Memo Date: February 17, 2015 To: Inst. Trott and GTA Mohini Dutt From: Joshua Epperson, Brooke Ott, Luisa Parish, and Ben Weisman Subject: Detection Circuit Lab___________________________________________________ Introduction During the microfluid lab, two different experimentation methods were performed to look at fluid flow and capillary forces. The capillary forces and fluid flow was examined in order to determine the movement of liquids in a chip. While another section of the procedure examined the capillary forces of water in the capillary tube. In the following memorandum, the results of the experimentation are presented, then the results are analyzed and discussed, and finally the NTM Questions are answered. Results A sample calculation for pressure change is shown below assuming a liquid density of 998.2 kg/m3, gravitational acceleration of 9.81 m/s2, and a change in height of water of 0.0050 m. βπ = −ππββ (1) βπ = πΆβππππ ππ ππππ π π’ππ π = π·πππ ππ‘π¦ ππ ππππ’ππ = 998.2 ππ/π3 π = πππππππππ‘πππ ππ’π π‘π ππππ£ππ‘π¦ = 9.81 π/π 2 ββ = πβππππ ππ βπππβπ‘ ππ ππππ’ππ = −.0050 π Figure 1, shown below, illustrates how pressure changes by varying the diameter of a capillary tube. Using the equation of the trend line created by the data points, the change in pressure of a capillary tube with a 200 micron diameter was extrapolated and calculated to be 33 kg/m-s2. Change in Pressure (kg/m-s2) Change in Pressure vs. Diameter 100 90 80 70 60 50 40 30 20 10 0 y = 17615x + 29.523 0 0.0005 0.001 0.0015 0.002 Diameter of Tube (m) Figure 1: Change in Pressure vs. Diameter for Capillary Tubes Discussion 0.0025 This paragraph discusses the effect of channel size on the flow in the channel. If the same amount of pressure is being pushed into the channel from the syringe, then the flow would be faster in a smaller channel compared to a wider or deeper channel. This occurs because the same amount of volume in going through a smaller channel, but in order to get that same amount of liquid to the detection well, for example, the channel that is smaller has to have a quicker flow. This shows that check valves should stop liquid flowing back up other staging wells because the liquid in the channels flow faster than in the check valve because the check valves have more volume and the flow of liquid in them is slower. The result of the lab show that the channel with the 90 degree angle with a check valve worked the best. However all of the channels met at one point before going into the detection well with was an issue with back flow into the other staging wells. If the channel ended in the detection well then the back flow into the other channels may have occurred once the detection well was filled but since the channels met up at one point the other channels got filled before the detection was. This happened with all of the staging wells regardless of the slight suction at the end of the waste well. The channel that had the straight channel path moved very quickly and the liquid had to be put in slower compared to the curved or 90 degree angle channels. This paragraph is going to discuss ways to improve the procedure of the lab was well as the chip design. To improve the chip the channels should end at the detection well and not meet up together before going into the detection well. In Lab 1 the wells that worked the best were the ones with a slice taken out in the staging wells. This should be incorporated into the chip design to make it perform better. To help stop the back flow into the other channels if it was completely possible to plug the staging wells that were not being used this would help the fluid from not entering the channels leading up to the staging well and the staging well itself. Another way to create this would be just to have one staging well so there are no other places for the fluids to go. Also in theory if there was more than one check valve this would help stop the liquid from going up the channels into the other staging wells. Also with the slight suction at the waste well and the injection of the fluid at the staging well both should be a consistent rate. However, if the suction was too quick the fluid would not fill the detection well completely and it would go directly into the waste well. If there was a way to have both flows be equal then that would not only fill the detection well but also stop the back flow. NTM Questions In detergents, surfactants are used to help dissolve substances that are organically hydrophobic. Surfactants assemble into micelles that bond to the hydrophobic tails of the molecules, thus allowing the hydrophilic heads to interact with the water molecules. Once the bonds between the hydrophobic tails are broken by the micelles the water molecules are able to separate the hydrophobic molecules and thus the oily substance is dissolved in the water. When the triglyceride is placed in pure water the hydrophobic tails maintain their bonds and triglyceride molecules are much less soluble. For this problem the number of molecules must first be calculated. This is done by dividing the total surface area by the area covered by one fatty acid molecule—yielding 1e13 molecules needed. Next, the number of grams must be found by dividing the molecules needed by the amount in 1 gram. This gives 5e-9 grams. Finally, the density is divided by this number to find the volume in mL. Therefore, 6.25 nL are needed, or 6.25e-6 mL. Conclusion In conclusion, this lab helped look at fluid flow on a small scale. The pressure was calculate of the capillary tubes in order to determine there was more pressure in a smaller capillary tube. This means that the fluid is going to flow at a higher pressure as the channels in the Lab-On-A-Chip get smaller. From testing the sample Lab-On-A-Chip, it was determined that the channels should not connect before going into the detection well otherwise the fluid flowed into other staging wells. During the lab, several difficulties were encountered. During the cleaning procedure, it was difficult to assemble the chip with proper alignments using tweezers. Another difficulty in testing the fluid flow was created the suction in the waste well while inserting the fluid into the staging wells. The fluid continually flowed back into the staging well before entering the detections wells. This was a reoccurring problem for all of the staging wells. Appendix: Table A1: Capillary Testing Data Capillary A: Inside Diameter = 2.26 mm Trial 1 Δh: -0.0069 m ΔP: 68 kg/m-s2 Trial 2 Δh: -0.0091 m ΔP: 89 kg/m-s2 Trial 3 Δh: -0.0052 m ΔP: 51 kg/m-s2 Capillary B: Inside Diameter = 1.03 mm Trial 1 Δh: -0.0031 m ΔP: 30 kg/m-s2 Trial 2 Δh: -0.0065m ΔP: 64 kg/m-s2 Trial 3 Δh: -0.0050 m ΔP: 49 kg/m-s2 Sample Calculations: Change in Pressure βπ = −ππββ βπ = −(998.2 ππ/π3 )(9.81π /π 2 )(−0.0050π) βπ = 49 ππ/(π ∗ π 2 ) Change in Pressure= (density)*(gravity)*(change in height) (1)