Warm Up Find AB. 1. A(0, 15), B(17, 0) 2. A(–4, 2), B(4, –2) Solve each equation. Round to the nearest tenth or nearest degree. 3. cos 26ο° = π₯ 7 4. sin 26ο° = π¦ 7 5. tan π = 41 52 6. tan π = 13 11 ============================================================================================== Geometry/Lesson 8-6: Vectors Objectives: ο· ο· Find the magnitude and direction of a vector. Use vectors and vector addition to solve real world problems. The speed and direction an object moves can be represented by a vector. A vector is a quantity that has both length and direction. You can think of a vector as a directed line segment. The vector below may be named βββββ π΄π΅ ππ π£ . 1 Example 1: Write the vector in component form. 1A. ββββββ π»πΊ 1B. βββββββ with M(–8, 1) and N(2, –7) ππ The horizontal change from H to G is –3 units. The vertical change from H to G is 5 units. ββββββ is <–3, 5>. So the component form of π»πΊ C.I.O.-Example 1: Write the vector in component form. 1a. β π 1b. the vector with initial point L(–1, 1) and terminal point M(6, 2) βββββ | or |π£ |. The magnitude of a vector is its length. The magnitude of a vector is written |π΄π΅ When a vector is used to represent speed in a given direction, the magnitude of the vector equals the speed. For example, if a vector represents the course a kayaker paddles, the magnitude of the vector is the kayaker’s speed. Example 2: Draw the vector <–1, 5> on a coordinate plane. Find its magnitude to the nearest tenth. Step 1 Draw the vector on a coordinate plane. Use the origin as the initial point. Then (–1, 5) is the terminal point. 2 C.I.O.-Example 2: Draw the vector <–3, 1> on a coordinate plane. Find its magnitude to the nearest tenth. Example 3: The force exerted by a skier is given by the vector <1, 4>. Draw the vector on a coordinate plane. Find the direction of the vector to the nearest degree. Step 1 Draw the vector on a coordinate plane. Use the origin as the initial point. Step 2 Find the direction. Draw right triangle ABC as shown. οA is the angle formed by the vector and the x-axis, and tan π΄ = 4 1 = 4. So, mοA = tan–1 (4) ≈ 76ο°. C.I.O.-Example 3: The force exerted by a tugboat is given by the vector <7, 3>. Draw the vector on a coordinate plane. Find the direction of the vector to the nearest degree. 3 Two vectors are equal vectors if they have the same magnitude and the same direction. For example, π’ β = π£ . Equal vectors do not have to have the same initial point and terminal point. Two vectors are parallel vectors if they have the same direction or if they have opposite directions. They may have different magnitudes. For example, π€ ββ βπ₯ . Equal vectors are always parallel vectors. Example 4: Identify each of the following. 4A. equal vectors 4B. parallel vectors C.I.O.-Example 4: Identify each of the following. 4a. equal vectors 4b. parallel vectors The resultant vector is the vector that represents the sum of two given vectors. To add two vectors geometrically, you can use the head-to-tail method or the parallelogram method. 4 Example 5: An airplane is flying at a constant speed of 400 mi/h at a bearing of N 70º E. A 60 mi/h wind is blowing due north. What are the plane’s actual speed and direction? Round the speed to the nearest tenth and the direction to the nearest degree. Lesson Quiz: Part I Round angles to the nearest degree and other values to the nearest tenth. 1. Write ββββ ππ with S(–5, 2) and T(8, –4) in component form. 2. Write π£ with magnitude 12 and direction 36° in component form. 3. Find the magnitude and direction of the vector <4, 5>. 5 Lesson Quiz: Part II 4. Find the sum of the vectors <2, –4> and <3, 6>. Then find the magnitude and direction of the resultant vector. 5. A boat is heading due east at a constant speed of 35 mi/h. There is an 8 mi/h current moving north. What is the boat’s actual speed and direction? p. 582: 18-20, 23, 25, 27-35, 39, 41, 45, 47 18) ο‘9, 2ο± 20) ο‘–4, –4ο± 28) All four vectors are parallel βββββ ; ββββββ ββββββ βπΉπΊ βββββ 30) ββββββ π¨π©βπΌπ½ πͺπ«βπΏπ 32) ο‘1, 8ο± 34) ο‘7, 1ο± 6