π = √ π+1 ο· ο· πΜ (1 − πΜ ) π Confidence interval for the population variance (π − 1)π 2 (π − 1)π 2 < π2 < 2 2 ℵπ−1,πΌ/2 ℵπ−1,1−πΌ/2 Chapter 8 Confidence Interval for; ο· ο· the difference between means π π πΜ ± π‘π−1,πΌ/2 √π Independent samples with known population variances (π₯Μ − π¦Μ ) ± π§πΌ/2 √ ο· ππ₯2 ππ₯ ο· Tests of the variance of a normal distribution; (π − 1)π 2 ℵ2 = π02 Chapter 10 Hypothesis Testing for Two Sample ο· Tests of the Difference Between Two Population Means: Dependent Samples; πΜ − π·0 π‘(π−π,πΆ) = π π /√π ο· Tests of the Difference Between Two Population Means: Independent Samples; 1. Known Variances π₯Μ − π¦Μ − π·0 π§πΌ = π2 π2 √ π₯+ π¦ ππ₯ ππ¦ ππ¦2 + ππ¦ Independent samples with unknown population variances and the variances are assumed to be equal π π2 π π2 (π₯Μ − π¦Μ ) ± π‘ππ₯ +ππ¦−2,πΌ/2 √ + ππ₯ ππ¦ π π2 = ο· [(ππ₯ − 1) π π₯2 + (ππ¦ − 1) π π¦2 ] ππ₯ + ππ¦ − 2 2. Independent samples with unknown population variances and the variances are not assumed to be equal π π₯2 π π¦2 (π₯Μ − π¦Μ ) ± π‘(π,πΌ/2) √ + ππ₯ ππ¦ [ π= ο· Unknown Population Variances: Assumed to be Equal π₯Μ − π¦Μ − π·0 π‘(ππ₯ +ππ¦−2,πΌ) = π 2 π 2 √ π+ π ππ₯ ππ¦ [(ππ₯ − 1) π π₯2 + (ππ¦ − 1) π π¦2 ] ππ₯ + ππ¦ − 2 Population Variances Unknown and Not Equal; π 2 π π¦2 [ π₯ + ]2 ππ₯ ππ¦ π= 2 2 π π¦2 π π₯2 ( ) ( ) ππ¦ ππ₯ + ππ₯ − 1 ππ¦ − 1 π π2 = 3. π π₯2 π π¦2 2 + ] ππ₯ ππ¦ 2 2 π π¦2 π 2 ( ) ( π₯) ππ¦ ππ₯ + ππ₯ − 1 ππ¦ − 1 the difference between two population proportion πΜπ₯ (1 − πΜπ₯ ) πΜπ¦ (1 − πΜπ¦ ) (πΜπ₯ − πΜπ¦ ) ± π§πΌ/2 √ + ππ₯ ππ¦ π‘(π,πΆ) = √ Sample Size determination ο· ο· for the mean of a normally distributed population with known population variance 2 zα/2 σ2 n= ME2 for population proportion (zα/2 )2 0.25 n= ME2 Chapter 9 Hypothesis Testing for One Sample ο· Tests of the mean of a normal distribution: population variance known; Μ Μ Μ (π₯ − π0 ) π§πΌ = π/√π ο· Tests of the mean of a normal distribution: population variance unknown; Μ Μ Μ − π0 ) (π₯ π‘(π−1,πΌ) = π /√π ο· Tests of the population proportion; π§πΌ = πΜ − π √π(1 − π)/π π₯Μ − π¦Μ − π·0 ο· π π₯2 π π¦2 + ππ₯ ππ¦ Tests of the Difference Between Two Population Proportions; ππ₯ π Μπ₯ + ππ¦ π Μπ¦ π Μ0 = ππ₯ + ππ¦ π§πΌ = (π Μπ₯ + π Μ) π¦ π Μ(1 − π Μ) π Μ(1 − π Μ) √ 0 π 0 + 0 π 0 π₯ π¦