Trigonometry Final Exam Study Guide General Study Tips: •rework all tests and take-home quizzes, example problems from class, and tests in online test archive •memorize formulas and names of formulas, and the cases to which you apply them Topics to Know: Algebra •manipulate fractions, including complex fractions •rationalize denominators •factor •apply the square root theorem, zero product property, and quadratic formula Basic Trig Topics (Ch. 5): • evaluate without a calculator all six trig functions of any angle in radians or degrees having a 0, 30, 45, 60, or 90 reference angle •evaluate without a calculator all six trig functions of any angle, given one of the six trig function values and the quadrant •apply concepts of cofunction and like reference angles to evaluate trig functions given angles that are complements or have the same reference angle but are in different quadrants •convert between radians and degrees •angles of elevation and depression •linear speed, angular speed, and arc length Graphing: •graph all 6 basic trig functions • find amplitude and period •rewrite all equations by factoring to find horizontal shift (-c/b) •apply horizontal and vertical shifts •graph sum and difference of basic trig and linear functions Identities (Ch. 6): •evaluate trig functions of a given angle using sum, difference, half, and double angle identities •simplify expressions using identities •evaluate double, half, sum, and difference identities of an angle, given trig functions of one or more original angles and the quadrant(s) •evaluate inverse trig functions and compositions of inverse functions •solve trig equations for both all real values of the variable and for all values of the variable in a given interval •prove trigonometric identities Solving Triangles (Ch. 7) •identify type of triangle (SSS,SAS,SSA,ASA,AAS) •solve any triangle given at least one side and two other measures •solve word problems involving the Law of Sines and Law of Cosines •find the area of any triangle Vectors (Ch. 7) •perform arithmetic operations with vectors (scalar multiplication and vector addition/subtraction) •find the magnitude and direction angle of any vector •write vectors in component form and in terms of ๐โ and ๐โ •find a unit vector in the direction of any vector •find the dot product of two given vectors •find the angle between two vectors •solve word problems involving a mass on an incline •solve word problems involving heading of boats and airplanes Trigonometric Form of Complex Numbers (Ch. 7) •convert between standard form and trigonometric form •determine the modulus and argument of a given complex number •multiply and divide complex numbers in trigonometric form Trig Functions of an Acute Angle ๐ ๐๐๐ ๐๐๐๐๐ ๐๐ก๐ ๐ sin ๐ = cos ๐ = tan ๐ = โ๐ฆ๐๐๐ก๐๐๐ข๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐๐๐๐ก ๐ก๐ ๐ โ๐ฆ๐๐๐ก๐๐๐ข๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐ ๐๐ก๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐๐๐๐ก ๐ก๐ ๐ csc ๐ = sec ๐ = cot ๐ = โ๐ฆ๐๐๐ก๐๐๐ข๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐ ๐๐ก๐ ๐ โ๐ฆ๐๐๐ก๐๐๐ข๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐๐๐๐ก ๐ก๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐๐๐๐ก ๐ก๐ ๐ ๐ ๐๐๐ ๐๐๐๐๐ ๐๐ก๐ ๐ Converting Between Degree & Radian Measure To convert from degree to radian measure, multiply by To convert from radian to degree measure, multiply by ๐ 180° 180° ๐ Arc Length and Angular Speed Variables ๐ = ๐๐๐ ๐ก๐๐๐๐ ๐ก๐๐๐ฃ๐๐๐๐ or ๐๐๐ ๐๐๐๐๐กโ (๐๐๐โ๐๐ , ๐๐๐๐๐๐๐ก๐๐๐ , ๐๐ก๐) ๐ก = ๐ก๐๐๐ (๐ ๐๐๐๐๐๐ , ๐๐๐๐ข๐ก๐๐ , โ๐๐ข๐๐ , ๐๐๐ฆ๐ , ๐๐ก๐) ๐ = ๐๐๐๐ข๐๐ก ๐๐ ๐๐๐ก๐๐ก๐๐๐ or ๐๐๐๐๐ข๐๐๐ ๐๐๐๐๐ (๐๐๐๐๐๐๐ , ๐๐๐๐๐๐๐ , ๐๐๐ก๐๐ก๐๐๐๐ , ๐๐๐ฃ๐๐๐ข๐ก๐๐๐๐ , ๐๐ก๐) ๐ = ๐๐๐๐๐ข๐ ๐๐ ๐๐๐ ๐ก๐๐๐๐ ๐๐๐๐ ๐กโ๐ ๐๐๐๐ก๐๐ ๐๐ ๐๐๐ก๐๐ก๐๐๐ (๐๐๐๐ก๐๐๐๐ก๐๐๐ , ๐๐๐โ๐๐ , ๐๐ก๐) ๐๐๐ ๐ก๐๐๐๐ v = linear speed = ๐ก๐๐๐ ๐๐๐๐ข๐๐ก ๐๐ ๐๐๐ก๐๐ก๐๐๐ ๐ = ๐๐๐๐ข๐๐๐ ๐ ๐๐๐๐ = ๐ก๐๐๐ Formulas ๐ θ ๐ = ๐๐ , ๐ฃ= , ω= , ๐ฃ = ๐ω ๐ก t Dimensional analysis conversion factors 5280 ๐๐ก 12 ๐๐ 2๐ ๐ 60 ๐๐๐ 60 ๐ ๐๐ , , , , , , ๐๐๐ ๐กโ๐๐๐ ๐๐๐๐๐๐๐๐๐๐๐ 1 ๐๐ 1 ๐๐ก 1 ๐๐๐ฃ 180° 1 โ๐ 1 ๐๐๐ Example problem: A car travels at 60 miles per hour. Its wheels have a 24-inch diameter. What is the angular speed of a point on the rim of a wheel in revolutions per minute? Solution: ๐ฃ = 60 ๐๐ 1 โ๐ , = 12 ๐๐ , ๐ = ? Equation relating these variables: ๐ฃ = ๐๐ ๐ฃ 1 60 ๐๐ 1 1 โ๐ 5280 ๐๐ก 12 ๐๐ 1 ๐๐๐ฃ 2640 ๐๐๐ฃ ๐= =๐ฃโ = โ โ โ โ โ = ๐ ๐ 1 โ๐ 12 ๐๐ 60 ๐๐๐ 1 ๐๐ 1 ๐๐ก 2๐ ๐ ๐๐๐ Reciprocal Identities 1 csc ๐ฅ = sin ๐ฅ 1 sin ๐ฅ = sec ๐ฅ = cos ๐ฅ = cot ๐ฅ = csc ๐ฅ 1 cos ๐ฅ 1 sec ๐ฅ 1 tan ๐ฅ 1 tan ๐ฅ = cot ๐ฅ Ratio Identities tan x = cot ๐ฅ = sinx cos x cos ๐ฅ Odd-Even Identities cos(−๐ฅ) = cos ๐ฅ , sin(−๐ฅ) = − sin ๐ฅ , tan(−๐ฅ) = − tan ๐ฅ sec(−๐ฅ) = sec ๐ฅ , csc(−๐ฅ) = − csc ๐ฅ , cot(−๐ฅ) = − cot ๐ฅ Sum and Difference Identities sin(๐ + ๐) = sin ๐ cos ๐ + cos ๐ sin ๐ sin(๐ − ๐) = sin ๐ cos ๐ − cos ๐ sin ๐ cos(๐ + ๐) = cos ๐ cos ๐ − sin ๐ sin ๐ cos(๐ − ๐) = cos ๐ cos ๐ + sin ๐ sin ๐ tan(๐ + ๐) = sin ๐ฅ Pythagorean Identities sin2 ๐ฅ + cos2 ๐ฅ = 1 , 1 + cot 2 ๐ฅ = csc 2 ๐ฅ , tan2 ๐ฅ + 1 = sec 2 ๐ฅ tan(๐ − ๐) = tan ๐+tan ๐ 1−tan ๐ tan ๐ tan ๐−tan ๐ 1+tan ๐ tan ๐ Cofunction Identities ๐ sin ( − ๐ฅ) = cos ๐ฅ 2 ๐ Half-Angle Identities , cos ( − ๐ฅ) = sin ๐ฅ 2 ๐ tan ( − ๐ฅ) = cot ๐ฅ 2 ๐ , 2 csc ( − ๐ฅ) = sec ๐ฅ 2 ๐ , sec ( − ๐ฅ) = csc ๐ฅ 2 Double-Angle Identities sin 2๐ฅ = 2 sin ๐ฅ cos ๐ฅ cos 2๐ฅ = cos2 ๐ฅ − sin2 ๐ฅ cos 2๐ฅ = 2 cos2 ๐ฅ − 1 cos 2๐ฅ = 1 − 2 sin2 ๐ฅ tan 2๐ฅ = 2 tan ๐ฅ 1−tan2 ๐ฅ 1−cos ๐ฅ 2 2 ๐ฅ 1+cos ๐ฅ cos = ±√ 2 2 ๐ฅ 1−cos ๐ฅ 2 ๐ฅ 1+cos ๐ฅ sin ๐ฅ tan = ±√ cot ( − ๐ฅ) = tan ๐ฅ ๐ ๐ฅ sin = ±√ tan = 2 ๐ฅ 1+cos ๐ฅ 1−cos ๐ฅ 2 sin ๐ฅ tan = Solving Triangles Law of Sines sin ๐ด ๐ = sin ๐ต ๐ = sin ๐ถ ๐ or ๐ sin ๐ด = ๐ sin ๐ต = ๐ sin ๐ถ Law of Cosines ๐ 2 = ๐2 + ๐ 2 − 2๐๐ cos ๐ถ ๐ 2 = ๐2 + ๐ 2 − 2๐๐ cos ๐ต ๐2 = ๐ 2 + ๐ 2 − 2๐๐ cos ๐ด Area of a Triangle 1 1 1 ๐พ = ๐๐ sin ๐ด = ๐๐ sin ๐ต = ๐๐ sin ๐ถ 2 2 2 Vectors โโโโโโ with ๐ด = (๐ฅ1 , ๐ฆ1 ) and ๐ถ = (๐ฅ2 , ๐ฆ2 ) is ๐ด๐ถ โโโโโโ = 〈๐ฅ2 − ๐ฅ1 , ๐ฆ2 − ๐ฆ1 〉 The component form of ๐ด๐ถ โโ| = √๐๐ + ๐๐ The magnitude of a vector ๐ฃโ with component form 〈๐, ๐〉 is |๐ ๐ The reference angle ๐ผ for the direction angle ๐ of the vector 〈๐, ๐〉 is given by ๐ผ = |tan−1 |. Figure out ๐ which quadrant this angle should be in and measure the angle counterclockwise from the positive x-axis. The horizontal component of the vector 〈๐, ๐〉 is ๐ = |๐ฃโ| cos ๐ The vertical component of the vector 〈๐, ๐〉 is ๐ = |๐ฃโ| sin ๐ For a real number ๐ and a vector ๐ฃโ = 〈๐ฃ1 , ๐ฃ2 〉, the scalar product of ๐ and ๐ฃโ is ๐๐ฃโ = ๐〈๐ฃ1 , ๐ฃ2 〉 = 〈๐๐ฃ1 , ๐๐ฃ2 〉. The vector ๐๐ฃโ is a scalar multiple of the vector ๐ฃโ. โโ ± ๐ โโ = 〈๐๐ ± ๐๐ , ๐๐ ± ๐๐ 〉 . Vector Addition/Subtraction: If ๐ข โโ = 〈๐ข1 , ๐ข2 〉 and ๐ฃโ = 〈๐ฃ1 , ๐ฃ2 〉, then ๐ โโ ๐ If ๐ฃโ is a vector and ๐ฃโ ≠ โ0โ, then |๐โโ| is a unit vector (vector with magnitude 1) in the direction of ๐ฃโ. โโ โ ๐ โโ = ๐๐ ๐๐ + ๐๐ ๐๐ . The dot product of two vectors ๐ข โโ = 〈๐ข1 , ๐ข2 〉 and ๐ฃโ = 〈๐ฃ1 , ๐ฃ2 〉 is ๐ โโโโ๐ โโ ๐ If ๐ is the angle between two nonzero vectors ๐ข โโ and ๐ฃโ, then ๐๐จ๐ฌ ๐ฝ = |๐โโโ||๐โโ| . Trigonometric Form of Complex Numbers A complex number ๐ง = ๐ + ๐๐, where ๐ = √−1 can be written in trigonometric form as ๐ง = ๐(cos ๐ + ๐ sin ๐) or ๐ง = ๐ cis ๐, where ๐ = √๐2 + ๐ 2 is the modulus of ๐ง and direction angle ๐ is referred to as the argument. ๐ง1 ๐ง2 = ๐1 ๐2 [cos(๐1 + ๐2 ) + ๐ sin(๐1 + ๐2 )] = ๐1 ๐2 cis ๐ ๐ง1 ๐1 ๐1 = [cos(๐1 − ๐2 ) + ๐ sin(๐1 − ๐2 )] = cis ๐ ๐ง2 ๐2 ๐2 ๐ง ๐ = ๐ ๐ [cos(๐๐) + ๐ sin(๐๐)] = ๐ ๐ cis(๐๐)