Complex Numbers Summary Academic Skills Advice What does a complex number mean? A complex number has a ‘real’ part and an ‘imaginary’ part (the imaginary part involves the square root of a negative number). e.g. Z = a + πb We use Z to denote a complex number: Real Example: Imaginary You might see the π before or after it’s number - it doesn’t matter which. Z = 4 + 3i Re(Z) = 4 Im(Z) = 3 Sometimes (especially in engineering) a j is used instead of π – they mean the same thing. Powers of i π stands for √−1 so: For any power of π take out as many π and they will all end up as ±π or ±1. Example: 2 π 2 = (√−1) = -1 π 4 = (π 2)2 = (-1)2 = 1 4’s and π 2’s as possible Summary: π = √−π ππ = −π ππ = π π−π = −π π−π = π π 11 = (π 4 )2 π 2 π = 12 × −1 × π = −π Adding & Subtracting This is easy – just add or subtract the real part and add or subtract the imaginary parts: Examples: (4 + 3π ) + (2 + 6π ) = (6 + 9π ) (3 + 7π ) – (1 – 3π ) = (2 + 10π ) Multiplying Multiply out the 2 brackets. Example: (3 + 5π )(4 – 2π ) = 12 – 6π +20π – 10π 2 = 12 + 14π – 10 (-1) = 22 + 14π Complex Conjugate The conjugate is exactly the same as the complex number but with the opposite sign in the middle. When multiplied together they always produce a real number because the middle terms disappear (like the difference of 2 squares with quadratics). Example: (4 + 6π )(4 – 6π ) = 16 – 24π + 24π – 36π 2 = 16 – 36(-1) = 16 + 36 = 52 © H Jackson 2010 / Academic Skills 1 Dividing Dividing by a real number: divide the real part and divide the imaginary part. Dividing by a complex number: Multiply top and bottom of the fraction by the complex conjugate of the denominator so that it becomes real, then do as above. Examples: 3+4π 2 4−5π 3+2π 3 = 2 4 + π = 1.5 + 2π 2 4−5π = 3+2π × 3−2π 12−8π−15π+10π 2 = 3−2π 9−6π+6π−4π 2 = 12−23π+10(−1) 9−4(−1) = 2−23π 13 = π ππ − ππ ππ π Graphical Representation A complex number can be represented on an Argand diagram by plotting the real part on the π₯-axis and the imaginary part on the y-axis. Example: Imaginary P (π§ = π₯ + π¦π) y 0 Nb Tan(θ) = π¦ π₯ π π₯ Real is written as |π| and is the length of OP, therefore |π§| = √π₯ 2 + π¦ 2 is the angle θ that is made with the horizontal axis (denoted by ∠). Modulus: Argument: Properties of the Modulus and Argument π§1 = Let π§2 Then |π§1 | = These let you find the modulus and the argument when one complex number is divided by another. π Examples: |π§2 | Then |π§1 | = |π§2 | × |π§3 | |π§3 | ∠π§1 = ∠π§2 − ∠π§3 And π And π§ if π§2 = 5π 2 π , π§3 = 3π 3 π , π§1 = π§2 3 Then |π§1 | = And |π§2 | |π§3 | 5 ∠π§1 = ∠π§2 − ∠π§3 π π 5 π ∴ π§1 = 3 π 6 π © H Jackson 2010 / Academic Skills ∠π§1 = ∠π§2 + ∠π§3 π if These let you find the modulus and the argument when one complex number is multiplied by another. π π§2 = 5π 2 π , π§3 = 3π 3 π , π§1 = π§2 π§3 Then |π§1 | = |π§2 | × |π§3 | = 15 =3 =2−3 = π§1 = π§2 π§3 Let π§3 π 6 And ∠π§1 = ∠π§2 + ∠π§3 π π =2+3 = 5π 6 5π ∴ π§1 = 15π 6 π 2 Polar Form Once you have shown a complex number on an Argand diagram then it’s easy to find the length of the line and the angle it makes with the π₯-axis. To find the length: use Pythagoras To find the angle: use tan π½ Once you have this info you can write the complex number in polar form: π = πππππ½ + ππππππ½ π = π(ππππ½ + πππππ½) Example: Express π§ = 3 + 4π in polar form imaginary Pythagoras: π = √32 + 42 = √16 + 9 = √25 = 5 π 0 Where π is the length of the line and π is the angle it makes with the π₯-axis. 4 π 3 4 π = 53.1o Tan π: tanπ = 3 Polar form: π§ = 5(cos 53.1 + ππ ππ53.1) real Nb if, when you draw the complex number, it’s in a different quadrant adjust the angle as necessary. Exponential Form π = ππππ½ The 3 forms: (where π and π are the same as in polar form but π must be in radians) Basic π = π + ππ Polar π = π(ππππ½ + πππππ½) Exponential π = ππππ½ De Moivres Theorem: Is used for raising a complex number to a power. ππ = ππ (πππππ½ + ππππππ½) π e.g e.g.2: (1 + π)100 If π§ = 3π 3 π then π§ 5 = 35 (πππ © H Jackson 2010 / Academic Skills 5π 3 + ππ ππ 5π ) 3 We could use De Moivres or: (1 + π)100 = ((1 + π)2 )50 3