Geometry Fall 2014 Lesson 060 _Using Similar triangles to prove

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Lesson Plan #60
Date: Friday February 6th, 2015
Class: Geometry
Topic: Using proportions involving corresponding line segments.
Aim: How can we use proportions involving corresponding line segments?
Objectives:
1) Students will students will know that properties of polygons
that are similar.
HW# 60:
Do Now:
Given:
βˆ†π΄π΅πΆ
Μ…Μ…Μ…Μ…
𝐷𝐸 𝑖𝑠 π‘Ž π‘šπ‘–π‘‘π‘ π‘’π‘”π‘šπ‘’π‘›π‘‘
Prove:
𝐴𝐡 𝐷𝐸
=
𝐴𝐢 𝐷𝐢
Statements
Reasons
1. βˆ†π΄π΅πΆ
1.
2. Μ…Μ…Μ…Μ…
𝐷𝐸
2.
𝑖𝑠 π‘Ž π‘šπ‘–π‘‘π‘ π‘’π‘”π‘šπ‘’π‘›π‘‘
3.
3.
Note: Below is a selection of definitions, theorems and postulates we’ve covered so far in this unit:
1) A line that is parallel to one side of a triangle and intersects the other two sides in different points cuts off a triangle similar
to the given triangle.
2) Two triangles are similar if two angles of one triangle are congruent to two corresponding angles of the other.
3) If a line divides two sides of a triangle proportionally, the line is parallel to the third side.
4) If a line is parallel to one side of a triangle and intersects the other two sides, the line divides those sides proportionally.
5) If a line segment joins the midpoints of two sides of a triangle, the segment is parallel to the third side and its length is onehalf the length of the third side.
6) In a proportion, the product of the means is equal to the product of the extremes.
7) If two polygons are similar, then their corresponding angles are congruent and their corresponding sides are in proportion.
Assignment #1:
Given: Μ…Μ…Μ…Μ…
𝐴𝐡 βˆ₯ Μ…Μ…Μ…Μ…
𝐷𝐢
Prove:
𝐴𝐸
𝐢𝐸
𝐡𝐸
= 𝐷𝐸
Statements
Reasons
2
PROCEDURE:
Write the Aim and Do Now
Get students working!
Take attendance
Give Back HW
Collect HW
Go over the Do Now
In the proof above, what reason could we use to prove 𝐢𝐸 π‘₯ 𝐡𝐸 = 𝐴𝐸 π‘₯ 𝐷𝐸
Assignment #2:
Μ…Μ…Μ…Μ…Μ…Μ… , Parallelogram ABCD
Given: 𝐷𝐸𝐹
Prove: 𝐷𝐸 π‘₯ 𝐡𝐸 = 𝐹𝐸 π‘₯ 𝐢𝐸
Statements
Assignment #3:
Μ…Μ…Μ…Μ… and Μ…Μ…Μ…Μ…
Given: βˆ†π΄π΅πΆ ~βˆ†π·πΈπΉ, 𝐴𝐷
𝐷𝐺 are altitudes
𝐴𝐷
𝐴𝐡
Prove:
=
𝐷𝐺
𝐷𝐸
Reasons
D
G
Statements
Reasons
Theorem: If two triangles are similar, the lengths of corresponding altitudes have the same ratio as the lengths of any two
corresponding sides.
Corollary: In two similar triangles, the lengths of any two corresponding line segments have the same ratio as the lengths of any
pair of corresponding sides.
Assignment #4:
3
Assignment #5: Answer the following multiple choice questions:
A)
B)
Assignment #6: Complete the proof below:
Statements
Assignment #7:
Reasons
4
If Enough Time: Answer the sample test questions
1)
2)
3)
4)
5)
6)
7)
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