AP CALCULUS - AB Section Number: 4.5 MR. RECORD Day: 52 Topics: Integration by Substitution Basic u-substitution Change of Variable Method The role of integration by substitution is similar to that of the Chain Rule for differentiation. Recall that the Chain Rule states d Given y F (u) and u g(x), then F (g(x)) F (g(x)) g (x) . dx From the definition of an antiderivative, it follows that F (g(x)) g(x)dx F (g(x)) C or F (u) C It may be easier to think of this idea written this way instead: du f (u) dx dx F (u) C U-Substitution and Recognizing Patterns Example 1: a. 2 x( x 2 The integrand in each of the following integrals fits the patterns above. Integrate each. 1) dx 4 b. 3x 2 x 3 1 dx c. sec 2 x(tan x 3)dx du is not a perfect match. What do we do? The following Example will illustrate this issue. dx Example 2: The integrand in each of the following integrals still fits the patterns above. They just need a “minor adjustment.” Integrate each. 7x2 dx a. x(x 2 1)6 dx b. 2 x 1 dx c. 4x3 5 Sometimes You can perform this same integration technique for trigonometric functions as well. Example 3: Integrate each. a. sin2x dx Example 4: Integrate b. csc 2 d 4 sin 3x cos3x dx 2 BEWARE: Some problems in the Textbook HW will not require a u-substitution method at all. Be alert. Change of Variable Method Here is a slightly different type of Integration by Substitution problem: x 2 x 1 dx . Although we will still utilize a “substitution,” we will go about it a bit differently. This method is called the “Change of Variable” method. Your textbook (oddly enough) calls it the “Method of Example 5” prior to Exercises 67-74. If you examine the method closely, however, it is the same as our typical “U-substitution Method.” Example 5: Integrate. a. x 2 x 1 dx b. 2x 1 dx x4 AP CALCULUS - AB Section Number: 4.5 MR. RECORD Day: 53 Topics: Integration by Substitution Substitution and Definite Integration The Accumulation Function – Part II Substitution with Definite Integration Example 6: Evaluate each of the following. Note: There are two ways that you can approach these problems. Watch carefully. 5 1 3 x 2 dx a. x x 1 dx b. 2x 1 0 1 Once again you can choose to either “back substitute” your expression in terms of x and keep the original boundaries OR you can keep your answer in terms of u and change the boundaries. The choice is up to you. The AP Exam likes to ask questions which require you to change the boundaries. x 3 Example 7: Which of the following is an equivalent integral expression for 2 3 (A) 1 3 2 u du u du 25 (B) 6 (C) 25 u du 25 1 3 6 1 (D) 3 6 u 2 du (E) None of the above 2 x3 2 dx ? The Accumulation Function- II x Example 7: Let F (x) f (t )dt where f is the function graphed below (consisting of lines and a semi-circle). 0 Find the following: a. F (0) b. F (2) c. F (4) d. F (6) e. F (1) f. F (2) g. F (3) h. F (4) i. F (4) j. F (2) k. F (6) l. F ( 3) m. On what subintervals 4,6 is F increasing and decreasing? Justify your answer. n. Where in the interval 4,6 does F achieve its minimum value? What is the minimum value? The information at the beginning of the problem has been recopied for your convenience. x Let F (x) f (t )dt where f is the function graphed below (consisting of lines and a semi-circle). 0 o. Where in the interval 4,6 does F achieve its maximum value? What is the maximum value? p. Where on the interval 4,6 is F concave up? Where is F concave down? Justify. q. Where does F have points of inflection? r. Sketch the function F.